狠狠撸shows by User: mikhajduk
/
http://www.slideshare.net/images/logo.gif狠狠撸shows by User: mikhajduk
/
Thu, 21 Jan 2016 18:19:19 GMT狠狠撸Share feed for 狠狠撸shows by User: mikhajdukPtolemy's theorem visualisation. 3D graphics.
/slideshow/ptolemys-theorem-visualisation-3d-graphics/57338468
ptolemystheorem-160121181919 Ptolemy's theorem states the following: a convex quadrilateral can be inscribed in a circle if and only if the product of the lengths of one pair of opposite sides added to the product of the lengths of the other pair is equal to the product of the lengths of the diagonals. Thus, in a cyclic quadrilateral ABCD we have
AB*DC + AD*BC = AC*BD
]]>
Ptolemy's theorem states the following: a convex quadrilateral can be inscribed in a circle if and only if the product of the lengths of one pair of opposite sides added to the product of the lengths of the other pair is equal to the product of the lengths of the diagonals. Thus, in a cyclic quadrilateral ABCD we have
AB*DC + AD*BC = AC*BD
]]>
Thu, 21 Jan 2016 18:19:19 GMT/slideshow/ptolemys-theorem-visualisation-3d-graphics/57338468mikhajduk@slideshare.net(mikhajduk)Ptolemy's theorem visualisation. 3D graphics.mikhajdukPtolemy's theorem states the following: a convex quadrilateral can be inscribed in a circle if and only if the product of the lengths of one pair of opposite sides added to the product of the lengths of the other pair is equal to the product of the lengths of the diagonals. Thus, in a cyclic quadrilateral ABCD we have
AB*DC + AD*BC = AC*BD
<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/ptolemystheorem-160121181919-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> Ptolemy's theorem states the following: a convex quadrilateral can be inscribed in a circle if and only if the product of the lengths of one pair of opposite sides added to the product of the lengths of the other pair is equal to the product of the lengths of the diagonals. Thus, in a cyclic quadrilateral ABCD we have
AB*DC + AD*BC = AC*BD
]]>
1964https://cdn.slidesharecdn.com/ss_thumbnails/ptolemystheorem-160121181919-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0An inequality painted on the vase body.
/slideshow/an-inequality-painted-on-the-vase-body/57286424
vaseinequality-160120165259 The 3D picture shows an attempt at combining applied art with pure mathematics. The vase shown in the picture is an example of ceramic vessel that could exist in real world.]]>
The 3D picture shows an attempt at combining applied art with pure mathematics. The vase shown in the picture is an example of ceramic vessel that could exist in real world.]]>
Wed, 20 Jan 2016 16:52:59 GMT/slideshow/an-inequality-painted-on-the-vase-body/57286424mikhajduk@slideshare.net(mikhajduk)An inequality painted on the vase body.mikhajdukThe 3D picture shows an attempt at combining applied art with pure mathematics. The vase shown in the picture is an example of ceramic vessel that could exist in real world.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/vaseinequality-160120165259-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> The 3D picture shows an attempt at combining applied art with pure mathematics. The vase shown in the picture is an example of ceramic vessel that could exist in real world.
]]>
1014https://cdn.slidesharecdn.com/ss_thumbnails/vaseinequality-160120165259-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Still life with vases - a 3D visualisation.
/slideshow/still-life-with-vases-a-3d-visualisation/57285587
stilllifewithvases-160120163328 The picture presenting a still life with two vases made of black polished ceramics, standing on blocks of granite and limestone, placed in an empty room illuminated by sunlight going through a big window.]]>
The picture presenting a still life with two vases made of black polished ceramics, standing on blocks of granite and limestone, placed in an empty room illuminated by sunlight going through a big window.]]>
Wed, 20 Jan 2016 16:33:28 GMT/slideshow/still-life-with-vases-a-3d-visualisation/57285587mikhajduk@slideshare.net(mikhajduk)Still life with vases - a 3D visualisation.mikhajdukThe picture presenting a still life with two vases made of black polished ceramics, standing on blocks of granite and limestone, placed in an empty room illuminated by sunlight going through a big window.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/stilllifewithvases-160120163328-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> The picture presenting a still life with two vases made of black polished ceramics, standing on blocks of granite and limestone, placed in an empty room illuminated by sunlight going through a big window.
]]>
1435https://cdn.slidesharecdn.com/ss_thumbnails/stilllifewithvases-160120163328-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0How to draw arcs of huge circles - usage of the "drawing tool".
/slideshow/how-to-draw-arcs-of-huge-circles-usage-of-the-drawing-tool/57285112
woodenblockusage-160120162324 The slide explaining visually the procedure of drawing huge circles. A theoretical background of the method has been described in another slide.]]>
The slide explaining visually the procedure of drawing huge circles. A theoretical background of the method has been described in another slide.]]>
Wed, 20 Jan 2016 16:23:24 GMT/slideshow/how-to-draw-arcs-of-huge-circles-usage-of-the-drawing-tool/57285112mikhajduk@slideshare.net(mikhajduk)How to draw arcs of huge circles - usage of the "drawing tool".mikhajdukThe slide explaining visually the procedure of drawing huge circles. A theoretical background of the method has been described in another slide.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/woodenblockusage-160120162324-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> The slide explaining visually the procedure of drawing huge circles. A theoretical background of the method has been described in another slide.
]]>
1184https://cdn.slidesharecdn.com/ss_thumbnails/woodenblockusage-160120162324-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0How to draw arcs of huge circles - description.
/mikhajduk/how-to-draw-arcs-of-huge-circles-description
woodenblockdescription-160120133534 In case you are interested in drawing circles with a huge diameter (by "huge" I mean here really big ones, measured in kilometers or so) there is a tricky idea needed because the rope-and-the-stick method won't work for circles with a diameter bigger than several dozen meters. Here you can use a method based on the well known fact from geometry stating that all angles inscribed in a circle and subtended by the same chord (lying on the same side of the chord) are equal.]]>
In case you are interested in drawing circles with a huge diameter (by "huge" I mean here really big ones, measured in kilometers or so) there is a tricky idea needed because the rope-and-the-stick method won't work for circles with a diameter bigger than several dozen meters. Here you can use a method based on the well known fact from geometry stating that all angles inscribed in a circle and subtended by the same chord (lying on the same side of the chord) are equal.]]>
Wed, 20 Jan 2016 13:35:34 GMT/mikhajduk/how-to-draw-arcs-of-huge-circles-descriptionmikhajduk@slideshare.net(mikhajduk)How to draw arcs of huge circles - description.mikhajdukIn case you are interested in drawing circles with a huge diameter (by "huge" I mean here really big ones, measured in kilometers or so) there is a tricky idea needed because the rope-and-the-stick method won't work for circles with a diameter bigger than several dozen meters. Here you can use a method based on the well known fact from geometry stating that all angles inscribed in a circle and subtended by the same chord (lying on the same side of the chord) are equal.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/woodenblockdescription-160120133534-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> In case you are interested in drawing circles with a huge diameter (by "huge" I mean here really big ones, measured in kilometers or so) there is a tricky idea needed because the rope-and-the-stick method won't work for circles with a diameter bigger than several dozen meters. Here you can use a method based on the well known fact from geometry stating that all angles inscribed in a circle and subtended by the same chord (lying on the same side of the chord) are equal.
]]>
1284https://cdn.slidesharecdn.com/ss_thumbnails/woodenblockdescription-160120133534-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Calculation of the volume of a bottle partially filled with a fluid.
/slideshow/calculation-of-the-volume-of-a-bottle-partially-filled-with-a-fluid/57276337
bottlesslideshare-160120132606 How to calculate the volume of a flat-bottomed, corked bottle, partially filled with a fluid having only the ruler as a measuring tool?
The 3D graphics made by me and presented below gives an answer to this question.]]>
How to calculate the volume of a flat-bottomed, corked bottle, partially filled with a fluid having only the ruler as a measuring tool?
The 3D graphics made by me and presented below gives an answer to this question.]]>
Wed, 20 Jan 2016 13:26:05 GMT/slideshow/calculation-of-the-volume-of-a-bottle-partially-filled-with-a-fluid/57276337mikhajduk@slideshare.net(mikhajduk)Calculation of the volume of a bottle partially filled with a fluid.mikhajdukHow to calculate the volume of a flat-bottomed, corked bottle, partially filled with a fluid having only the ruler as a measuring tool?
The 3D graphics made by me and presented below gives an answer to this question.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/bottlesslideshare-160120132606-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> How to calculate the volume of a flat-bottomed, corked bottle, partially filled with a fluid having only the ruler as a measuring tool?
The 3D graphics made by me and presented below gives an answer to this question.
]]>
1834https://cdn.slidesharecdn.com/ss_thumbnails/bottlesslideshare-160120132606-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Permutation theorem and its use to proving inequalities.
/slideshow/permutation-theorem-and-its-use-to-proving-inequalities/53902672
permutationtheorem-151013234839-lva1-app6891 The permutation theorem is very useful when dealing with inequalities between sums of products of the two real number sequences. In numerous cases inequalities otherwise difficult to prove can be proven almost automatically.]]>
The permutation theorem is very useful when dealing with inequalities between sums of products of the two real number sequences. In numerous cases inequalities otherwise difficult to prove can be proven almost automatically.]]>
Tue, 13 Oct 2015 23:48:39 GMT/slideshow/permutation-theorem-and-its-use-to-proving-inequalities/53902672mikhajduk@slideshare.net(mikhajduk)Permutation theorem and its use to proving inequalities.mikhajdukThe permutation theorem is very useful when dealing with inequalities between sums of products of the two real number sequences. In numerous cases inequalities otherwise difficult to prove can be proven almost automatically.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/permutationtheorem-151013234839-lva1-app6891-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> The permutation theorem is very useful when dealing with inequalities between sums of products of the two real number sequences. In numerous cases inequalities otherwise difficult to prove can be proven almost automatically.
]]>
1084https://cdn.slidesharecdn.com/ss_thumbnails/permutationtheorem-151013234839-lva1-app6891-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0The sum of the triangle sides lengths reciprocals vs a cyclic sum of a specific form.
/slideshow/the-sum-of-the-triangle-sides-lengths-reciprocals-vs-a-cyclic-sum-of-a-specific-form/53839371
trianglesidesineqproof-151012173705-lva1-app6892 Proof of the inequality between the sum of the reciprocals of a triangle sides lengths and a cyclic sum of a specific form. Use of a transformed inequality between the arithmetic mean and the harmonic mean. ]]>
Proof of the inequality between the sum of the reciprocals of a triangle sides lengths and a cyclic sum of a specific form. Use of a transformed inequality between the arithmetic mean and the harmonic mean. ]]>
Mon, 12 Oct 2015 17:37:05 GMT/slideshow/the-sum-of-the-triangle-sides-lengths-reciprocals-vs-a-cyclic-sum-of-a-specific-form/53839371mikhajduk@slideshare.net(mikhajduk)The sum of the triangle sides lengths reciprocals vs a cyclic sum of a specific form.mikhajdukProof of the inequality between the sum of the reciprocals of a triangle sides lengths and a cyclic sum of a specific form. Use of a transformed inequality between the arithmetic mean and the harmonic mean. <img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/trianglesidesineqproof-151012173705-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> Proof of the inequality between the sum of the reciprocals of a triangle sides lengths and a cyclic sum of a specific form. Use of a transformed inequality between the arithmetic mean and the harmonic mean.
]]>
2294https://cdn.slidesharecdn.com/ss_thumbnails/trianglesidesineqproof-151012173705-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Complex Integral
/slideshow/complex-integral/52870680
complexintegralfb-150917003048-lva1-app6892 Evaluation of integrals of the given functions along the unit circle on the complex plane. Application of the parametrization method. Evaluation of the integral of an odd function.]]>
Evaluation of integrals of the given functions along the unit circle on the complex plane. Application of the parametrization method. Evaluation of the integral of an odd function.]]>
Thu, 17 Sep 2015 00:30:48 GMT/slideshow/complex-integral/52870680mikhajduk@slideshare.net(mikhajduk)Complex IntegralmikhajdukEvaluation of integrals of the given functions along the unit circle on the complex plane. Application of the parametrization method. Evaluation of the integral of an odd function.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/complexintegralfb-150917003048-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> Evaluation of integrals of the given functions along the unit circle on the complex plane. Application of the parametrization method. Evaluation of the integral of an odd function.
]]>
10924https://cdn.slidesharecdn.com/ss_thumbnails/complexintegralfb-150917003048-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Indescribable numbers
/slideshow/indescribable-numbers/51633621
indescribable-150814150439-lva1-app6892 A few digressions on the theme of indescribable numbers. Proof of the fact that there exist real numbers that may be indescribable, i.e. impossible to express in any language based on the finite alphabet of symbols.]]>
A few digressions on the theme of indescribable numbers. Proof of the fact that there exist real numbers that may be indescribable, i.e. impossible to express in any language based on the finite alphabet of symbols.]]>
Fri, 14 Aug 2015 15:04:38 GMT/slideshow/indescribable-numbers/51633621mikhajduk@slideshare.net(mikhajduk)Indescribable numbersmikhajdukA few digressions on the theme of indescribable numbers. Proof of the fact that there exist real numbers that may be indescribable, i.e. impossible to express in any language based on the finite alphabet of symbols.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/indescribable-150814150439-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> A few digressions on the theme of indescribable numbers. Proof of the fact that there exist real numbers that may be indescribable, i.e. impossible to express in any language based on the finite alphabet of symbols.
]]>
1775https://cdn.slidesharecdn.com/ss_thumbnails/indescribable-150814150439-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Late Spring 2015 Photos
/mikhajduk/late-spring2015
latespring2015-150623192337-lva1-app6892 Photos taken in May and June 2015.]]>
Photos taken in May and June 2015.]]>
Tue, 23 Jun 2015 19:23:37 GMT/mikhajduk/late-spring2015mikhajduk@slideshare.net(mikhajduk)Late Spring 2015 PhotosmikhajdukPhotos taken in May and June 2015.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/latespring2015-150623192337-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> Photos taken in May and June 2015.
]]>
1431https://cdn.slidesharecdn.com/ss_thumbnails/latespring2015-150623192337-lva1-app6892-thumbnail.jpg?width=120&height=120&fit=boundspresentationBlackhttp://activitystrea.ms/schema/1.0/posthttp://activitystrea.ms/schema/1.0/posted0Cube root
/slideshow/cube-root-49631334/49631334
cuberoot-150620125338-lva1-app6891 A mathematical explanation of a simple trick that shows how to quickly calculate the cube root of a maximally 6-digit number that was given by a spectator. The spectator chooses a natural two-digit number, keeps it in secret and only information he/she gives publicly is its cube. Conjurer's task is to quickly guess the original number.]]>
A mathematical explanation of a simple trick that shows how to quickly calculate the cube root of a maximally 6-digit number that was given by a spectator. The spectator chooses a natural two-digit number, keeps it in secret and only information he/she gives publicly is its cube. Conjurer's task is to quickly guess the original number.]]>
Sat, 20 Jun 2015 12:53:37 GMT/slideshow/cube-root-49631334/49631334mikhajduk@slideshare.net(mikhajduk)Cube rootmikhajdukA mathematical explanation of a simple trick that shows how to quickly calculate the cube root of a maximally 6-digit number that was given by a spectator. The spectator chooses a natural two-digit number, keeps it in secret and only information he/she gives publicly is its cube. Conjurer's task is to quickly guess the original number.<img style="border:1px solid #C3E6D8;float:right;" alt="" src="https://cdn.slidesharecdn.com/ss_thumbnails/cuberoot-150620125338-lva1-app6891-thumbnail.jpg?width=120&height=120&fit=bounds" /><br> A mathematical explanation of a simple trick that shows how to quickly calculate the cube root of a maximally 6-digit number that was given by a spectator. The spectator chooses a natural two-digit number, keeps it in secret and only information he/she gives publicly is its cube. Conjurer's task is to quickly guess the original number.