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Assume no energie loss, calculate
difference in pressure




     D=0,15 m     D=0,30 m

    Q=140 l/s
Cu06997 computation lecture3
Cu06997 computation lecture3
Cu06997 computation lecture3
Cu06997 computation lecture3
Cu06997 computation lecture3
Solution

   u2/2g=3,14 m                  u2/2g=0,20 m

                     ∆p=3,14 – 0,20 = 2,94 m




  D=0,15 m        D=0,30 m


  Q=140 l/s
Assume no energie loss, calculate
difference in pressure




    D1=0.3m                D2=0.15m

                 Q=0.14 m3/s
Cu06997 computation lecture3
Solution


   u2/2g=0,20 m        u2/2g=3,14 m


                      ∆p=0,20-3,14 = -2,94 m




   D1=0.3m                  D2=0.15m

                  Q=0.14 m3/s

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Cu06997 computation lecture3

  • 1. Assume no energie loss, calculate difference in pressure D=0,15 m D=0,30 m Q=140 l/s
  • 7. Solution u2/2g=3,14 m u2/2g=0,20 m ∆p=3,14 – 0,20 = 2,94 m D=0,15 m D=0,30 m Q=140 l/s
  • 8. Assume no energie loss, calculate difference in pressure D1=0.3m D2=0.15m Q=0.14 m3/s
  • 10. Solution u2/2g=0,20 m u2/2g=3,14 m ∆p=0,20-3,14 = -2,94 m D1=0.3m D2=0.15m Q=0.14 m3/s