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P4 Multiplication & Division Problem Sums

Erin Kwan
Erin Kwan

The document contains worked examples of word problems involving multiplication and division. It provides step-by-step explanations and diagrams showing how to extract relevant information, model the relationships mathematically, and arrive at the solution. The problems cover a range of scenarios involving groups of people, costs, lengths, and masses. Key steps involve identifying the quantities given, determining relationships between quantities, and setting up and solving equations to find the unknown value.

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Primary 4 Multiplication and Division Word Problems
Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party?
Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extract Info: C -> 4u Draw the models A -> 1u according to your extracted info. Notice the number of children remains unchanged. Therefore, we multiply 4u by 5 to get 20u for the children. Logically, we also multiply 1u by 5 for the adults. C -> 20u ? A -> 5u - 16
Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extracted Info C -> 20u A -> 5u - 16 C ? A 16
Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extracted Info C -> 20u A -> 5u - 16 C ? A 16 4u -> 16 1u -> 16 歎 4 = 4
Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extracted Info C -> 20u A -> 5u - 16 C ? A 16 4u -> 16 1u -> 16 歎 4 = 4 25u -> 25 x 4 = 100 100 people attended the party.
Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul?
Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> 2u Draw the models Paul -> 1u according to your extracted info. Notice Mark's money remains unchanged. Therefore, we multiply 2u by 3 to get 6u for Mark. Logically, we also multiply 1u by 3 for Paul. Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60
Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark ? Paul 60
Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark 2u -> 60 ? Paul 60
Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark 2u -> 60 1u -> 60 歎 2 = 30 ? Paul 60
Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark 2u -> 60 1u -> 60 歎 2 = 30 ? 3u -> 30 x 3 = 90 Paul 60 Mark brought $90 more than Paul.
Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 We know the cost of 1 pen. So let's find the cost of 5 pens.
Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 P -> $8 5P -> 5 x $8 = $40
Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 P -> $8 5P -> 5 x $8 = $40 Cost of 3 erasers -> Total cost Cost of 5 pens -> $52 $40 -> $12
Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 P -> $8 5P -> 5 x $8 = $40 Cost of 3 erasers -> Total cost Cost of 5 pens -> $52 $40 -> $12 Cost of 1 eraser -> $12 歎 3 = $4
Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes.
Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes. R -> 46 cm 4R -> 46 x 4 = 184 cm
Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes. R -> 46 cm 4R -> 46 x 4 = 184 cm Length of 6 strings -> Total length 4R -> 334 184 -> 150 cm
Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes. R -> 46 cm 4R -> 46 x 4 = 184 cm Length of 6 strings -> Total length 4R -> 334 184 -> 150 cm Length of 1 string -> 150 歎 6 = 25 cm
Multiplication & Division Problem Sums The total mass of 3 watermelons and 8 mangoes is 76kg. Each watermelon weighs 12kg. Find the mass of each mango. Extract Info: 3W + 8M = 76 (Total mass) W = 12 We know the mass of 1 watermelon. So let's find the mass of 3 watermelons.
Multiplication & Division Problem Sums The total mass of 3 watermelons and 8 mangoes is 76kg. Each watermelon weighs 12kg. Find the mass of each mango. Extract Info: 3W + 8M = 76 (Total mass) W = 12 We know the mass of 1 watermelon. So let's find the mass of 3 watermelons. W -> 12 kg 3W -> x = Mass of 8 mangoes -> Total mass 3W Mass of 1 mango -> Mass of 8 mangoes 歎 8 =

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P4 Multiplication & Division Problem Sums

  • 1. Primary 4 Multiplication and Division Word Problems
  • 2. Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party?
  • 3. Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extract Info: C -> 4u Draw the models A -> 1u according to your extracted info. Notice the number of children remains unchanged. Therefore, we multiply 4u by 5 to get 20u for the children. Logically, we also multiply 1u by 5 for the adults. C -> 20u ? A -> 5u - 16
  • 4. Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extracted Info C -> 20u A -> 5u - 16 C ? A 16
  • 5. Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extracted Info C -> 20u A -> 5u - 16 C ? A 16 4u -> 16 1u -> 16 歎 4 = 4
  • 6. Multiplication & Division Problem Sums There were 4 times as many children as adults in a party. After 16 adults left, the number of children in the party was 20 times the number of the remaining adults. How many people attended the party? Extracted Info C -> 20u A -> 5u - 16 C ? A 16 4u -> 16 1u -> 16 歎 4 = 4 25u -> 25 x 4 = 100 100 people attended the party.
  • 7. Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul?
  • 8. Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> 2u Draw the models Paul -> 1u according to your extracted info. Notice Mark's money remains unchanged. Therefore, we multiply 2u by 3 to get 6u for Mark. Logically, we also multiply 1u by 3 for Paul. Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60
  • 9. Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark ? Paul 60
  • 10. Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark 2u -> 60 ? Paul 60
  • 11. Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark 2u -> 60 1u -> 60 歎 2 = 30 ? Paul 60
  • 12. Multiplication & Division Problem Sums Mark went shopping with twice as much money as Paul. After Paul spent $60, Mark had 6 times as much money as Paul. How much more money did Mark bring along for shopping than Paul? Extract Info: Mark -> (2u x 3) = 6u Paul -> (1u x 3) = 3u - 60 Mark 2u -> 60 1u -> 60 歎 2 = 30 ? 3u -> 30 x 3 = 90 Paul 60 Mark brought $90 more than Paul.
  • 13. Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 We know the cost of 1 pen. So let's find the cost of 5 pens.
  • 14. Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 P -> $8 5P -> 5 x $8 = $40
  • 15. Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 P -> $8 5P -> 5 x $8 = $40 Cost of 3 erasers -> Total cost Cost of 5 pens -> $52 $40 -> $12
  • 16. Multiplication & Division Problem Sums The total cost of 3 erasers and 5 pens is $52. Each pen costs $8. Find the cost of each eraser. Extract Info: 3E + 5P = 52 (Total cost) P = 8 P -> $8 5P -> 5 x $8 = $40 Cost of 3 erasers -> Total cost Cost of 5 pens -> $52 $40 -> $12 Cost of 1 eraser -> $12 歎 3 = $4
  • 17. Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes.
  • 18. Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes. R -> 46 cm 4R -> 46 x 4 = 184 cm
  • 19. Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes. R -> 46 cm 4R -> 46 x 4 = 184 cm Length of 6 strings -> Total length 4R -> 334 184 -> 150 cm
  • 20. Multiplication & Division Problem Sums The total length of 4 ropes and 6 strings is 334cm. The length of each rope is 46cm. Find the length of each string. Extract Info: 4R + 6S = 334 (Total length) R = 46 We know the length of 1 rope. So let's find the length of 4 ropes. R -> 46 cm 4R -> 46 x 4 = 184 cm Length of 6 strings -> Total length 4R -> 334 184 -> 150 cm Length of 1 string -> 150 歎 6 = 25 cm
  • 21. Multiplication & Division Problem Sums The total mass of 3 watermelons and 8 mangoes is 76kg. Each watermelon weighs 12kg. Find the mass of each mango. Extract Info: 3W + 8M = 76 (Total mass) W = 12 We know the mass of 1 watermelon. So let's find the mass of 3 watermelons.
  • 22. Multiplication & Division Problem Sums The total mass of 3 watermelons and 8 mangoes is 76kg. Each watermelon weighs 12kg. Find the mass of each mango. Extract Info: 3W + 8M = 76 (Total mass) W = 12 We know the mass of 1 watermelon. So let's find the mass of 3 watermelons. W -> 12 kg 3W -> x = Mass of 8 mangoes -> Total mass 3W Mass of 1 mango -> Mass of 8 mangoes 歎 8 =