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NO
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41

A
DATA
MINAT
68
69
70
71
71
71
71
72
72
72
73
73
74
75
75
76
76
76
76
76
76
77
77
77
77
78
78
78
79
79
79
79
79
80
80
80
80
81
81
81
81

B
DATA
SAINS
60
63
66
70
71
71
72
72
72
73
74
75
75
76
76
76
77
78
78
78
78
79
79
79
79
80
80
80
80
80
80
81
81
82
82
83
83
83
83
83
84

A-B
8
6
4
1
0
0
-1
0
0
-1
-1
-2
-1
-1
-1
0
-1
-2
-2
-2
-2
-2
-2
-2
-2
-2
-2
-2
-1
-1
-1
-2
-2
-2
-2
-3
-3
-2
-2
-2
-3

RANK-B
RANK
POSITIF NEGATIF
A-B
45
45
44
44
38.5
38.5
6
6

6

6

6
6
21.5
6
6
6

6
6
21.5
6
6
6

6
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
6
6
6
21.5
21.5
21.5
21.5
33.5
33.5
21.5
21.5
21.5
33.5

6
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
21.5
6
6
6
21.5
21.5
21.5
21.5
33.5
33.5
21.5
21.5
21.5
33.5

42
43
44
45
46
47
48
49
50

81
84
-3
82
84
-2
82
86
-4
82
86
-4
82
86
-4
83
87
-4
83
87
-4
83
88
-5
84
89
-5
JUMLAH NILAI W HITUNG =

33.5
21.5
38.5
38.5
38.5
38.5
38.5
42.5
42.5
133.5

33.5
21.5
38.5
38.5
38.5
38.5
38.5
42.5
42.5
901.5

W untuk tabel A-B
W = n(n+1) – x √n(n+1) (2n+1)
4
24
= 50(50+1) – 2,5758 √50(50+1) (2x50+1)
4
24
= 50(51) – 2,5758 √50(51) (101)
4
24
= 2550 – 2,5758 √257.550
4
24
= 637,5 – 2,5758 √10731,25
= 637,5 – (2,5758 x 103,591)
= 637,5 – 266,829
= 370,671
Whit : 133,5
Keterangan : Whit kurang dari Wdaftar maka data tersebut berbeda dengan sangat
signifikan.

NO
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43

A

C
68
69
70
71
71
71
71
72
72
72
73
73
74
75
75
76
76
76
76
76
76
77
77
77
77
78
78
78
79
79
79
79
79
80
80
80
80
81
81
81
81
81
82

A-C
54
55
57
58
58
58
60
60
61
61
62
63
63
64
64
64
64
64
66
67
67
70
71
71
72
75
75
75
76
77
78
79
81
82
83
83
84
85
85
86
86
87
87

14
14
13
13
13
13
11
12
11
11
11
10
11
11
11
12
12
12
10
9
9
7
6
6
5
3
3
3
3
2
1
0
-2
-2
-3
-3
-4
-4
-4
-5
-5
-6
-5

AC
48,5
48,5
45,5
45,5
45,5
45,5
36
41,5
36
36
36
47
36
36
36
41,5
41,5
41,5
47
44
44
78,5
65,5
65,5
16
7,5
7,5
7,5
7,5
3
1
3
3
7,5
7,5
12
12
12
16
16
65,5
16

RANK
positif
negatif
48,5
48,5
45,5
45,5
45,5
45,5
36
41,5
36
36
36
47
36
36
36
41,5
41,5
41,5
47
44
44
78,5
65,5
65,5
16
7,5
7,5
7,5
7,5
3
1
3
3
7,5
7,5
12
12
12
16
16
65,5
16

44
45
46
47
48
49
50
ket
:

82
87
-5
82
89
-7
82
89
-7
83
89
-6
83
90
-7
83
91
-8
84
92
-8
Jumlah nilai w hitung

16
78,5
78,5
65,5
78,5
41
41
1138,5

16
78,5
78,5
65,5
78,5
41
41
569,5

Jumlah nilai terkecil = jumlah nilai w hitung

W 0 , 01

W 0 , 01

n(n

1)

x

n(n

4
n(n

1)( 2 n

1)

24
1)

4

x

n(n

1)( 2 n

1)

24

W untuk Tabel Data A-C
W0,01 = n(n+1) – x √n(n+1) (2n+1)
4
24
= 50(50+1) – 2,5758 √50(50+1) (2x50+1)
4
24
= 50(51) – 2,5758 √50(51) (101)
4
24
= 2550 – 2,5758 √257.550
4
24
= 637,5 – 2,5758 √10731,25
= 637,5 – (2,5758 x 103,591)
= 637,5 – 266,829
= 370,671
Whit = 290,5
Keterangan : Whit kurang dari Wdaftar maka data tersebut berbeda dengan sangat
signifikan.

Untuk tabel B – C dengan uji t dan t1
Tabel B (Data Sains)
A. UJI NORMALITAS
n=50 nb=89 nk=60
1) K = 1+3.3 log n
= 1+3,3 log 50
= 1+3,3 (1,699)
= 1+5,6067
= 6,6067 = 6,6 = 7
=8
2) R = nb – nk
= 89 – 60
= 29
3) P =
=

= 4,14 = 4

4) Membuat Tabel Distribusi Frekuensi
No
1
2
3
4
5
6
7
8
?

Kelas
Interval
60 – 63
64 – 67
68 – 71
72 – 75
76 – 79
80 – 8384 – 87
88 – 91
-

fi
2
1
3
7
12
15
8
2
50

5) Menghitung Mean
X = XO + P

= 81,5 + 4 (-37)

xi
61.5
65.5
69.5
73.5
77.5
81.5
85.5
89.5
-

ci
-5
-4
-3
-2
-1
0
1
2
-

ci?
25
16
9
4
1
0
1
4
-

fici
-10
-4
-9
-14
-12
0
8
4
-37

fici?
50
16
27
28
12
0
8
8
149

50
= 81,5 + 4 (-0,74)
= 81,5 + -2,96
= 78,54
6) Menghitung Standar Deviasi
Sd2 = p2 x n x ∑ fici2 – (∑fici)2
n(n-1)
= 16 x 50 x 149 – 1369
50(50-1)
= 16 (7450-1369)
2450
= 16 x 6081
2450
= 16 x 2,482
= 39,712
Sd = 6,301

Tabel C (Data Prestasi Umum)
A. Uji Normalitas
n=50
nb=89 nk=60
1) K= 1+3.3 log n
= 1+3,3 log 50
= 1+3,3 (1,699)
= 1+5,6067
= 6,6067 = 6,6 = 7
2) R= nb – nk
= 92 – 54
= 38
3) P=
=

= = 5,43 = 6

4) Membuat Tabel Daftar Distribusi

NO

Kelas Interval

fi

xi

ci

ci?

fici

fici?

1
2
3
4
5
6
7
∑

54 – 59
60 – 65
66 – 71
72 – 77
78 – 83
84 – 89
90 – 95
-

6
12
6
6
6
11
2
49

56.5
62.5
68.5
74.5
80.5
86.5
92.5
-

-1
0
1
2
3
4
5
-

1
0
1
4
9
16
25
-

-6
0
6
12
18
44
10
84

6
0
6
24
54
176
50
316

5) Menghitung Mean
X = XO + P

= 62,5 + 6 (84)
50
= 62,5 + 6(1,68)
= 62,5 + 10,08
= 72,58
6) Standar Deviasi
Sd2

= p2 x n x ∑ fici2 – (∑fici)2
n(n-1)
= 36x (50 x 316) – 7056
50(50-1)
= 36 x (15800 - 7056)
2450
=36 x 8744
2450
= 36 x 3,568
= 128,448
Sd = 11,33
Vb = Sd b2 = 128,448
Vk = Sd k2 = 39,712
Maka Thit = Vb
= Sd b2 = 128,448 = 3,234
Vk
Sd k2 39,712

Sdg = √(n1-1)V1 + (n2 -1) V2
(n1 + n2) - 2

=

√(50 -1) 39,712 + (50-1)128,448
(50 + 50) – 2
√49 x 39,712 + 49 x 128,448
98
√1945,888 + 6293,952

=
=

=

98
√8239,84
98
√84,08

=

9,169

=

Menghitung thit :
thit

=
xi – x2
Sdg√1/n1 + 1/n2
= 78,54 – 72,58
9,169√1/50 + 1/50
=

5,96
9,169√2/50

=

5,96
9,169√0,04

=

5,96
9,169 x 0,2
= 5,96
1,833
= 3,25

Mencari t daftar
db

= n1 + n2 – 2
= 50 + 50 – 2
= 100 – 2
= 98

t( 1 – ? α ) (db) = t (1 – ? (0,01)) (98)
= t (1 – 0,005) (98)
= t (0,995) (98)

t0,995(60)

= 2,66

t0,995(120)

= 2,62

t0,995(98)

= 2,66 – 38/60 ( 2,66 – 2,62 )
= 2,66 – 38/60 ( 0,04 )
= 2,66 – 0,25
= 2,41

t( 1- ? α ) (db) = t ( 1 – ? (0,05)) (98)
= t ( 1 – 0,025 ) (98)
= t (0,975) (98)

t0,975(60)

= 2,00

t0,975(120)

= 1,98

t0,975 (98)

= 2,00 – 38/60 ( 2,00 – 1,98 )
= 2,00 – 38/60 ( 0,02 )
= 2,00 – 0,13
= 1,87

Kriteria : jika –tdaftar ≤ thit ≤ tdaftar ; tidak terdapat perbedaan
: -t0,995 (98) ≤ thit ≥ t0,975(98)
: -2,41≤ 3,25 ≥ 1,87 ; terdapat perbedaan

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