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Canal design

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MANJUNATH BORAKANAVAR
MANJUNATH BORAKANAVAR

Design Parameters, Kennedy's Theory (Steps), Case 1 and Case 2, Design of canal by using Kennedy's Theory.

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UNIT- 5 Design of Canal Prof. Manjunath. B Assistant Professor Sanjivani College of Engineering Kopargaon
Design Parameters 1. Cross sectional Area (A) 2. Depth of water over the bed (D) 3. Slope of the bed (S) 4. RugosityCo-efficient (N) 5. Hyd Mean Depth ( R) 6. Velocity of Flow (V) 7. Non-Silting Velocity/Non Scouring Velocity / Critical Velocity (Vo) 8. Discharge (Q) 9. Silt Factor (f) 10. B/D ratio
Kennedy’s Theory-Design Steps
Canal design
Kennedy’s Theory Given Value :- Q, N, m, & S Q – Discharge N – Rugosity Coefficient m – Critical Velocity Ratio S – Slope of Bed
Canal design
 DESIGN AN IRRIGATION CHANNEL ON KENNEDY’S THEORY, TO CARRYA DISCHARGE OF 40 CUMECS. TAKE N=0.0225 AND m=1.05. THE CHANNEL HAS A BED SLOPE OF 1IN 5000
Given: Q=45 cumecs, N=0.025, m=1.05 Solution: Step1: Assume value of D =2 m Step 2: Vo from Vo= 0.55mD0.64 = 0.9m/s Step 3: Find A from A=Q/Vo = 50sqm Step 4: Knowing D and A Find bed width B for a trapezoidal channel ( side slope is ½:1) A= BD+ (D2/2) , B=24m
Step 5: Calculate Perimeter and hydraulic mean depth P=B+D√5=28.47m R=A/P R=(BD+ (D2/2) /(B+D√5), =1.756m Step 6: Calculate the mean velocity by Kutter’sequation V>VO( INCREASE THE VALUE OF D & TRY AGAIN)
Given: Q=45 cumecs, N=0.025, m=1.05 Solution: Step1: Assume value of D =2.2 m Step 2: Vo from Vo= 0.55mD0.64 = 0.957m/s Step 3: Find A from A=Q/Vo = 47.04 sqm Step 4: Knowing D and A Find bed width B for a trapezoidal channel ( side slope is ½:1) A= BD+ (D2/2) , B=20.28 m
Step 5: Calculate Perimeter and hydraulic mean depth P=B+D√5=25.2 m R=A/P R=(BD+ (D2/2) /(B+D√5), =1.867 m Step 6: Calculate the mean velocity by Kutter’sequation  V= Vo Hence the assumed D is correct. For further precision, D can be assumed as 2.23m
ï‚— DESIGN AN IRRIGATION CHANNEL TO CARRYA DISCHARGE OF 14 CUMECS. ASSUME N=0.0225, M=1 AND B/D=5.7
Canal design

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Canal design

  • 1. UNIT- 5 Design of Canal Prof. Manjunath. B Assistant Professor Sanjivani College of Engineering Kopargaon
  • 2. Design Parameters 1. Cross sectional Area (A) 2. Depth of water over the bed (D) 3. Slope of the bed (S) 4. RugosityCo-efficient (N) 5. Hyd Mean Depth ( R) 6. Velocity of Flow (V) 7. Non-Silting Velocity/Non Scouring Velocity / Critical Velocity (Vo) 8. Discharge (Q) 9. Silt Factor (f) 10. B/D ratio
  • 5. Kennedy’s Theory Given Value :- Q, N, m, & S Q – Discharge N – Rugosity Coefficient m – Critical Velocity Ratio S – Slope of Bed
  • 7. ï‚— DESIGN AN IRRIGATION CHANNEL ON KENNEDY’S THEORY, TO CARRYA DISCHARGE OF 40 CUMECS. TAKE N=0.0225 AND m=1.05. THE CHANNEL HAS A BED SLOPE OF 1IN 5000
  • 8. Given: Q=45 cumecs, N=0.025, m=1.05 Solution: Step1: Assume value of D =2 m Step 2: Vo from Vo= 0.55mD0.64 = 0.9m/s Step 3: Find A from A=Q/Vo = 50sqm Step 4: Knowing D and A Find bed width B for a trapezoidal channel ( side slope is ½:1) A= BD+ (D2/2) , B=24m
  • 9. Step 5: Calculate Perimeter and hydraulic mean depth P=B+D√5=28.47m R=A/P R=(BD+ (D2/2) /(B+D√5), =1.756m Step 6: Calculate the mean velocity by Kutter’sequation V>VO( INCREASE THE VALUE OF D & TRY AGAIN)
  • 10. Given: Q=45 cumecs, N=0.025, m=1.05 Solution: Step1: Assume value of D =2.2 m Step 2: Vo from Vo= 0.55mD0.64 = 0.957m/s Step 3: Find A from A=Q/Vo = 47.04 sqm Step 4: Knowing D and A Find bed width B for a trapezoidal channel ( side slope is ½:1) A= BD+ (D2/2) , B=20.28 m
  • 11. Step 5: Calculate Perimeter and hydraulic mean depth P=B+D√5=25.2 m R=A/P R=(BD+ (D2/2) /(B+D√5), =1.867 m Step 6: Calculate the mean velocity by Kutter’sequation ï‚— V= Vo Hence the assumed D is correct. For further precision, D can be assumed as 2.23m
  • 12. ï‚— DESIGN AN IRRIGATION CHANNEL TO CARRYA DISCHARGE OF 14 CUMECS. ASSUME N=0.0225, M=1 AND B/D=5.7