This video discusses how to calculate quartiles, deciles, and percentiles for discrete, simple, and grouped frequency distributions. It demonstrates calculating the third quartile, sixth decile, and 70th percentile for a discrete data set. For a grouped frequency distribution, it shows how to find the median, lower quartile, upper quartile, third decile, and 95th percentile. The key steps shown are arranging the data in ascending order, determining the cumulative frequency, and using formulas to calculate the values of interest based on the total sample size.
2. PREVIEW
THIS VIDEO WOULD BE USEFUL FOR GRADE 11 STUDENTS STUDYING MATHEMATICS.
IT WOULD ALSO BE USEFUL FOR STUDENTS AT THE COLLEGE LEVEL STUDYING STATISTICS.
HERE WE SHOW HOW QUARTILES, DECILES AND PERCENTILES CAN BE CALCULATED
.
CALCULATION OF THE ABOVE IS DONE FOR DISCRETE, SIMPLE AND GROUPED
FREQUENCY DISTRIBUTIONS
3. IF A GIVEN SET IS ARRANGED IN ASCENDING OR DESCENDING ORDER OF MAGNITUDE,
MEDIAN DIVIDES THE SET INTO 2 EQUAL PARTS.
QUARTILES DIVIDE THE SET INTO 4 QUARTERS. THERE ARE 3 QUARTILES 1, 2, 3
DECILES DIVIDE THE SET INTO 10 EQUAL PARTS. THERE ARE 9 DECILES, 1, 2,------9
PERCENTILES DIVIDE THE SET INTO 100 EQUAL PARTS.
THERE ARE 99 PERCENTILES
1, 2, 99
4. 1 =
+ 1
4
基瑞
FOR A DISCRETE DISTRIBUTION OR A SIMPLE FREQUENCY DISTRIBUTION
2 =
+ 1
2
基瑞
3 = 3
+ 1
4
基瑞
=MEDIAN
倹 =
(+1) ≠
10
value
=
( + 1) ≠
100
p
5. Question 1
Calculate the 3rd quartile, 6th decile and 70th percentile
28, 17, 12, 25,26, 19, 13, 27, 21,16
We first arrange in ascending order
12, 13, 16, 17, 19, 21, 25,26, 27, 28
3 = 3
11
4
≠. Value = 8.25th value
= 8≠ p + 0.25 9≠ p 8≠ p = 26 + 0.25 27 26 = 26.25
9. 201
4
= 50.25
From the table, we look at the cf greater than 50.25 ie 58
Value of x corresponding to 58 is 20
1 = 20
3(201)
4
= 150.75
3 = 24
6 = 22
45
201
100
= 90.45
45 = 22
6
201
10
= 120.6
10. QUESTION 3
For the following table, find the median, lower quartile, upper quartile, 3rd decile, 95th percentile
C I f
600-700 40
700-800 68
800-900 86
900-1000 120
1000-1100 90
1100-1200 40
1200-1300 26
11. For a grouped frequency distribution, we use n instead of n+1
1 = + (
4
)
Where l = lower boundary of the class in which
1
cf = cumulative frequency of the class
preceeding this class
f = frequency of the class in which 1
= ゐ≠ ≠ $p
2 = +
(
2
)
3 = + (
3
4
)
13. C I f c f
600-700 40 40
700-800 68 108
800-900 86 194
900-1000 120 314
1000-1100 90 404
1100-1200 40 444
1200-1300 26 470
470
4
= 117.5
We take 800 -900 as the class in which 1
1 = 800 + (
117.5 108
86
) 100
= 811.04