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Sol prob equilibrium

AHMED SABER
AHMED SABER

The document contains solutions to 10 different statics problems involving forces, moments, and free body diagrams. Each problem is labeled 5-1 through 5-10 and shows the relevant equations set up to solve for unknown forces and reactions. Key values calculated include forces of RA, RB, Rc, T, weights, and reactions Ax, Ay, Cx, Cy.

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5-1 FBD Det Reaction in 5-11 Fx=0 RBcos 30-RAsin30=0 RA= 3 RB 1 Fy=RBSin30+RACos30-9.8*50=0 2 From1in2 RB=245N RA=424.35N 5-2
Fx= RACos60-150+Bx=0 Fy= By+360+RASin60=0 MB =800+150*3-RA*12*Sin60-RACos60 *3=0 RA=105.12Ib Bx=22.44Ib By=-451.027Ib 5-3
Fx Ax=0.6T Fy Ay-80*9.8+T+0.8T=0 MA=2T+2.4T=4312 T=980N Ay=-980N Ax=588N 5-5
Cx-TCos30=0 Cy-7000+TSin30=0 6000+4000*4-2TCos30-4TSin30=0 T=5894.88N Cx=5105.18N Cy=4052.56N 5-6
Ax-12/13T=0 Ay-650-1250-5/13T=0 15*15 3T/3+650*7.5 3 +15 3T-5/3-60T=0 T=197.84N Ax=182.622N Ay=1976.09N 5-7 Fx= RB+Ax=0 Fy= Ay=20Ib MA RB-140=0 RB=140Ib
Ax=-140Ib 5-8 Fx RACos45-T-1250=0 Fy=0 RB+1250+T-1250 3=0 MA= 2500sin60*4+4000-3T-10RB=0 T=269.97N RB=-1185.03N RA=2149.56N 5-9
FX Rcsin30+RB-RA-10cos30=0 Fy= RcCos30-10sin30=0 Mc 10sin30*3-10cos30*13-5RA-3tan30*RB=0 RA=-12.91N RB=-74.53N RC=5.773N 5-10
Fx Cx+3RA/ 13=0 Fy= Cy-2RA/ 13=500 Mc= -500*4+18RA/ 13=0 RA=400.66Ib RB=400.66Ib Cx=-333.33Ib Cy=722.246Ib 5-19
5-20 5-21
Sol prob equilibrium

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