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T┴n hi?u, h? th?ng v┐ ph?n gi?i m?ch 8

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Linh Tr?n L┷

- The document contains information about an individual named Tran Le Duy Linh with student ID 18200032 from class 18DTV1_L1. - It describes solving exercises from week 8, including finding the transfer function H(s) and impulse response h(t) of a system, and determining whether the system is stable or not. - The transfer function is found to be H(s) = (3/35(s-2)) + (1/5(s+3)) - (2/7(s+5)) and the impulse response is h(t) = (3/35)e^2t + (1/5)e^-3t - (

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-H? v┐ t┷n: Tr?n L┷ Duy Linh. -MSSV: 18200032. - L?p : 18DTV1_L1. - Tu?n 8. B┐i t?p c?ng c? bu?i 8. Tr━nh b┐y 1. Cho h? th?ng c?c-kh?ng sau: T┏m t?t b┐i l┐m: 1. ?. H┐m s? chuy?n H(s) : ?(?) = 3 35(? ? 2) + 1 5(? + 3) ? 2 7(? + 5) ?│p ?ng xung h(t): ??1(?(?)) = ?(?) = ( 3 35 ?2? + 1 5 ??3? ? 2 7 ??5? ) ?(?) b. lim ?★0 (??(?)) 』 lim ?★± (?(?)) ? H? th?ng kh?ng ?n ??nh.
a. T━m h┐m s? chuy?n H(s) v┐ ?│p ?ng xung h(t) b. X│c ??nh t┴nh ?n ??nh c?a h? th?ng? H┐m s? chuy?n H(s) : ?(?) = ? + 1 (? ? 2)(? + 3)(? + 5) = 3 35(? ? 2) + 1 5(? + 3) ? 2 7(? + 5) ?│p ?ng xung h(t): ??1(?(?)) = ?(?) = ( 3 35 ?2? + 1 5 ??3? ? 2 7 ??5? ) ?(?) b. Ta c┏ : lim ?★0 (??(?)) = 0 lim ?★± (?(?)) = ± lim ?★0 (??(?)) 』 lim ?★± (?(?)) ? H? th?ng kh?ng ?n ??nh.

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T┴n hi?u, h? th?ng v┐ ph?n gi?i m?ch 8

  • 1. -H? v┐ t┷n: Tr?n L┷ Duy Linh. -MSSV: 18200032. - L?p : 18DTV1_L1. - Tu?n 8. B┐i t?p c?ng c? bu?i 8. Tr━nh b┐y 1. Cho h? th?ng c?c-kh?ng sau: T┏m t?t b┐i l┐m: 1. ?. H┐m s? chuy?n H(s) : ?(?) = 3 35(? ? 2) + 1 5(? + 3) ? 2 7(? + 5) ?│p ?ng xung h(t): ??1(?(?)) = ?(?) = ( 3 35 ?2? + 1 5 ??3? ? 2 7 ??5? ) ?(?) b. lim ?★0 (??(?)) 』 lim ?★± (?(?)) ? H? th?ng kh?ng ?n ??nh.
  • 2. a. T━m h┐m s? chuy?n H(s) v┐ ?│p ?ng xung h(t) b. X│c ??nh t┴nh ?n ??nh c?a h? th?ng? H┐m s? chuy?n H(s) : ?(?) = ? + 1 (? ? 2)(? + 3)(? + 5) = 3 35(? ? 2) + 1 5(? + 3) ? 2 7(? + 5) ?│p ?ng xung h(t): ??1(?(?)) = ?(?) = ( 3 35 ?2? + 1 5 ??3? ? 2 7 ??5? ) ?(?) b. Ta c┏ : lim ?★0 (??(?)) = 0 lim ?★± (?(?)) = ± lim ?★0 (??(?)) 』 lim ?★± (?(?)) ? H? th?ng kh?ng ?n ??nh.