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1. The document contains 4 math word problems. The first problem involves finding the width of a field given the total land area and required field area. The second finds the base area and dimensions of a prism. The third equates volumes before and after increasing a radius. The fourth finds the time to print a document using two printers. 2. The second problem involves finding the base area and dimensions of a prism given its total volume. It is solved by setting up and solving two equations for the base length and width in terms of the unknown dimension X. 3. The third problem equates the volumes of a cylinder before and after increasing its radius by 24. It sets up and solves the equation relating the
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The document summarizes three word problems involving quadratic equations and their solutions:
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Tugas 1
- 1. TUGAS 1 1. Dik ; Luas tanah = 60m 30m Luas lapangan =1000m L lap =(30-X) Luas lapangan = P lap L lap =(60-X)(30-X) = 1000 = 1800-60X-30X X2 = 1000 = 1800-90X X2 = 1000 = X2-90X 1800-1000 = 0 = X2-90X+800=0 = (X - 10)(X - 80) X= 10 atau X=80 2. Dik ; Luas alas = 200 Panjang alas = 50 - 2X Lebar alas = 40 C 2X Luas = panjang 200 = (50 C 2X) (40 C 2X) 2000 C 100X C 80X + 4X2 = 200 2000 C 200 C 180X + 4X2 = 0 1800 C 180X + 4X2 = 0 4X2 C 180X + 1800 = 0 2X( 2X C 30) C 60(2X + 30) = 0 (2X C 60) (2X C 3) 4X2 C I80X + 1800 = 0 2X = 60 atau 2x = 30 x= 30 x = 15 p alas = 50 C 2x = 50 C 2.15 = 50 C 30 = 20 cm l alas = 40 C 2x
- 2. = 40 C 2. 15 = 40 C 30 = 10 cm V=p = 20. 10. 30 = 6000 cm2 3. Dik ; V = 1/3. r2.t = 1/3. . r2.3 Volume akibat penambahan jari V1 = 1/3. . (r + 24)2 3 V2 = 1/3. . r2( 3 + 24) = 1/3. . r2.27 V1 = V2 1/3. (r + 24)2 3 = 1/3. . r2.27 1/3. (r + 24)2 3 = r2 . 9 (r + 24)2 = r2 . 9 (r + 24)2 = r2 . 9 r + 24 = r + 24 = 3r 24 = 3r C r 24 = 2r =r 12 = r 4. Misl ; Waktu printer 1 = x Waktu printer 2 = x + 1 Maka ; = 1,2 = 1,2
- 3. = 1,2 = 1,2 = 1,2 = 1,2 = 1,2 X + 1 = 3,6 X = 3,6 C 1 X = 2,6