ºÝºÝߣ

ºÝºÝߣShare a Scribd company logo
Mathtype

 f ( x) = an x n + an ?1 x n ?1 + L , an ¡Ù 0
       an ?1 n ?1
= (x +     n
            x + L), exist
        an
= ( x m + bm ?1 x m ?1 + L)

³Ìʽ¾ŽÝ‹Æ÷

claim: ¡Æ
         hx          n        1 3
          n¡Ý0
                n
                         = (1 ? x )

     13 + 23 +L + n3 =?
     A=B

     A= A1 = A2 = L =B B= B1 = B2 = L =A

     (1 + x ) 2 =1+2x+ x 2

       1 3        1        1        1             2           2           2
Pf: (1 ? x ) = (1 ? x ) (1 ? x ) (1 ? x ) = (1+x+x +L ) (1+x+x +L ) (1+x+x +L )


                =
                  ¡Æxei ¡Ý 0
                             e1
                                  x e2 x e3
                                              =
                                                ¡Æx
                                               ei ¡Ý 0
                                                        e1 + e2 + e3

                                                                       = ¡Æ (# of sols of e1 + e2 + e3 =n) x
                                                                                                            n
                                                                         n¡Ý 0


     On the other hand,we have by newton¡¯s binomial theorem
                                     ? ?3 ?           ? n + 2? n ? 2?
                                                                      n

              ) = ( x ? 1) ?3 = ¡Æ ? ? (? x ) n = ¡Æ ?         ? x ? ? = ¡Æ n ¡­.(1)
          1 3                                                           h xn
     (
         1? x                   n¡Ý 0
                                     ?n?         n¡Ý 0
                                                      ? 2 ? ? 1 ? n¡Ý0

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Êýѧ²âÊÔ

  • 1. Mathtype f ( x) = an x n + an ?1 x n ?1 + L , an ¡Ù 0 an ?1 n ?1 = (x + n x + L), exist an = ( x m + bm ?1 x m ?1 + L) ³Ìʽ¾ŽÝ‹Æ÷ claim: ¡Æ hx n 1 3 n¡Ý0 n = (1 ? x ) 13 + 23 +L + n3 =? A=B A= A1 = A2 = L =B B= B1 = B2 = L =A (1 + x ) 2 =1+2x+ x 2 1 3 1 1 1 2 2 2 Pf: (1 ? x ) = (1 ? x ) (1 ? x ) (1 ? x ) = (1+x+x +L ) (1+x+x +L ) (1+x+x +L ) = ¡Æxei ¡Ý 0 e1 x e2 x e3 = ¡Æx ei ¡Ý 0 e1 + e2 + e3 = ¡Æ (# of sols of e1 + e2 + e3 =n) x n n¡Ý 0 On the other hand,we have by newton¡¯s binomial theorem ? ?3 ? ? n + 2? n ? 2? n ) = ( x ? 1) ?3 = ¡Æ ? ? (? x ) n = ¡Æ ? ? x ? ? = ¡Æ n ¡­.(1) 1 3 h xn ( 1? x n¡Ý 0 ?n? n¡Ý 0 ? 2 ? ? 1 ? n¡Ý0