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Graphing PolynomialsBy: Haley Root
Step 1Count the exponents on each parentheses, (find the degree)(x-5) (x+2)^2 (x+4)There would be 4 exponents or the degree would be 4 because there is one exponent on (x-5), two exponents on (x+2), and one exponent on (x+4).
Step 2Find out whether the degree is even or odd. If it is even or odd without a negative in front of the problem then it is known to be normal.  Ex. (x+4) (x-6) (x+3) this is normal because it has no negative sign. On an even normal then both of your arrows will be point upwards. On an odd normal then the first arrow is facing down and the second arrow is facing up.
Step 2 cont.If it is even or odd with a negative sign in front of the problem then it is un-normal. Ex. -1(x-4)^3(x+8) this would be un-normal because there is a negative sign in front of the whole problem. On an even un-normal you would flip the both of the arrows, so now they will both be pointing downwards. On an odd un-normal you would also flip both the arrows, so now the first arrow is pointing up and the second arrow is pointing down.
Step 3Next you will plot the points you have on the graph. Then you will determine if the line is going to bounce off, squiggle through, or pass through.If the problem has a 2 or an even number as an exponent then the line is going to bounce off, if the problem has a 3 or an odd number other than 1 as an exponent then the line is going to squiggle through, and if the problem has 1 exponent or doesnt show one then the line is just going to pass through.Ex: (x+3)^1 or (x+3)- line will pass throughEx: (x-5)^2 or even number- line will bounce offEx: (x-7)^3 or odd number- line will squiggle through
Step 4The last step is to connect all of the lines together.

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  • 2. Step 1Count the exponents on each parentheses, (find the degree)(x-5) (x+2)^2 (x+4)There would be 4 exponents or the degree would be 4 because there is one exponent on (x-5), two exponents on (x+2), and one exponent on (x+4).
  • 3. Step 2Find out whether the degree is even or odd. If it is even or odd without a negative in front of the problem then it is known to be normal. Ex. (x+4) (x-6) (x+3) this is normal because it has no negative sign. On an even normal then both of your arrows will be point upwards. On an odd normal then the first arrow is facing down and the second arrow is facing up.
  • 4. Step 2 cont.If it is even or odd with a negative sign in front of the problem then it is un-normal. Ex. -1(x-4)^3(x+8) this would be un-normal because there is a negative sign in front of the whole problem. On an even un-normal you would flip the both of the arrows, so now they will both be pointing downwards. On an odd un-normal you would also flip both the arrows, so now the first arrow is pointing up and the second arrow is pointing down.
  • 5. Step 3Next you will plot the points you have on the graph. Then you will determine if the line is going to bounce off, squiggle through, or pass through.If the problem has a 2 or an even number as an exponent then the line is going to bounce off, if the problem has a 3 or an odd number other than 1 as an exponent then the line is going to squiggle through, and if the problem has 1 exponent or doesnt show one then the line is just going to pass through.Ex: (x+3)^1 or (x+3)- line will pass throughEx: (x-5)^2 or even number- line will bounce offEx: (x-7)^3 or odd number- line will squiggle through
  • 6. Step 4The last step is to connect all of the lines together.