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Arithmetic Sequence.ppt

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Camiling Catholic School
Camiling Catholic School

The document discusses arithmetic and geometric sequences and series. It defines sequences and series, and introduces the key concepts of common difference for arithmetic sequences and common ratio for geometric sequences. Formulas are provided for finding the nth term and sum of terms for arithmetic and geometric sequences. Examples are worked through to demonstrate applying the formulas and concepts.

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Chapter 11 Investigating Sequences and Series
Section 11-1 Arithmetic Sequences
Arithmetic Sequences Every day a radio station asks a question for a prize of $150. If the 5th caller does not answer correctly, the prize money increased by $150 each day until someone correctly answers their question.
Arithmetic Sequences Make a list of the prize amounts for a week (Mon - Fri) if the contest starts on Monday and no one answers correctly all week.
Arithmetic Sequences Monday : $150 Tuesday: $300 Wednesday: $450 Thursday: $600 Friday: $750
Arithmetic Sequences These prize amounts form a sequence, more specifically each amount is a term in an arithmetic sequence. To find the next term we just add $150.
Definitions Sequence: a list of numbers in a specific order. Term: each number in a sequence
Definitions Arithmetic Sequence: a sequence in which each term after the first term is found by adding a constant, called the common difference (d), to the previous term.
Explanations 150, 300, 450, 600, 750 The first term of our sequence is 150, we denote the first term as a1. What is a2? a2 : 300 (a2 represents the 2nd term in our sequence)
Explanations a3 = ? a4 = ? a5 = ? a3 : 450 a4 : 600 a5 : 750 an represents a general term (nth term) where n can be any number.
Explanations Sequences can continue forever. We can calculate as many terms as we want as long as we know the common difference in the sequence.
Explanations Find the next three terms in the sequence: 2, 5, 8, 11, 14, __, __, __ 2, 5, 8, 11, 14, 17, 20, 23 The common difference is? 3!!!
Explanations To find the common difference (d), just subtract any term from the term that follows it. FYI: Common differences can be negative.
Formula What if I wanted to find the 50th (a50) term of the sequence 2, 5, 8, 11, 14, ? Do I really want to add 3 continually until I get there? There is a formula for finding the nth term.
Formula Lets see if we can figure the formula out on our own. a1 = 2, to get a2 I just add 3 once. To get a3 I add 3 to a1 twice. To get a4 I add 3 to a1 three times.
Formula What is the relationship between the term we are finding and the number of times I have to add d? The number of times I had to add is one less then the term I am looking for.
Formula So if I wanted to find a50 then how many times would I have to add 3? 49 If I wanted to find a193 how many times would I add 3? 192
Formula So to find a50 I need to take d, which is 3, and add it to my a1, which is 2, 49 times. Thats a lot of adding. But if we think back to elementary school, repetitive adding is just multiplication.
Formula 3 + 3 + 3 + 3 + 3 = 15 We added five terms of three, that is the same as multiplying 5 and 3. So to add three forty-nine times we just multiply 3 and 49.
Formula So back to our formula, to find a50 we start with 2 (a1) and add 349. (3 is d and 49 is one less than the term we are looking for) So a50 = 2 + 3(49) = 149
Formula a50 = 2 + 3(49) using this formula we can create a general formula. a50 will become an so we can use it for any term. 2 is our a1 and 3 is our d.
Formula a50 = 2 + 3(49) 49 is one less than the term we are looking for. So if I am using n as the term I am looking for, I multiply d by n - 1.
Formula Thus my formula for finding any term in an arithmetic sequence is an = a1 + d(n-1). All you need to know to find any term is the first term in the sequence (a1) and the common difference.
Example Lets go back to our first example about the radio contest. Suppose no one correctly answered the question for 15 days. What would the prize be on day 16?
Example an = a1 + d(n-1) We want to find a16. What is a1? What is d? What is n-1? a1 = 150, d = 150, n -1 = 16 - 1 = 15 So a16 = 150 + 150(15) = $2400
Example 17, 10, 3, -4, -11, -18, What is the common difference? Subtract any term from the term after it. -4 - 3 = -7 d = - 7
Definition 17, 10, 3, -4, -11, -18, Arithmetic Means: the terms between any two nonconsecutive terms of an arithmetic sequence.
Arithmetic Means 17, 10, 3, -4, -11, -18, Between 10 and -18 there are three arithmetic means 3, -4, -11. Find three arithmetic means between 8 and 14.
Arithmetic Means So our sequence must look like 8, __, __, __, 14. In order to find the means we need to know the common difference. We can use our formula to find it.
Arithmetic Means 8, __, __, __, 14 a1 = 8, a5 = 14, & n = 5 14 = 8 + d(5 - 1) 14 = 8 + d(4) subtract 8 6 = 4d divide by 4 1.5 = d
Arithmetic Means 8, __, __, __, 14 so to find our means we just add 1.5 starting with 8. 8, 9.5, 11, 12.5, 14
Additional Example 72 is the __ term of the sequence -5, 2, 9, We need to find n which is the term number. 72 is an, -5 is a1, and 7 is d. Plug it in.
Additional Example 72 = -5 + 7(n - 1) 72 = -5 + 7n - 7 72 = -12 + 7n 84 = 7n n = 12 72 is the 12th term.
Section 11-2 Arithmetic Series
Arithmetic Series The African-American celebration of Kwanzaa involves the lighting of candles every night for seven nights. The first night one candle is lit and blown out.
Arithmetic Series The second night a new candle and the candle from the first night are lit and blown out. The third night a new candle and the two candles from the second night are lit and blown out.
Arithmetic Series This process continues for the seven nights. We want to know the total number of lightings during the seven nights of celebration.
Arithmetic Series The first night one candle was lit, the 2nd night two candles were lit, the 3rd night 3 candles were lit, etc. So to find the total number of lightings we would add: 1 + 2 + 3 + 4 + 5 + 6 + 7
Arithmetic Series 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 Series: the sum of the terms in a sequence. Arithmetic Series: the sum of the terms in an arithmetic sequence.
Arithmetic Series Arithmetic sequence: 2, 4, 6, 8, 10 Corresponding arith. series: 2 + 4 + 6 + 8 + 10 Arith. Sequence: -8, -3, 2, 7 Arith. Series: -8 + -3 + 2 + 7
Arithmetic Series Sn is the symbol used to represent the first n terms of a series. Given the sequence 1, 11, 21, 31, 41, 51, 61, 71, find S4 We add the first four terms 1 + 11 + 21 + 31 = 64
Arithmetic Series Find S8 of the arithmetic sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36
Arithmetic Series What if we wanted to find S100 for the sequence in the last example. It would be a pain to have to list all the terms and try to add them up. Lets figure out a formula!! :)
Sum of Arithmetic Series Lets find S7 of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, If we add S7 in too different orders we get: S7 = 1 + 2 + 3 + 4 + 5 + 6 + 7 S7 = 7 + 6 + 5 + 4 + 3 + 2 + 1 2S7 = 8 + 8 + 8 + 8 + 8 + 8 + 8
Sum of Arithmetic Series S7 = 1 + 2 + 3 + 4 + 5 + 6 + 7 S7 = 7 + 6 + 5 + 4 + 3 + 2 + 1 2S7 = 8 + 8 + 8 + 8 + 8 + 8 + 8 2S7 = 7(8) S7 =7/2(8) 7 sums of 8
Sum of Arithmetic Series S7 =7/2(8) What do these numbers mean? 7 is n, 8 is the sum of the first and last term (a1 + an) So Sn = n/2(a1 + an)
Examples Sn = n/2(a1 + an) Find the sum of the first 10 terms of the arithmetic series with a1 = 6 and a10 =51 S10 = 10/2(6 + 51) = 5(57) = 285
Examples Find the sum of the first 50 terms of an arithmetic series with a1 = 28 and d = -4 We need to know n, a1, and a50. n= 50, a1 = 28, a50 = ?? We have to find it.
Examples a50 = 28 + -4(50 - 1) = 28 + -4(49) = 28 + -196 = -168 So n = 50, a1 = 28, & an =-168 S50 = (50/2)(28 + -168) = 25(-140) = -3500
Examples To write out a series and compute a sum can sometimes be very tedious. Mathematicians often use the greek letter sigma & summation notation to simplify this task.
Examples This means to find the sum of the sums n + 1 where we plug in the values 1 - 5 for n last value of n First value of n formula used to find sequence
Examples Basically we want to find (1 + 1) + (2 + 1) + (3 + 1) + (4 + 1) + (5 + 1) = 2 + 3 + 4 + 5 + 6 = 20
Examples So Try: First we need to plug in the numbers 2 - 7 for x.
Examples [3(2)-2]+[3(3)-2]+[3(4)-2]+ [3(5)-2]+[3(6)-2]+[3(7)-2] = (6-2)+(9-2)+(12-2)+(15-2)+ (18-2)+ (21-2) = 4 + 7 + 10 + 13 + 17 + 19 = 70
Section 11-3 Geometric Sequences
GeometricSequence What if your pay check started at $100 a week and doubled every week. What would your salary be after four weeks?
GeometricSequence Starting $100. After one week - $200 After two weeks - $400 After three weeks - $800 After four weeks - $1600. These values form a geometric sequence.
Geometric Sequence Geometric Sequence: a sequence in which each term after the first is found by multiplying the previous term by a constant value called the common ratio.
Geometric Sequence Find the first five terms of the geometric sequence with a1 = -3 and common ratio (r) of 5. -3, -15, -75, -375, -1875
Geometric Sequence Find the common ratio of the sequence 2, -4, 8, -16, 32, To find the common ratio, divide any term by the previous term. 8 歎 -4 = -2 r = -2
Geometric Sequence Just like arithmetic sequences, there is a formula for finding any given term in a geometric sequence. Lets figure it out using the pay check example.
Geometric Sequence To find the 5th term we look 100 and multiplied it by two four times. Repeated multiplication is represented using exponents.
Geometric Sequence Basically we will take $100 and multiply it by 24 a5 = 10024 = 1600 A5 is the term we are looking for, 100 was our a1, 2 is our common ratio, and 4 is n-1.
Examples Thus our formula for finding any term of a geometric sequence is an = a1rn-1 Find the 10th term of the geometric sequence with a1 = 2000 and a common ratio of 1/2.
Examples a10 = 2000 (1/2)9 = 2000 1/512 = 2000/512 = 500/128 = 250/64 = 125/32 Find the next two terms in the sequence -64, -16, -4 ...
Examples -64, -16, -4, __, __ We need to find the common ratio so we divide any term by the previous term. -16/-64 = 1/4 So we multiply by 1/4 to find the next two terms.
Examples -64, -16, -4, -1, -1/4
Geometric Means Just like with arithmetic sequences, the missing terms between two nonconsecutive terms in a geometric sequence are called geometric means.
Geometric Means Looking at the geometric sequence 3, 12, 48, 192, 768 the geometric means between 3 and 768 are 12, 48, and 192. Find two geometric means between -5 and 625.
Geometric Means -5, __, __, 625 We need to know the common ratio. Since we only know nonconsecutive terms we will have to use the formula and work backwards.
Geometric Means -5, __, __, 625 625 is a4, -5 is a1. 625 = -5r4-1 divide by -5 -125 = r3 take the cube root of both sides -5 = r
Geometric Means -5, __, __, 625 Now we just need to multiply by -5 to find the means. -5 -5 = 25 -5, 25, __, 625 25 -5 = -125 -5, 25, -125, 625
Section 11-4 Geometric Series
Geometric Series Geometric Series - the sum of the terms of a geometric sequence. Geo. Sequence: 1, 3, 9, 27, 81 Geo. Series: 1+3 + 9 + 27 + 81 What is the sum of the geometric series?
Geometric Series 1 + 3 + 9 + 27 + 81 = 121 The formula for the sum Sn of the first n terms of a geometric series is given by
Geometric Series Find You can actually do it two ways. Lets use the old way. Plug in the numbers 1 - 4 for n and add. [-3(2)1-1]+[-3(2)2-1]+[-3(2)3- 1]+ [-3(2)4-1]
Geometric Series [-3(1)] + [-3(2)] + [-3(4)] + [-3(8)] = -3 + -6 + -12 + -24 = -45 The other method is to use the sum of geometric series formula.
Geometric Series use a1 = -3, r = 2, n = 4
Geometric Series use a1 = -3, r = 2, n = 4
Geometric Series

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Arithmetic Sequence.ppt

  • 3. Arithmetic Sequences Every day a radio station asks a question for a prize of $150. If the 5th caller does not answer correctly, the prize money increased by $150 each day until someone correctly answers their question.
  • 4. Arithmetic Sequences Make a list of the prize amounts for a week (Mon - Fri) if the contest starts on Monday and no one answers correctly all week.
  • 5. Arithmetic Sequences Monday : $150 Tuesday: $300 Wednesday: $450 Thursday: $600 Friday: $750
  • 6. Arithmetic Sequences These prize amounts form a sequence, more specifically each amount is a term in an arithmetic sequence. To find the next term we just add $150.
  • 7. Definitions Sequence: a list of numbers in a specific order. Term: each number in a sequence
  • 8. Definitions Arithmetic Sequence: a sequence in which each term after the first term is found by adding a constant, called the common difference (d), to the previous term.
  • 9. Explanations 150, 300, 450, 600, 750 The first term of our sequence is 150, we denote the first term as a1. What is a2? a2 : 300 (a2 represents the 2nd term in our sequence)
  • 10. Explanations a3 = ? a4 = ? a5 = ? a3 : 450 a4 : 600 a5 : 750 an represents a general term (nth term) where n can be any number.
  • 11. Explanations Sequences can continue forever. We can calculate as many terms as we want as long as we know the common difference in the sequence.
  • 12. Explanations Find the next three terms in the sequence: 2, 5, 8, 11, 14, __, __, __ 2, 5, 8, 11, 14, 17, 20, 23 The common difference is? 3!!!
  • 13. Explanations To find the common difference (d), just subtract any term from the term that follows it. FYI: Common differences can be negative.
  • 14. Formula What if I wanted to find the 50th (a50) term of the sequence 2, 5, 8, 11, 14, ? Do I really want to add 3 continually until I get there? There is a formula for finding the nth term.
  • 15. Formula Lets see if we can figure the formula out on our own. a1 = 2, to get a2 I just add 3 once. To get a3 I add 3 to a1 twice. To get a4 I add 3 to a1 three times.
  • 16. Formula What is the relationship between the term we are finding and the number of times I have to add d? The number of times I had to add is one less then the term I am looking for.
  • 17. Formula So if I wanted to find a50 then how many times would I have to add 3? 49 If I wanted to find a193 how many times would I add 3? 192
  • 18. Formula So to find a50 I need to take d, which is 3, and add it to my a1, which is 2, 49 times. Thats a lot of adding. But if we think back to elementary school, repetitive adding is just multiplication.
  • 19. Formula 3 + 3 + 3 + 3 + 3 = 15 We added five terms of three, that is the same as multiplying 5 and 3. So to add three forty-nine times we just multiply 3 and 49.
  • 20. Formula So back to our formula, to find a50 we start with 2 (a1) and add 349. (3 is d and 49 is one less than the term we are looking for) So a50 = 2 + 3(49) = 149
  • 21. Formula a50 = 2 + 3(49) using this formula we can create a general formula. a50 will become an so we can use it for any term. 2 is our a1 and 3 is our d.
  • 22. Formula a50 = 2 + 3(49) 49 is one less than the term we are looking for. So if I am using n as the term I am looking for, I multiply d by n - 1.
  • 23. Formula Thus my formula for finding any term in an arithmetic sequence is an = a1 + d(n-1). All you need to know to find any term is the first term in the sequence (a1) and the common difference.
  • 24. Example Lets go back to our first example about the radio contest. Suppose no one correctly answered the question for 15 days. What would the prize be on day 16?
  • 25. Example an = a1 + d(n-1) We want to find a16. What is a1? What is d? What is n-1? a1 = 150, d = 150, n -1 = 16 - 1 = 15 So a16 = 150 + 150(15) = $2400
  • 26. Example 17, 10, 3, -4, -11, -18, What is the common difference? Subtract any term from the term after it. -4 - 3 = -7 d = - 7
  • 27. Definition 17, 10, 3, -4, -11, -18, Arithmetic Means: the terms between any two nonconsecutive terms of an arithmetic sequence.
  • 28. Arithmetic Means 17, 10, 3, -4, -11, -18, Between 10 and -18 there are three arithmetic means 3, -4, -11. Find three arithmetic means between 8 and 14.
  • 29. Arithmetic Means So our sequence must look like 8, __, __, __, 14. In order to find the means we need to know the common difference. We can use our formula to find it.
  • 30. Arithmetic Means 8, __, __, __, 14 a1 = 8, a5 = 14, & n = 5 14 = 8 + d(5 - 1) 14 = 8 + d(4) subtract 8 6 = 4d divide by 4 1.5 = d
  • 31. Arithmetic Means 8, __, __, __, 14 so to find our means we just add 1.5 starting with 8. 8, 9.5, 11, 12.5, 14
  • 32. Additional Example 72 is the __ term of the sequence -5, 2, 9, We need to find n which is the term number. 72 is an, -5 is a1, and 7 is d. Plug it in.
  • 33. Additional Example 72 = -5 + 7(n - 1) 72 = -5 + 7n - 7 72 = -12 + 7n 84 = 7n n = 12 72 is the 12th term.
  • 35. Arithmetic Series The African-American celebration of Kwanzaa involves the lighting of candles every night for seven nights. The first night one candle is lit and blown out.
  • 36. Arithmetic Series The second night a new candle and the candle from the first night are lit and blown out. The third night a new candle and the two candles from the second night are lit and blown out.
  • 37. Arithmetic Series This process continues for the seven nights. We want to know the total number of lightings during the seven nights of celebration.
  • 38. Arithmetic Series The first night one candle was lit, the 2nd night two candles were lit, the 3rd night 3 candles were lit, etc. So to find the total number of lightings we would add: 1 + 2 + 3 + 4 + 5 + 6 + 7
  • 39. Arithmetic Series 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 Series: the sum of the terms in a sequence. Arithmetic Series: the sum of the terms in an arithmetic sequence.
  • 40. Arithmetic Series Arithmetic sequence: 2, 4, 6, 8, 10 Corresponding arith. series: 2 + 4 + 6 + 8 + 10 Arith. Sequence: -8, -3, 2, 7 Arith. Series: -8 + -3 + 2 + 7
  • 41. Arithmetic Series Sn is the symbol used to represent the first n terms of a series. Given the sequence 1, 11, 21, 31, 41, 51, 61, 71, find S4 We add the first four terms 1 + 11 + 21 + 31 = 64
  • 42. Arithmetic Series Find S8 of the arithmetic sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36
  • 43. Arithmetic Series What if we wanted to find S100 for the sequence in the last example. It would be a pain to have to list all the terms and try to add them up. Lets figure out a formula!! :)
  • 44. Sum of Arithmetic Series Lets find S7 of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, If we add S7 in too different orders we get: S7 = 1 + 2 + 3 + 4 + 5 + 6 + 7 S7 = 7 + 6 + 5 + 4 + 3 + 2 + 1 2S7 = 8 + 8 + 8 + 8 + 8 + 8 + 8
  • 45. Sum of Arithmetic Series S7 = 1 + 2 + 3 + 4 + 5 + 6 + 7 S7 = 7 + 6 + 5 + 4 + 3 + 2 + 1 2S7 = 8 + 8 + 8 + 8 + 8 + 8 + 8 2S7 = 7(8) S7 =7/2(8) 7 sums of 8
  • 46. Sum of Arithmetic Series S7 =7/2(8) What do these numbers mean? 7 is n, 8 is the sum of the first and last term (a1 + an) So Sn = n/2(a1 + an)
  • 47. Examples Sn = n/2(a1 + an) Find the sum of the first 10 terms of the arithmetic series with a1 = 6 and a10 =51 S10 = 10/2(6 + 51) = 5(57) = 285
  • 48. Examples Find the sum of the first 50 terms of an arithmetic series with a1 = 28 and d = -4 We need to know n, a1, and a50. n= 50, a1 = 28, a50 = ?? We have to find it.
  • 49. Examples a50 = 28 + -4(50 - 1) = 28 + -4(49) = 28 + -196 = -168 So n = 50, a1 = 28, & an =-168 S50 = (50/2)(28 + -168) = 25(-140) = -3500
  • 50. Examples To write out a series and compute a sum can sometimes be very tedious. Mathematicians often use the greek letter sigma & summation notation to simplify this task.
  • 51. Examples This means to find the sum of the sums n + 1 where we plug in the values 1 - 5 for n last value of n First value of n formula used to find sequence
  • 52. Examples Basically we want to find (1 + 1) + (2 + 1) + (3 + 1) + (4 + 1) + (5 + 1) = 2 + 3 + 4 + 5 + 6 = 20
  • 53. Examples So Try: First we need to plug in the numbers 2 - 7 for x.
  • 54. Examples [3(2)-2]+[3(3)-2]+[3(4)-2]+ [3(5)-2]+[3(6)-2]+[3(7)-2] = (6-2)+(9-2)+(12-2)+(15-2)+ (18-2)+ (21-2) = 4 + 7 + 10 + 13 + 17 + 19 = 70
  • 56. GeometricSequence What if your pay check started at $100 a week and doubled every week. What would your salary be after four weeks?
  • 57. GeometricSequence Starting $100. After one week - $200 After two weeks - $400 After three weeks - $800 After four weeks - $1600. These values form a geometric sequence.
  • 58. Geometric Sequence Geometric Sequence: a sequence in which each term after the first is found by multiplying the previous term by a constant value called the common ratio.
  • 59. Geometric Sequence Find the first five terms of the geometric sequence with a1 = -3 and common ratio (r) of 5. -3, -15, -75, -375, -1875
  • 60. Geometric Sequence Find the common ratio of the sequence 2, -4, 8, -16, 32, To find the common ratio, divide any term by the previous term. 8 歎 -4 = -2 r = -2
  • 61. Geometric Sequence Just like arithmetic sequences, there is a formula for finding any given term in a geometric sequence. Lets figure it out using the pay check example.
  • 62. Geometric Sequence To find the 5th term we look 100 and multiplied it by two four times. Repeated multiplication is represented using exponents.
  • 63. Geometric Sequence Basically we will take $100 and multiply it by 24 a5 = 10024 = 1600 A5 is the term we are looking for, 100 was our a1, 2 is our common ratio, and 4 is n-1.
  • 64. Examples Thus our formula for finding any term of a geometric sequence is an = a1rn-1 Find the 10th term of the geometric sequence with a1 = 2000 and a common ratio of 1/2.
  • 65. Examples a10 = 2000 (1/2)9 = 2000 1/512 = 2000/512 = 500/128 = 250/64 = 125/32 Find the next two terms in the sequence -64, -16, -4 ...
  • 66. Examples -64, -16, -4, __, __ We need to find the common ratio so we divide any term by the previous term. -16/-64 = 1/4 So we multiply by 1/4 to find the next two terms.
  • 67. Examples -64, -16, -4, -1, -1/4
  • 68. Geometric Means Just like with arithmetic sequences, the missing terms between two nonconsecutive terms in a geometric sequence are called geometric means.
  • 69. Geometric Means Looking at the geometric sequence 3, 12, 48, 192, 768 the geometric means between 3 and 768 are 12, 48, and 192. Find two geometric means between -5 and 625.
  • 70. Geometric Means -5, __, __, 625 We need to know the common ratio. Since we only know nonconsecutive terms we will have to use the formula and work backwards.
  • 71. Geometric Means -5, __, __, 625 625 is a4, -5 is a1. 625 = -5r4-1 divide by -5 -125 = r3 take the cube root of both sides -5 = r
  • 72. Geometric Means -5, __, __, 625 Now we just need to multiply by -5 to find the means. -5 -5 = 25 -5, 25, __, 625 25 -5 = -125 -5, 25, -125, 625
  • 74. Geometric Series Geometric Series - the sum of the terms of a geometric sequence. Geo. Sequence: 1, 3, 9, 27, 81 Geo. Series: 1+3 + 9 + 27 + 81 What is the sum of the geometric series?
  • 75. Geometric Series 1 + 3 + 9 + 27 + 81 = 121 The formula for the sum Sn of the first n terms of a geometric series is given by
  • 76. Geometric Series Find You can actually do it two ways. Lets use the old way. Plug in the numbers 1 - 4 for n and add. [-3(2)1-1]+[-3(2)2-1]+[-3(2)3- 1]+ [-3(2)4-1]
  • 77. Geometric Series [-3(1)] + [-3(2)] + [-3(4)] + [-3(8)] = -3 + -6 + -12 + -24 = -45 The other method is to use the sum of geometric series formula.
  • 78. Geometric Series use a1 = -3, r = 2, n = 4
  • 79. Geometric Series use a1 = -3, r = 2, n = 4