際際滷

際際滷Share a Scribd company logo

ASK T2 1.1.2 MENUKAR NO PERPULUHAN KEPADA NO PERLAPANAN

Download as PPTX, PDF
S
Shamsul Ponijan

This document discusses converting decimal numbers to binary numbers. It provides two examples of taking decimal numbers and dividing them by 8 at each place value to get the corresponding binary representation. In the first example, 12510 is converted to 1758 in binary. In the second example, 226610 is converted to 43328 in binary. The document is teaching a computer science concept to students in secondary school about representing data in binary number systems.

1 of 5
Download to read offline
ASAS SAINS KOMPUTER TINGKATAN 2 BAB 1 : PERWAKILAN DATA 1.1 SISTEM NOMBOR PERLAPANAN 1.1.2(i) MENUKAR NOMBOR PERPULUHAN KEPADA NOMBOR PERLAPANAN CIKGU SHAMSUL BIN PONIJAN SMK SEG HWA (CF) SEGAMAT, JOHOR.
Soalan : 12510 Bahagi 8 5 1 7 = 1758Jawapan : 12510
Soalan : 12510 = 1758 83 82 81 80 semakan 512 64 8 1 1 X 64 7 X 8 5 X 1 64 + 56 + 5 = 125 Maka 12510 = 1758
Soalan : 226610 Bahagi 8 2 3 4 3 = 43328Jawapan : 226610
Soalan : 226610 = 43328 83 82 81 80 semakan 512 64 8 1 4 X 512 3 X 64 3 X 8 2 X 1 2048 + 192 + 24 + 2 = 2266 Maka 226610 = 43328

More Related Content

ASK T2 1.1.2 MENUKAR NO PERPULUHAN KEPADA NO PERLAPANAN

  • 1. ASAS SAINS KOMPUTER TINGKATAN 2 BAB 1 : PERWAKILAN DATA 1.1 SISTEM NOMBOR PERLAPANAN 1.1.2(i) MENUKAR NOMBOR PERPULUHAN KEPADA NOMBOR PERLAPANAN CIKGU SHAMSUL BIN PONIJAN SMK SEG HWA (CF) SEGAMAT, JOHOR.
  • 2. Soalan : 12510 Bahagi 8 5 1 7 = 1758Jawapan : 12510
  • 3. Soalan : 12510 = 1758 83 82 81 80 semakan 512 64 8 1 1 X 64 7 X 8 5 X 1 64 + 56 + 5 = 125 Maka 12510 = 1758
  • 4. Soalan : 226610 Bahagi 8 2 3 4 3 = 43328Jawapan : 226610
  • 5. Soalan : 226610 = 43328 83 82 81 80 semakan 512 64 8 1 4 X 512 3 X 64 3 X 8 2 X 1 2048 + 192 + 24 + 2 = 2266 Maka 226610 = 43328