Balencio por redox
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The document describes several chemical reactions: 1) Copper oxide and hydrogen sulfide react to form copper sulfide and other products. 2) Copper and sulfur undergo oxidation/reduction reactions. 3) Copper reacts with sulfuric acid to form copper sulfate, water, and sulfur dioxide. 4) Several equations show the mass calculations for the reactants and products in the reactions.
Balencio por redox
- 1. CuO + H1 2S6 O-2 4--------------Cu2 S6 O-2 4 + H1 2 O-2 + S4 O-2 2 Cu0 +2 e-------------- Cu2 S6 -2e-------------- S4 2(Cu0 +2 e-------------- Cu2 ) = 2Cu0 +4e-------------- 2Cu2 2(S6 -2e-------------- S4 ) = 2S6 -4e-------------- 2S4 Cu + 2H2SO4--------------CuSO4 +2 H2O + SO2 1-Cu-1 2-S-2 8-O-8 4-H-4
- 2. Mg 1 Cu = 63 x1 63 g/m Mg 2 H= 1 x 4 = 4 S= 32 x 2 = 64 O=16 x 8 = 128 196 m/g Mg3 Cu= 63 x1 =63 S= 32 x1= 32 O= 16 x 4= 64 =159 m/g Mg4 H= 1x4= 4 O= 16 x 2= 32 =36 m/g Mg 5 S =32 x 1 = 32 O= 16 x 2 = 32 =64 m/g
- 3. Fe3 2 O-2 3 + C2 O-2 ------------ Fe0 + C4 O-2 2 Fe3 -3e- ------------ Fe0 C2+2e ------------ C4 2(Fe3 -3e- ------------ Fe0 ) = 2Fe3 -6e- ------------ 2Fe0 3(C2+2e ------------ C4 ) = 3C2+6e ------------ 3C4 Fe2 O3 + 3CO ------------ 2Fe +3CO2 2-Fe-2 6-O-6 3-C-3
- 4. Mg 1 Fe= 56 x 2 =112 O = 16 x 3 =48 = 160 m/g Mg 2 C = 12 x 3 = 36 O= 16 x 3 =48 =84 m/g Mg 3 Fe= 56 x 2= 112 =122 m/g Mg 4 C =12 x 3 = 36 O=16 x 6 = 96 =132 m/g