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Khai Truong

Bi畛u 畛 t動董ng t叩c

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BIEU O TNG TAC BIEU O TNG TAC Vi畉t t畉ng c叩c th畉y, c担 d畉y m担n B棚 t担ng c畛t th辿p, hy v畛ng 動畛c qu箪 th畉y c担 動a ph畉n ny vo gi叩o tr狸nh gi畉ng d畉y cho sinh vi棚n v nh畛 ghi xu畉t x畛 ngu畛n tham kh畉o. Senior lecturer AnhHoang Le 1 -4000 -2000 0 2000 4000 6000 8000 10000 12000 14000 -2000 -1500 -1000 -500 0 500 1000 1500 2000 Bi 1
I. T働NG QUAN GI畛A NC V MC M畛t c畛t ng畉n kh担ng c畛t th辿p ti畉t di畛n Ac=b.h, ch畛u l畛c n辿n l NC. N畉u c動畛ng 畛 gi畛i h畉n s畛 d畛ng c畛a b棚 t担ng l Rb, th狸 c畛t c畛t s畉 ch畛u 動畛c 畉n t畉i tr畛ng t鱈nh to叩n l NC=Ac.Rb; Do c畛t kh担ng c坦 c畛t th辿p n棚n kh担ng ch畛u th棚m 動畛c Moment, ta c坦 moment t動董ng 畛ng l M=0, v n畉u c畛t kh担ng c坦 ch畛u t畉i tr畛ngNc=0 (kh担ng x辿t 畉n tr畛ng l動畛ng c畛a c畛t), th狸 c畛t c滴ng kh担ng ch畛u 動畛c moment M=0 h x NC MC b h/2
Ta c坦: NC=0; t動董ng 畛ng MC=0, v湛ng ch畛u n辿n c畛a b棚 t担ng x=0; NC=Ac.Rb; t動董ng 畛ng MC=0, v湛ng ch畛u n辿n c畛a b棚 t担ng x=h N畉u c畛t ch畛 ch畛u m畛t t畉i tr畛ng NC=sbAc< RbAc ch動a 畉t gi畛i h畉n th狸 c畛t c坦 th畛 ch畛u th棚m m畛t moment M do :sb<Rb NC=sb.b.x<Rb.b.h T畛 c担ng th畛c tr棚n cho sb=Rb, th狸 x<h khi 坦 l畛c NC s畉 c坦 畛 l畛ch t但m l e=遜(hx) n棚n ph叩t sinh ra moment MC=NC.e MC=NC.e=Rb.b.x.遜(hx); (v畛i NC=Rb.b.x) MC=遜.Rb.b.h2.(x/h)(1-x/h) v畛i xh=x/h NC=Rb.b.h.x MC=Rb.b.h2.[遜.xh.(1xh)] h x Nb MC e b h/2 x/2
Ta c坦 th畛 動a v畛 d畉ng kh担ng th畛 nguy棚n theo nguy棚n t畉c: chia N cho 畊=Rb.b.h; chia M cho 畊=Rb.b.h2: xh= a= 0 0 0.125 0.055 0.25 0.094 0.5 0.125 0.75 0.094 0.875 0.055 1 0.000 0 0.055 0.094 0.125 0.094 0.055 0.000 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 x a 0.055 0.094 0.125 0.875 0.25 0.125 0.5 0.75 T動董ng quan xh v a 動畛c th畛 hi畛n nh動 sau: h b C h b R N nuy x = = . . ) ( (xi) a x x = = ) .( . , . . . ) ( 1 5 0 2 h b R M muy b C (alpha)
Suy ra T動董ng quan gi畛a MC, v NC 動董c thi畉t l畉p theo tham s畛 x nh動 sau: x=0; N=0; M=0 x=遜.h N=遜.Rb.b.h; M= .Rb.b.h2 x=h N=Rb.b.h M=0 Ch炭 箪: Khi t鱈nh to叩n t動董ng t叩c gi畛a NC v MC do c坦 moment u畛n M n棚n kh担ng s畛 d畛ng c畉 chi畛u cao h nh動 trong n辿n thu畉n t炭y m ph畉i d湛ng 畉n chi畛u cao ho, v畛i gi畉 thi畉t v湛ng ch畛u n辿n 1 ph畉n trong b棚t担ng l x=x.ho c坦 畛ng su畉t ph但n b畛 畛u v 畉t gi畛i h畉n l Rb.. h x NC MC=NC.e e b h/2 x/2
Ta c坦 m畛t Parabol theo tr畛c honh. b=0,3m AC=0,235m Rb=11500 kPa RS =365000kPa h=0,45m ho=0,42m xR=0,590 AS=1016 mm2 a=0,03m ZS=0,39m x=x/h0 x= NC=Rb.b.x e=0,5*(h0-x) MC=NC*e 0 0.000 0 0.225 0.0 0.269 0.113 390 0.1685 65.7 0.536 0.225 776 0.1125 87.3 0.802 0.337 1163 0.0565 65.7 1 0.420 1449 0.015 21.7 1.071 0.450 1553 0 0.0 Th鱈 d畛: C畛t (0,30,45)m, b棚 t担ng Rb=11.500kPa, xR=0,590
Y L NGH懲A C B畉N C畛A BI畛U 畛 T働NG TC GI畛A NC V MC THAY 畛I THEO THAM S畛 x, VNG CH畛U NN C畛A BTNG 畉T TON B畛 GA TRI GI畛I H畉N S畛 D畛NG Rb T動董ng Quan gi畛a NC theo MC 0 390 776 1163 1449 1553 0 200 400 600 800 1000 1200 1400 1600 1800 0.0 20.0 40.0 60.0 80.0 100.0 Khi t鱈nh bi畛u 畛 t動董ng t叩c c坦 vai tr嘆 t叩c 畛ng c畛a Moment v畛i gi畉 thi畉t v湛ng ch畛u n辿n c畛a b棚 t担ng ph但n b畛 畛u n棚n khi t鱈nh l畛c n辿n NC trong b棚 t担ng ch畛 t鱈nh t畛i gi叩 tr畛 t畛i a c畛a v湛ng ch畛u n辿n x=ho. x=ho Kh担ng t鱈nh 畉n khi x=h
Cho tham s畛 x thay 畛i t畛 0 畉n ho t畛ng b動畛c 0,1.ho 畛i v畛i b棚 t担ng: T鱈nh Nb=Rb.b.hox v Mb= Rb.b.ho 2遜.x(1-x) theo x=x/ho, 畛i v畛i c畛t th辿p v湛ng ch畛u k辿o AS: V畛i gi畉 thi畉t 畛ng su畉t k辿o sS kh担ng v動畛t qu叩 RS, Do坦 khi x (nh畛): x xR th狸 sS=RS : L畛ch t但m l畛n khi x (l畛n): x> xR th狸 sS<RS :L畛ch t但m nh畛 cho 畉n khi sS= 0 sau 坦 chuy畛n qua b畛 n辿n sS< 0 ta c坦 th畛 xem 坦 l tr畉ng th叩i l畛ch t但m r畉t nh畛 (hay b辿) Khi x=ho: x=1: c畛t th辿p 畉t gi叩 tr畛 n辿n t畛i a sS=-RS T畛 bi畛u 畛 t動董ng t叩c c畛a c畛t b棚t担ng lm c董 s畛 畛 ti畉p theo ta c畛ng th棚m t叩c d畛ng c畛a n畛i l畛c c畛t th辿p m畛t b棚n ch畛u k辿o AS v m畛t b棚n ch畛u n辿n AS . NGUYN T畉C THI畉T L畉P
x= 0 xRho 0,5(1+xR)ho ho sS= RS =RS =0 =-RS Tr畉ng Th叩i L畛ch t但m l畛n L畛ch t但m nh畛 L畛ch t但m r畉t nh畛 N辿n RS -RS x=xR.ho x=0 x=ho x=1/2(1+xR).ho RS K辿o 畛ng su畉t sS c畛t th辿p trong v湛ng ch畛u k辿o c畛a b棚 t担ng 動董c m担 t畉 theo bi畛u 畛 sau v畛i gi畉 thi畉t l畉y RS=RS: T畛 坦 ta c坦 c担ng th畛c: S R S R S S R R R ]. ) ( ) ( [ ; : 1 1 1 2 = = x x s x x s x x :
1).Tr畉ng th叩i l畛ch t但m l畛n 動畛c m担 t畉 khi x=x/h0 t畛 0 畉n xR N畛i l畛c trong c畛t g畛m: L畛c n辿n c畛t: (sS=RS) NC=Nb+NS=Rb.b.xRS.AS (v狸 ng動畛c chi畛u) Moment c畛t: MC=Nb.e+NS.ZS/2 (v狸 c湛ng chi畛u) II. C畛T THP VNG CH畛U KO C畛A B TNG AS: ho x Nb MC e b h/2 x/2 NS Z2/2 a
x=x/ho x= Nb= Rb.b.x NS= RS.AS NC= Nb-NS e= 0,5*(ho-x) Mb= Nb*e MS= NS.ZS/2 MC= Nb+NS 0.000 0.000 0 (L畛c k辿o trong th辿p kh担ng 畛i =) 371 -371 0.225 0 (Moment kh担ng 畛i=) 36.2 36.2 0.100 0.042 145 -226 0.204 30 65.7 0.200 0.084 290 -81 0.183 53 89.2 0.300 0.126 435 64 0.162 70 106.6 0.400 0.168 580 209 0.141 82 117.9 0.500 0.210 725 354 0.12 87 123.1 0.590 0.248 855 484 0.1011 86 122.6 36.2, -371 122.6, 484 -500 -300 -100 100 300 500 700 900 1100 1300 1500 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 Nh動 v畉y trong tr畉ng th叩i ny (0xR) L畛c n辿n gi畉m v畛i gi叩 tr畛 kh担ng 畛i: RS.AS, 畛ng th畛i moment tng v畛i gi叩 tr畛 kh担ng 畛i: NS.ZS/2 T畛nh ti畉n ph畉n l畛ch t但ml畛n t畛 1 ph畉n bi畛u 畛 c畛a b棚t担ng Vect董 t畛nh ti畉n -371 36.2 1 ph畉n bi畛u 畛 c畛a b棚 t担ng 動畛c t畛nh ti畉n theo vect董 V1(36,2,-371) xR=0.59 C畛t kh担ng c畛t th辿p V1
2. Tr畉ng th叩i l畛ch t但m nh畛 Khi x= xR 畉n 0,5(1+xR) th狸 sS thay 畛i t畛 RS xu畛ng =0 N畛i l畛c trong c畛t g畛m: L畛c n辿n c畛t: NC=Nb+NS=Rb.b.xsS.AS Moment c畛t: MC=Nb.e+NS.ZS/2 ho x Nb Mb e b h/2 x/2 NS=0 ZS/2 a
-500 0 500 1000 1500 2000 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 x= x/ho x= Nb= Rb.b.x sS= Ns= sS.AS Nc= Nb-NS e= 0,5*(ho-x) Mb= Nb*e MS= NS.ZS/2 Mc= Nb+NS 0.590 0.248 855 365000 371 484 0.101 86 36.2 122.6 0.6 0.252 869 347195 353 517 0.099 86 34.4 120.5 0.7 0.294 1014 169146 172 842 0.078 79 16.8 95.9 0.795 0.334 1152 0 0 1152 0.058 67 0.0 66.9 x=xR=0,590 x=0,795 Tr畉ng th叩i l畛ch t但m nh畛 V1 V1
3. Tr畉ng th叩i l畛ch t但m r畉t nh畛 (b辿) Khi x=0,5(1+xR) 畉n 1 :sS thay 畛i t畛 =0 xu畛ng n辿n -RS N畛i l畛c trong c畛t g畛m: L畛c n辿n c畛t: NC=Nb+NS=Rb.b.xsS.AS Moment c畛t: MC=Nb.e+NS.ZS/2 x=ho Nb MC e b h/2 x/2 NS ZS/2 a
-500 0 500 1000 1500 2000 -40.0 -20.0 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 x= x/h0 x Nb= Rb.b.x sS= NS= RS.AS NC= Nb-NS e= 0,5*(h-x) Mb= Nb*e MS= NS.ZS/2 MC= Nb+NS 0.795 0.334 1152 0 0 1152 0.058 67 0.0 66.9 0.900 0.378 1304 -178049 -181 1485 0.036 47 -17.6 29.3 1 0.420 1449 -365000 -371 1820 0.015 22 -36.2 -14.4 x=0,795 x=1 Tr畉ng th叩i l畛ch t但m b辿
III. C畛T THP VNG CH畛U NN C畛A B TNG AS: C畛t th辿p AS 畛 v湛ng ch畛u n辿n c畛a b棚 t担ng v畛i c動畛ng 畛 t鱈nh b畉ng c動畛ng 畛 ch畛u k辿o RS: NS=RS.AS N畉m trong v湛ng ch畛u n辿n v畛i gi叩 tr畛 kh担ng 畛i v v畛 tr鱈 c畛 畛nh (ZS/2) n棚n khi c畛ng th棚m t叩c d畛ng c畛a c畛t th辿p ny th狸 n畛i l畛c trong c畛t gia tng v畛i gi叩 tr畛 c畛 畛nh kh担ng t湛y thu畛c vo tham s畛 x (v湛ng ch畛u n辿n c畛a b棚 t担ng) Ta 動畛c: L畛c n辿n: NS=RS.AS Moment: MS=RS.AS.ZS/2 h/2 x NC MC e b Z/2 NS Z/2 a N'S a x/2 h/2 VNG CH畛U NN
x= x/ho x= NC= Nb-NS NS= AS.RS NR= Nb-NS+NS MC= Mb+MS MS= NS.ZS/2 MR= Mb+MS+MS 0.000 0.000 -371 (L畛c n辿n c畛a c畛t th辿p n辿n kh担ng 畛i=) 371 0 36.2 (Moment c畛a c畛t th辿p n辿n kh担ng 畛i =) 36.2 72.4 0.100 0.042 -226 145 65.7 101.9 0.200 0.084 -81 290 89.2 125.4 0.300 0.126 64 435 106.6 142.8 0.400 0.168 209 580 117.9 154.1 0.500 0.210 354 725 123.1 159.3 0.590 0.248 484 855 122.6 158.8 0.600 0.252 517 887 120.5 156.7 0.700 0.294 842 1213 95.9 132.1 0.795 0.334 1152 1523 66.9 103.1 0.900 0.378 1304 1675 29.3 65.5 1.000 0.420 1449 1820 -14.4 21.8 Nh動 v畉y trong 畛 th畛 ta ch畛 c畉n t畛nh ti畉n 動畛ng cong c畛a b棚 t担ng v c畛t th辿p v湛ng ch畛u k辿o i l棚n theo vect董 V2(MS,NS) TA 働畛C BI畛U 畛 T働NG TC B畉ng t鱈nh t畛ng h畛p th棚m ph畉n t叩c 畛ng c畛a c畛t th辿p AS trong v湛ng ch畛u n辿n c畛a b棚 t担ng NR t畛ng l畛c n辿n, MR t畛ng moment
-500 0 500 1000 1500 2000 2500 -20.0 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 160.0 180.0 36.2 371 sS=0 sS=-RS B棚 t担ng+c畛t th辿p AS+C畛t th辿p AS B棚 t担ng kh担ng c畛t th辿p B棚 t担ng+c畛t th辿p AS sS=RS sS=RS BI畛U 畛 T働NG TC V2 V2 V2 V2 V2 V2
T畛 c叩c 箪 ngh挑a tr棚n, ta ch畛 c畉n v畉 c叩c 4 i畛m gi畛i h畉n c畛a c叩c tr畉ng th叩i l x=0; x=xR; x=0,5.(1+xR) v x=1. Tuy nhi棚n do trong o畉n l畛ch t但m l畛n l o畉n c坦 畛 cong l畛n n棚n khi n畛i c叩c i畛m d畛 dng h董n ta b畛 xung th棚m m畛t i畛m n畛a l x=0,5xR. IV. TRNH T畛 THI畉T L畉P BI畛U 畛 T働NG TC: 畛 董n gi畉n ta l畉y c叩c s畛 li畛u AS=AS; a=a; RS=RS T畉i Tr畛ng N0=T畉i tr畛ng N辿n t叩c 畛ng M0=T畉i tr畛ng moment CHI畛U CAO C畛T= H(m) H畛 s畛 u畛n d畛c K Chi畛u cao t鱈nh to叩n Ho=K.H B畛 r畛ng ti畉t di畛n c畛t= b(m) L畛p b畉o v畛 a(cm) ho=Chi畛u cao h畛u 鱈ch B畛 cao ti畉t di畛n c畛t= h(m) ZS=@ c畛t th辿p k辿o v n辿n C畉p 畛 b畛n b棚 t担ng= B# Rb=C動畛ng 畛 n辿n b棚 t担ng xR=. Lo畉i th辿p A? Rs=C動畛ng 畛 k辿o, n辿n th辿p
L畛ch t但m T畉i tr畛ng eN=M0/N0= L畛ch t但m Ng畉u nhi棚n eNg= (H/600; h/30; 1cm) L畛ch t但m ban 畉u eo=eN+eNg= L畛c n辿n t畛i h畉n: H畛 s畛 u畛n d畛c T畉i tr畛ng d湛ng 畛 ki畛m tra L畛ch t但m t鱈nh to叩n ett=h.eO= Ntt= N0 Mtt=Ntt.ett = = h CR N N 1 1 1) x=0.hO=0 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 k辿o sS=RS=365000 NS=0 (ng動畛c chi畛u) MS=AS.RS.ZS ZOb=(h-x)/2=0.250 NR=Nb MR=Mb+MS 2) x=0,5.hO=0.230 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 k辿o sS=RS=365000 NS=0 (ng動畛c chi畛u) MS=AS.RS.ZS ZOb=(h-x)/2=0.135 NR=Nb MR=Mb+MS 3) x=xR.hO=0.259 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 k辿o sS=RS=365000 NS=0 (ng動畛c chi畛u) MS=AS.RS.ZS ZOb=(h-x)/2=0.121 NR=Nb+NS MR=Mb+MS 4) x=(1+xR).hO/2=0.359 Nb=Rb.b.x Mb=Rb.b.x.ZOb sS=0 NS=AS.RS (c畛t th辿p n辿n) MS=AS.RS.ZS/2 ZOb=(h-x)/2=0.070 NR=Nb+NS MR=Mb+MS
Ntt=2100 Mtt=224 342 0 500 1000 1500 2000 2500 3000 3500 4000 4500 0 50 100 150 200 250 300 350 400 450 Bi畛u 畛 T動董ng T叩c gi畛a NR v MR L畛ch t但m l畛n L畛ch t但m nh畛 L畛ch t但m b辿 x=1 x=0,5(1+xR) x=xR x=0 5) x=hO=0.460 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 n辿n sS=-RS=-365000 NS=2AS.RS(c畉 hai b畛 n辿n) MS=0(ng動畛cchi畛u) ZOb=(h-x)/2=0.020 NR=NR+NR MR=Mb
V. CCH XC 畛NH H畛 S畛 AN TON CHO C畛T: 畛 x叩c 畛nh h畛 s畛 an ton cho c畛t do c坦 2 tr畛 s畛 c畉n t鱈nh to叩n l Ntt v Mtt n棚n 動畛c x叩c 畛nh tr棚n nguy棚n t畉c sau: 1. Cho HSAT c畛a Ntt l 1 (kN=1) ta t鱈nh 動畛c h畛 s畛 an ton c畛a Moment l kM=MK/Mtt>1 2. Cho HSAT c畛a Mtt l 1 (kM=1) ta t鱈nh 動畛c h畛 s畛 an ton c畛a L畛c n辿n l kN=NK/Ntt>1 3. H畛 s畛 an ton chung cho c畉 hai Ntt v Mtt t動董ng 畛ng khi kN=kM 4. 畛 th畛c hi畛n i畛u ny ta v畉 trong h畛 th畛ng tr畛c t畛a 畛 xOy hai i畛m N(1,kM); M(kN, 1) 5. V畉 動畛ng ph但n gi叩c th畛 1 c畉t o畉n th畉ng NM t畉i i畛m c坦 kN=kM 坦 ch鱈nh l h畛 s畛 an ton c畛a c畛t kC=kN=kM
C担ng th畛c t鱈nh: kC=(1-kN.kM)/(2-kN-kM)
C叩ch x叩c 畛nh kM v kN D畛a vo bi畛u 畛 t動董ng t叩c v t畛a 畛 c畛a Mtt v Ntt K辿o di honh 畛 Mtt c畉t bi畛u 畛 t畉i i畛m c坦 tung 畛 l NK K辿o di tung 畛 Ntt c畉t bi畛u 畛 t畉i i畛m c坦 honh 畛 l MK Dung ph辿p n畛i suy ta t鱈nh 動畛c MK v NK 2100 224 0 500 1000 1500 2000 2500 3000 3500 4000 4500 0 50 100 150 200 250 300 350 400 450 (Mtt, Ntt) NK MK H畛 s畛 an ton c畛a Mtt: kM=MK/Mtt H畛 s畛 an ton c畛a Ntt: kN=NK/Ntt Ntt Mtt
5 aR = 0.248 K= 5 1 lb=Ho/ b = 8 10 14 18 22 26 32 38 Ho = 4.6 j = 1 0.98 0.93 0.85 0.77 0.68 0.54 0.4 N.heo N 0 1 6 0 0 Co辰 t cao H 2 0 4 1 6 0 0 N(kN)= 1600 M(kNm)= 120 h(m)= 0.4 b(m) = 0.25 4.6 2 0 4 0 a(cm)= 3 ho= 0.37 ZS= 0.34 lb=Ho/b= 18.4 j1 Mac BT Ca叩 p 単o辰be n B# 30.0 Rb = 17,000 Eb = 3.3E+07 J b = 0.00133 1.55 4 0 0 3 RS= 365,000 ES= 2.0E+08 J S= 0.000027 xR = 0.540 xR=xR.ho= 0.200 a= 6.15 b= 0.020 925 0.8091 28<l<30 Ab = 0.10000 Jb = 0.00133 0.000925 0.014463 0.075 deMIN= 0.215 1492 0.013 de=eo/ho= 0.239 S= 0.4247 2 f 25 0.088 La叩 y de= 0.239 4 f 22 L旦誰 c do誰 c T I HA N NCR(kN)= 5209 2502 h = 1.443 he0= 0.127 Ca叩 uTa誰 o xB = N/(Rb.b)= 0.376 Moment (kN.m) 2 f 25 e = 0.297 N*e = 476 4 f 22 e0gh= 0.120 2502 N/(Rb.b)=0.376 Hay j = 0.83 -41.6 cm2 USThe湛 p 228,126 Cho誰 n 5 f 25 0.043 [N*e] = 542 kN.m 2453 0.120 x = 0.257 T鱈nh Toa湛 n theo Quy Pha誰 m na棚 m 1991 The湛 p Rs(Kpa) = Co叩 t The湛 p As(m2 )= JS Co叩 t The湛 p(m4 )= DT/Be但 to但 ng (m2 ) J Be但 to但 ng (m4 ) Ha淡 m l旦担誰 ng co叩 t the湛 p ta誰 m t鱈nh= 1% = BI E U O TNG TA C OK Chie u cao vu淡 ng ch嘆 u Ne湛 n Kie達 m tra 単ie u kie辰 n: N.e < [Ne] 0,4.(1,25.h - ao.ho) = Cho誰 n As(mm2 ) = T鱈nh A's(mm2 )= Cho誰 n A's(mm2 ) = L担湛 p ba短 o ve辰 a --> Tie叩 t die辰 n co辰 t: chie u cao h, be ro辰 ng b Ta短 i Tro誰 ng He辰 so叩 uo叩 n do誰 c Le辰 ch ta但 m the湛 p ne湛 n Ke叩 t Lua辰 n T鱈nh As(mm2 )= TI NH CO T THE P KHO NG O I X NG T鱈nh toa湛 n ca叩 u kie 辰 n ne 湛 n Le 辰 ch ta但 m Theo He辰tho叩 ng 単担n v嘆SI CA U KI E N CH U NE N Tha誰 c s坦 Le但Anh Hoa淡 ng Cho誰 n s担 単o : ? --> N = j .(Rb*Ab + Rs*As) NHA P SO LIE U VA O TRONG CA C O MA U VA NG CH O , be但 n ca誰 nh o但 xanh CO T THE P Le辰 ch ta但 m Nga奪 u nhie但 n eNg= Le辰 ch ta但 m ban 単a u eO= LE CH TA M BE 1,2-0,02*lb = Le辰 ch ta但 m eN=M/N= OK Co叩 t the湛 p Fa = Fa'= Ke叩 t Lua辰 n TinhToanBTCTNenLT1D.xls CO T THE P KE O CO T THE P NE N TI NH CO T THE P O I X NG Ye但 u ca u Co叩 t the湛 p Fa=Fa'= Chie u cao vu淡 ng ch嘆 u ne湛 n: x= 0,4*(1,25*h-xo.ho)= j 0 500 1000 1500 2000 2500 3000 3500 4000 0 50 100 150 200 250 300 350 400 K=1 S担 単 o1 S担 単 o2 S担 単 o3 S担 単 o5 S担 単 o4 K=0 ,7 K=0 ,5 K=2 K=0 ,7 b R A A R N x n s s s . ) ' .( = = d = ) . , , ( 01 1 0 11 0 e S ] . . [ ) ( . , b a j = 1 2 4 6 S H J E N O b b CR Ch動董ng Tr狸nh t鱈nh to叩n v ki畛m tra c畛t n辿n l畛ch t但m Ti棚u chu畉n 5574-1991
N = 800 M= 180 Mdh = 180 5 f 20 0.001571 3.4 K= 1.0 Ho= 3.4 0 f 14 0 0.4 a(cm)= h o= 0.460 zs=ZS/h= HO/ h = 6.80 AS= 0.001571 0.5 4 ZS= 0.420 0.840 J b= 0.0042 m4 20 Rb= 11500 Kpa Eb= 27000 B T # 2 5 0 The湛 p A 1 Rs= 225000 Kpa Es= 210000 w= 0.758 xR= 0.645 s= 0.007 J S= eN= M/N = 0.225 m 0.317 eNg= H /600;h/30 ;1 0.013 m 0.596 eo= eN+eNg= 0.238 m 0.596 2.000 N CR= 24145 kN 0.247 q= 0.617 N t t = 8 0 0 kN 19 7 kN.M 0 Ke湛 o ss=-Rs= -225000 N R= 0 0.250 MR= 1 4 8 0.230 N = 8 0 0 Mr = 2 7 9 Ke湛 o ss=-Rs= -225000 N R= 1 0 5 8 0.174 OK 0.135 MR= 2 9 1 0.297 Ke湛 o ss=-Rs= -225000 N R= 1 3 6 5 0.102 MR= 2 8 7 0.378 ss= 0 N R= 2 0 9 4 0.061 MR= 1 8 0 0.460 Ne湛 n ss=Rs= 225000 N R= 2 8 2 3 0.020 MR= 4 2 5) x =h O= ZOb=(h-x)/2= Le辰 ch ta但 m Ta短 i tro誰 ng H畛 s畛 demin= ZOb=(h-x)/2= ZOb=(h-x)/2= ZOb=(h-x)/2= 1) x =0.h O= 2) x =0,5.h O= 3) x =xR .h O= S O T NH CO T NE N L E CH T A M 1D Le辰 ch ta但 m t鱈nh toa湛 n h.eO= Ths Le但 anh H oa淡 ng aushoang@gmail.com 1.034 T畉i Tr畛ng CO T CAO H(m)= B畛 r畛ng b(m)= B畛 cao h(m)= Ti e 叩 t di e 辰 n CO T v担湛 i Ke 叩 t Lua 辰 n Ta短 i Tro誰 ng T鱈nh Toa湛 n o 辰 B e n C a 叩 u K ie 辰 n C h 嘆 u N e 湛 n N R v a 淡 C h 嘆 u Uo 叩 n MR 0.258 H畛 s畛 L畛ch ta但 m u畛n d畛c C畛t th辿p 畛i x畛ng: Le 辰 c h Ta 但 m L担湛 n demin=0,5-0,01*Ho/h-0,01*Rb Mt t =N t t .h.eO= Mpa a= 7.78 0.000138545 H畛 s畛 de=eo/h = L 旦 誰 c n e湛 n t 担湛 i h a誰 n : B IE U O T N G T A C C畉p 畛 b畛n B# H畛 s畛 de= Le辰 ch ta但 m Nga達 u nhie但 n Le辰 ch ta但 m ban 単a u 4) x =(1+xR).h O/2= ZOb=(h-x)/2= 0 0.1 0.2 0.3 0.4 0.5 0.6 0 0.1 0.2 0.3 0.4 0.5 = d = ) . , , ( 01 1 0 11 0 e S = = h CR N N 1 1 = b = j ) / (. M Md h 1 1 ] . . [ ) ( . , S b O b CR J S J H E N a j = 1 2 4 6 x x / 2 Z a =h o -a a a h o ZOb = (h / 2-x / 2) h / 2 A s .ss A 's .Rs S s S b R A R x b R N ). ( . . s = 2 / . ). ( . . . S S s S Ob b R Z A R Z x b R M s = 204 800 279 0 500 1000 1500 2000 2500 3000 0 50 100 150 200 250 300 350 Ch動董ng Tr狸nh ki畛m tra c畛t n辿n l畛ch t但m theo Bi畛u 畛 t動董ng t叩c

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BieuDoTuongTac1.ppt

  • 1. BIEU O TNG TAC BIEU O TNG TAC Vi畉t t畉ng c叩c th畉y, c担 d畉y m担n B棚 t担ng c畛t th辿p, hy v畛ng 動畛c qu箪 th畉y c担 動a ph畉n ny vo gi叩o tr狸nh gi畉ng d畉y cho sinh vi棚n v nh畛 ghi xu畉t x畛 ngu畛n tham kh畉o. Senior lecturer AnhHoang Le 1 -4000 -2000 0 2000 4000 6000 8000 10000 12000 14000 -2000 -1500 -1000 -500 0 500 1000 1500 2000 Bi 1
  • 2. I. T働NG QUAN GI畛A NC V MC M畛t c畛t ng畉n kh担ng c畛t th辿p ti畉t di畛n Ac=b.h, ch畛u l畛c n辿n l NC. N畉u c動畛ng 畛 gi畛i h畉n s畛 d畛ng c畛a b棚 t担ng l Rb, th狸 c畛t c畛t s畉 ch畛u 動畛c 畉n t畉i tr畛ng t鱈nh to叩n l NC=Ac.Rb; Do c畛t kh担ng c坦 c畛t th辿p n棚n kh担ng ch畛u th棚m 動畛c Moment, ta c坦 moment t動董ng 畛ng l M=0, v n畉u c畛t kh担ng c坦 ch畛u t畉i tr畛ngNc=0 (kh担ng x辿t 畉n tr畛ng l動畛ng c畛a c畛t), th狸 c畛t c滴ng kh担ng ch畛u 動畛c moment M=0 h x NC MC b h/2
  • 3. Ta c坦: NC=0; t動董ng 畛ng MC=0, v湛ng ch畛u n辿n c畛a b棚 t担ng x=0; NC=Ac.Rb; t動董ng 畛ng MC=0, v湛ng ch畛u n辿n c畛a b棚 t担ng x=h N畉u c畛t ch畛 ch畛u m畛t t畉i tr畛ng NC=sbAc< RbAc ch動a 畉t gi畛i h畉n th狸 c畛t c坦 th畛 ch畛u th棚m m畛t moment M do :sb<Rb NC=sb.b.x<Rb.b.h T畛 c担ng th畛c tr棚n cho sb=Rb, th狸 x<h khi 坦 l畛c NC s畉 c坦 畛 l畛ch t但m l e=遜(hx) n棚n ph叩t sinh ra moment MC=NC.e MC=NC.e=Rb.b.x.遜(hx); (v畛i NC=Rb.b.x) MC=遜.Rb.b.h2.(x/h)(1-x/h) v畛i xh=x/h NC=Rb.b.h.x MC=Rb.b.h2.[遜.xh.(1xh)] h x Nb MC e b h/2 x/2
  • 4. Ta c坦 th畛 動a v畛 d畉ng kh担ng th畛 nguy棚n theo nguy棚n t畉c: chia N cho 畊=Rb.b.h; chia M cho 畊=Rb.b.h2: xh= a= 0 0 0.125 0.055 0.25 0.094 0.5 0.125 0.75 0.094 0.875 0.055 1 0.000 0 0.055 0.094 0.125 0.094 0.055 0.000 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 x a 0.055 0.094 0.125 0.875 0.25 0.125 0.5 0.75 T動董ng quan xh v a 動畛c th畛 hi畛n nh動 sau: h b C h b R N nuy x = = . . ) ( (xi) a x x = = ) .( . , . . . ) ( 1 5 0 2 h b R M muy b C (alpha)
  • 5. Suy ra T動董ng quan gi畛a MC, v NC 動董c thi畉t l畉p theo tham s畛 x nh動 sau: x=0; N=0; M=0 x=遜.h N=遜.Rb.b.h; M= .Rb.b.h2 x=h N=Rb.b.h M=0 Ch炭 箪: Khi t鱈nh to叩n t動董ng t叩c gi畛a NC v MC do c坦 moment u畛n M n棚n kh担ng s畛 d畛ng c畉 chi畛u cao h nh動 trong n辿n thu畉n t炭y m ph畉i d湛ng 畉n chi畛u cao ho, v畛i gi畉 thi畉t v湛ng ch畛u n辿n 1 ph畉n trong b棚t担ng l x=x.ho c坦 畛ng su畉t ph但n b畛 畛u v 畉t gi畛i h畉n l Rb.. h x NC MC=NC.e e b h/2 x/2
  • 6. Ta c坦 m畛t Parabol theo tr畛c honh. b=0,3m AC=0,235m Rb=11500 kPa RS =365000kPa h=0,45m ho=0,42m xR=0,590 AS=1016 mm2 a=0,03m ZS=0,39m x=x/h0 x= NC=Rb.b.x e=0,5*(h0-x) MC=NC*e 0 0.000 0 0.225 0.0 0.269 0.113 390 0.1685 65.7 0.536 0.225 776 0.1125 87.3 0.802 0.337 1163 0.0565 65.7 1 0.420 1449 0.015 21.7 1.071 0.450 1553 0 0.0 Th鱈 d畛: C畛t (0,30,45)m, b棚 t担ng Rb=11.500kPa, xR=0,590
  • 7. Y L NGH懲A C B畉N C畛A BI畛U 畛 T働NG TC GI畛A NC V MC THAY 畛I THEO THAM S畛 x, VNG CH畛U NN C畛A BTNG 畉T TON B畛 GA TRI GI畛I H畉N S畛 D畛NG Rb T動董ng Quan gi畛a NC theo MC 0 390 776 1163 1449 1553 0 200 400 600 800 1000 1200 1400 1600 1800 0.0 20.0 40.0 60.0 80.0 100.0 Khi t鱈nh bi畛u 畛 t動董ng t叩c c坦 vai tr嘆 t叩c 畛ng c畛a Moment v畛i gi畉 thi畉t v湛ng ch畛u n辿n c畛a b棚 t担ng ph但n b畛 畛u n棚n khi t鱈nh l畛c n辿n NC trong b棚 t担ng ch畛 t鱈nh t畛i gi叩 tr畛 t畛i a c畛a v湛ng ch畛u n辿n x=ho. x=ho Kh担ng t鱈nh 畉n khi x=h
  • 8. Cho tham s畛 x thay 畛i t畛 0 畉n ho t畛ng b動畛c 0,1.ho 畛i v畛i b棚 t担ng: T鱈nh Nb=Rb.b.hox v Mb= Rb.b.ho 2遜.x(1-x) theo x=x/ho, 畛i v畛i c畛t th辿p v湛ng ch畛u k辿o AS: V畛i gi畉 thi畉t 畛ng su畉t k辿o sS kh担ng v動畛t qu叩 RS, Do坦 khi x (nh畛): x xR th狸 sS=RS : L畛ch t但m l畛n khi x (l畛n): x> xR th狸 sS<RS :L畛ch t但m nh畛 cho 畉n khi sS= 0 sau 坦 chuy畛n qua b畛 n辿n sS< 0 ta c坦 th畛 xem 坦 l tr畉ng th叩i l畛ch t但m r畉t nh畛 (hay b辿) Khi x=ho: x=1: c畛t th辿p 畉t gi叩 tr畛 n辿n t畛i a sS=-RS T畛 bi畛u 畛 t動董ng t叩c c畛a c畛t b棚t担ng lm c董 s畛 畛 ti畉p theo ta c畛ng th棚m t叩c d畛ng c畛a n畛i l畛c c畛t th辿p m畛t b棚n ch畛u k辿o AS v m畛t b棚n ch畛u n辿n AS . NGUYN T畉C THI畉T L畉P
  • 9. x= 0 xRho 0,5(1+xR)ho ho sS= RS =RS =0 =-RS Tr畉ng Th叩i L畛ch t但m l畛n L畛ch t但m nh畛 L畛ch t但m r畉t nh畛 N辿n RS -RS x=xR.ho x=0 x=ho x=1/2(1+xR).ho RS K辿o 畛ng su畉t sS c畛t th辿p trong v湛ng ch畛u k辿o c畛a b棚 t担ng 動董c m担 t畉 theo bi畛u 畛 sau v畛i gi畉 thi畉t l畉y RS=RS: T畛 坦 ta c坦 c担ng th畛c: S R S R S S R R R ]. ) ( ) ( [ ; : 1 1 1 2 = = x x s x x s x x :
  • 10. 1).Tr畉ng th叩i l畛ch t但m l畛n 動畛c m担 t畉 khi x=x/h0 t畛 0 畉n xR N畛i l畛c trong c畛t g畛m: L畛c n辿n c畛t: (sS=RS) NC=Nb+NS=Rb.b.xRS.AS (v狸 ng動畛c chi畛u) Moment c畛t: MC=Nb.e+NS.ZS/2 (v狸 c湛ng chi畛u) II. C畛T THP VNG CH畛U KO C畛A B TNG AS: ho x Nb MC e b h/2 x/2 NS Z2/2 a
  • 11. x=x/ho x= Nb= Rb.b.x NS= RS.AS NC= Nb-NS e= 0,5*(ho-x) Mb= Nb*e MS= NS.ZS/2 MC= Nb+NS 0.000 0.000 0 (L畛c k辿o trong th辿p kh担ng 畛i =) 371 -371 0.225 0 (Moment kh担ng 畛i=) 36.2 36.2 0.100 0.042 145 -226 0.204 30 65.7 0.200 0.084 290 -81 0.183 53 89.2 0.300 0.126 435 64 0.162 70 106.6 0.400 0.168 580 209 0.141 82 117.9 0.500 0.210 725 354 0.12 87 123.1 0.590 0.248 855 484 0.1011 86 122.6 36.2, -371 122.6, 484 -500 -300 -100 100 300 500 700 900 1100 1300 1500 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 Nh動 v畉y trong tr畉ng th叩i ny (0xR) L畛c n辿n gi畉m v畛i gi叩 tr畛 kh担ng 畛i: RS.AS, 畛ng th畛i moment tng v畛i gi叩 tr畛 kh担ng 畛i: NS.ZS/2 T畛nh ti畉n ph畉n l畛ch t但ml畛n t畛 1 ph畉n bi畛u 畛 c畛a b棚t担ng Vect董 t畛nh ti畉n -371 36.2 1 ph畉n bi畛u 畛 c畛a b棚 t担ng 動畛c t畛nh ti畉n theo vect董 V1(36,2,-371) xR=0.59 C畛t kh担ng c畛t th辿p V1
  • 12. 2. Tr畉ng th叩i l畛ch t但m nh畛 Khi x= xR 畉n 0,5(1+xR) th狸 sS thay 畛i t畛 RS xu畛ng =0 N畛i l畛c trong c畛t g畛m: L畛c n辿n c畛t: NC=Nb+NS=Rb.b.xsS.AS Moment c畛t: MC=Nb.e+NS.ZS/2 ho x Nb Mb e b h/2 x/2 NS=0 ZS/2 a
  • 13. -500 0 500 1000 1500 2000 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 x= x/ho x= Nb= Rb.b.x sS= Ns= sS.AS Nc= Nb-NS e= 0,5*(ho-x) Mb= Nb*e MS= NS.ZS/2 Mc= Nb+NS 0.590 0.248 855 365000 371 484 0.101 86 36.2 122.6 0.6 0.252 869 347195 353 517 0.099 86 34.4 120.5 0.7 0.294 1014 169146 172 842 0.078 79 16.8 95.9 0.795 0.334 1152 0 0 1152 0.058 67 0.0 66.9 x=xR=0,590 x=0,795 Tr畉ng th叩i l畛ch t但m nh畛 V1 V1
  • 14. 3. Tr畉ng th叩i l畛ch t但m r畉t nh畛 (b辿) Khi x=0,5(1+xR) 畉n 1 :sS thay 畛i t畛 =0 xu畛ng n辿n -RS N畛i l畛c trong c畛t g畛m: L畛c n辿n c畛t: NC=Nb+NS=Rb.b.xsS.AS Moment c畛t: MC=Nb.e+NS.ZS/2 x=ho Nb MC e b h/2 x/2 NS ZS/2 a
  • 15. -500 0 500 1000 1500 2000 -40.0 -20.0 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 x= x/h0 x Nb= Rb.b.x sS= NS= RS.AS NC= Nb-NS e= 0,5*(h-x) Mb= Nb*e MS= NS.ZS/2 MC= Nb+NS 0.795 0.334 1152 0 0 1152 0.058 67 0.0 66.9 0.900 0.378 1304 -178049 -181 1485 0.036 47 -17.6 29.3 1 0.420 1449 -365000 -371 1820 0.015 22 -36.2 -14.4 x=0,795 x=1 Tr畉ng th叩i l畛ch t但m b辿
  • 16. III. C畛T THP VNG CH畛U NN C畛A B TNG AS: C畛t th辿p AS 畛 v湛ng ch畛u n辿n c畛a b棚 t担ng v畛i c動畛ng 畛 t鱈nh b畉ng c動畛ng 畛 ch畛u k辿o RS: NS=RS.AS N畉m trong v湛ng ch畛u n辿n v畛i gi叩 tr畛 kh担ng 畛i v v畛 tr鱈 c畛 畛nh (ZS/2) n棚n khi c畛ng th棚m t叩c d畛ng c畛a c畛t th辿p ny th狸 n畛i l畛c trong c畛t gia tng v畛i gi叩 tr畛 c畛 畛nh kh担ng t湛y thu畛c vo tham s畛 x (v湛ng ch畛u n辿n c畛a b棚 t担ng) Ta 動畛c: L畛c n辿n: NS=RS.AS Moment: MS=RS.AS.ZS/2 h/2 x NC MC e b Z/2 NS Z/2 a N'S a x/2 h/2 VNG CH畛U NN
  • 17. x= x/ho x= NC= Nb-NS NS= AS.RS NR= Nb-NS+NS MC= Mb+MS MS= NS.ZS/2 MR= Mb+MS+MS 0.000 0.000 -371 (L畛c n辿n c畛a c畛t th辿p n辿n kh担ng 畛i=) 371 0 36.2 (Moment c畛a c畛t th辿p n辿n kh担ng 畛i =) 36.2 72.4 0.100 0.042 -226 145 65.7 101.9 0.200 0.084 -81 290 89.2 125.4 0.300 0.126 64 435 106.6 142.8 0.400 0.168 209 580 117.9 154.1 0.500 0.210 354 725 123.1 159.3 0.590 0.248 484 855 122.6 158.8 0.600 0.252 517 887 120.5 156.7 0.700 0.294 842 1213 95.9 132.1 0.795 0.334 1152 1523 66.9 103.1 0.900 0.378 1304 1675 29.3 65.5 1.000 0.420 1449 1820 -14.4 21.8 Nh動 v畉y trong 畛 th畛 ta ch畛 c畉n t畛nh ti畉n 動畛ng cong c畛a b棚 t担ng v c畛t th辿p v湛ng ch畛u k辿o i l棚n theo vect董 V2(MS,NS) TA 働畛C BI畛U 畛 T働NG TC B畉ng t鱈nh t畛ng h畛p th棚m ph畉n t叩c 畛ng c畛a c畛t th辿p AS trong v湛ng ch畛u n辿n c畛a b棚 t担ng NR t畛ng l畛c n辿n, MR t畛ng moment
  • 18. -500 0 500 1000 1500 2000 2500 -20.0 0.0 20.0 40.0 60.0 80.0 100.0 120.0 140.0 160.0 180.0 36.2 371 sS=0 sS=-RS B棚 t担ng+c畛t th辿p AS+C畛t th辿p AS B棚 t担ng kh担ng c畛t th辿p B棚 t担ng+c畛t th辿p AS sS=RS sS=RS BI畛U 畛 T働NG TC V2 V2 V2 V2 V2 V2
  • 19. T畛 c叩c 箪 ngh挑a tr棚n, ta ch畛 c畉n v畉 c叩c 4 i畛m gi畛i h畉n c畛a c叩c tr畉ng th叩i l x=0; x=xR; x=0,5.(1+xR) v x=1. Tuy nhi棚n do trong o畉n l畛ch t但m l畛n l o畉n c坦 畛 cong l畛n n棚n khi n畛i c叩c i畛m d畛 dng h董n ta b畛 xung th棚m m畛t i畛m n畛a l x=0,5xR. IV. TRNH T畛 THI畉T L畉P BI畛U 畛 T働NG TC: 畛 董n gi畉n ta l畉y c叩c s畛 li畛u AS=AS; a=a; RS=RS T畉i Tr畛ng N0=T畉i tr畛ng N辿n t叩c 畛ng M0=T畉i tr畛ng moment CHI畛U CAO C畛T= H(m) H畛 s畛 u畛n d畛c K Chi畛u cao t鱈nh to叩n Ho=K.H B畛 r畛ng ti畉t di畛n c畛t= b(m) L畛p b畉o v畛 a(cm) ho=Chi畛u cao h畛u 鱈ch B畛 cao ti畉t di畛n c畛t= h(m) ZS=@ c畛t th辿p k辿o v n辿n C畉p 畛 b畛n b棚 t担ng= B# Rb=C動畛ng 畛 n辿n b棚 t担ng xR=. Lo畉i th辿p A? Rs=C動畛ng 畛 k辿o, n辿n th辿p
  • 20. L畛ch t但m T畉i tr畛ng eN=M0/N0= L畛ch t但m Ng畉u nhi棚n eNg= (H/600; h/30; 1cm) L畛ch t但m ban 畉u eo=eN+eNg= L畛c n辿n t畛i h畉n: H畛 s畛 u畛n d畛c T畉i tr畛ng d湛ng 畛 ki畛m tra L畛ch t但m t鱈nh to叩n ett=h.eO= Ntt= N0 Mtt=Ntt.ett = = h CR N N 1 1 1) x=0.hO=0 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 k辿o sS=RS=365000 NS=0 (ng動畛c chi畛u) MS=AS.RS.ZS ZOb=(h-x)/2=0.250 NR=Nb MR=Mb+MS 2) x=0,5.hO=0.230 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 k辿o sS=RS=365000 NS=0 (ng動畛c chi畛u) MS=AS.RS.ZS ZOb=(h-x)/2=0.135 NR=Nb MR=Mb+MS 3) x=xR.hO=0.259 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 k辿o sS=RS=365000 NS=0 (ng動畛c chi畛u) MS=AS.RS.ZS ZOb=(h-x)/2=0.121 NR=Nb+NS MR=Mb+MS 4) x=(1+xR).hO/2=0.359 Nb=Rb.b.x Mb=Rb.b.x.ZOb sS=0 NS=AS.RS (c畛t th辿p n辿n) MS=AS.RS.ZS/2 ZOb=(h-x)/2=0.070 NR=Nb+NS MR=Mb+MS
  • 21. Ntt=2100 Mtt=224 342 0 500 1000 1500 2000 2500 3000 3500 4000 4500 0 50 100 150 200 250 300 350 400 450 Bi畛u 畛 T動董ng T叩c gi畛a NR v MR L畛ch t但m l畛n L畛ch t但m nh畛 L畛ch t但m b辿 x=1 x=0,5(1+xR) x=xR x=0 5) x=hO=0.460 Nb=Rb.b.x Mb=Rb.b.x.ZOb AS b畛 n辿n sS=-RS=-365000 NS=2AS.RS(c畉 hai b畛 n辿n) MS=0(ng動畛cchi畛u) ZOb=(h-x)/2=0.020 NR=NR+NR MR=Mb
  • 22. V. CCH XC 畛NH H畛 S畛 AN TON CHO C畛T: 畛 x叩c 畛nh h畛 s畛 an ton cho c畛t do c坦 2 tr畛 s畛 c畉n t鱈nh to叩n l Ntt v Mtt n棚n 動畛c x叩c 畛nh tr棚n nguy棚n t畉c sau: 1. Cho HSAT c畛a Ntt l 1 (kN=1) ta t鱈nh 動畛c h畛 s畛 an ton c畛a Moment l kM=MK/Mtt>1 2. Cho HSAT c畛a Mtt l 1 (kM=1) ta t鱈nh 動畛c h畛 s畛 an ton c畛a L畛c n辿n l kN=NK/Ntt>1 3. H畛 s畛 an ton chung cho c畉 hai Ntt v Mtt t動董ng 畛ng khi kN=kM 4. 畛 th畛c hi畛n i畛u ny ta v畉 trong h畛 th畛ng tr畛c t畛a 畛 xOy hai i畛m N(1,kM); M(kN, 1) 5. V畉 動畛ng ph但n gi叩c th畛 1 c畉t o畉n th畉ng NM t畉i i畛m c坦 kN=kM 坦 ch鱈nh l h畛 s畛 an ton c畛a c畛t kC=kN=kM
  • 23. C担ng th畛c t鱈nh: kC=(1-kN.kM)/(2-kN-kM)
  • 24. C叩ch x叩c 畛nh kM v kN D畛a vo bi畛u 畛 t動董ng t叩c v t畛a 畛 c畛a Mtt v Ntt K辿o di honh 畛 Mtt c畉t bi畛u 畛 t畉i i畛m c坦 tung 畛 l NK K辿o di tung 畛 Ntt c畉t bi畛u 畛 t畉i i畛m c坦 honh 畛 l MK Dung ph辿p n畛i suy ta t鱈nh 動畛c MK v NK 2100 224 0 500 1000 1500 2000 2500 3000 3500 4000 4500 0 50 100 150 200 250 300 350 400 450 (Mtt, Ntt) NK MK H畛 s畛 an ton c畛a Mtt: kM=MK/Mtt H畛 s畛 an ton c畛a Ntt: kN=NK/Ntt Ntt Mtt
  • 25. 5 aR = 0.248 K= 5 1 lb=Ho/ b = 8 10 14 18 22 26 32 38 Ho = 4.6 j = 1 0.98 0.93 0.85 0.77 0.68 0.54 0.4 N.heo N 0 1 6 0 0 Co辰 t cao H 2 0 4 1 6 0 0 N(kN)= 1600 M(kNm)= 120 h(m)= 0.4 b(m) = 0.25 4.6 2 0 4 0 a(cm)= 3 ho= 0.37 ZS= 0.34 lb=Ho/b= 18.4 j1 Mac BT Ca叩 p 単o辰be n B# 30.0 Rb = 17,000 Eb = 3.3E+07 J b = 0.00133 1.55 4 0 0 3 RS= 365,000 ES= 2.0E+08 J S= 0.000027 xR = 0.540 xR=xR.ho= 0.200 a= 6.15 b= 0.020 925 0.8091 28<l<30 Ab = 0.10000 Jb = 0.00133 0.000925 0.014463 0.075 deMIN= 0.215 1492 0.013 de=eo/ho= 0.239 S= 0.4247 2 f 25 0.088 La叩 y de= 0.239 4 f 22 L旦誰 c do誰 c T I HA N NCR(kN)= 5209 2502 h = 1.443 he0= 0.127 Ca叩 uTa誰 o xB = N/(Rb.b)= 0.376 Moment (kN.m) 2 f 25 e = 0.297 N*e = 476 4 f 22 e0gh= 0.120 2502 N/(Rb.b)=0.376 Hay j = 0.83 -41.6 cm2 USThe湛 p 228,126 Cho誰 n 5 f 25 0.043 [N*e] = 542 kN.m 2453 0.120 x = 0.257 T鱈nh Toa湛 n theo Quy Pha誰 m na棚 m 1991 The湛 p Rs(Kpa) = Co叩 t The湛 p As(m2 )= JS Co叩 t The湛 p(m4 )= DT/Be但 to但 ng (m2 ) J Be但 to但 ng (m4 ) Ha淡 m l旦担誰 ng co叩 t the湛 p ta誰 m t鱈nh= 1% = BI E U O TNG TA C OK Chie u cao vu淡 ng ch嘆 u Ne湛 n Kie達 m tra 単ie u kie辰 n: N.e < [Ne] 0,4.(1,25.h - ao.ho) = Cho誰 n As(mm2 ) = T鱈nh A's(mm2 )= Cho誰 n A's(mm2 ) = L担湛 p ba短 o ve辰 a --> Tie叩 t die辰 n co辰 t: chie u cao h, be ro辰 ng b Ta短 i Tro誰 ng He辰 so叩 uo叩 n do誰 c Le辰 ch ta但 m the湛 p ne湛 n Ke叩 t Lua辰 n T鱈nh As(mm2 )= TI NH CO T THE P KHO NG O I X NG T鱈nh toa湛 n ca叩 u kie 辰 n ne 湛 n Le 辰 ch ta但 m Theo He辰tho叩 ng 単担n v嘆SI CA U KI E N CH U NE N Tha誰 c s坦 Le但Anh Hoa淡 ng Cho誰 n s担 単o : ? --> N = j .(Rb*Ab + Rs*As) NHA P SO LIE U VA O TRONG CA C O MA U VA NG CH O , be但 n ca誰 nh o但 xanh CO T THE P Le辰 ch ta但 m Nga奪 u nhie但 n eNg= Le辰 ch ta但 m ban 単a u eO= LE CH TA M BE 1,2-0,02*lb = Le辰 ch ta但 m eN=M/N= OK Co叩 t the湛 p Fa = Fa'= Ke叩 t Lua辰 n TinhToanBTCTNenLT1D.xls CO T THE P KE O CO T THE P NE N TI NH CO T THE P O I X NG Ye但 u ca u Co叩 t the湛 p Fa=Fa'= Chie u cao vu淡 ng ch嘆 u ne湛 n: x= 0,4*(1,25*h-xo.ho)= j 0 500 1000 1500 2000 2500 3000 3500 4000 0 50 100 150 200 250 300 350 400 K=1 S担 単 o1 S担 単 o2 S担 単 o3 S担 単 o5 S担 単 o4 K=0 ,7 K=0 ,5 K=2 K=0 ,7 b R A A R N x n s s s . ) ' .( = = d = ) . , , ( 01 1 0 11 0 e S ] . . [ ) ( . , b a j = 1 2 4 6 S H J E N O b b CR Ch動董ng Tr狸nh t鱈nh to叩n v ki畛m tra c畛t n辿n l畛ch t但m Ti棚u chu畉n 5574-1991
  • 26. N = 800 M= 180 Mdh = 180 5 f 20 0.001571 3.4 K= 1.0 Ho= 3.4 0 f 14 0 0.4 a(cm)= h o= 0.460 zs=ZS/h= HO/ h = 6.80 AS= 0.001571 0.5 4 ZS= 0.420 0.840 J b= 0.0042 m4 20 Rb= 11500 Kpa Eb= 27000 B T # 2 5 0 The湛 p A 1 Rs= 225000 Kpa Es= 210000 w= 0.758 xR= 0.645 s= 0.007 J S= eN= M/N = 0.225 m 0.317 eNg= H /600;h/30 ;1 0.013 m 0.596 eo= eN+eNg= 0.238 m 0.596 2.000 N CR= 24145 kN 0.247 q= 0.617 N t t = 8 0 0 kN 19 7 kN.M 0 Ke湛 o ss=-Rs= -225000 N R= 0 0.250 MR= 1 4 8 0.230 N = 8 0 0 Mr = 2 7 9 Ke湛 o ss=-Rs= -225000 N R= 1 0 5 8 0.174 OK 0.135 MR= 2 9 1 0.297 Ke湛 o ss=-Rs= -225000 N R= 1 3 6 5 0.102 MR= 2 8 7 0.378 ss= 0 N R= 2 0 9 4 0.061 MR= 1 8 0 0.460 Ne湛 n ss=Rs= 225000 N R= 2 8 2 3 0.020 MR= 4 2 5) x =h O= ZOb=(h-x)/2= Le辰 ch ta但 m Ta短 i tro誰 ng H畛 s畛 demin= ZOb=(h-x)/2= ZOb=(h-x)/2= ZOb=(h-x)/2= 1) x =0.h O= 2) x =0,5.h O= 3) x =xR .h O= S O T NH CO T NE N L E CH T A M 1D Le辰 ch ta但 m t鱈nh toa湛 n h.eO= Ths Le但 anh H oa淡 ng aushoang@gmail.com 1.034 T畉i Tr畛ng CO T CAO H(m)= B畛 r畛ng b(m)= B畛 cao h(m)= Ti e 叩 t di e 辰 n CO T v担湛 i Ke 叩 t Lua 辰 n Ta短 i Tro誰 ng T鱈nh Toa湛 n o 辰 B e n C a 叩 u K ie 辰 n C h 嘆 u N e 湛 n N R v a 淡 C h 嘆 u Uo 叩 n MR 0.258 H畛 s畛 L畛ch ta但 m u畛n d畛c C畛t th辿p 畛i x畛ng: Le 辰 c h Ta 但 m L担湛 n demin=0,5-0,01*Ho/h-0,01*Rb Mt t =N t t .h.eO= Mpa a= 7.78 0.000138545 H畛 s畛 de=eo/h = L 旦 誰 c n e湛 n t 担湛 i h a誰 n : B IE U O T N G T A C C畉p 畛 b畛n B# H畛 s畛 de= Le辰 ch ta但 m Nga達 u nhie但 n Le辰 ch ta但 m ban 単a u 4) x =(1+xR).h O/2= ZOb=(h-x)/2= 0 0.1 0.2 0.3 0.4 0.5 0.6 0 0.1 0.2 0.3 0.4 0.5 = d = ) . , , ( 01 1 0 11 0 e S = = h CR N N 1 1 = b = j ) / (. M Md h 1 1 ] . . [ ) ( . , S b O b CR J S J H E N a j = 1 2 4 6 x x / 2 Z a =h o -a a a h o ZOb = (h / 2-x / 2) h / 2 A s .ss A 's .Rs S s S b R A R x b R N ). ( . . s = 2 / . ). ( . . . S S s S Ob b R Z A R Z x b R M s = 204 800 279 0 500 1000 1500 2000 2500 3000 0 50 100 150 200 250 300 350 Ch動董ng Tr狸nh ki畛m tra c畛t n辿n l畛ch t但m theo Bi畛u 畛 t動董ng t叩c