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C program for discharge

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PRAJWAL SHRIRAO

The document discusses Simpson's 3/8th rule for calculating discharge of a river. It provides the formula which involves summing the first and last depth measurements, twice the sum of odd intermediate depths, four times the sum of even intermediate depths, multiplied by 1/3 the distance between measurements. An example C program is given to calculate the area of a reservoir using this rule, taking depth measurements at intervals to sum in the formula and output the final area.

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3/8th C PROGRAM TO FIND OUT DISCHARGE BY USING SIMPON’S RULE
Discharge by Simpson’s 3/8th Rule Statement :- It states that, sum of first and last ordinates has to be done. Add twice the sum of remaining odd ordinates and four times the sum of remaining even ordinates.Multiply to this total sum by 1/3rd of the common distance between the ordinates which gives the required area. Application :- A greater accuracy in the computation of discharge may be obtained by using simpson’s rule . In this method the whole river width is divided into an even number of equal segments so That there are odd number of depths taken at the end of each segments as shown in figure. Then area of flow,
C program to find out Discharge by Simpson’s 3/8th Rule Description - : To find Discharge by Simpson’s 3/8th Rule contain formula, 1) Area -: 2) Discharge -: Q = AV Where, A = Area of whole river h = length of each segment fo , fn = depth taken at end of End section of segment f1,f2,f3, … = depth at middle section Q = discharge V = velocity of flow
PROGRAM -: #include<stdio.h> #include<conio.h> #include<math.h> int main(); { int h=6; float f(x0),f(x1),f(x2),f(x3),f(x4),f(xn),Area; printf("enter the value of area of respective depth"); h= (b-a)/n; f(x0)=1.2; f(x1)=1.47; f(x2)=1.56; f(x3)=1.68; f(x4)=1.72; f(xn)=1.86; Area=(3h/8)*(f(x0)+f(xn)+2*(f(x1)+f(x3))+3*(f(x2)+f(x4))); printf("The capacity of reservoir = %f",Area); getch(); }
OUTPUT -:
C program for discharge

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C program for discharge

  • 1. 3/8th C PROGRAM TO FIND OUT DISCHARGE BY USING SIMPON’S RULE
  • 2. Discharge by Simpson’s 3/8th Rule Statement :- It states that, sum of first and last ordinates has to be done. Add twice the sum of remaining odd ordinates and four times the sum of remaining even ordinates.Multiply to this total sum by 1/3rd of the common distance between the ordinates which gives the required area. Application :- A greater accuracy in the computation of discharge may be obtained by using simpson’s rule . In this method the whole river width is divided into an even number of equal segments so That there are odd number of depths taken at the end of each segments as shown in figure. Then area of flow,
  • 3. C program to find out Discharge by Simpson’s 3/8th Rule Description - : To find Discharge by Simpson’s 3/8th Rule contain formula, 1) Area -: 2) Discharge -: Q = AV Where, A = Area of whole river h = length of each segment fo , fn = depth taken at end of End section of segment f1,f2,f3, … = depth at middle section Q = discharge V = velocity of flow
  • 4. PROGRAM -: #include<stdio.h> #include<conio.h> #include<math.h> int main(); { int h=6; float f(x0),f(x1),f(x2),f(x3),f(x4),f(xn),Area; printf("enter the value of area of respective depth"); h= (b-a)/n; f(x0)=1.2; f(x1)=1.47; f(x2)=1.56; f(x3)=1.68; f(x4)=1.72; f(xn)=1.86; Area=(3h/8)*(f(x0)+f(xn)+2*(f(x1)+f(x3))+3*(f(x2)+f(x4))); printf("The capacity of reservoir = %f",Area); getch(); }