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States of Matter Particle vibration fluid motion rapid, random motion Rigid positions move past independent of each other   each other Fixed volume fixed volume volume of container
Phases and Transitions Sublimation Condensation Evaporation Melting Freezing
Intermolecular Forces Strongest = IONIC FORCES High melting points Oppositely charged ions
Dipole-Dipole Forces Dipole: contains both positively and negatively charged regions:
Hydrogen Bonding Special case of dipole-dipole forces Causes water to have higher than expected boiling point
Water Properties Surface tension
Water Properties Capillary action
Boiling Points Molecule Boiling Point H 2 O 100属C H 2 S  60.7 属C H 2 Se  41属C H 2 Te  2属C
Hydrogen Bonding Weak bond between H and electronegative atom: Recall
Hydrogen Bonding
Hydrogen Bonding DNA
Dipole-Dipole Forces
London (Dispersion) Forces Weak attractions between non-polar Increases with size of molecule  (number of electrons) Molecular Shape (less compact > compact)   >  >
London (Dispersion) Forces Weak attractions between non-polar  Temporary  or instantaneous dipoles
Intermolecular Forces IONIC  >>  Dipole  Dipole >> London
Intermolecular Forces Which intermolecular force is expected? CH 4
Intermolecular Forces Which intermolecular force is expected? CH 4 Non-polar covalent molecule London (dispersion) forces
Intermolecular Forces Which intermolecular force is expected? Butanol CH 3 CH 2 CH 2 CH 2 OH
Intermolecular Forces Which intermolecular force is expected? Butanol CH 3 CH 2 CH 2 CH 2 OH Dipole-Dipole
Energy of Phase Changes Energy is required for all phase changes
Phase Diagram (H 2 O)
Phase Diagram (CO 2 ) Triple Point Triple Point:  where all three phases co-exist (T, p)
Phase Diagrams (carbon)
Properties of Matter   Force Pressure  =  area   h  = 760 mm = 1 atm   Torricelli   barometer
Robert Boyle
Boyles Law For a gas at constant T and n V and p are  inversely proportional   pV = constant
Charles Law At constant pressure, V/T = constant
Charles Law
Gay  Lussacs Law In a constant volume: P/T = constant
Gay-Lussacs Law
Combined Gas Law Boyles Law  pV  =  constant Charles Law  V/T  = constant Gay-Lussacs Law  p/T = constant Combining all three: p 1 V 1   p 2 V 2 So:  T 1   =  T 2
Combined Gas Law A sample of gas has a volume of 400 liters when its temperature is 20属C and its pressure is 300 mm Hg. What volume will the gas occupy at STP?
Combined Gas Law p 1 V 1   p 2 V 2 T 1   =  T 2  T in Kelvin (300/760 mm Hg)(400 L)  =  (760 mm Hg) (V 2 ) (293 K) (273 K) V 2   =  147 Liters
Combined Gas Law A sample of He gas has a volume of 250 mL at 456 torr and 25属C. At what temperature does this gas have a volume of 150 mL and 561 torr? p 1 V 1   p 2 V 2 T 1   =  T 2
Combined Gas Law A sample of He gas has a volume of 250 mL at 456 torr and 25属C. At what temperature does this gas have a volume of 150 mL and 561 torr? p 1 V 1   p 2 V 2  T 2  =  p 2 V 2  T 1 T 1   =  T 2     p 1 V 1
Combined Gas Law A sample of He gas has a volume of 250 mL at 456 torr and 25属C. At what temperature does this gas have a volume of 150 mL and 561 torr? p 1 V 1   p 2 V 2    (561/760)(0.15L)(298K) T 1   =  T 2   T 2  =  (456/760)(0.25L)   =  220 K = -53属C
Ideal Gases Non-interacting Point particles Randomly moving with elastic  collisions (no energy lost)
Ideal Gases Avogadros Law: Equal volumes of gas contain the same number of molecules at the same T & p. n = number of moles p 1 V 1   =  constant n T 1
Ideal Gas Law p 1 V 1   =  constant  =  0.082 L atm  =  R n T 1   K mole    =  Universal Gas Constant One mole of gas at  STP : Volume = nRT/p  =  (1 mole)(0.082 Latm)(273K)/1 atm      =  22.4 Liters
Ideal Gas Law pV  =  nRT How many moles of Helium are present in a balloon that has a volume of 65 L at 20属 C and 705 torr? Given Needed V, T, p, R n   n  =  pV/RT
Ideal Gas Law pV  =  nRT How many moles of Helium are present in a balloon that has a volume of 65 L at 20属 C and 705 torr?   n  =  pV/RT = (705/760 atm)(65 L)   (0.082 Latm/K)(293) = 2.5 moles He
Ideal Gas 6.2 liters of an ideal gas are contained at 3.0 atm and 37 属C. How many moles of this gas are present?
Ideal Gas 6.2 liters of an ideal gas are contained at 3.0 atm and 37 属C. How many moles of this gas are present? n = pV/RT = (3 atm)(6.2 L) (0.082 L atm/mole K ) (310 K) = 0.73 moles
Ideal Gases and Density
Density Gas density increases with molecular mass.
Density What is the density of NO 2  gas at 0.97 atm and 35属C? MW = 46 g/mole Molar mass  p  (46 g/mole)(0.97 atm) Density =  RT   (0.082 L atm/mole K) (308 K) =  1.767 g/L
Gas Diffusion Movement of particles from region of  Higher density to lower density
Gas Diffusion Movement of particles from region of  Higher density to lower density Depends on density (molar mass)
Grahams Law proportionality Rate of effusion inversely to square root of molar mass Smaller molecules escape FASTER than larger molecules
Daltons Law PT  =  P1  +  P2 +  P3 + . . . . Total pressure of a gas sample is the sun of the partial pressures.
Daltons Law A mixture of O 2 , CO 2  and N 2  has a p T  of 0.97 atm; if p O2  = 0.7 atm and p N2  = 0.12 atm, what is p CO2 ?
Daltons Law A mixture of O 2 , CO 2  and N 2  has a p T  of 0.97 atm; if p O2  = 0.7 atm and p N2  = 0.12 atm, what is p CO2 ? pT = p O2  +   p N2  +   p CO2  =  0.97 atm p CO2  =  0.97 atm  - (0.7 atm + 0.12 atm)   = 0.15 atm
Daltons Law The partial pressures of CH 4  and O 2  are 0.175 atm and 0.25 atm. At 65属C in a volume of 2 L, how many moles of each gas are present?
Daltons Law The partial pressures of CH 4  and O 2  are 0.175 atm and 0.25 atm. At 65属C in a volume of 2 L, how many moles of each gas are present?  n CH4  = pV/RT   = 0.175 atm (2L)/0.082 L atm/mole K (338 K   =  0.126 moles n O2  = pV/RT  = 0.25 atm (2L)/ 0.082 L atm/mole K (338 K) =  0.018 moles
Unit 7 Review Phases of Matter and Transitions Intermolecular Forces Phase Diagrams Boyles, Charles, Gay Lussacs Laws Ideal Gas Law pV = nRT Grahams Law of Diffusion Partial Pressure
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Chem Unit7

  • 1. States of Matter Particle vibration fluid motion rapid, random motion Rigid positions move past independent of each other each other Fixed volume fixed volume volume of container
  • 2. Phases and Transitions Sublimation Condensation Evaporation Melting Freezing
  • 3. Intermolecular Forces Strongest = IONIC FORCES High melting points Oppositely charged ions
  • 4. Dipole-Dipole Forces Dipole: contains both positively and negatively charged regions:
  • 5. Hydrogen Bonding Special case of dipole-dipole forces Causes water to have higher than expected boiling point
  • 8. Boiling Points Molecule Boiling Point H 2 O 100属C H 2 S 60.7 属C H 2 Se 41属C H 2 Te 2属C
  • 9. Hydrogen Bonding Weak bond between H and electronegative atom: Recall
  • 13. London (Dispersion) Forces Weak attractions between non-polar Increases with size of molecule (number of electrons) Molecular Shape (less compact > compact) > >
  • 14. London (Dispersion) Forces Weak attractions between non-polar Temporary or instantaneous dipoles
  • 15. Intermolecular Forces IONIC >> Dipole Dipole >> London
  • 16. Intermolecular Forces Which intermolecular force is expected? CH 4
  • 17. Intermolecular Forces Which intermolecular force is expected? CH 4 Non-polar covalent molecule London (dispersion) forces
  • 18. Intermolecular Forces Which intermolecular force is expected? Butanol CH 3 CH 2 CH 2 CH 2 OH
  • 19. Intermolecular Forces Which intermolecular force is expected? Butanol CH 3 CH 2 CH 2 CH 2 OH Dipole-Dipole
  • 20. Energy of Phase Changes Energy is required for all phase changes
  • 22. Phase Diagram (CO 2 ) Triple Point Triple Point: where all three phases co-exist (T, p)
  • 24. Properties of Matter Force Pressure = area h = 760 mm = 1 atm Torricelli barometer
  • 26. Boyles Law For a gas at constant T and n V and p are inversely proportional pV = constant
  • 27. Charles Law At constant pressure, V/T = constant
  • 29. Gay Lussacs Law In a constant volume: P/T = constant
  • 31. Combined Gas Law Boyles Law pV = constant Charles Law V/T = constant Gay-Lussacs Law p/T = constant Combining all three: p 1 V 1 p 2 V 2 So: T 1 = T 2
  • 32. Combined Gas Law A sample of gas has a volume of 400 liters when its temperature is 20属C and its pressure is 300 mm Hg. What volume will the gas occupy at STP?
  • 33. Combined Gas Law p 1 V 1 p 2 V 2 T 1 = T 2 T in Kelvin (300/760 mm Hg)(400 L) = (760 mm Hg) (V 2 ) (293 K) (273 K) V 2 = 147 Liters
  • 34. Combined Gas Law A sample of He gas has a volume of 250 mL at 456 torr and 25属C. At what temperature does this gas have a volume of 150 mL and 561 torr? p 1 V 1 p 2 V 2 T 1 = T 2
  • 35. Combined Gas Law A sample of He gas has a volume of 250 mL at 456 torr and 25属C. At what temperature does this gas have a volume of 150 mL and 561 torr? p 1 V 1 p 2 V 2 T 2 = p 2 V 2 T 1 T 1 = T 2 p 1 V 1
  • 36. Combined Gas Law A sample of He gas has a volume of 250 mL at 456 torr and 25属C. At what temperature does this gas have a volume of 150 mL and 561 torr? p 1 V 1 p 2 V 2 (561/760)(0.15L)(298K) T 1 = T 2 T 2 = (456/760)(0.25L) = 220 K = -53属C
  • 37. Ideal Gases Non-interacting Point particles Randomly moving with elastic collisions (no energy lost)
  • 38. Ideal Gases Avogadros Law: Equal volumes of gas contain the same number of molecules at the same T & p. n = number of moles p 1 V 1 = constant n T 1
  • 39. Ideal Gas Law p 1 V 1 = constant = 0.082 L atm = R n T 1 K mole = Universal Gas Constant One mole of gas at STP : Volume = nRT/p = (1 mole)(0.082 Latm)(273K)/1 atm = 22.4 Liters
  • 40. Ideal Gas Law pV = nRT How many moles of Helium are present in a balloon that has a volume of 65 L at 20属 C and 705 torr? Given Needed V, T, p, R n n = pV/RT
  • 41. Ideal Gas Law pV = nRT How many moles of Helium are present in a balloon that has a volume of 65 L at 20属 C and 705 torr? n = pV/RT = (705/760 atm)(65 L) (0.082 Latm/K)(293) = 2.5 moles He
  • 42. Ideal Gas 6.2 liters of an ideal gas are contained at 3.0 atm and 37 属C. How many moles of this gas are present?
  • 43. Ideal Gas 6.2 liters of an ideal gas are contained at 3.0 atm and 37 属C. How many moles of this gas are present? n = pV/RT = (3 atm)(6.2 L) (0.082 L atm/mole K ) (310 K) = 0.73 moles
  • 44. Ideal Gases and Density
  • 45. Density Gas density increases with molecular mass.
  • 46. Density What is the density of NO 2 gas at 0.97 atm and 35属C? MW = 46 g/mole Molar mass p (46 g/mole)(0.97 atm) Density = RT (0.082 L atm/mole K) (308 K) = 1.767 g/L
  • 47. Gas Diffusion Movement of particles from region of Higher density to lower density
  • 48. Gas Diffusion Movement of particles from region of Higher density to lower density Depends on density (molar mass)
  • 49. Grahams Law proportionality Rate of effusion inversely to square root of molar mass Smaller molecules escape FASTER than larger molecules
  • 50. Daltons Law PT = P1 + P2 + P3 + . . . . Total pressure of a gas sample is the sun of the partial pressures.
  • 51. Daltons Law A mixture of O 2 , CO 2 and N 2 has a p T of 0.97 atm; if p O2 = 0.7 atm and p N2 = 0.12 atm, what is p CO2 ?
  • 52. Daltons Law A mixture of O 2 , CO 2 and N 2 has a p T of 0.97 atm; if p O2 = 0.7 atm and p N2 = 0.12 atm, what is p CO2 ? pT = p O2 + p N2 + p CO2 = 0.97 atm p CO2 = 0.97 atm - (0.7 atm + 0.12 atm) = 0.15 atm
  • 53. Daltons Law The partial pressures of CH 4 and O 2 are 0.175 atm and 0.25 atm. At 65属C in a volume of 2 L, how many moles of each gas are present?
  • 54. Daltons Law The partial pressures of CH 4 and O 2 are 0.175 atm and 0.25 atm. At 65属C in a volume of 2 L, how many moles of each gas are present? n CH4 = pV/RT = 0.175 atm (2L)/0.082 L atm/mole K (338 K = 0.126 moles n O2 = pV/RT = 0.25 atm (2L)/ 0.082 L atm/mole K (338 K) = 0.018 moles
  • 55. Unit 7 Review Phases of Matter and Transitions Intermolecular Forces Phase Diagrams Boyles, Charles, Gay Lussacs Laws Ideal Gas Law pV = nRT Grahams Law of Diffusion Partial Pressure