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Class Notes: 26-11-2012
                       Pre-Calculus Group A
           Contributed by Jose Antonio Weymann
Inverse Function (Trivial Result, Just Exemplifies)
f(x)= x/ 2x-1
x= y/ 2y-1 Switch x’s with y’s
x(2y-1)= y isolate y
2xy-x= y
2xy-y-x= 0
2xy-y=x
y(2x-1)= x
f^-1= x/2x-1 This is the inverse of f(x), in this case the function is
its own inverse, this is a rare example and it just serve to show
the properties of an inverse function.
Now lets prove there are inverses mathematically with f(3)
f(3)= 3/6-1= 3/5
f(3/5) (3/5)/(6/5-1)= (3/5)/(1/5)
(3/5)*(5/1)= 3/1= 3 Again it proves it is its own inverse.
Lets try another problem
f(x)= 2 √(x-1)
x= 2√(y-1)
x^2/4 = y-1
x^2/ 4+1 = y
f^-1= x^2/4+1
f^-1= 1/4x^2+1
Now let’s evaluate the Domain and Range in functions and their
inverses
g(x)= x^2 D: all Reals
          R: [0, oo)
The domain of one is the range of the other, so…
+/- √(x)= y D: [0, oo)
           R: all Reals
Let’s try another problem
f(x)= 96,000+80x
x= 96,000+80y
x-96,000/80= 80y/ 80 y/80-1200= y
f(x)^-1= 1/80x-1200
End of lesson

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Class notes

  • 1. Class Notes: 26-11-2012 Pre-Calculus Group A Contributed by Jose Antonio Weymann Inverse Function (Trivial Result, Just Exemplifies) f(x)= x/ 2x-1 x= y/ 2y-1 Switch x’s with y’s x(2y-1)= y isolate y 2xy-x= y 2xy-y-x= 0 2xy-y=x y(2x-1)= x f^-1= x/2x-1 This is the inverse of f(x), in this case the function is its own inverse, this is a rare example and it just serve to show the properties of an inverse function. Now lets prove there are inverses mathematically with f(3) f(3)= 3/6-1= 3/5 f(3/5) (3/5)/(6/5-1)= (3/5)/(1/5) (3/5)*(5/1)= 3/1= 3 Again it proves it is its own inverse. Lets try another problem f(x)= 2 √(x-1) x= 2√(y-1)
  • 2. x^2/4 = y-1 x^2/ 4+1 = y f^-1= x^2/4+1 f^-1= 1/4x^2+1 Now let’s evaluate the Domain and Range in functions and their inverses g(x)= x^2 D: all Reals R: [0, oo) The domain of one is the range of the other, so… +/- √(x)= y D: [0, oo) R: all Reals Let’s try another problem f(x)= 96,000+80x x= 96,000+80y x-96,000/80= 80y/ 80 y/80-1200= y f(x)^-1= 1/80x-1200 End of lesson