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CONVERGENCE TESTING
AP CALCULUS BC EXAM REVIEW
SERIES ON THE AP EXAM
 SERIES WILL BE TESTED ON BOTH THE MULTIPLE CHOICE AND THE FREE
RESPONSE SECTIONS OF THE EXAM.
 BEING ABLE TO CLASSIFY A SERIES AS BEING CONVERGENT OR DIVERGENT USING
THE TESTS WE LEARNED IN THE COURSE WILL BE ESSENTIAL.
 FOR EACH OF THE SERIES ON THE FOLLOWING SLIDES, CLASSIFY IT AS BEING
CONVERGENT OR DIVERGENT AND MAKE SURE YOU CAN JUSTIFY YOUR CHOICE.
YOU SHOULD BE ABLE TO CITE A SPECIFIC TEST FOR EACH ONE.
CONVERGENT OR DIVERGENT? WHY?
=1

2 + 1
DIVERGENT!
 LIM

2+1

= 
 SINCE THE LIMIT DOES NOT EQUAL 0, THIS SERIES DIVERGES BY THE NTH-TERM
TEST.
CONVERGENT OR DIVERGENT? WHY?
=1

1
CONVERGENT!
 THIS IS A P-SERIES.
 SINCE P (WHICH IS PI) IS GREATER THAN 1, THE SERIES WILL CONVERGE.
CONVERGENT OR DIVERGENT? WHY?
=1

2 +1
5
CONVERGENT!
 THIS IS A GEOMETRIC SERIES, WHICH WE CAN SEE MORE CLEARLY IF WE REWRITE
IT AS =1

2
2
5

.
 SINCE THE COMMON RATIO OF 2/5 IS LESS THAN 1, THIS IS A CONVERGENT
GEOMETRIC SERIES.
CONVERGENT OR DIVERGENT? WHY?
=1

1 

 + 1
CONVERGENT!
 THIS IS AN ALTERNATING SERIES, AND SINCE THE SEQUENCE PART OF THE
SERIES IS ALWAYS POSITIVE, IS ALWAYS DECREASING, AND IS HEADED TOWARDS
0, THE SERIES CONVERGES.
 WE COULD FURTHER CLASSIFY THIS ONE AS BEING CONDITIONALLY
CONVERGENT BECAUSE THE SEQUENCE AS ITS OWN SERIES WOULD DIVERGE (BY
COMPARISON TO A P-SERIES WHERE P = 遜).

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Classifying Infinite Series

  • 2. SERIES ON THE AP EXAM SERIES WILL BE TESTED ON BOTH THE MULTIPLE CHOICE AND THE FREE RESPONSE SECTIONS OF THE EXAM. BEING ABLE TO CLASSIFY A SERIES AS BEING CONVERGENT OR DIVERGENT USING THE TESTS WE LEARNED IN THE COURSE WILL BE ESSENTIAL. FOR EACH OF THE SERIES ON THE FOLLOWING SLIDES, CLASSIFY IT AS BEING CONVERGENT OR DIVERGENT AND MAKE SURE YOU CAN JUSTIFY YOUR CHOICE. YOU SHOULD BE ABLE TO CITE A SPECIFIC TEST FOR EACH ONE.
  • 3. CONVERGENT OR DIVERGENT? WHY? =1 2 + 1
  • 4. DIVERGENT! LIM 2+1 = SINCE THE LIMIT DOES NOT EQUAL 0, THIS SERIES DIVERGES BY THE NTH-TERM TEST.
  • 6. CONVERGENT! THIS IS A P-SERIES. SINCE P (WHICH IS PI) IS GREATER THAN 1, THE SERIES WILL CONVERGE.
  • 7. CONVERGENT OR DIVERGENT? WHY? =1 2 +1 5
  • 8. CONVERGENT! THIS IS A GEOMETRIC SERIES, WHICH WE CAN SEE MORE CLEARLY IF WE REWRITE IT AS =1 2 2 5 . SINCE THE COMMON RATIO OF 2/5 IS LESS THAN 1, THIS IS A CONVERGENT GEOMETRIC SERIES.
  • 9. CONVERGENT OR DIVERGENT? WHY? =1 1 + 1
  • 10. CONVERGENT! THIS IS AN ALTERNATING SERIES, AND SINCE THE SEQUENCE PART OF THE SERIES IS ALWAYS POSITIVE, IS ALWAYS DECREASING, AND IS HEADED TOWARDS 0, THE SERIES CONVERGES. WE COULD FURTHER CLASSIFY THIS ONE AS BEING CONDITIONALLY CONVERGENT BECAUSE THE SEQUENCE AS ITS OWN SERIES WOULD DIVERGE (BY COMPARISON TO A P-SERIES WHERE P = 遜).