การใช้ Turbo C ชุดที่ 6 condition
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การใช้ Turbo C ชุดที่ 6 condition โดย อ.กำธร เรือนฝายกาศ มหาวิทยาลัยเทคดนโลยีราชมงคลล้านนา วิทยาเขคภาคพายัพ
การใช้ Turbo C ชุดที่ 6 condition
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- 2. -2- ¢¡¤£¦¥¨§© ¢¢ ¡¨ ¢££¦ !#%$' ( )0 12 43¨5'6 7'8@9ACBD ECF GIHA'PQG'R PQS9QP'T U V'W XY ¢` a b cd¢efg hpi4q¨rts uCvCrtwx y€ ‚ ƒ „Q…¨† ‡ ˆ ‰‘¦‰ ’“Q”'•—–Q˜• ™ d—e f¢g—e‘“4h¢’“Q”%ei j4kjQlm¨nonqp rs¤t¤uvw j x yz { |} #~€ ' ~ |} #~€ '‚| } ~ ƒ%„†… ‡ ˆC‰ Š ‹ Œ¢Ž¨#¨‘@4’ “#”•¤–#”‘¨——˜¤‘q‘™ š›—œoŒo”Q ž¨Ÿ ž ¡¢Q£¤¢%¥p¦¢§%¨© ª «#¬¤®¨¯¨°%± ²³ ´Cµ—´Q¶—· ¸ ¹pº »¼ ½ ¾¿À Á ¾Â Á ÃÄ Å ÆÇ—È ÉÊËÌ ÍqÎ ÏÐ Ñ Ç¢Æ¤Ò¨ÃpÓ Ô Ñ Ë ÕÖ Q×#ÆpØ Ù¨Ú Ù¨Ú Ù Û ÜÝ Þ ß¢à¤á¨âpã'à—äCåoæQçèæ%éߢêCë¢ë¢ì Û åíàoèêQæ Û åoæî¤ï¨ð Û ñ î¤ï¨ðóò#æݤߤèêQæ'ô õê Û àö¨àoèêQæ ÷ø4ù¨ú—û%û4ü¤ý—øþ¤ú—û ÿ ¡ ¢ £¥¤ ¦¨§©© ! $# %' (0)132 46587 9¥@ ACB ACB D E8FHG¥IQPSR$I T UQV W8XQVYFH`!aCRRcb de3f3E!V'g FhaCRHi `!fQf3Eb pq!r s tu¥vSw xy€‚3ƒ „¨…S† ‡ˆ „ ‰C† ‡ˆ $0‘!’ “¥‘ ” •C– —˜ $™0d!e f¥dg— ˜ ” h!– f¨ij— k l'm nCo p q8rSs¥tQuSv$t w xQy z8{QyYrH|!}Cvvc~ €33q!y'‚ r —˜ nCo p3o n ƒ¥„ … ƒ¥†‡!ˆH‰ ŠC‹ Š Œ ŠC‹YŽH! ‘’3“3‡“Q” • – —Š 3”''˜0†™ Œ '‹YŽH! ‘’3“3‡›š’3“œ‹' Žj˜0ˆ’3“CžC¨– ‹' Ž ŸC ¡3 ¡ ˆ• ¢c£C¤¤ if (condition) statement; ¥ ¦H§3¨'©3ª « ª §3¨ ¬Q®°¯ ± ² ®8³3´Cµ¶ · ² ¸¥¹ º¨»¼¼ ½ ¾¿ À¯ ÁÂ!³ Ã$Ä Å'Æ ¹0Ç3® È6É!Ê Ë¥Æ Ì Í¨Î Ï6Î Ð!ÑÒÐ!Ó'Î ÔÕQÖ × Ø¨ÙQÚ3Û8×QÜ!Ý'Þ ß à Þ'á âÒ× Ø âCã Ýä à Ù8å3æCç0ã èé!å ê$ë ì'í î × Ø âSïß8× Ø¨ÙQÚ3Û8×QÜ!Ý'ïQâ'ðQð!ñ òâ Só0åô àÝ hõ8ö¥÷ بÙCÝ!ÙQÚ ø òù ¥åð!úSÙ8û ü0ýCþ'ÿHþ¡ ¢£¥¤§¦¨§©©¡ þ if (condition) { statement_1; statement_2; ... statement_n; }
- 3. -3- ¢¡ £¤¡ ¥ ¦¨§¤©¨ ! $#© ¢¡ £¤¡ % ' (¢)¨0 1 $#2 354 6 78 9 @BABCED$F¤GFH¢I @P float dx,dy; void main() { clrscr(); printf(Enter delta Y : ); scanf(%f,dy); printf(Enter delta X : ); scanf(%f,dx); if(dy!=0) printf(Slope = %fn,dy/dx); getch(); } Enter delta Y : 3 Enter delta X : 4 Slope = 0.750000 Q5R2S T U T V RV UWXU2YV `5abcd e d ab fg hi
- 4. -4- ¢¡ £ ¤¦¥¨§©¨© ¦ ¥!$#¢%' ()101¤$32 ¥ 45 67$8 97 ¢¡ £1¡ @A B @C%¤$§D E¢ E F E¢ ¥!$ ()101¤HGI ¥!IP B ¥ QR1S3T14 U 4R 1S VW$C XY `37 a$bc32 ¥ dce f3e g$hig$pqe r¦s tu v¢w xy$€ qf¦‚ dg ƒ¦„c…3† v ‡ˆ ‰3ˆ $‘i$’qˆ “” •¢– —1– ˜ ™d e'f¢g%g if(condition) statement_A; else statement_B; h ™i1j if(statement) { statement_A1; statement_A2; ... statement_An; } else { statement_B1; statement_B2; statement_Bn; } •¢– —1– k flmnpo¨qrf$s1t1u¦v$o¨™cw3x ou3o¨m yz { $| ‡ }c~ 3~ €$r€¦‚3~ ƒ¦„ …†$‚3‡$ˆ ~ ˆ †$‚ ‰ ¦Š }c€ ‹$Œ € Žc 3 ‘$’r‘¦“3 ”•
- 5. -5- ¢¡ £¤¡ ¥ ¦ § ¨¢© !$# % ' )()01 2$0 3 4656798@ ¥ @A ¡ 4 B #include stdio.h #include conio.h int choice; float radius, circum, area; void main() { clrscr(); textcolor(LIGHTRED); cprintf(Menu); printf(n); textcolor(LIGHTGREEN); cprintf(1.Circumference of the circle); printf(n); cprintf(2.Area of the circle); printf(n); printf(Enter your choice 1 or 2 : ); scanf(%d,choice); printf(Enter radius of the circle : ); scanf(%f,radius); if(choice==1) { circum = 2*3.14156*radius; printf(Circumference of the circle = %fn,circum); } else { area = 3.14156*radius*radius; printf(Area of the circle = %fn,area); } getch(); }
- 6. -6- ¡£¢¥¤§¦©¨ Menu 1.Circumference of the circle 2.Area of the circle Enter your choice 1 or 2 : 1 Enter radius of the circle : 3 Circumference of the circle = 18.84936 ¡£¢¥¤§¦ Menu 1.Circumference of the circle 2.Area of the circle Enter your choice 1 or 2 : 2 Enter radius of the circle : 3 Area of the circle = 28.274040
- 7. -7- ¢¡ £ ¤¦¥¨§©¨© ¦ ¥!$#¢%' ()101¤$32 ¥ 45 67$8 97@4 5 ¢¡ £A¡ BC D BE%¤$§F G¢ G H G¢ ¥!$ ()101¤I¥3¤¤$ P¥ RQS ¥!$ ()101¤IT3UV1#¦WXP (YX ¥!$ ()101¤ G1 !) H 0¦E1`¢aA G H #¦W%¤1WXP ¥!¦¤ b E ¢¡ £A¡ Q §c d'#¢% #¢%% G H$ #¢%% G H3Q if(condition_A) statement_A else if(condition_B) statement_B else if(condition_C) statement_C ... else if(condition_n) statement_n e ¥¢V1 e W f3g h¨f iqp r s t uwvqx y €‚ ƒ¦„… †‡qˆ ‰ ’‘3“ ” •%–— ˜ ™ dXe f g if(condition_A) { statement_A ... } else if(condition_B) { statement_A ... } else if(condition_C) { statement_A ... } ... else if(condition_n) { statement_A ... } h¢i jAi k lm1noAp¨qrl$s1t1u¦v$p¨wXx3y pu3p¨nz|{¢u }~ €$ ‚€@} ~ ƒX„ …3„ †$‡r†¦ˆ3„ ‰¦Š ‹ …¦Œ ƒX† $Ž † ‘ ’ “ ”• ”‘ ’ – — ˜ ™ š › œ œ™ š ž Ÿ X¡ ¢3¡ £$¤r£¦¥3¡ ¦§ ¨$© ª £ X¡ ¢3¡ £$¤r£¦¥3¡ ¦$« ¬ ¢¦ X£
- 8. -8- ¢¡ £¤¡ £ ¥ ¦ §¢¨© !# $ % ('()0 1#)2% 3 4656798@BAC@D ¡ 4E #include stdio.h #include conio.h int point; void main() { clrscr(); printf(Enter your's point :); scanf(%d,point); if( ( point = 100 ) ( point = 80 ) ) printf(Grade = An); else if( ( point 80 ) ( point = 70 ) ) printf(Grade = Bn); else if( ( point 70 ) ( point = 60 ) ) printf(Grade = Cn); else if( ( point 60 ) ( point = 50 ) ) printf(Grade = Dn); else if( ( point 50 ) ( point = 0 ) ) printf(Grade = Fn); getch(); } Enter your's point :99 Grade = A
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- 10. -10- ¢¡ £¤¡ ¥ ¦§ ©¨¤!$#% '( )©021 345 #include stdio.h char grade; void main() { clrscr(); printf(Enter your grade : ); scanf(%c,grade); switch(grade) { case 'a': printf(point = 80-100n); break; case 'b': printf(point = 70-79n); break; case 'c': printf(point = 60-69n); break; case 'd': printf(point = 50-59n); break; case 'f': printf(point = 0-49n); break; default : printf(unknown); } getch(); } Enter your grade : a point = 80-100
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