�ݺ�ߣ

1
EMT 529 VLSI design
Circuit characterization and
performance estimation:
Wires
Fazrul Faiz Zakaria, Ph.D
Faculty of Electronic Engineering Technology
Universiti Malaysia Perlis

Outline
• Introduction
• Wire Resistance
• Wire Capacitance
• Wire RC Delay
• Crosstalk
• Wire Engineering
• Repeaters

Introduction
• Chips are mostly made of wires called interconnect
• In stick diagram, wires set size
• Transistors are little things under the wires
• Many layers of wires
• Wires are as important as transistors
• Speed
• Power
• Noise
• Alternating layers run orthogonally

Wire Geometry
• Pitch = w + s
• Aspect ratio: AR = t/w
• Old processes had AR << 1
• Modern processes have AR  2
• Pack in many skinny wires
l
w s
t
h

Layer Stack
• AMI 0.6 mm process has 3 metal layers
• Modern processes use 6-10+ metal layers
• Example:
Intel 180 nm process
• M1: thin, narrow (< 3l)
• High density cells
• M2-M4: thicker
• For longer wires
• M5-M6: thickest
• For VDD, GND, clk
Layer T (nm) W (nm) S (nm) AR
6 1720 860 860 2.0
1000
5 1600 800 800 2.0
1000
4 1080 540 540 2.0
700
3 700 320 320 2.2
700
2 700 320 320 2.2
700
1 480 250 250 1.9
800
Substrate

Wire Resistance
• r = resistivity (W*m)
l
w
t
R 

Wire Resistance
l
w
t
l
R
t w
r


Interconnect �ݺ�ߣ 8
Wire Resistance
• R = sheet resistance (W/)
•  is a dimensionless unit(!)
• Count number of squares
• R = R * (# of squares) l
w
t
1RectangularBlock
R = R (L/W) W
4RectangularBlocks
R =R (2L/2W) W
= R (L/W) W
t
l
w w
l
l l
R R
t w w
r
 

Choice of Metals
• Until 180 nm generation, most wires were aluminum
• Modern processes often use copper
• Cu atoms diffuse into silicon and damage FETs
• Must be surrounded by a diffusion barrier
Metal Bulk resistivity (mW*cm)
Silver (Ag) 1.6
Copper (Cu) 1.7
Gold (Au) 2.2
Aluminum (Al) 2.8
Tungsten (W) 5.3
Molybdenum (Mo) 5.3

Sheet Resistance
• Typical sheet resistances in 180 nm process
Layer Sheet Resistance (W/)
Diffusion (silicided) 3-10
Diffusion (no silicide) 50-200
Polysilicon (silicided) 3-10
Polysilicon (no silicide) 50-400
Metal1 0.08
Metal2 0.05
Metal3 0.05
Metal4 0.03
Metal5 0.02
Metal6 0.02

Contacts Resistance
• Contacts and vias also have 2-20 W
• Use many contacts for lower R
• Many small contacts for current crowding around periphery

Wire Capacitance
• Wire has capacitance per unit length
• To neighbors
• To layers above and below
• Ctotal = Ctop + Cbot + 2Cadj
layer n+1
layer n
layer n-1
Cadj
Ctop
Cbot
w
s
t
h1
h2

Capacitance Trends
• Parallel plate equation: C = eA/d
• Wires are not parallel plates, but obey trends
• Increasing area (W, t) increases capacitance
• Increasing distance (s, h) decreases capacitance
• Dielectric constant
• e = ke0
• e0 = 8.85 x 10-14 F/cm (dielectric constant of free space)
• k = 3.9 for SiO2
• Processes are starting to use low-k dielectrics
• k  3 (or less) as dielectrics use air pockets

Typical wiring Capacitance Values

M2 Capacitance Data
• Typical wires have ~ 0.2 fF/mm
• Compare to 2 fF/mm for gate capacitance
0
50
100
150
200
250
300
350
400
0 500 1000 1500 2000
C
total
(aF/mm)
w (nm)
Isolated
M1, M3 planes
s = 320
s = 480
s = 640
s=
8
s = 320
s = 480
s = 640
s=
8

Diffusion & Polysilicon
• Diffusion capacitance is very high (about 2 fF/mm)
• Comparable to gate capacitance
• Diffusion also has high resistance
• Avoid using diffusion runners for wires!
• Polysilicon has lower C but high R
• Use for transistor gates
• Occasionally for very short wires between gates

Lumped Element Models
• Wires are a distributed system
• Approximate with lumped element models
• 3-segment p-model is accurate to 3% in simulation
• L-model needs 100 segments for same accuracy!
• Use single segment p-model for Elmore delay
C
R
C/N
R/N
C/N
R/N
C/N
R/N
C/N
R/N
R
C
L-model
R
C/2 C/2
R/2 R/2
C
N segments
p-model T-model

Example
• Metal2 wire in 180 nm process
• 5 mm long
• 0.32 mm wide
• Construct a 3-segment p-model
• R = 0.05 W/ => R = 781 W
• Cpermicron = 0.2 fF/mm => C = 1 pF
260 W
167 fF 167 fF
260 W
167 fF 167 fF
260 W
167 fF 167 fF

Wire RC Delay
• Estimate the delay of a 10x inverter driving a 2x inverter at
the end of the 5mm wire from the previous example.
• R = 2.5 kW*mm for gates
• Unit inverter: 0.36 mm nMOS, 0.72 mm pMOS
• tpd = 1.1 ns
781 W
500 fF 500 fF
Driver Wire
4 fF
Load
690 W

Crosstalk
• A capacitor does not like to change its voltage
instantaneously.
• A wire has high capacitance to its neighbor.
• When the neighbor switches from 1-> 0 or 0->1, the wire tends to
switch too.
• Called capacitive coupling or crosstalk.
• Crosstalk effects
• Noise on nonswitching wires
• Increased delay on switching wires

Crosstalk Delay
• Assume layers above and below on average are quiet
• Second terminal of capacitor can be ignored
• Model as Cgnd = Ctop + Cbot
• Effective Cadj depends on behavior of neighbors
• Miller effect
A B
Cadj
Cgnd Cgnd
B DV Ceff(A) MCF
Constant VDD Cgnd + Cadj 1
Switching with A 0 Cgnd 0
Switching opposite A 2VDD Cgnd + 2 Cadj 2

Crosstalk Noise
• Crosstalk causes noise on nonswitching wires
• If victim is floating:
• model as capacitive voltage divider
Cadj
Cgnd-v
Aggressor
Victim
DVaggressor
DVvictim
adj
victim aggressor
gnd v adj
C
V V
C C

D  D


Driven Victims
• Usually victim is driven by a gate that fights noise
• Noise depends on relative resistances
• Victim driver is in linear region, agg. in saturation
• If sizes are same, Raggressor = 2-4 x Rvictim
1
1
adj
victim aggressor
gnd v adj
C
V V
C C k

D  D
 
 
 
aggressor gnd a adj
aggressor
victim victim gnd v adj
R C C
k
R C C





 

Cadj
Cgnd-v
Aggressor
Victim
DVaggressor
DVvictim
Raggressor
Rvictim
Cgnd-a

Coupling Waveforms
Aggressor
Victim (undriven): 50%
Victim (half size driver): 16%
Victim (equal size driver): 8%
Victim (double size driver): 4%
t(ps)
0 200 400 600 800 1000 1200 1400 1800 2000
0
0.3
0.6
0.9
1.2
1.5
1.8
• Simulated coupling for Cadj = Cvictim

Noise Implications
• So what if we have noise?
• If the noise is less than the noise margin, nothing happens
• Static CMOS logic will eventually settle to correct output
even if disturbed by large noise spikes
• But glitches cause extra delay
• Also cause extra power from false transitions
• Dynamic logic never recovers from glitches
• Memories and other sensitive circuits also can produce the
wrong answer

Wire Engineering
• Goal: achieve delay, area, power goals with acceptable noise
• Degrees of freedom:
• Width
• Spacing
• Layer
• Shielding
Delay
(ns):
RC/2
WireSpacing
(nm)
Coupling:
2C
adj
/
(2C
adj
+C
gnd
)
0
0.2
0.4
0.6
0.8
1.0
1.2
1.4
1.6
1.8
2.0
0 500 1000 1500 2000
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0 500 1000 1500 2000
320
480
640
Pitch (nm)
Pitch (nm)
vdd a0
a1
gnd a2
vdd b0
a1
a2
b2
vdd a0
a1
gnd a2
a3
vdd gnd a0
b1

Repeaters
• R and C are proportional to l
• RC delay is proportional to l2
• Unacceptably great for long wires
• Break long wires into N shorter segments
• Drive each one with an inverter or buffer
Wire Length: l
Driver Receiver
l/N
Driver
Segment
Repeater
l/N
Repeater
l/N
Receiver
Repeater
NSegments

Repeater Design
• How many repeaters should we use?
• How large should each one be?
• Equivalent Circuit
• Wire length l
• Wire Capacitance Cw*l, Resistance Rw*l
• Inverter width W (nMOS = W, pMOS = 2W)
• Gate Capacitance C’*W, Resistance R/W
R/W
C'W
Cw
l/2N Cw
l/2N
Rw
lN

Repeater Results
• Write equation for Elmore Delay
• Differentiate with respect to W and N
• Set equal to 0, solve
2
w w
l RC
N R C


 
2 2
pd
w w
t
RC R C
l

 
w
w
RC
W
R C


~60-80 ps/mm
in 180 nm process

�ݺ�ߣ

EMT529-VLSI-Design-�ݺ�ߣ 5.pptx

Recommended

More Related Content

Similar to EMT529-VLSI-Design-�ݺ�ߣ 5.pptx (20)

Recently uploaded (20)

EMT529-VLSI-Design-�ݺ�ߣ 5.pptx