1) The ortho center of a triangle with vertices along the lines x=0, y=0, and 3x-5y+7=0 is (0,0).
2) The slope-intercept form of the equation 6x+3y+5=0 is y=-2x-5/3.
3) To find the y-intercept of a line perpendicular to 3x+y=3 and passing through (2,2), set y=-3x+b and substitute the point to find b=3.
2. Question 1
Write the coordinates of the Ortho center of the triangle whose sides lie along the lines x =0, y = 0
And 3x 5y +7=0
Ortho Centre is the point of intersection of
The altitudes
In this case it is (0,0)
3. Question 2
Reduce the following equation to the slope intercept form. Also find the slope and y
intercept
6x +3y +5 =0
3y =. -6x -5
y = m x + c
4. Question 3
A line passes through (2,2) and is perpendicular to 3x +y=3. Find its y intercept
y = - 3x + 3
m = - 3
6. Question 4
Find the equation of a line parallel to x 3y + 5 = 0 and with y intercept 5
3y = x + 5
The line passes through (0, 5)
7. 3 y 15 = x
3y x + 15 = 0
Question 5
In what ratio is the line segment joining (1,3) and (2,7) divided by 3x + y 9 = 0
Let the line divide the line segment in the ratio m: n
10. Question 6
Find k so that the 3 lines 2x + y 3 =0, 5 x + ky 3 = 0 , 3x - y 2 = 0 are concurrent
3 lines are said to be concurrent if they intersect at a point
2x + y 3 = 0
3x y - 2 = 0
5x = 5
x = 1 y = 1
11. Point of intersection = ( 1, 1)
Substitute in 5x + ky 3 = 0
k = - 2
Question 7
Find the coordinates of the Ortho center of the triangle whose vertices are
(1,2), (3,-4) ,(5, -6)