JB Marion 8.27.doc
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The spacecraft orbits Earth with a speed of 10,160 m/s at a perigee of 6,680 km. Using the law of conservation of angular momentum, the speed of the spacecraft at its apogee of 42,200 km can be calculated. Substituting the given values into the angular momentum equation and solving for the apogee speed gives a value of 1,608.26 m/s.
JB Marion 8.27.doc
- 1. 1 A spacecraft in an orbit about Earth has the speed of 10,160 m/s at a perigee of 6,680 km from Earth's center. What speed does the spacecraft have at apogee of 42,200 km? Solution Apogee The point in the orbit of an object (such as a satellite) orbiting the earth that is at the greatest distance from the center of the earth. (OR) The point farthest from a planet or a satellite (such as the moon) reached by an object orbiting it.
- 2. 2 Perigee the point in the orbit of an object (such as a satellite) orbiting the earth that is nearest to the center of the earth. (OR) The point nearest a planet or a satellite (such as the moon) reached by an object orbiting it. 1 According to conservation of angular momentum, we have ( ) ( ) 42200 6680 10160 2 2 42200000 6680000 10160 2 2 6680000 2 10160 2 42200000 1608.26 mvr apogee mvr perigee m mXvX km mX X km s m vX m X m s m v X mX m s m v s CLASSICA DYNAMICS OF PARTICLES AND SYSTEMS