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An object weighing half a kilogram at the end of a string 40 cm
long acts as a pendulum. Its speed when it is vertically straight is
0.42 m/s. What is the greatest angle the pendulum can achieve?
¦Ø = (g/L)-1/2 = (9.8 m/s2/0.40 m)-1/2 = 1.57 rad/s
A = smax = vmax/¦Ø = (0.42 m/s)/(1.57 rad/s) = 0.2675 m
¦È = smax/L = (0.2675 m)/(0.40 m) = 0.66875 rad = 38.3¡ã

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  • 1. An object weighing half a kilogram at the end of a string 40 cm long acts as a pendulum. Its speed when it is vertically straight is 0.42 m/s. What is the greatest angle the pendulum can achieve? ¦Ø = (g/L)-1/2 = (9.8 m/s2/0.40 m)-1/2 = 1.57 rad/s A = smax = vmax/¦Ø = (0.42 m/s)/(1.57 rad/s) = 0.2675 m ¦È = smax/L = (0.2675 m)/(0.40 m) = 0.66875 rad = 38.3¡ã