Mat lab[1]
- 1. INTEGRANTES: DANIEL CHILLAGANA RODRIGO SILVA JEFERSON ULLOA JEANCARLOS BUESTAN LUIS ARAUJO
- 2. EJERCICIO:(1/2 A+ 2B+1/4C) X (A- 1/2B-2C)( Ac) . (A x B ) DATOSA= (-3i ; 12j ; -9k)B= (10 cm ; S 40? O)C= 15cm (0.612i ; -0.791j )COMANDOS:Modulo de un vector: norm ( a )
- 3. Unitario: unic = ( 1/norm (a))*a
- 4. Producto punto: dot ( a.b)
- 5. Producto cruz: cross (a,b)
- 6. Proyeccion de Ab: A cosθUb
- 7. Coseno del anglo: cosang=dot(a,b)/(norm(a)*norm(b))PRIMER PASO>>A=[-3 12 -9]A = -3 12 -9>> B=[6.43 7.66 0]B = 6.4300 7.6600 0>> C=[9.18 -11.87 0]C = 9.1800 -11.8700 0SEGUNDO PASO>> E=1/2*AE = -1.5000 6.0000 -4.5000>> F=2*BF = 12.8600 15.3200 0>> G=1/4*CG = 2.2950 -2.9675 0 TERCER PASO* >> X=[E+F+G]* X =* 13.6550 18.3525 -4.5000* >> y=[A-1/2*B-2*C]* y =* -24.5750 31.9100 -9.0000 CUARTO PASO* cross(X,y)* ans =* -21.5775 233.4825 886.7437
- 8. QUINTO PASO>> dot(A,C)ans = -169.9800>> sqrt(3^2+12^2+9^2)ans = 15.2971>> sqrt(9.18^2+11.87^2+0^2)ans =15.0056>> cosang=dot(A,C)/(sqrt(3^2+12^2+9^2)*sqrt(9.18^2+11.87^2+0^2))cosang = -0.7405proyAC=sqrt(3^2+12^2+9^2)*cosang*C/sqrt(9.18^2+11.87^2+0^2)proyAC = -6.9300 8.9606 0
- 9. SEPTIMO PASO>> T=cross(X,y)T =-21.5775 233.4825 886.7437>>uniT=cross(X,y)/dot(proyAC,cross(A,B))uniT = 0.0217 -0.2343 -0.8900SEXTO PASO>> dot(proyAC,cross(A,B))ans = -996.3047