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Mechanics of Orthogonal Cutting
t1 is un-cut chip thickness
t2 is cut chip thickness
r is chip thickness ratio
r = t1/t2 < 1 ( t1 < t2)
k = 1/r = chip reduction coefficient
留 is rake angle
 is shear angle
Assumptions
1. No contact at the flank.
2. Width of chip remains constant.
3. Uniform cutting velocity.
4. A continues chip is produced.
5. Volumetric changes of material during machining is zero.
That is
Volume before cutting = volume after cutting
t1 *b*l1 = t2*b*l2 t1/t2 = l2/l1 = r
Also we can say that volumetric flow rate is also equal
t1*b*Vc = t2*b*Vf t1/t2 = Vf/ Vc
Vc is cutting velocity
Vf is chip flow velocity
Vs is shear velocity
WORKPIECE
t1
留
Shear
plane
Friction
planeVertical
plane
Vs
Vc
Vf
TOOL
width
WORKPIECE
TOOL
t1
留
Shear
plane
Friction
plane
Vertical
plane
Vs
Vc
Vf

留

AC
B
t1
sin个 = t1 / AB
90-个
sin(90- 个+ 留 ) = sin (90-(个-留)) = cos(个-留) = t2/AB
t1 = AB*sin个
t2 = AB cos (个-留)
Therefore
t1/t2 = (AB*sin个) / (AB*cos(个-留) )
r = sin个 / cos (个-留)
r = sin个 / ( cos个*cos留+ sin个*sin留 )
r = ( sin个 /cos 个 ) / [( cos个*cos留+ sin个*sin留 ) / cos个]
r = tan个/ (cos留 + tan个*sin留 )
rcos留 + r*tan个*sin留 = tan个
tan个 -r*tan个*sin留 = rcos留
tan个 (1- rsin留) = rcos 留
tan个 = rcos留 / (1- rsin留)
From triangle ABC & ACD
D
90-个+留
个-留
RELATION BETWEEN R, 陸 AND 留
WORKPIECE
TOOL
t1
留
Shear
plane
Friction
plane
Vertical
plane
Vs
Vc
Vf

Vc
Vf Vs
90-留
90-(个-留)
By applying SINE rule
(Vf / sin个) =[Vs / sin(90-留)] = [Vc/sin(90-(个-留)]
(Vf / sin个) = (Vs / cos留) = [Vc/cos(个-留)]
Vf = [Vc*sin 留 /cos(个-留)]
Vf = Vc*r
Vs = [(Vc*cos 留 /cos(个-留)]
VELOCITY RELATIONSHIPS
work piece
tool
R2
F
N
Fc
Ft
R1
FS
Fn

留
FS
R
F
N
硫

Ft
Fc
Fn
留
硫-留
Fc is Cutting Force
Ft is Thrust Force
R1 is Resultant Force of Fc & Ft
F is Friction Force
N is Normal Force of F
R2 is Resultant Force of F& N
Fs is Shear Force
Fn Normal Force to Fs
R1 isalso Resultant Force of Fs & Fn
Weknow
F = 袖N
From diagram
tan硫 = F/N
F = tan硫*N
Therefore
袖= tan硫
硫 is Angle of friction
袖 is coefficient of friction
Ft
Fc
硫-留
R
FS
R
F
N
硫

Ft
Fc
Fn
留
硫 -留
R = (Fc ^2) + (Fv^2)
Tan(硫-留) = Fc /Ft
R

Fn R = (Fs^2) + (Ns^2)
FS
Tan(硫-留+) = Fs/Ns
硫
硫-留
留
R = (F^2) + (N^2)
R
F
N
Theories of Angles
Lee & Shaffer theory : 陸+硫-留 = 45
Stabler theory : 陸+硫-(留/2)= 45
Merchant Constant (Cm) : 2陸+硫-留
Energy for Cutting (Ec) = Fc * VC
Energy for friction (Ef) = F * VF
Energy for shearing (Es) = Fs * Vs
Percentage of energy loss in friction
= (Ec/Ef)*100
Percentage of energy loss in shearing
= (Ec/Ef)*100
R
F
N
硫

Ft
Fc
留
硫 -留
A
O
D
C
E
G
B
留
9O-留
9O-留
Relationship of Fs & Fn with Fc & Ft
Fn = AE = AD+DE = DE+CB = Fc sin  + Ft cos 
Fs = OA = OB-AB = OB-BC = Fc cos  - Ft sin 
Relationship of F & N with Fc & Ft
F= OA = CB = CG+GB = ED+GB = Fc sin 留 + Ft cos 留
N= AB = OD CD = OD- GE = Fc COS 留 - Ft sin留
FS
R
陸
Ft
Fc
Fn
留
硫 -留
O
B
A
C
G
E
9O-陸
9O-陸
Shear area = As = W*t1 / sin 陸
Shear stress =  = Fs / As  = Fs sin陸 / (w*t1)
Shear strain = 導 = Cot 陸 + tan (陸-留) = cos / [sin 陸*cos (陸-留)]
Shear strain rate = Vs/ts
WORKPIECE
t1
Fs
 W
Vs
The minimum value of shear strain when rake angle is zero
Shear strain = 導 = Cot 陸 + tan 陸
(d/d陸) {cot 陸 + tan 陸 } = 0
-cosec^2 陸 + sec^2 陸 =0
-(1/sin^2 陸)+ (1/cos^2 陸) =0
cos^2 陸-sin^2 陸=0
[(1-cos 2陸)/2] - [(1-sin 2陸)/2] =0
2cos 2 陸 = 0
2陸 =90
陸 =45
For minimum value
2陸 - 留 =90
For orthogonal cutting
Depth of cut = t1 = feed*慮 ( 慮 is side cutting edge angle )
Width of cut = t1/ sin 慮
Fc
Ft
N
F
袖 = Tan硫 = F/N = Ft/Fc
But when Ft > Fc, 硫 > 45 袖 > 1
In this case use formulae for finding 袖
The classical friction theory
袖 = [ln ( 1/r)] / [( /2)  留]
Actuvally the value of 袖 is always comes less than one
Ft < Fc, 硫 < 45 袖 < 1
 Taylorstool life equation:-
VTn=C
 Tool life equation (generalized)
VTnfn1dn2=C
 Tool life exponents n,n1, n2 are found by plotting
experimental data on log V  log T,log T log fand
log T log d scales.
Determination of toollife constants n,n1, n2
 Longand expensive test, involves considerableamount
of material, labor and machiningtime.
 Recourseis taken to experimental design techniques
suchasfactorial design, multiple regression analysis and
response surface methodology to reduce cost and no. of
observations.
RAMDAS BHUKYA
mighty engineer

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Mechanics of Orthogonal Cutting

  • 2. t1 is un-cut chip thickness t2 is cut chip thickness r is chip thickness ratio r = t1/t2 < 1 ( t1 < t2) k = 1/r = chip reduction coefficient 留 is rake angle is shear angle Assumptions 1. No contact at the flank. 2. Width of chip remains constant. 3. Uniform cutting velocity. 4. A continues chip is produced. 5. Volumetric changes of material during machining is zero. That is Volume before cutting = volume after cutting t1 *b*l1 = t2*b*l2 t1/t2 = l2/l1 = r Also we can say that volumetric flow rate is also equal t1*b*Vc = t2*b*Vf t1/t2 = Vf/ Vc Vc is cutting velocity Vf is chip flow velocity Vs is shear velocity WORKPIECE t1 留 Shear plane Friction planeVertical plane Vs Vc Vf TOOL width
  • 3. WORKPIECE TOOL t1 留 Shear plane Friction plane Vertical plane Vs Vc Vf 留 AC B t1 sin个 = t1 / AB 90-个 sin(90- 个+ 留 ) = sin (90-(个-留)) = cos(个-留) = t2/AB t1 = AB*sin个 t2 = AB cos (个-留) Therefore t1/t2 = (AB*sin个) / (AB*cos(个-留) ) r = sin个 / cos (个-留) r = sin个 / ( cos个*cos留+ sin个*sin留 ) r = ( sin个 /cos 个 ) / [( cos个*cos留+ sin个*sin留 ) / cos个] r = tan个/ (cos留 + tan个*sin留 ) rcos留 + r*tan个*sin留 = tan个 tan个 -r*tan个*sin留 = rcos留 tan个 (1- rsin留) = rcos 留 tan个 = rcos留 / (1- rsin留) From triangle ABC & ACD D 90-个+留 个-留 RELATION BETWEEN R, 陸 AND 留
  • 4. WORKPIECE TOOL t1 留 Shear plane Friction plane Vertical plane Vs Vc Vf Vc Vf Vs 90-留 90-(个-留) By applying SINE rule (Vf / sin个) =[Vs / sin(90-留)] = [Vc/sin(90-(个-留)] (Vf / sin个) = (Vs / cos留) = [Vc/cos(个-留)] Vf = [Vc*sin 留 /cos(个-留)] Vf = Vc*r Vs = [(Vc*cos 留 /cos(个-留)] VELOCITY RELATIONSHIPS
  • 5. work piece tool R2 F N Fc Ft R1 FS Fn 留 FS R F N 硫 Ft Fc Fn 留 硫-留 Fc is Cutting Force Ft is Thrust Force R1 is Resultant Force of Fc & Ft F is Friction Force N is Normal Force of F R2 is Resultant Force of F& N Fs is Shear Force Fn Normal Force to Fs R1 isalso Resultant Force of Fs & Fn Weknow F = 袖N From diagram tan硫 = F/N F = tan硫*N Therefore 袖= tan硫 硫 is Angle of friction 袖 is coefficient of friction
  • 6. Ft Fc 硫-留 R FS R F N 硫 Ft Fc Fn 留 硫 -留 R = (Fc ^2) + (Fv^2) Tan(硫-留) = Fc /Ft R Fn R = (Fs^2) + (Ns^2) FS Tan(硫-留+) = Fs/Ns 硫 硫-留 留 R = (F^2) + (N^2) R F N Theories of Angles Lee & Shaffer theory : 陸+硫-留 = 45 Stabler theory : 陸+硫-(留/2)= 45 Merchant Constant (Cm) : 2陸+硫-留 Energy for Cutting (Ec) = Fc * VC Energy for friction (Ef) = F * VF Energy for shearing (Es) = Fs * Vs Percentage of energy loss in friction = (Ec/Ef)*100 Percentage of energy loss in shearing = (Ec/Ef)*100
  • 7. R F N 硫 Ft Fc 留 硫 -留 A O D C E G B 留 9O-留 9O-留 Relationship of Fs & Fn with Fc & Ft Fn = AE = AD+DE = DE+CB = Fc sin + Ft cos Fs = OA = OB-AB = OB-BC = Fc cos - Ft sin Relationship of F & N with Fc & Ft F= OA = CB = CG+GB = ED+GB = Fc sin 留 + Ft cos 留 N= AB = OD CD = OD- GE = Fc COS 留 - Ft sin留 FS R 陸 Ft Fc Fn 留 硫 -留 O B A C G E 9O-陸 9O-陸
  • 8. Shear area = As = W*t1 / sin 陸 Shear stress = = Fs / As = Fs sin陸 / (w*t1) Shear strain = 導 = Cot 陸 + tan (陸-留) = cos / [sin 陸*cos (陸-留)] Shear strain rate = Vs/ts WORKPIECE t1 Fs W Vs The minimum value of shear strain when rake angle is zero Shear strain = 導 = Cot 陸 + tan 陸 (d/d陸) {cot 陸 + tan 陸 } = 0 -cosec^2 陸 + sec^2 陸 =0 -(1/sin^2 陸)+ (1/cos^2 陸) =0 cos^2 陸-sin^2 陸=0 [(1-cos 2陸)/2] - [(1-sin 2陸)/2] =0 2cos 2 陸 = 0 2陸 =90 陸 =45 For minimum value 2陸 - 留 =90 For orthogonal cutting Depth of cut = t1 = feed*慮 ( 慮 is side cutting edge angle ) Width of cut = t1/ sin 慮
  • 9. Fc Ft N F 袖 = Tan硫 = F/N = Ft/Fc But when Ft > Fc, 硫 > 45 袖 > 1 In this case use formulae for finding 袖 The classical friction theory 袖 = [ln ( 1/r)] / [( /2) 留] Actuvally the value of 袖 is always comes less than one Ft < Fc, 硫 < 45 袖 < 1
  • 10. Taylorstool life equation:- VTn=C Tool life equation (generalized) VTnfn1dn2=C Tool life exponents n,n1, n2 are found by plotting experimental data on log V log T,log T log fand log T log d scales.
  • 11. Determination of toollife constants n,n1, n2 Longand expensive test, involves considerableamount of material, labor and machiningtime. Recourseis taken to experimental design techniques suchasfactorial design, multiple regression analysis and response surface methodology to reduce cost and no. of observations.