Micro lesson (jje)
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The document provides step-by-step instructions for solving word problems using the GRESA (Given, Required, Equation, Solution, Answer) method. It works through two sample problems, showing how to identify the relevant information, set up equations relating the information, solve the equations, and check that the solution satisfies the original problem statement. The first problem involves individuals' ages now and in the past/future, while the second deals with one person's current and future ages.
![Present 6 years from now
Joegie L L+5
Jay-Ar L+10 L+10+6
L+15= (L+10+6) 5/6
Multiply both sides by 6
6[(L+5=L+16) 5/6]6
6L+30=L+80
6L-L=80-30
5L/5 =50/5
L=10](https://image.slidesharecdn.com/microlessonjje-131005221348-phpapp01/85/Micro-lesson-jje-20-320.jpg)
Micro lesson (jje)
- 2. TIPS IN ANSWERING PROBLEM SOLVING: 1. Analyze the problem first. 2. Gather all the given data or use the GRESA method. G-iven R-equired E-quation S-olution A-nswer
- 3. For us to begin this lesson, I will give sample problems that we will answer together. Are you ready? YES LATER
- 5. Hey! My name is Arnie, I am now 28 years old. I want to know how many years will my future age be 18 years more than my past age when I was the same number of my years younger. Can you help me? YES LATER Ax+Bx+C=0
- 6. First, lets gather all the given data. Let X stand as years. X years ago Present X years from now 28-x 28 28+x
- 7. Now that we gather all the given data let us now solve Arnies problem. Let X stand as years. X years ago Present X years from now 28-x 28 28+x
- 8. S O L U T I O N: Let us equate the given data as: 28+x=18+(28-x) To solve the problem, let us put together the given that has the same variables . x+x=18+28-28 2x=18 To know the value of x we need to let x alone. So we need to divide both side by 2. 2x/2 = 18/2 Cancel the 2 in the left side and divide 18 by 2. The x equals: X=9
- 9. Lets substitute the value of x we get. Will it satisfy the required data? Lets see X years ago Present X years from now 28-x 28 28+x X=9
- 10. Substitution: X years ago Present X years from now 28-9 =19 28 28+9 =37
- 11. As stated in the problem Arnie wants to know how many years will her future age 18 more than her past age. Now lets subtract her future age and her past age. 37-19 18,Therefore the answer we get satisfied Arnies problem.
- 12. Now I know that in 9 years my age will become 18 years more than my past age. Thanks for the help! See you next time!
- 14. Jay-Ar is 10 years older than Joegie 5 years from now, Joegies age will be 5/6 that of Jay-Ars age. What is the present age of Joegie. (Time limit: 5 minutes) a.) 10 b.) 15 c.) 20 d.) 12
- 15. I am now 27 years old. In how many years will my future age be 16 years more than my past age when I was the same number of years younger (Time limit: 5 minutes) a.) 3 b.) 5 c.) 8 d.) 12
- 17. Congratulations. Youre right. Now, lets see the solution.
- 18. Lets gather all the data.
- 19. Present 6 years from now Joegie L L+5 Jay-Ar L+10 L+10+6 REPRESENTATION: Let L be the present age of Joegie
- 20. Present 6 years from now Joegie L L+5 Jay-Ar L+10 L+10+6 L+15= (L+10+6) 5/6 Multiply both sides by 6 6[(L+5=L+16) 5/6]6 6L+30=L+80 6L-L=80-30 5L/5 =50/5 L=10
- 21. Present 6 years from now Joegie 10 10+5 Jay-Ar 10+10 10+10+6 Substitution:
- 22. Question #
- 23. Congratulations. Youre right. Now, lets see the solution.
- 24. Lets gather all the data.
- 25. T years ago Present T years from now 27-T 27 27+T
- 26. 27+T=16+(27-T) 2T=16 T=8 T years ago Present T years from now 27-T 27 27+T
- 27. Substitution: T years ago Present T years from now 27-8 27 27+8 19 35
- 29. Submitted by: Jay-Ar A. Barquilla Joegie R. Fontejon Elry John P. Matriano IV-Ruby Submitted to: Mr. Eric de Guzman
- 34. Your answer is wrong. Try again. Back
- 35. Your answer is wrong. Try again. Back