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PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
T . Z
COMPANY :
REV NO : -
DATE :
DESIGN CALCULATION REPORT
Section (1) Panels Arrangement
PREPARED BY :
11-Apr-22
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Design Calculation Results (SECTION 1)
SUMMARY
EXTERNAL STABILITY
Sliding
Case I F.S = 3.17 > 1.50 OK
Case II F.S = 3.82 > 1.50 OK
Case III F.S = 4.24 > 1.50 OK
Case IV F.S = 3.01 > 1.50 OK
Case V F.S = 3.82 > 1.50 OK
Overturning
Case I F.S = 7.01 > 2.00 OK
Case II F.S = 7.53 > 2.00 OK
Case III F.S = 8.48 > 2.00 OK
Case IV F.S = 3.82 > 2.00 OK
Case V F.S = 7.53 > 2.00 OK
Bearing Capacity
Case I q = 110.71 kN/m2
Case II q = 173.98 kN/m2
Control
Case III q = 118.19 kN/m2
Case IV q = 128.60 kN/m2
Case V q = 173.98 kN/m2
INTERNAL STABILITY
Pullout Resistance
Layer 1 Tmax = 9.77 kN per strip < 16.20 kN OK
Layer 2 Tmax = 13.05 kN per strip < 21.75 kN OK
Layer 3 Tmax = 16.77 kN per strip < 28.28 kN OK
Layer 4 Tmax = 18.73 kN per strip < 33.97 kN OK
Tensile Resistance
Layer 1 Tmax = 18.82 kN per strip < 33.51 kN OK
Layer 2 Tmax = 22.99 kN per strip < 33.51 kN OK
Layer 3 Tmax = 26.68 kN per strip < 33.51 kN OK
Layer 4 Tmax = 30.20 kN per strip < 33.51 kN OK
Pullout Resistance
Layer 1 Tmax = 14.56 kN per strip < 18.00 kN OK
Layer 2 Tmax = 18.17 kN per strip < 24.17 kN OK
Layer 3 Tmax = 22.58 kN per strip < 31.42 kN OK
Layer 4 Tmax = 25.22 kN per strip < 37.74 kN OK
Tensile Resistance
Layer 1 Tmax = 23.61 kN per strip < 44.67 kN OK
Layer 2 Tmax = 28.11 kN per strip < 44.67 kN OK
Layer 3 Tmax = 32.49 kN per strip < 44.67 kN OK
Layer 4 Tmax = 36.70 kN per strip < 44.67 kN OK
Pullout Resistance
Layer 1 Tmax = 12.13 kN per strip < 18.00 kN OK
Layer 2 Tmax = 16.59 kN per strip < 24.17 kN OK
Layer 3 Tmax = 20.31 kN per strip < 31.42 kN OK
Layer 4 Tmax = 22.27 kN per strip < 37.74 kN OK
Tensile Resistance
Layer 1 Tmax = 22.97 kN per strip < 44.67 kN OK
Layer 2 Tmax = 29.21 kN per strip < 44.67 kN OK
Layer 3 Tmax = 32.90 kN per strip < 44.67 kN OK
Layer 4 Tmax = 36.42 kN per strip < 44.67 kN OK
Seismic
Impact
Seismic
Impact
Static
Seismic
Impact
Static
Static
Seismic
Impact
Static
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Wall Information
Section name = SECTION 1
Wall Height H = 4.52 m
Reinforcing fill length L = 4.50 m
B = 4.64 m
Reinforced Soil Unit Weight Ï’soil = 21.00 kN/m3
Reinforcement fill φ = 34.00 Degree
Retained Soil Unit Weight Ï’soil = 21.00 kN/m3
Retained fill φ = 34.00 Degree
Foundation Soil Unit Weight Ï’foundation = 19.00 kN/m3
Foundation internal friction angle φ = 30.00 Degree
Foundation cohesion c = 0.00 kN/m2
Nr = 22.40
Traffic surcharge q = 13.00 kN/m2
Panel
First strip location = 1.88 m
Location of slab bottom = 1.10 m
Vertical sapcing of strip Sv = 0.75 m
Panel width b = 1.50 m
Panel height h = 1.50 m
Panel thickness t = 0.14 m
Strip width b = 50.00 mm
Stritp thickness t = 4.00 mm
Horizontal spacing of strip (1st
Layer) Sh = 0.50 m
Horizontal spacing of strip Sh = 0.75 m
Steel reinforcement strength fy = 448.00 Mpa
Load Factor, Ï’ (LRFD 11.5.5)
Typical application
Bearing Resistance
Vertical Ï’EV = 1.35
Horizontal Ï’EH = 1.5
Sliding and Eccentricity
Vertical Ï’EV = 1
Horizontal Ï’EH = 1.5
Live Load Surcharge on MSE Wall
Bearing and reinforcement tensile Resistance Ï’LS = 1.75
Sliding, eccentricity and reinforcement pullout resistance
Ï’LS = 1.75
Resistance Factor, φ (LRFD Table 11.5.6-1)
Mechanically Stabilized Earth Walls
Pullout resistance of tensile reinforcement
Static loading = 0.9
MSE WALL DESIGN CALCULATION REPORT
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Load Cases
Vertical
Load
Horizontal
Load
Live
Load
Load Factor Ï’ (LRFD 11.5.5) Ï’EV Ï’EH Ï’LS
Case I Strength I 1.00 1.50 -
Case II Strength II 1.35 1.50 1.75
Case III Service I 1.00 1.00 1.00
Resistance Factor φP φT
Case IV Static loading 0.90 0.75
Case V Combined static and impact loading 1.00 1.00
I. External Stability
Static Mass Stability
Vertical loads
Reinforced Soil
V1 = Ï’soil H L
= 21.00 x 4.52 x 4.50
= 427.14 kN/m
Case I V1 = 427.14 x 1
V1 = 427.14 kN/m
Case II V1 = 427.14 x 1.35
V1 = 576.64 kN/m
Case III V1 = 427.14 x 1
V1 = 427.14 kN/m
Forces acting on the MSE Wall
Forces :
V1 = Ï’soil H L
V2 = qs L
F1 = 0.5 Ï’ H2 Ka
F2 = qs H Kaf
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Moment arm of V1 = 2.25 m
MV1 = 427.14 x 2.25
MV1 = 961.065 kN-m/m
Case I MV1 = 961.065 KN-m/m
Case II MV1 = 1297.44 KN-m/m
Case III MV1 = 961.07 KN-m/m
Traffic surcharge
V2 = q L
V2 = 13.00 x 4.5
V2 = 58.50 kN/m
Factored V2 = 58.50 x 1.75
Factored V2 = 102.38 kN/m
Moment arm of V2 = 2.25 m
MV2 = 58.50 x 2.25
MV2 = 131.63 kN-m/m
Factored MV2 = 102.38 x 2.25
Factored MV2 = 230.34 kN-m/m
Case I ∑V = 427.14 kN/m
Case II ∑V = 679.01 kN/m
Case III ∑V = 485.64 kN/m
Case I ∑Mv = 961.07 kN-m/m
Case II ∑Mv = 1527.78 kN-m/m
Case III ∑Mv = 1092.69 kN-m/m
Horizontal loads
ka = tan(45 - φ/2)2
For retained ka = 0.28
For surcharge kaf = 0.28
Retained Soil
F1 = 0.5 Ï’soil H2
Ka
= 60.65 kN/m
Case I F1 = 90.97 kN/m
Case II F1 = 90.97 kN/m
Case III F1 = 60.65 kN/m
Moment arm of F1 = 1.51 m
Case I MF1 = 137.07 kN-m/m
Case II MF1 = 137.07 kN-m/m
Case III MF1 = 91.38 kN-m/m
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Traffic surcharge
F2 = q H Kaf
F2 = 16.61 kN/m
Factored F2 = 29.07 kN/m
Moment arm of F2 = 2.26 m
MF2 = 37.54 kN-m/m
Factored MF2 = 65.70 kN-m/m
Case I ∑F = 90.97 kN/m
Case II ∑F = 120.04 kN/m
Case III ∑F = 77.26 kN/m
Case I ∑MF = 137.07 kN-m/m
Case II ∑MF = 202.77 kN-m/m
Case III ∑MF = 128.92 kN-m/m
Sliding (LRFD 11.10.5.3)
Sliding F.S = ∑V x tanφ
∑F
Case I F.S = 3.17 > 1.5 OK
Case II F.S = 3.82 > 1.5 OK
Case III F.S = 4.24 > 1.5 OK
Overturning (LRFD 11.10.5.3)
Overturning F.S = ∑Mv
∑MF
Case I = 7.01 ≥ 2 OK
Case II = 7.53 ≥ 2 OK
Case III = 8.48 ≥ 2 OK
Bearing Capacity at Base
Eccentricity e = L - ∑Mv-∑Mf
2 ∑V
Case I e = 0.32 m ≤ 0.77 m OK
Case II e = 0.30 m ≤ 0.75 m OK
Case III e = 0.27 m ≤ 0.75 m OK
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
σv = ∑V
L-2e
Case I σv = 110.71 kN/m2
Case II σv = 173.98 kN/m2
Case III σv = 118.19 kN/m2
11.4.2 (f) qult = cf Nc + 0.5 (L-2e) Ï’f Nr
qult = 844.62 kN/m2
F.S = qult
σv
= 7.63 > 1.5 OK
Sliding at base of first grid
F1 at first grid F1 = 0.5 Ï’b d2
Ka
= 50.12 kN/m
F2 = q d ka
= 15.88 kN/m
∑F = 66.00 kN/m
F.S = ϒb d L tanφ C
∑F
= 4.17 > 1.5 OK
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
II. Internal Stability
Distance from Top Steel Strip Tributary Spacing
d1 = 1.88 m V1 = 1.18 m
d2 = 2.63 m V2 = 0.75 m
d3 = 3.38 m V3 = 0.75 m
d4 = 4.13 m V4 = 0.77 m
Force developed in the reinforcement
Static Load
Compute Kr (LRFD Figure 11.10.6.2.1-3)
At Z = 0 Kr = 0.48
Under Z = 6 m Kr = 0.34
MSE Wall Panel Arrangement for Section 1
LRFD 11.4.3.Fig 29
Variation of stress ratio with depth in MSE Wall
Friction
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Layer 1
Vertical Stress
1 Reinforced Soil
Kr = 0.44
σv = ϒsoil H
= 39.48 kN/m2
Case I σv = 39.48 kN/m2
Case II σv = 53.30 kN/m2
Case III σv = 39.48 kN/m2
=
2 Traffic Surcharge
σv = 13.00 kN/m2
σv = 22.75 kN/m2
Case I ∑σv = 39.48 kN/m2
Case II ∑σv = 76.05 kN/m2
Case III ∑σv = 52.48 kN/m2
Horizontal Stress
σh = ϒp (σv kr + Δσh)
σh = σv kr
Case I σh = 26.06 kN/m2
Case II σh = 50.19 kN/m2
Case III σh = 23.09 kN/m2
At per strip At = 0.38 m2
Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2.
Tmax = σh Sv
For Pullout Tmax = 9.77 kN per strip < 16.20 kN OK
For Tensile Tmax = 18.82 kN per strip < 33.51 kN OK
Layer 2
Vertical Stress
1 Reinforced Soil
Kr = 0.42
σv = ϒsoil H
= 55.23 kN/m2
Case I σv = 55.23 kN/m2
Case II σv = 74.56 kN/m2
Case III σv = 55.23 kN/m2
2 Traffic Surcharge
σv = 13.00 kN/m2
σv = 22.75 kN/m2
BP 5
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Case I ∑σv = 55.23 kN/m2
Case II ∑σv = 97.31 kN/m2
Case III ∑σv = 68.23 kN/m2
Horizontal Stress
σh = ϒp (σv kr + Δσh)
σh = σv kr
Case I σh = 23.20 kN/m2
Case II σh = 40.87 kN/m2
Case III σh = 28.66 kN/m2
At per strip At = 0.56 m2
Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2.
Tmax = σh Sv
For Pullout Tmax = 13.05 kN per strip < 21.75 kN OK
For Tensile Tmax = 22.99 kN per strip < 33.51 kN OK
Layer 3
Vertical Stress
1 Reinforced Soil
Kr = 0.40
σv = ϒsoil H
= 70.98 kN/m2
Case I σv = 70.98 kN/m2
Case II σv = 95.82 kN/m2
Case III σv = 70.98 kN/m2
2 Traffic Surcharge
σv = 13.00 kN/m2
σv = 22.75 kN/m2
Case I ∑σv = 70.98 kN/m2
Case II ∑σv = 118.57 kN/m2
Case III ∑σv = 83.98 kN/m2
Horizontal Stress
σh = ϒp (σv kr + Δσh)
σh = σv kr
Case I σh = 29.81 kN/m2
Case II σh = 47.43 kN/m2
Case III σh = 33.59 kN/m2
At per strip At = 0.56 m2
BP 5
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2.
Tmax = σh Sv
For Pullout Tmax = 16.77 kN per strip < 28.28 kN OK
For Tensile Tmax = 26.68 kN per strip < 33.51 kN OK
Layer 4
Vertical Stress
1 Reinforced Soil
Kr = 0.38
σv = ϒsoil H
= 86.73 kN/m2
Case I = 86.73 kN/m2
Case II = 117.09 kN/m2
Case III = 86.73 kN/m2
2 Traffic Surcharge
σv = 13.00 kN/m2
σv = 22.75 kN/m2
Case I ∑σv = 86.73 kN/m2
Case II ∑σv = 139.84 kN/m2
Case III ∑σv = 99.73 kN/m2
Horizontal Stress
σh = ϒp (σv kr + Δσh)
σh = σv kr
Case I σh = 33.30 kN/m2
Case II σh = 53.70 kN/m2
Case III σh = 38.30 kN/m2
At per strip At = 0.56 m2
Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2.
Tmax = σh Sv
For Pullout Tmax = 18.73 kN per strip < 33.97 kN OK
For Tensile Tmax = 30.20 kN per strip < 33.51 kN OK
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Resistance in friction of one strip against soil (LRFD Equation 11.10.6.3.2-1)
At Z = 0 F*
= 1.80
Under Z = 6 m F*
= 0.67
LRFD Figure 11.10.6.3.2-1
Default Values for the Pullout Friction Factor, F*
α = 1
C = 2.00 for strip
Rc = 0.10 For 3 strip per panel
Rc = 0.07 For 2 strip per panel
Pullout calculation at each reinforcement level
Le ≥ Tmax ≥ 1 m
φ F* α σv C Rc
Layer 1
F*
= 1.45
Le = 1.83 m ≥ 1 m
Take Le = 1.83 m
Layer 2
F*
= 1.3
Le = 2.67 m ≥ 1 m
Take Le = 2.67 m
Layer 3
F*
= 1.16
Le = 2.70 m ≥ 1 m
Take Le = 2.70 m
Layer 4
F*
= 1.02
Le = 2.85 m ≥ 1 m
Take Le = 2.85 m
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Calculate L A at each layer
for H/2 from bottom LA = 0.6 (H1 - d) for inextensible reinforcement
for H/2 from top LA = 0.3 H1 for inextensible reinforcement
LA1 = 1.36 m
LA2 = 1.13 m
LA3 = 0.68 m
LA4 = 0.23 m
LRFD Figure 11.10.6.3.1-1
Location of Potential Failure Surface for Internal Stability Design of MSE Walls
Calculate L T at each layer
Layer 1 LT1 = 3.18 m < 4.50 m OK
Layer 2 LT2 = 3.80 m < 4.50 m OK
Layer 3 LT3 = 3.38 m < 4.50 m OK
Layer 4 LT4 = 3.08 m < 4.50 m OK
Allowable Tensile Strength
Design Life = 100 years
For Corrosion Losses Ec = En - Es
Loss of galvanizing = 0.015 mm/yr for first 2 year
= 0.004 mm/yr for subsequent years
Zinc coating lift = 16.00 years
Loss of carbon steel = 0.012 mm/yr after zinc depletion
Ec = 1.99 mm
Ac = 99.72 mm2
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Tal = AC FY
Case V φTall = 44.67 kN
Case IV φTall = 33.51 kN
Pullout Resistance Strength
C11.10.6.3.2 P = F*
α σv Le C b
Layer 1 Case V φP = 18.00 kN
Case IV φP = 16.20 kN
Layer 2 Case V φP = 24.17 kN
Case IV φP = 21.75 kN
Layer 3 Case V φP = 31.42 kN
Case IV φP = 28.28 kN
Layer 4 Case V φP = 37.74 kN
Case IV φP = 33.97 kN
Connection Strength
Strip width b = 60 mm
Stritp thickness t = 4 mm
Yield Strength Fy = 345 Mpa
C11.10.6.3.2 Tac = AC FY
Case V φTac = 63.48 kN > 44.67 kN OK
Case IV φTac = 47.61 kN > 33.51 kN OK
III. External Stability with Seismic
Peak Ground Acceleration a0/g = 0.46
11.6.5.2.1 Horizontal acceleration coefficient
kh = 0.5 Kho
= 0.23
ζ = Arc tan(Kh)
= 12.95
kae = cos2
(φ - ζ)
cos ( ζ ) cos (ζ + δ) (1 + √(sin(φ + δ) sin(φ - ζ - δ)/cos (ζ + δ) cosδ))2
kae = 0.871
0.950 x 2.114
= 0.434
11.6.5.3-2 Horizontal Seismic Thrust PAE = 0.5 KAE Ï’ H2
= 93.06 kN/m
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Moment arm of PAE = 1.51 m
Moment MAE = 140.22 KN-m
Horizontal Inertia Force PIR = 0.5 Kh Ï’ H2
= 49.34 kN/m
Moment arm of PIR = 2.26 m
Moment MIR = 111.51 KN-m
∑MF = 251.72 KN-m
Sliding (LRFD 11.10.5.3)
Sliding F.S = ∑V x tanφ
∑F
Rv = 427.14 kN/m
Moment arm of Pv = 2.25 m
Moment Mv = 961.07 KN-m
Rh = 95.87 kN/m
F.S = 3.01 > 1.5 OK
Overturning (LRFD 11.10.5.3)
Overturning F.S = ∑Mv
∑MF
= 3.82 > 2 OK
Bearing Capacity at Base
Eccentricity e = L - ∑Mv-∑Mf
2 ∑V
= 0.59 < 0.75 OK
σv = ∑V
L - 2e
σv = 128.60 kN/m2
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
qult = cf Nc + 0.5 (L-2e) Ï’f Nr
qult = 706.78 kN/m2
F.S = qult
σv
= 5.50 > 1.5 OK
IV. Internal Stability with Seismic
PI = Kh Wa
= 22.20 kN/m
Tmd = Pi Lei / ∑Lei
Layer 1 Tmd = 4.78 kN per strip
Layer 2 Tmd = 5.12 kN per strip
Layer 3 Tmd = 5.81 kN per strip
Layer 4 Tmd = 6.49 kN per strip
Ttotal = Tmax + Tmd
Layer 1 For Pullout Ttotal = 14.56 kN per strip < 18.00 kN OK
For Tensile Ttotal = 23.61 kN per strip < 44.67 kN OK
Layer 2 For Pullout Ttotal = 18.17 kN per strip < 24.17 kN OK
For Tensile Ttotal = 28.11 kN per strip < 44.67 kN OK
Layer 3 For Pullout Ttotal = 22.58 kN per strip < 31.42 kN OK
For Tensile Ttotal = 32.49 kN per strip < 44.67 kN OK
Layer 4 For Pullout Ttotal = 25.22 kN per strip < 37.74 kN OK
For Tensile Ttotal = 36.70 kN per strip < 44.67 kN OK
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
V. Impact Load
Width of slab b = 2.1 m
Depth of slab h = 1.1 m
Eccetricity of traffic barrier e = 0.12 m
Slab Length L = 6 m
11.10.10.2 Static impact Load P = 44.48 kN
Earth pressure F1 = 0.5 Ka Ï’ h2
Case I F1 = 3.59 kN/m
Case II F1 = 4.85 kN/m
Traffic surcharge F2 = Ka q h
Case I F2 = 4.04 kN/m
Case II F2 = 7.08 kN/m
PH1 = 7.41 kN/m
Case I ∑ F 11.01 kN/m
Case II ∑ F = 19.34 kN/m
Horizontal pressure due to traffic barrier
L1 = (cr + bf - 2e') (tan 45 + φ/2)
= 3.50 m
Δσhmax = 2 ∑F / L1
Case I Δσhmax = 6.29 kN/m2
Case II Δσhmax = 11.06 kN/m2
PROJECT :
PREPARED BY :
DATE :
T.Z.S.K
4/11/2022
Tmax = σh Sv
Layer 1
For Pullout Tmax = 12.13 kN per strip < 18.00 kN OK
For Tensile Tmax = 22.97 kN per strip < 44.67 kN OK
Layer 2
For Pullout Tmax = 16.59 kN per strip < 24.17 kN OK
For Tensile Tmax = 29.21 kN per strip < 44.67 kN OK
Layer 3
For Pullout Tmax = 20.31 kN per strip < 31.42 kN OK
For Tensile Tmax = 32.90 kN per strip < 44.67 kN OK
Layer 4
For Pullout Tmax = 22.27 kN per strip < 37.74 kN OK
For Tensile Tmax = 36.42 kN per strip < 44.67 kN OK

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  • 1. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 T . Z COMPANY : REV NO : - DATE : DESIGN CALCULATION REPORT Section (1) Panels Arrangement PREPARED BY : 11-Apr-22
  • 2. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Design Calculation Results (SECTION 1) SUMMARY EXTERNAL STABILITY Sliding Case I F.S = 3.17 > 1.50 OK Case II F.S = 3.82 > 1.50 OK Case III F.S = 4.24 > 1.50 OK Case IV F.S = 3.01 > 1.50 OK Case V F.S = 3.82 > 1.50 OK Overturning Case I F.S = 7.01 > 2.00 OK Case II F.S = 7.53 > 2.00 OK Case III F.S = 8.48 > 2.00 OK Case IV F.S = 3.82 > 2.00 OK Case V F.S = 7.53 > 2.00 OK Bearing Capacity Case I q = 110.71 kN/m2 Case II q = 173.98 kN/m2 Control Case III q = 118.19 kN/m2 Case IV q = 128.60 kN/m2 Case V q = 173.98 kN/m2 INTERNAL STABILITY Pullout Resistance Layer 1 Tmax = 9.77 kN per strip < 16.20 kN OK Layer 2 Tmax = 13.05 kN per strip < 21.75 kN OK Layer 3 Tmax = 16.77 kN per strip < 28.28 kN OK Layer 4 Tmax = 18.73 kN per strip < 33.97 kN OK Tensile Resistance Layer 1 Tmax = 18.82 kN per strip < 33.51 kN OK Layer 2 Tmax = 22.99 kN per strip < 33.51 kN OK Layer 3 Tmax = 26.68 kN per strip < 33.51 kN OK Layer 4 Tmax = 30.20 kN per strip < 33.51 kN OK Pullout Resistance Layer 1 Tmax = 14.56 kN per strip < 18.00 kN OK Layer 2 Tmax = 18.17 kN per strip < 24.17 kN OK Layer 3 Tmax = 22.58 kN per strip < 31.42 kN OK Layer 4 Tmax = 25.22 kN per strip < 37.74 kN OK Tensile Resistance Layer 1 Tmax = 23.61 kN per strip < 44.67 kN OK Layer 2 Tmax = 28.11 kN per strip < 44.67 kN OK Layer 3 Tmax = 32.49 kN per strip < 44.67 kN OK Layer 4 Tmax = 36.70 kN per strip < 44.67 kN OK Pullout Resistance Layer 1 Tmax = 12.13 kN per strip < 18.00 kN OK Layer 2 Tmax = 16.59 kN per strip < 24.17 kN OK Layer 3 Tmax = 20.31 kN per strip < 31.42 kN OK Layer 4 Tmax = 22.27 kN per strip < 37.74 kN OK Tensile Resistance Layer 1 Tmax = 22.97 kN per strip < 44.67 kN OK Layer 2 Tmax = 29.21 kN per strip < 44.67 kN OK Layer 3 Tmax = 32.90 kN per strip < 44.67 kN OK Layer 4 Tmax = 36.42 kN per strip < 44.67 kN OK Seismic Impact Seismic Impact Static Seismic Impact Static Static Seismic Impact Static
  • 3. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Wall Information Section name = SECTION 1 Wall Height H = 4.52 m Reinforcing fill length L = 4.50 m B = 4.64 m Reinforced Soil Unit Weight Ï’soil = 21.00 kN/m3 Reinforcement fill φ = 34.00 Degree Retained Soil Unit Weight Ï’soil = 21.00 kN/m3 Retained fill φ = 34.00 Degree Foundation Soil Unit Weight Ï’foundation = 19.00 kN/m3 Foundation internal friction angle φ = 30.00 Degree Foundation cohesion c = 0.00 kN/m2 Nr = 22.40 Traffic surcharge q = 13.00 kN/m2 Panel First strip location = 1.88 m Location of slab bottom = 1.10 m Vertical sapcing of strip Sv = 0.75 m Panel width b = 1.50 m Panel height h = 1.50 m Panel thickness t = 0.14 m Strip width b = 50.00 mm Stritp thickness t = 4.00 mm Horizontal spacing of strip (1st Layer) Sh = 0.50 m Horizontal spacing of strip Sh = 0.75 m Steel reinforcement strength fy = 448.00 Mpa Load Factor, Ï’ (LRFD 11.5.5) Typical application Bearing Resistance Vertical Ï’EV = 1.35 Horizontal Ï’EH = 1.5 Sliding and Eccentricity Vertical Ï’EV = 1 Horizontal Ï’EH = 1.5 Live Load Surcharge on MSE Wall Bearing and reinforcement tensile Resistance Ï’LS = 1.75 Sliding, eccentricity and reinforcement pullout resistance Ï’LS = 1.75 Resistance Factor, φ (LRFD Table 11.5.6-1) Mechanically Stabilized Earth Walls Pullout resistance of tensile reinforcement Static loading = 0.9 MSE WALL DESIGN CALCULATION REPORT
  • 4. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Load Cases Vertical Load Horizontal Load Live Load Load Factor Ï’ (LRFD 11.5.5) Ï’EV Ï’EH Ï’LS Case I Strength I 1.00 1.50 - Case II Strength II 1.35 1.50 1.75 Case III Service I 1.00 1.00 1.00 Resistance Factor φP φT Case IV Static loading 0.90 0.75 Case V Combined static and impact loading 1.00 1.00 I. External Stability Static Mass Stability Vertical loads Reinforced Soil V1 = Ï’soil H L = 21.00 x 4.52 x 4.50 = 427.14 kN/m Case I V1 = 427.14 x 1 V1 = 427.14 kN/m Case II V1 = 427.14 x 1.35 V1 = 576.64 kN/m Case III V1 = 427.14 x 1 V1 = 427.14 kN/m Forces acting on the MSE Wall Forces : V1 = Ï’soil H L V2 = qs L F1 = 0.5 Ï’ H2 Ka F2 = qs H Kaf
  • 5. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Moment arm of V1 = 2.25 m MV1 = 427.14 x 2.25 MV1 = 961.065 kN-m/m Case I MV1 = 961.065 KN-m/m Case II MV1 = 1297.44 KN-m/m Case III MV1 = 961.07 KN-m/m Traffic surcharge V2 = q L V2 = 13.00 x 4.5 V2 = 58.50 kN/m Factored V2 = 58.50 x 1.75 Factored V2 = 102.38 kN/m Moment arm of V2 = 2.25 m MV2 = 58.50 x 2.25 MV2 = 131.63 kN-m/m Factored MV2 = 102.38 x 2.25 Factored MV2 = 230.34 kN-m/m Case I ∑V = 427.14 kN/m Case II ∑V = 679.01 kN/m Case III ∑V = 485.64 kN/m Case I ∑Mv = 961.07 kN-m/m Case II ∑Mv = 1527.78 kN-m/m Case III ∑Mv = 1092.69 kN-m/m Horizontal loads ka = tan(45 - φ/2)2 For retained ka = 0.28 For surcharge kaf = 0.28 Retained Soil F1 = 0.5 Ï’soil H2 Ka = 60.65 kN/m Case I F1 = 90.97 kN/m Case II F1 = 90.97 kN/m Case III F1 = 60.65 kN/m Moment arm of F1 = 1.51 m Case I MF1 = 137.07 kN-m/m Case II MF1 = 137.07 kN-m/m Case III MF1 = 91.38 kN-m/m
  • 6. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Traffic surcharge F2 = q H Kaf F2 = 16.61 kN/m Factored F2 = 29.07 kN/m Moment arm of F2 = 2.26 m MF2 = 37.54 kN-m/m Factored MF2 = 65.70 kN-m/m Case I ∑F = 90.97 kN/m Case II ∑F = 120.04 kN/m Case III ∑F = 77.26 kN/m Case I ∑MF = 137.07 kN-m/m Case II ∑MF = 202.77 kN-m/m Case III ∑MF = 128.92 kN-m/m Sliding (LRFD 11.10.5.3) Sliding F.S = ∑V x tanφ ∑F Case I F.S = 3.17 > 1.5 OK Case II F.S = 3.82 > 1.5 OK Case III F.S = 4.24 > 1.5 OK Overturning (LRFD 11.10.5.3) Overturning F.S = ∑Mv ∑MF Case I = 7.01 ≥ 2 OK Case II = 7.53 ≥ 2 OK Case III = 8.48 ≥ 2 OK Bearing Capacity at Base Eccentricity e = L - ∑Mv-∑Mf 2 ∑V Case I e = 0.32 m ≤ 0.77 m OK Case II e = 0.30 m ≤ 0.75 m OK Case III e = 0.27 m ≤ 0.75 m OK
  • 7. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 σv = ∑V L-2e Case I σv = 110.71 kN/m2 Case II σv = 173.98 kN/m2 Case III σv = 118.19 kN/m2 11.4.2 (f) qult = cf Nc + 0.5 (L-2e) Ï’f Nr qult = 844.62 kN/m2 F.S = qult σv = 7.63 > 1.5 OK Sliding at base of first grid F1 at first grid F1 = 0.5 Ï’b d2 Ka = 50.12 kN/m F2 = q d ka = 15.88 kN/m ∑F = 66.00 kN/m F.S = Ï’b d L tanφ C ∑F = 4.17 > 1.5 OK
  • 8. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 II. Internal Stability Distance from Top Steel Strip Tributary Spacing d1 = 1.88 m V1 = 1.18 m d2 = 2.63 m V2 = 0.75 m d3 = 3.38 m V3 = 0.75 m d4 = 4.13 m V4 = 0.77 m Force developed in the reinforcement Static Load Compute Kr (LRFD Figure 11.10.6.2.1-3) At Z = 0 Kr = 0.48 Under Z = 6 m Kr = 0.34 MSE Wall Panel Arrangement for Section 1 LRFD 11.4.3.Fig 29 Variation of stress ratio with depth in MSE Wall Friction
  • 9. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Layer 1 Vertical Stress 1 Reinforced Soil Kr = 0.44 σv = Ï’soil H = 39.48 kN/m2 Case I σv = 39.48 kN/m2 Case II σv = 53.30 kN/m2 Case III σv = 39.48 kN/m2 = 2 Traffic Surcharge σv = 13.00 kN/m2 σv = 22.75 kN/m2 Case I ∑σv = 39.48 kN/m2 Case II ∑σv = 76.05 kN/m2 Case III ∑σv = 52.48 kN/m2 Horizontal Stress σh = Ï’p (σv kr + Δσh) σh = σv kr Case I σh = 26.06 kN/m2 Case II σh = 50.19 kN/m2 Case III σh = 23.09 kN/m2 At per strip At = 0.38 m2 Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2. Tmax = σh Sv For Pullout Tmax = 9.77 kN per strip < 16.20 kN OK For Tensile Tmax = 18.82 kN per strip < 33.51 kN OK Layer 2 Vertical Stress 1 Reinforced Soil Kr = 0.42 σv = Ï’soil H = 55.23 kN/m2 Case I σv = 55.23 kN/m2 Case II σv = 74.56 kN/m2 Case III σv = 55.23 kN/m2 2 Traffic Surcharge σv = 13.00 kN/m2 σv = 22.75 kN/m2 BP 5
  • 10. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Case I ∑σv = 55.23 kN/m2 Case II ∑σv = 97.31 kN/m2 Case III ∑σv = 68.23 kN/m2 Horizontal Stress σh = Ï’p (σv kr + Δσh) σh = σv kr Case I σh = 23.20 kN/m2 Case II σh = 40.87 kN/m2 Case III σh = 28.66 kN/m2 At per strip At = 0.56 m2 Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2. Tmax = σh Sv For Pullout Tmax = 13.05 kN per strip < 21.75 kN OK For Tensile Tmax = 22.99 kN per strip < 33.51 kN OK Layer 3 Vertical Stress 1 Reinforced Soil Kr = 0.40 σv = Ï’soil H = 70.98 kN/m2 Case I σv = 70.98 kN/m2 Case II σv = 95.82 kN/m2 Case III σv = 70.98 kN/m2 2 Traffic Surcharge σv = 13.00 kN/m2 σv = 22.75 kN/m2 Case I ∑σv = 70.98 kN/m2 Case II ∑σv = 118.57 kN/m2 Case III ∑σv = 83.98 kN/m2 Horizontal Stress σh = Ï’p (σv kr + Δσh) σh = σv kr Case I σh = 29.81 kN/m2 Case II σh = 47.43 kN/m2 Case III σh = 33.59 kN/m2 At per strip At = 0.56 m2 BP 5
  • 11. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2. Tmax = σh Sv For Pullout Tmax = 16.77 kN per strip < 28.28 kN OK For Tensile Tmax = 26.68 kN per strip < 33.51 kN OK Layer 4 Vertical Stress 1 Reinforced Soil Kr = 0.38 σv = Ï’soil H = 86.73 kN/m2 Case I = 86.73 kN/m2 Case II = 117.09 kN/m2 Case III = 86.73 kN/m2 2 Traffic Surcharge σv = 13.00 kN/m2 σv = 22.75 kN/m2 Case I ∑σv = 86.73 kN/m2 Case II ∑σv = 139.84 kN/m2 Case III ∑σv = 99.73 kN/m2 Horizontal Stress σh = Ï’p (σv kr + Δσh) σh = σv kr Case I σh = 33.30 kN/m2 Case II σh = 53.70 kN/m2 Case III σh = 38.30 kN/m2 At per strip At = 0.56 m2 Traffic Load are NEGLECTED in pullout calculation as per AASHTO LRFD 11.10.6.3.2. Tmax = σh Sv For Pullout Tmax = 18.73 kN per strip < 33.97 kN OK For Tensile Tmax = 30.20 kN per strip < 33.51 kN OK
  • 12. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Resistance in friction of one strip against soil (LRFD Equation 11.10.6.3.2-1) At Z = 0 F* = 1.80 Under Z = 6 m F* = 0.67 LRFD Figure 11.10.6.3.2-1 Default Values for the Pullout Friction Factor, F* α = 1 C = 2.00 for strip Rc = 0.10 For 3 strip per panel Rc = 0.07 For 2 strip per panel Pullout calculation at each reinforcement level Le ≥ Tmax ≥ 1 m φ F* α σv C Rc Layer 1 F* = 1.45 Le = 1.83 m ≥ 1 m Take Le = 1.83 m Layer 2 F* = 1.3 Le = 2.67 m ≥ 1 m Take Le = 2.67 m Layer 3 F* = 1.16 Le = 2.70 m ≥ 1 m Take Le = 2.70 m Layer 4 F* = 1.02 Le = 2.85 m ≥ 1 m Take Le = 2.85 m
  • 13. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Calculate L A at each layer for H/2 from bottom LA = 0.6 (H1 - d) for inextensible reinforcement for H/2 from top LA = 0.3 H1 for inextensible reinforcement LA1 = 1.36 m LA2 = 1.13 m LA3 = 0.68 m LA4 = 0.23 m LRFD Figure 11.10.6.3.1-1 Location of Potential Failure Surface for Internal Stability Design of MSE Walls Calculate L T at each layer Layer 1 LT1 = 3.18 m < 4.50 m OK Layer 2 LT2 = 3.80 m < 4.50 m OK Layer 3 LT3 = 3.38 m < 4.50 m OK Layer 4 LT4 = 3.08 m < 4.50 m OK Allowable Tensile Strength Design Life = 100 years For Corrosion Losses Ec = En - Es Loss of galvanizing = 0.015 mm/yr for first 2 year = 0.004 mm/yr for subsequent years Zinc coating lift = 16.00 years Loss of carbon steel = 0.012 mm/yr after zinc depletion Ec = 1.99 mm Ac = 99.72 mm2
  • 14. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Tal = AC FY Case V φTall = 44.67 kN Case IV φTall = 33.51 kN Pullout Resistance Strength C11.10.6.3.2 P = F* α σv Le C b Layer 1 Case V φP = 18.00 kN Case IV φP = 16.20 kN Layer 2 Case V φP = 24.17 kN Case IV φP = 21.75 kN Layer 3 Case V φP = 31.42 kN Case IV φP = 28.28 kN Layer 4 Case V φP = 37.74 kN Case IV φP = 33.97 kN Connection Strength Strip width b = 60 mm Stritp thickness t = 4 mm Yield Strength Fy = 345 Mpa C11.10.6.3.2 Tac = AC FY Case V φTac = 63.48 kN > 44.67 kN OK Case IV φTac = 47.61 kN > 33.51 kN OK III. External Stability with Seismic Peak Ground Acceleration a0/g = 0.46 11.6.5.2.1 Horizontal acceleration coefficient kh = 0.5 Kho = 0.23 ζ = Arc tan(Kh) = 12.95 kae = cos2 (φ - ζ) cos ( ζ ) cos (ζ + δ) (1 + √(sin(φ + δ) sin(φ - ζ - δ)/cos (ζ + δ) cosδ))2 kae = 0.871 0.950 x 2.114 = 0.434 11.6.5.3-2 Horizontal Seismic Thrust PAE = 0.5 KAE Ï’ H2 = 93.06 kN/m
  • 15. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Moment arm of PAE = 1.51 m Moment MAE = 140.22 KN-m Horizontal Inertia Force PIR = 0.5 Kh Ï’ H2 = 49.34 kN/m Moment arm of PIR = 2.26 m Moment MIR = 111.51 KN-m ∑MF = 251.72 KN-m Sliding (LRFD 11.10.5.3) Sliding F.S = ∑V x tanφ ∑F Rv = 427.14 kN/m Moment arm of Pv = 2.25 m Moment Mv = 961.07 KN-m Rh = 95.87 kN/m F.S = 3.01 > 1.5 OK Overturning (LRFD 11.10.5.3) Overturning F.S = ∑Mv ∑MF = 3.82 > 2 OK Bearing Capacity at Base Eccentricity e = L - ∑Mv-∑Mf 2 ∑V = 0.59 < 0.75 OK σv = ∑V L - 2e σv = 128.60 kN/m2
  • 16. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 qult = cf Nc + 0.5 (L-2e) Ï’f Nr qult = 706.78 kN/m2 F.S = qult σv = 5.50 > 1.5 OK IV. Internal Stability with Seismic PI = Kh Wa = 22.20 kN/m Tmd = Pi Lei / ∑Lei Layer 1 Tmd = 4.78 kN per strip Layer 2 Tmd = 5.12 kN per strip Layer 3 Tmd = 5.81 kN per strip Layer 4 Tmd = 6.49 kN per strip Ttotal = Tmax + Tmd Layer 1 For Pullout Ttotal = 14.56 kN per strip < 18.00 kN OK For Tensile Ttotal = 23.61 kN per strip < 44.67 kN OK Layer 2 For Pullout Ttotal = 18.17 kN per strip < 24.17 kN OK For Tensile Ttotal = 28.11 kN per strip < 44.67 kN OK Layer 3 For Pullout Ttotal = 22.58 kN per strip < 31.42 kN OK For Tensile Ttotal = 32.49 kN per strip < 44.67 kN OK Layer 4 For Pullout Ttotal = 25.22 kN per strip < 37.74 kN OK For Tensile Ttotal = 36.70 kN per strip < 44.67 kN OK
  • 17. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 V. Impact Load Width of slab b = 2.1 m Depth of slab h = 1.1 m Eccetricity of traffic barrier e = 0.12 m Slab Length L = 6 m 11.10.10.2 Static impact Load P = 44.48 kN Earth pressure F1 = 0.5 Ka Ï’ h2 Case I F1 = 3.59 kN/m Case II F1 = 4.85 kN/m Traffic surcharge F2 = Ka q h Case I F2 = 4.04 kN/m Case II F2 = 7.08 kN/m PH1 = 7.41 kN/m Case I ∑ F 11.01 kN/m Case II ∑ F = 19.34 kN/m Horizontal pressure due to traffic barrier L1 = (cr + bf - 2e') (tan 45 + φ/2) = 3.50 m Δσhmax = 2 ∑F / L1 Case I Δσhmax = 6.29 kN/m2 Case II Δσhmax = 11.06 kN/m2
  • 18. PROJECT : PREPARED BY : DATE : T.Z.S.K 4/11/2022 Tmax = σh Sv Layer 1 For Pullout Tmax = 12.13 kN per strip < 18.00 kN OK For Tensile Tmax = 22.97 kN per strip < 44.67 kN OK Layer 2 For Pullout Tmax = 16.59 kN per strip < 24.17 kN OK For Tensile Tmax = 29.21 kN per strip < 44.67 kN OK Layer 3 For Pullout Tmax = 20.31 kN per strip < 31.42 kN OK For Tensile Tmax = 32.90 kN per strip < 44.67 kN OK Layer 4 For Pullout Tmax = 22.27 kN per strip < 37.74 kN OK For Tensile Tmax = 36.42 kN per strip < 44.67 kN OK