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A farmer had a twice as many chicken as ducks. After he had sold 200 chickens, he had thrice as
many ducks as chickens. How many chickens did he have at first? Ans.: 240

chicken

ducks

2u x 3
= 6u
1u x 3
= 3u

-200

x

6u  1u --> 200
5u --> 200
1u --> 200 歎 5 = 40
6u --> 6 x 40 = 240 (ans.)

1u

3u
Jane and Ivan had $60. After giving Ivan $8, Jane had the same amount of money as Ivan. How
much money did Ivan have at first? Ans.: $22

-8

Jane

1u
60

60
Ivan

?

+8

2u --> 60
1u --> 60 歎 2 = 30
30 - 8 = 22 (ans.)

1u (30)
Thomas is 4 times as old as Sandra. Thomas will be twice as old as Sandra in 8 years time. How
old is Thomas now? Ans.:16

Thomas

Sandra

+8

4u

1u

3u

+8

6u  4u --> 8
2u --> 8
1u --> 8 歎 2 = 4
Thomas (now): 4u --> 4 x 4 = 16 (ans.)

2u x 3 =6u

1u x 3 =3u

1u x3
=3u
John and Ramesh had an equal amount of sweets at first. John bought another 6 sweets and
Ramesh lost 12 of her sweets. John had thrice as many sweets as Ramesh. Find the number of
sweets each of them have first? Ans.:21
3u
John
Ramesh

6
1u

12
3u  1u --> 12+ 6
2u --> 18
1u --> 18 歎 2 = 9
Each (1st): 1u + 12 --> 9 + 12 = 21 (ans.)
Some children were sharing oranges. If each child took 3 oranges, there would be 2 left over.
But if each child took 4 oranges, there would be 2 oranges short. How many oranges were
there? Ans.:14

Total
3 each (12)

2

2

4 each
4 each  3 each --> 2 + 2
1 each --> 4
3 each --> 3 x 4 = 12
Total:12 + 2 = 14 (ans.)
A moment ago, Wendy had 2/5 as much money as Mike. Wendy withdrew $50 from her bank
account. Now Wendy has 1/2 as much money as Mike.
(a) How much money does Wendy have now? Ans.:$250
(b) What was the total amount of money the two of them had a moment ago? Ans.: $700

Wendy
Mike

2u x 2
= 4u

+50

5u x 2
= 10u

x

1u x 5
= 5u
2u x 5
= 10u

5u  4u --> 50
1u --> 50
Wendy (now) 5u --> 5 x 50 = 250 (ans.)
Total (Before): 4u +10 u = 14u
14u --> 14 x 50 = 700 (ans.)
Alex and his sister, Amber have a total of 120 computer games. If Alex gives Amber 5 games,
Amber will have nine times as many games as Alex. How many more games does Amber have
than Alex? Ans.: 86

Alex

?

17

-5

1u

120

120
Amber

103

+5

1u + 9u --> 120
10u --> 120
1u --> 120 歎 10 = 12
Alex (1st): 1u + 5 = 12 +5 = 17
120  17 = 103
103  17 = 86 (ans.)

9u
Olivia's mother was 4 times Olivia age 4 years ago. If their total age now is 48, how old is Olivia
now? Ans.:12

4 years ago
48  4  4
= 40

mother
Olivia

4u
1u

now
+4
+4

4u + 1u --> 40
5u --> 40
1u --> 40 歎 5 = 8
Olivia (Now): 1u + 4 = 8 +4 = 12 (ans.)

48
A moment ago, 84 pears and 65 apples were displayed at a fruit stall. 28 pears were sold and
some more apples were displayed. Now, 5 times as many apples as pears are displayed. How
many apples have just been displayed? Ans.:215

A moment ago
pears
apples

84
65

Now
-28
+?

1u --> 84  28 = 56
5u --> 5 x 56 = 280
?: 280  65 = 215 (ans.)

1u
5u

(280)
Mrs. Tay has a bag of sweets. If she gives each child 7 sweets, she will be left with 5 sweets. If
she gives each child 9 sweets, she will need 5 more sweets.
a)How many children are there? Ans.:5
b)How many sweets are there? Ans.:40

Total
7 each

(35)

5

5

9 each
9 each  7each --> 5 + 5
2 each --> 10

1 each --> 10 歎 2 = 5 (a)
7 each --> 7 x 5 = 35
Total: 35 + 5 = 40 (b)
Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day
respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin
spent $50 and $100 each day respectively, Jason would have $3700 when Kevin spent all his
money. How much money was given to Jason in the beginning? Ans.:$4500
Jason
Kevin

100u

1300

-100 u
-50 u

50u

1300
0
75u

Jason
Kevin

100u
50u

1300

-50 p 歎2
-25u
-100 p 歎2
-50u

1300
3700

0

75u --> 3700  1300 = 2400
1u --> 2400 歎 75 = 32
Jason (1st): 100u + 1300 --> 100 x 32 + 1300 = 4500 (ans.)
Joe has 60% more marbles than Fred. First, Joe gave 20% of his marbles to Fred. In return, Fred
gave 1/6 of his marbles to Joe. Finally, Fred had 80 fewer marbles than Joe. How many marbles
did Joe have at first? Ans.:320
3/5

1/5

Joe

8u x 5 = 40u

-8u

Fred

5u x 5 = 25u

+8u

32u

33u

10u --> 80
1u --> 80 歎 10 = 8
40u --> 40 x 8 = 320 (ans.)

+5.5u

-1/6
-5.5u

8/40

37.5u

27.5u

80
10u
When Mr Wong was Meimei's present age, she was 3 years old. When Meimei is Mr Wong's
present age, he will be 81 years old.
a)How much older is Mr Wong than Meimei? Ans.:26
b)How old is Mr Wong now? Ans.:55
Was
Wong
Meimei's

3
3

Present
1u

3

1u

3

Future

2u
1u

81
1u

3

2u

1u

2u + 1u --> 81 - 3
3u --> 78
1u --> 78 歎 3 = 26 (a)
Wong (Now): 3 +2u --> 3 + 2 x 26 = 55 (b)
Alex and Betty each had $600 at first. Alex spent $6 per day and Betty spent $2 per day. How
long did it take for Betty's money to be twice as much as Alex's money? Ans.:60 days
Alex

Betty

-6 u

600

600

-2 u

x2 1p --> 600  6u
2p --> 1200  12u

1p

2p

2p --> 600  2u
1200

2p

12u

2p

2u
600

12u  2u -->1200  600
10u --> 600

1u --> 600 歎 10 = 60 (ans.)
If Eddie uses his money to buy 7 similar bags, he will have $5 more than Alice. If Alice uses some
of her money to buy same 7 bags, she will have $47 less than Eddie.
a)Find the cost of 1 bag. Ans.:$3
b)How much more money does Eddie have than Alice? Ans.:$26
?
Eddie

7 bags
$5

Alice

7 bags
$47

7 bags + 7 bags --> 47 - 5
14 bags --> 42
1 bag --> 42 歎 14 = 3 (a)
7 bags --> 7 x 3 = 21
21 + 5 = 26 (b)
Mr Tan had some apples and oranges in the ratio 4:5. After selling 170 apples and 25% of the
oranges, the ratio of the apples to oranges left became 1:2. What was the number of fruits Mr
Tan had in the end ? Ans.:450
1/4
5/20

apples

oranges

4u x 4 = 16u

5u x 4 = 20u

-170
1p x 7.5 = 7.5u
-5u

16u  7.5u --> 170
8.5u --> 170
1u --> 170 歎 8.5 = 20
Total (end): 7.5u 15u = 22.5u
+2.5u --> 22.5 x 20 = 450 (ans.)
2

15u
2p x 7.5 = 15u
Box A contained 350 black marbles and 500 white marbles. Box B contained 400 black marbles
and 100 white marbles. After some black and white marbles were removed from Box B to be
placed in Box A, 1/2 of the marbles in Box A were black and 3/4 of the marbles in Box B were
black.
a)How many black marbles were removed from Box B to be placed in Box A? Ans.:175
b)How many white marbles were removed from Box B to be placed in Box A? Ans.:25
Box A
black
white

+?

350

Box B
-?

1u

+?

500

1u

1u + 1p --> 500 + 100
1u + 1p --> 600
1u --> 600  1p

1u + 3p --> 350 + 400
1u + 3p --> 750
1u --> 750  3p
750
1u
1u
600

3p
1p
3p  1p --> 750 - 600
2p --> 150

400
100

-?

(225)
3p
1p
(75)

1p --> 150 歎 2 = 75
3p --> 3 x 75 = 225
400 - 225 = 175 (a)
100 - 75 = 25 (b)
When Kok's age was twice as Bala's age, Mike's age was 30. When Mike's age was twice Kok's
age, Bala's age was 21. Given that Mike was the oldest among the three persons, find Bala's age
when Mike was 62 years old. Ans.:35
Mikes
Koks
Balas

2p

30
2u
1u

1u
1u

1p

1p

21
21

2u + 1u --> 30 - 21
3u --> 9
1u --> 9 歎 3 = 3

62

(1u + 21)
1u

?

2u + 21 --> 2 x 3 + 21 = 27
62  27 = 35 (ans.)

2u + 21
(27)
Jane and Iris has 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25%
as many sweets as Iris. She was left with twice as many sweets as Iris.
a)How many sweets did Iris give away? Ans.:60
1/4
b)How many sweets did Jane have in the end? Ans.:120
Jane
255
Iris

-1u

135
15

120

-4u

2p
1p

Iris: (255  15) 歎 2 = 120
Jane: 120 + 15 = 135
2p --> 135  1u x2 1p --> 120  4u
2p --> 240  8u
240
2p
2p
135

8u
1u
8u  1u --> 240 - 135
7u --> 105

1u --> 105 歎 7 = 15
Iris (gave): 4u --> 4 x 15 = 60 (a)
Jane (end): 135  1u --> 135  15 = 120 (b)
If I buy 3 Oranges and 5 Apples, I will have $0.70 left. If I buy 4 oranges and 4 apples, I will need
another $0.50. Given that an apple costs $0.80, find the amount of money I have. Ans.:$10.70
$4

$3.20

Total
3 OR

$4
4 OR

$0.70

$0.50
$3.20

4 OR  3 OR --> 4 + 0.70 + 0.50  3.20
1OR --> 2
Total: 3 OR + 4 + 0.70 --> 3 x 2 + 4.70 = $10.70 (ans.)

More Related Content

P 2014 lesson 1 2014 01-05

  • 1. A farmer had a twice as many chicken as ducks. After he had sold 200 chickens, he had thrice as many ducks as chickens. How many chickens did he have at first? Ans.: 240 chicken ducks 2u x 3 = 6u 1u x 3 = 3u -200 x 6u 1u --> 200 5u --> 200 1u --> 200 歎 5 = 40 6u --> 6 x 40 = 240 (ans.) 1u 3u
  • 2. Jane and Ivan had $60. After giving Ivan $8, Jane had the same amount of money as Ivan. How much money did Ivan have at first? Ans.: $22 -8 Jane 1u 60 60 Ivan ? +8 2u --> 60 1u --> 60 歎 2 = 30 30 - 8 = 22 (ans.) 1u (30)
  • 3. Thomas is 4 times as old as Sandra. Thomas will be twice as old as Sandra in 8 years time. How old is Thomas now? Ans.:16 Thomas Sandra +8 4u 1u 3u +8 6u 4u --> 8 2u --> 8 1u --> 8 歎 2 = 4 Thomas (now): 4u --> 4 x 4 = 16 (ans.) 2u x 3 =6u 1u x 3 =3u 1u x3 =3u
  • 4. John and Ramesh had an equal amount of sweets at first. John bought another 6 sweets and Ramesh lost 12 of her sweets. John had thrice as many sweets as Ramesh. Find the number of sweets each of them have first? Ans.:21 3u John Ramesh 6 1u 12 3u 1u --> 12+ 6 2u --> 18 1u --> 18 歎 2 = 9 Each (1st): 1u + 12 --> 9 + 12 = 21 (ans.)
  • 5. Some children were sharing oranges. If each child took 3 oranges, there would be 2 left over. But if each child took 4 oranges, there would be 2 oranges short. How many oranges were there? Ans.:14 Total 3 each (12) 2 2 4 each 4 each 3 each --> 2 + 2 1 each --> 4 3 each --> 3 x 4 = 12 Total:12 + 2 = 14 (ans.)
  • 6. A moment ago, Wendy had 2/5 as much money as Mike. Wendy withdrew $50 from her bank account. Now Wendy has 1/2 as much money as Mike. (a) How much money does Wendy have now? Ans.:$250 (b) What was the total amount of money the two of them had a moment ago? Ans.: $700 Wendy Mike 2u x 2 = 4u +50 5u x 2 = 10u x 1u x 5 = 5u 2u x 5 = 10u 5u 4u --> 50 1u --> 50 Wendy (now) 5u --> 5 x 50 = 250 (ans.) Total (Before): 4u +10 u = 14u 14u --> 14 x 50 = 700 (ans.)
  • 7. Alex and his sister, Amber have a total of 120 computer games. If Alex gives Amber 5 games, Amber will have nine times as many games as Alex. How many more games does Amber have than Alex? Ans.: 86 Alex ? 17 -5 1u 120 120 Amber 103 +5 1u + 9u --> 120 10u --> 120 1u --> 120 歎 10 = 12 Alex (1st): 1u + 5 = 12 +5 = 17 120 17 = 103 103 17 = 86 (ans.) 9u
  • 8. Olivia's mother was 4 times Olivia age 4 years ago. If their total age now is 48, how old is Olivia now? Ans.:12 4 years ago 48 4 4 = 40 mother Olivia 4u 1u now +4 +4 4u + 1u --> 40 5u --> 40 1u --> 40 歎 5 = 8 Olivia (Now): 1u + 4 = 8 +4 = 12 (ans.) 48
  • 9. A moment ago, 84 pears and 65 apples were displayed at a fruit stall. 28 pears were sold and some more apples were displayed. Now, 5 times as many apples as pears are displayed. How many apples have just been displayed? Ans.:215 A moment ago pears apples 84 65 Now -28 +? 1u --> 84 28 = 56 5u --> 5 x 56 = 280 ?: 280 65 = 215 (ans.) 1u 5u (280)
  • 10. Mrs. Tay has a bag of sweets. If she gives each child 7 sweets, she will be left with 5 sweets. If she gives each child 9 sweets, she will need 5 more sweets. a)How many children are there? Ans.:5 b)How many sweets are there? Ans.:40 Total 7 each (35) 5 5 9 each 9 each 7each --> 5 + 5 2 each --> 10 1 each --> 10 歎 2 = 5 (a) 7 each --> 7 x 5 = 35 Total: 35 + 5 = 40 (b)
  • 11. Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively, Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin spent all his money. How much money was given to Jason in the beginning? Ans.:$4500 Jason Kevin 100u 1300 -100 u -50 u 50u 1300 0 75u Jason Kevin 100u 50u 1300 -50 p 歎2 -25u -100 p 歎2 -50u 1300 3700 0 75u --> 3700 1300 = 2400 1u --> 2400 歎 75 = 32 Jason (1st): 100u + 1300 --> 100 x 32 + 1300 = 4500 (ans.)
  • 12. Joe has 60% more marbles than Fred. First, Joe gave 20% of his marbles to Fred. In return, Fred gave 1/6 of his marbles to Joe. Finally, Fred had 80 fewer marbles than Joe. How many marbles did Joe have at first? Ans.:320 3/5 1/5 Joe 8u x 5 = 40u -8u Fred 5u x 5 = 25u +8u 32u 33u 10u --> 80 1u --> 80 歎 10 = 8 40u --> 40 x 8 = 320 (ans.) +5.5u -1/6 -5.5u 8/40 37.5u 27.5u 80 10u
  • 13. When Mr Wong was Meimei's present age, she was 3 years old. When Meimei is Mr Wong's present age, he will be 81 years old. a)How much older is Mr Wong than Meimei? Ans.:26 b)How old is Mr Wong now? Ans.:55 Was Wong Meimei's 3 3 Present 1u 3 1u 3 Future 2u 1u 81 1u 3 2u 1u 2u + 1u --> 81 - 3 3u --> 78 1u --> 78 歎 3 = 26 (a) Wong (Now): 3 +2u --> 3 + 2 x 26 = 55 (b)
  • 14. Alex and Betty each had $600 at first. Alex spent $6 per day and Betty spent $2 per day. How long did it take for Betty's money to be twice as much as Alex's money? Ans.:60 days Alex Betty -6 u 600 600 -2 u x2 1p --> 600 6u 2p --> 1200 12u 1p 2p 2p --> 600 2u 1200 2p 12u 2p 2u 600 12u 2u -->1200 600 10u --> 600 1u --> 600 歎 10 = 60 (ans.)
  • 15. If Eddie uses his money to buy 7 similar bags, he will have $5 more than Alice. If Alice uses some of her money to buy same 7 bags, she will have $47 less than Eddie. a)Find the cost of 1 bag. Ans.:$3 b)How much more money does Eddie have than Alice? Ans.:$26 ? Eddie 7 bags $5 Alice 7 bags $47 7 bags + 7 bags --> 47 - 5 14 bags --> 42 1 bag --> 42 歎 14 = 3 (a) 7 bags --> 7 x 3 = 21 21 + 5 = 26 (b)
  • 16. Mr Tan had some apples and oranges in the ratio 4:5. After selling 170 apples and 25% of the oranges, the ratio of the apples to oranges left became 1:2. What was the number of fruits Mr Tan had in the end ? Ans.:450 1/4 5/20 apples oranges 4u x 4 = 16u 5u x 4 = 20u -170 1p x 7.5 = 7.5u -5u 16u 7.5u --> 170 8.5u --> 170 1u --> 170 歎 8.5 = 20 Total (end): 7.5u 15u = 22.5u +2.5u --> 22.5 x 20 = 450 (ans.) 2 15u 2p x 7.5 = 15u
  • 17. Box A contained 350 black marbles and 500 white marbles. Box B contained 400 black marbles and 100 white marbles. After some black and white marbles were removed from Box B to be placed in Box A, 1/2 of the marbles in Box A were black and 3/4 of the marbles in Box B were black. a)How many black marbles were removed from Box B to be placed in Box A? Ans.:175 b)How many white marbles were removed from Box B to be placed in Box A? Ans.:25 Box A black white +? 350 Box B -? 1u +? 500 1u 1u + 1p --> 500 + 100 1u + 1p --> 600 1u --> 600 1p 1u + 3p --> 350 + 400 1u + 3p --> 750 1u --> 750 3p 750 1u 1u 600 3p 1p 3p 1p --> 750 - 600 2p --> 150 400 100 -? (225) 3p 1p (75) 1p --> 150 歎 2 = 75 3p --> 3 x 75 = 225 400 - 225 = 175 (a) 100 - 75 = 25 (b)
  • 18. When Kok's age was twice as Bala's age, Mike's age was 30. When Mike's age was twice Kok's age, Bala's age was 21. Given that Mike was the oldest among the three persons, find Bala's age when Mike was 62 years old. Ans.:35 Mikes Koks Balas 2p 30 2u 1u 1u 1u 1p 1p 21 21 2u + 1u --> 30 - 21 3u --> 9 1u --> 9 歎 3 = 3 62 (1u + 21) 1u ? 2u + 21 --> 2 x 3 + 21 = 27 62 27 = 35 (ans.) 2u + 21 (27)
  • 19. Jane and Iris has 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris. a)How many sweets did Iris give away? Ans.:60 1/4 b)How many sweets did Jane have in the end? Ans.:120 Jane 255 Iris -1u 135 15 120 -4u 2p 1p Iris: (255 15) 歎 2 = 120 Jane: 120 + 15 = 135 2p --> 135 1u x2 1p --> 120 4u 2p --> 240 8u 240 2p 2p 135 8u 1u 8u 1u --> 240 - 135 7u --> 105 1u --> 105 歎 7 = 15 Iris (gave): 4u --> 4 x 15 = 60 (a) Jane (end): 135 1u --> 135 15 = 120 (b)
  • 20. If I buy 3 Oranges and 5 Apples, I will have $0.70 left. If I buy 4 oranges and 4 apples, I will need another $0.50. Given that an apple costs $0.80, find the amount of money I have. Ans.:$10.70 $4 $3.20 Total 3 OR $4 4 OR $0.70 $0.50 $3.20 4 OR 3 OR --> 4 + 0.70 + 0.50 3.20 1OR --> 2 Total: 3 OR + 4 + 0.70 --> 3 x 2 + 4.70 = $10.70 (ans.)