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Fractions  Problem Solving


 Pain is temporary. It may last a
 minute, or an hour, or a day, or a
 year, but eventually it will subside
 and something else will take its
 place. If I quit, however, it lasts
 forever.  Lance Armstrong
Fractions  Problem Solving

 Using the model approach to solve
 problem sums on fractions, always keep in
 mind, the denominator is always the
 whole. The numerator is part of the whole.
Fractions  Problem Solving

 Using the model approach to solve
 problem sums on fractions, always keep in
 mind, the denominator is always the
 whole. The numerator is part of the whole.
                  4
 How do you put       into a visual form of a
 bar model ?      7
Fractions  Problem Solving

 Using the model approach to solve
 problem sums on fractions, always keep in
 mind, the denominator is always the
 whole. The numerator is part of the whole.
                  4
 How do you put       into a visual form of a
 bar model ?      7
Fractions  Problem Solving
The total cost of a pen and a pencil is $4. The
                        1
cost of the pencil is   3
                            the cost of the pen. How
much does the pen cost?

   pen
                             $4
pencil
Fractions  Problem Solving
The total cost of a pen and a pencil is $4. The
                        1
cost of the pencil is   3
                            the cost of the pen. How
much does the pen cost?
                                  Total number of units
   pen                                  3+1=4
                             $4   4u      4
pencil
                                  1u      4歎4=1
                                  3u      1x3=3
                                  The pen costs $3.
Fractions  Problem Solving
The total length of a thread and a needle is
100cm. The length of the needle is the length
of 3 the thread. How long is the thread?
   7



             The denominator '7' stands for 7u which is
             the length of the thread.
Fractions  Problem Solving
The total length of a thread and a needle is
100cm. The length of the needle is the length
of 3 the thread. How long is the thread?
   7
        T
Fractions  Problem Solving
The total length of a thread and a needle is
100cm. The length of the needle is the length
of 3 the thread. How long is the thread?
   7
        T
                                           100
        N
Fractions  Problem Solving
The total length of a thread and a needle is
100cm. The length of the needle is the length
of 3 the thread. How long is the thread?
   7
         T
                                           100
         N
       7u + 3 u = 10u
       10u       100
       1u        100 歎 10 = 10
       7u        10 x 7 = 70
       The thread is 70cm long.
Fractions  Problem Solving
Jasmine is 21 kg heavier than Lingling.
                     2
Lingling's mass is     of Jasmine's mass. Find
                     5
the total mass of the two girls.
                                   The denominator '5'
                                   stands for 5u which is
                                   Jasmine's mass.
Fractions  Problem Solving
Jasmine is 21 kg heavier than Lingling.
                     2
Lingling's mass is     of Jasmine's mass. Find
                     5
the total mass of the two girls.

    J
                                   ?
    L                 21
Fractions  Problem Solving
Jasmine is 21 kg heavier than Lingling.
                     2
Lingling's mass is     of Jasmine's mass. Find
                     5
the total mass of the two girls.

    J
                                   ?
    L                 21

  3u    -> 21
  1u    -> 21 歎 3    = 7
  7u    -> 7 x 7     = 49
  Their total mass is 49kg.
Fractions  Problem Solving
Jeremy has 3 as many books as Kelvin. Kelvin
            5
has 64 more books than Jeremy. How
many books do they have altogether?
                                The denominator '5'
                                stands for 5u which is
                                Kelvin's books.
Fractions  Problem Solving
Jeremy has 3 as many books as Kelvin. Kelvin
            5
has 64 more books than Jeremy. How
many books do they have altogether?
   K
                              ?
   J                 64
Fractions  Problem Solving
Jeremy has 3 as many books as Kelvin. Kelvin
            5
has 64 more books than Jeremy. How
many books do they have altogether?
   K
                              ?
   J                     64
  5u  3u = 2u
  2u    -> 64
  1u    -> 64 歎 2 = 32
  8u    -> 32 x 8 = 256
  They have 256 books altogether.
Fractions  Problem Solving
A fruit seller started his day with a total of 222
                                        3
mangoes and bananas. After selling         of his mangoes
                                        7
and 35 bananas, he had an equal number of mangoes
and bananas left. How many mangoes did he start with at
the beginning of his day?


              Fruit seller has 7u of mangoes at the start.
                     After selling 3u, he has 4u left.

                  Notice after selling 35 bananas,
        he had an equal number of mangoes and bananas left.
               This means he also had 4u of bananas.
Fractions  Problem Solving
A fruit seller started his day with a total of 222
                                        3
mangoes and bananas. After selling         of his mangoes
                                        7
and 35 bananas, he had an equal number of mangoes
and bananas left. How many mangoes did he start with at
the beginning of his day?
                                 M
                                                            222
                                  B                35
Fractions  Problem Solving
A fruit seller started his day with a total of 222
                                        3
mangoes and bananas. After selling         of his mangoes
                                        7
and 35 bananas, he had an equal number of mangoes
and bananas left. How many mangoes did he start with at
the beginning of his day?
   222  35 = 187                M
                                                            222
   11u      -> 187                B                35

   1u    -> 187 歎 11 = 17
   7u    -> 17 x 7 = 119
   He started with 119 mangoes.
Fractions  Problem Solving
A bag of sweets was shared among Zhihao, Titus and
                        1
Glenn. Zhihao received     of the sweets. Titus received
                        8
 1 of the sweets. Glenn received the remaining 25
 4
sweets. How many sweets were there?
                                       Find the common
                                       denominator and
                                   their equivalent fractions
                                   before drawing the model.
Fractions  Problem Solving
 1 of the fruit in the basket are apples, 3 of them
 4                                        8
are oranges and the remaining 96 are bananas. How
many fruits are there in the basket altogether?



             A             O         B (96)

    3u    -> 96
    1u    -> 96 歎 3 = 32
    8u    -> 32 x 8 = 256
    There are 256 fruits in the basket altogether.
Fractions  Problem Solving
3 of the students in a class are Malays. 5 of them
7                                        11
are Indians and the remaining 81 students are Chinese.
(a) Find the total number of students in the class.
(b) Express the number of Chinese students as a fraction
of the number of Malay students in its simplest form.

        Find the fraction of the Chinese students by
     fnding the common denominator and their equivalent
                           fractions.
Fractions  Problem Solving
3 of the students in a class are Malays. 5 of them
7                                        11
are Indians and the remaining 81 students are Chinese.
(a) Find the total number of students in the class.
(b) Express the number of Chinese students as a fraction
of the number of Malay students in its simplest form.

   Fraction of the Chinese students
   = Whole  Fraction of the Malays  Fraction of the Indians
Fractions  Problem Solving
 1
   Of the people in the auditorium are men. 3 Of
 9                                          8
the remainder are women and the rest are children.
There are 400 more children than women. How
many people are there in the stadium altogether?


                  Find the whole.
                    In this case,
                  the whole is 9u.
Fractions  Problem Solving
 1
   Of the people in the auditorium are men. 3 Of
 9                                          8
the remainder are women and the rest are children.
There are 400 more children than women. How
many people are there in the stadium altogether?
Fractions  Problem Solving
 1
   Of the people in the auditorium are men. 3 Of
 9                                          8
the remainder are women and the rest are children.
There are 400 more children than women. How
many people are there in the stadium altogether?
Fractions  Problem Solving
 1
   Of the people in the auditorium are men. 3 Of
 9                                          8
the remainder are women and the rest are children.
There are 400 more children than women. How
many people are there in the stadium altogether?


          M       W                  C
Fractions  Problem Solving
 1
   Of the people in the auditorium are men. 3 Of
 9                                          8
the remainder are women and the rest are children.
There are 400 more children than women. How
many people are there in the stadium altogether?


          M       W                  C
   5u  3u = 2u
   2u    -> 400
   1u    -> 400 歎 2 = 200
   9u    -> 9 x 200 = 1800
   There are 1800 people in the stadium.
Fractions  Problem Solving
        2                             1
I spent   of my money on a shirt and of the
        5                             3
remainder on a pair of pants. I had $90 left. How
much money did I have at first?

                                   This means that 'I' have
                                   a total of 5u of money.
                                   2u is spent on the shirt.
Fractions  Problem Solving
        2                             1
I spent   of my money on a shirt and of the
        5                             3
remainder on a pair of pants. I had $90 left. How
much money did I have at first?



            S
Fractions  Problem Solving
        2                             1
I spent   of my money on a shirt and of the
        5                             3
remainder on a pair of pants. I had $90 left. How
much money did I have at first?



          S        P
Fractions  Problem Solving
        2                             1
I spent   of my money on a shirt and of the
        5                             3
remainder on a pair of pants. I had $90 left. How
much money did I have at first?

                          90
          S        P       L
Fractions  Problem Solving
        2                             1
I spent   of my money on a shirt and of the
        5                             3
remainder on a pair of pants. I had $90 left. How
much money did I have at first?

                            90
           S        P       L
   2u     -> 90
   1u     -> 90 歎 2 = 45
   5u     -> 45 x 5 = 225
   I had $225 at first.

More Related Content

P4 Fraction Sums (23Jan)

  • 1. Fractions Problem Solving Pain is temporary. It may last a minute, or an hour, or a day, or a year, but eventually it will subside and something else will take its place. If I quit, however, it lasts forever. Lance Armstrong
  • 2. Fractions Problem Solving Using the model approach to solve problem sums on fractions, always keep in mind, the denominator is always the whole. The numerator is part of the whole.
  • 3. Fractions Problem Solving Using the model approach to solve problem sums on fractions, always keep in mind, the denominator is always the whole. The numerator is part of the whole. 4 How do you put into a visual form of a bar model ? 7
  • 4. Fractions Problem Solving Using the model approach to solve problem sums on fractions, always keep in mind, the denominator is always the whole. The numerator is part of the whole. 4 How do you put into a visual form of a bar model ? 7
  • 5. Fractions Problem Solving The total cost of a pen and a pencil is $4. The 1 cost of the pencil is 3 the cost of the pen. How much does the pen cost? pen $4 pencil
  • 6. Fractions Problem Solving The total cost of a pen and a pencil is $4. The 1 cost of the pencil is 3 the cost of the pen. How much does the pen cost? Total number of units pen 3+1=4 $4 4u 4 pencil 1u 4歎4=1 3u 1x3=3 The pen costs $3.
  • 7. Fractions Problem Solving The total length of a thread and a needle is 100cm. The length of the needle is the length of 3 the thread. How long is the thread? 7 The denominator '7' stands for 7u which is the length of the thread.
  • 8. Fractions Problem Solving The total length of a thread and a needle is 100cm. The length of the needle is the length of 3 the thread. How long is the thread? 7 T
  • 9. Fractions Problem Solving The total length of a thread and a needle is 100cm. The length of the needle is the length of 3 the thread. How long is the thread? 7 T 100 N
  • 10. Fractions Problem Solving The total length of a thread and a needle is 100cm. The length of the needle is the length of 3 the thread. How long is the thread? 7 T 100 N 7u + 3 u = 10u 10u 100 1u 100 歎 10 = 10 7u 10 x 7 = 70 The thread is 70cm long.
  • 11. Fractions Problem Solving Jasmine is 21 kg heavier than Lingling. 2 Lingling's mass is of Jasmine's mass. Find 5 the total mass of the two girls. The denominator '5' stands for 5u which is Jasmine's mass.
  • 12. Fractions Problem Solving Jasmine is 21 kg heavier than Lingling. 2 Lingling's mass is of Jasmine's mass. Find 5 the total mass of the two girls. J ? L 21
  • 13. Fractions Problem Solving Jasmine is 21 kg heavier than Lingling. 2 Lingling's mass is of Jasmine's mass. Find 5 the total mass of the two girls. J ? L 21 3u -> 21 1u -> 21 歎 3 = 7 7u -> 7 x 7 = 49 Their total mass is 49kg.
  • 14. Fractions Problem Solving Jeremy has 3 as many books as Kelvin. Kelvin 5 has 64 more books than Jeremy. How many books do they have altogether? The denominator '5' stands for 5u which is Kelvin's books.
  • 15. Fractions Problem Solving Jeremy has 3 as many books as Kelvin. Kelvin 5 has 64 more books than Jeremy. How many books do they have altogether? K ? J 64
  • 16. Fractions Problem Solving Jeremy has 3 as many books as Kelvin. Kelvin 5 has 64 more books than Jeremy. How many books do they have altogether? K ? J 64 5u 3u = 2u 2u -> 64 1u -> 64 歎 2 = 32 8u -> 32 x 8 = 256 They have 256 books altogether.
  • 17. Fractions Problem Solving A fruit seller started his day with a total of 222 3 mangoes and bananas. After selling of his mangoes 7 and 35 bananas, he had an equal number of mangoes and bananas left. How many mangoes did he start with at the beginning of his day? Fruit seller has 7u of mangoes at the start. After selling 3u, he has 4u left. Notice after selling 35 bananas, he had an equal number of mangoes and bananas left. This means he also had 4u of bananas.
  • 18. Fractions Problem Solving A fruit seller started his day with a total of 222 3 mangoes and bananas. After selling of his mangoes 7 and 35 bananas, he had an equal number of mangoes and bananas left. How many mangoes did he start with at the beginning of his day? M 222 B 35
  • 19. Fractions Problem Solving A fruit seller started his day with a total of 222 3 mangoes and bananas. After selling of his mangoes 7 and 35 bananas, he had an equal number of mangoes and bananas left. How many mangoes did he start with at the beginning of his day? 222 35 = 187 M 222 11u -> 187 B 35 1u -> 187 歎 11 = 17 7u -> 17 x 7 = 119 He started with 119 mangoes.
  • 20. Fractions Problem Solving A bag of sweets was shared among Zhihao, Titus and 1 Glenn. Zhihao received of the sweets. Titus received 8 1 of the sweets. Glenn received the remaining 25 4 sweets. How many sweets were there? Find the common denominator and their equivalent fractions before drawing the model.
  • 21. Fractions Problem Solving 1 of the fruit in the basket are apples, 3 of them 4 8 are oranges and the remaining 96 are bananas. How many fruits are there in the basket altogether? A O B (96) 3u -> 96 1u -> 96 歎 3 = 32 8u -> 32 x 8 = 256 There are 256 fruits in the basket altogether.
  • 22. Fractions Problem Solving 3 of the students in a class are Malays. 5 of them 7 11 are Indians and the remaining 81 students are Chinese. (a) Find the total number of students in the class. (b) Express the number of Chinese students as a fraction of the number of Malay students in its simplest form. Find the fraction of the Chinese students by fnding the common denominator and their equivalent fractions.
  • 23. Fractions Problem Solving 3 of the students in a class are Malays. 5 of them 7 11 are Indians and the remaining 81 students are Chinese. (a) Find the total number of students in the class. (b) Express the number of Chinese students as a fraction of the number of Malay students in its simplest form. Fraction of the Chinese students = Whole Fraction of the Malays Fraction of the Indians
  • 24. Fractions Problem Solving 1 Of the people in the auditorium are men. 3 Of 9 8 the remainder are women and the rest are children. There are 400 more children than women. How many people are there in the stadium altogether? Find the whole. In this case, the whole is 9u.
  • 25. Fractions Problem Solving 1 Of the people in the auditorium are men. 3 Of 9 8 the remainder are women and the rest are children. There are 400 more children than women. How many people are there in the stadium altogether?
  • 26. Fractions Problem Solving 1 Of the people in the auditorium are men. 3 Of 9 8 the remainder are women and the rest are children. There are 400 more children than women. How many people are there in the stadium altogether?
  • 27. Fractions Problem Solving 1 Of the people in the auditorium are men. 3 Of 9 8 the remainder are women and the rest are children. There are 400 more children than women. How many people are there in the stadium altogether? M W C
  • 28. Fractions Problem Solving 1 Of the people in the auditorium are men. 3 Of 9 8 the remainder are women and the rest are children. There are 400 more children than women. How many people are there in the stadium altogether? M W C 5u 3u = 2u 2u -> 400 1u -> 400 歎 2 = 200 9u -> 9 x 200 = 1800 There are 1800 people in the stadium.
  • 29. Fractions Problem Solving 2 1 I spent of my money on a shirt and of the 5 3 remainder on a pair of pants. I had $90 left. How much money did I have at first? This means that 'I' have a total of 5u of money. 2u is spent on the shirt.
  • 30. Fractions Problem Solving 2 1 I spent of my money on a shirt and of the 5 3 remainder on a pair of pants. I had $90 left. How much money did I have at first? S
  • 31. Fractions Problem Solving 2 1 I spent of my money on a shirt and of the 5 3 remainder on a pair of pants. I had $90 left. How much money did I have at first? S P
  • 32. Fractions Problem Solving 2 1 I spent of my money on a shirt and of the 5 3 remainder on a pair of pants. I had $90 left. How much money did I have at first? 90 S P L
  • 33. Fractions Problem Solving 2 1 I spent of my money on a shirt and of the 5 3 remainder on a pair of pants. I had $90 left. How much money did I have at first? 90 S P L 2u -> 90 1u -> 90 歎 2 = 45 5u -> 45 x 5 = 225 I had $225 at first.