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Projectile motion

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Ces Joanne Fajarito

This document defines terms related to projectile motion such as range, time of flight, and maximum height. It provides equations to calculate initial velocity, time, and maximum height for a projectile. As an example, it shows the calculation to find the range of a long jumper leaving the ground at 30 degrees and 6 m/s, determining the time of flight is 0.61s and range is 3.18m.

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Projectile motion
Definition of terms Range Time of Flight Maximum Height Trajectory
Projectile motion
The trajectory of a high speed projectile falls short of a parabolic path.
To solve initial velocity: Vix = Vi cos Viy = Vi sin
Vfy = Viy + gt For maximum height: (Vi sin )2 2g
t = Vi sin g t = 2Vi sin g
Vi 2 sin 2 g
A long jumper leaves the ground at an angle 30属 to the horizontal and at a speed of 6m/s. How far does he jump?
= 30属 Vi = 6m/s Find: dx or R
t = 0.61s R = 3.20m dx = 3.18m

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Projectile motion

  • 2. Definition of terms Range Time of Flight Maximum Height Trajectory
  • 4. The trajectory of a high speed projectile falls short of a parabolic path.
  • 5. To solve initial velocity: Vix = Vi cos Viy = Vi sin
  • 6. Vfy = Viy + gt For maximum height: (Vi sin )2 2g
  • 7. t = Vi sin g t = 2Vi sin g
  • 8. Vi 2 sin 2 g
  • 9. A long jumper leaves the ground at an angle 30属 to the horizontal and at a speed of 6m/s. How far does he jump?
  • 10. = 30属 Vi = 6m/s Find: dx or R
  • 11. t = 0.61s R = 3.20m dx = 3.18m