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GHRCEM_Amravati_際際滷r Crank Chain Mechanism

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Pravinkumar Wankhade
Pravinkumar Wankhade

GHRCEM_Amravati,students should solve the given problem on 際際滷r Crank Chain Mechanism in sketch book

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A1 A2 A3 A4 A5 A6 A7 A8 B1 B3 B2 B4 B5 B6 B7 B8 P1 P2 P3 P4 P5 P6 P7 P8 O TRAVEL OF SLIDER SLIDER CRANK MECHANISM STEP 1: DRAW HORIZONTAL AXIS STEP 2: MARK CENTER POINT O STEP 3: DRAW VERTICAL AXIS STEP 4: DRAW CIRCLE WITH CENTER O & RADIUS EQUAL TO CRANK LENGTH STEP 5: DEVIDE CIRCLE INTO 8 EQUAL PARTS (A1 TO A8) STEP 6: MARK POINT B1 ON HORIZONTAL AXIS AT A DISTANCE EQUAL TO C.R. AB FROM POINT A1 STEP 7: JOIN C.R. A1B1 & MARK POINT P1 ON IT AT A DISTANCE OF 55 CM FROM POINT A STEP 8: REPEAT STEPS 6 & 7 TO MARK POINTS B2 TO B8 AND POINTS P2 TO P8 STEP 9: JOIN POINTS P1 TO P8 WITH SMOOTH CURVE STEP 10: HIGHLIGHT ONE OF THE CRANK AND C.R. POSITION & SHOW THE TRAVEL OF SLIDER GIVEN DATA: CRANK OA = 30 CM C.R. AB = 110 CM LOCUS Pt. PA = 55 CM LOCUS OF POINT P

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GHRCEM_Amravati_際際滷r Crank Chain Mechanism

  • 1. A1 A2 A3 A4 A5 A6 A7 A8 B1 B3 B2 B4 B5 B6 B7 B8 P1 P2 P3 P4 P5 P6 P7 P8 O TRAVEL OF SLIDER SLIDER CRANK MECHANISM STEP 1: DRAW HORIZONTAL AXIS STEP 2: MARK CENTER POINT O STEP 3: DRAW VERTICAL AXIS STEP 4: DRAW CIRCLE WITH CENTER O & RADIUS EQUAL TO CRANK LENGTH STEP 5: DEVIDE CIRCLE INTO 8 EQUAL PARTS (A1 TO A8) STEP 6: MARK POINT B1 ON HORIZONTAL AXIS AT A DISTANCE EQUAL TO C.R. AB FROM POINT A1 STEP 7: JOIN C.R. A1B1 & MARK POINT P1 ON IT AT A DISTANCE OF 55 CM FROM POINT A STEP 8: REPEAT STEPS 6 & 7 TO MARK POINTS B2 TO B8 AND POINTS P2 TO P8 STEP 9: JOIN POINTS P1 TO P8 WITH SMOOTH CURVE STEP 10: HIGHLIGHT ONE OF THE CRANK AND C.R. POSITION & SHOW THE TRAVEL OF SLIDER GIVEN DATA: CRANK OA = 30 CM C.R. AB = 110 CM LOCUS Pt. PA = 55 CM LOCUS OF POINT P