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SOLUTION OF EQUATIONS FOR ITERATIVOS METHODSBY:DUBAN CASTRO FLOREZ NUMERICS METHODS IN ENGINEERING2010
JACOBIA iterative method is a method that progressively it calculates approaches to the solution of a problem. To difference of the direct methods, in which the process should be finished to have the answer, in the iterative methods you can suspend the process to the i finish of an iteration and an approach is obtained to the solution.For example the method of Newton-RaphsonNUMERICS METHODS
NUMERICS METHODS
NUMERICS METHODSThe Jacobi method de is the iterative method to solve system of equations simple ma and it is applied alone to square systems, that is to say to systems with as many equations as incognito.The following steps should be continued:  First the equation de recurrence is determined. Of the equation  i and the incognito iclears. In notation matricial is written:        where x is the vector of incognito  It takes an approach for the solutions and to this it is designated for 3.    You itera in the cycle that changes the approach
NUMERICS METHODSLeaving of x=1, y=2 applies two iterations of the Jacobi method to solve the system:
NUMERICS METHODSThis Di it is used as unemployment approach in the iterations until Di it is smaller than certain given value.Being Di:
NUMERICS METHODSGAUSS-SEIDELGiven a square system of n linear equations with unknown x:Where:
NUMERICS METHODSGAUSS-SEIDELThen A can be decomposed into a lower triangular component L*, and a strictly upper triangular component U:The system of linear equations may be rewritten as:
NUMERICS METHODSGAUSS-SEIDELThe Gauss–Seidel method is an iterative technique that solves the left hand side of this expression for x, using previous value for x on the right hand side. Analytically, this may be written as:However, by taking advantage of the triangular form of L*, the elements of x(k+1) can be computed sequentially using forward substitution:
To solve the following exercise for the method of Gauss-Seidel with an initial value of (0,0,0). Use three iterationsNUMERICS METHODS1ra iteration2da iterationNUMERICS METHODS3ra iterationNUMERICS METHODSGAUSS-SEIDEL RELAXATIONTo solve the previous exercise for the gauss method for relaxation.               .Use two iterationsReplacing with the initial values (0,0,0)
1ra iterationNUMERICS METHODS
2da iterationNUMERICS METHODS
BIBLIOGRAFIAhttp://en.wikipedia.org/wiki/Gauss%E2%80%93Seidel_method
http://es.wikipedia.org/wiki/M%C3%A9todo_iterativo
http://search.conduit.com/Results.aspx?q=METODOS+ITERATIVOS&meta=all&hl=es&gl=co&SearchSourceOrigin=13&SelfSearch=1&ctid=CT2247187NUMERICS METHODS

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