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S U N S H I N E C H R I S T I A N B I L I N G UA L S C H O O L


               ANTONIO RODRÍGUEZ


                  MR. JOSÉ POPOFF


   C H E M I S T RY L A B R E P O RT: E N E RG Y O F
                     ELECTRONS


                       03/07/2013
INTRODUCTION

        Electromagnetic Radiation


 The characteristics of electromagnetic radiation are that energy can
travel by a combination of an electrical and magnetic field, radiation
means that it can travel through a vacuum. Emission spectrum shows
bright lines or bands of color, this means that it emits or reflects the
colors. Absorption spectrum has intermittent dark lines, so it means that
it absorbs the colors.
OBJECTIVES


 Observe how a simply diffraction grating spectroscope works.



 Observe and draw the spectra of several salts.
MATERIALS

 Bunsen Burner            Copper (II) Sulfate
 Lithium Chloride         Color Pencils
 Potassium Chloride       Diffraction Grating
 Copper (III) Chloride   Spectroscope

 Sodium Chloride          Matches

 Calcium Chloride         Presoaked Wood Splints

 Weight Paper             Incandescent Light
PROCEDURE
1.   First I observed the incandescent light, which was hydrogen. I observed
the incandescent light’s spectrum with the diffraction grating spectroscope.

2.   We labeled 6 weight papers with the names of the salts, one salt per paper.

3.   After that, we lighted the Bunsen burner and we adjusted it until we saw
that the color of the flame was light blue or slightly colorless.

4.   Then, we dipped one soaked wood strip into a salt and burned it in the
Bunsen burner.
PROCEDURE

5. We stared at the light emitted by the salts when being burned with
   de diffraction grating spectroscope.

6. After that, we filled in the data table with what we saw while
   doing the test.

7. We repeated step #4 with all the salts.
Lithium Chloride
POTASSIUM CHLORIDE
IRON (III) CHLORIDE
SODIUM CHLORIDE
CALCIUM CHLORIDE
COPPER (II) SULFATE
DATA ANALYSIS

1. Since each element produces a characteristic spectrum, what can
you conclude about the location of the electron?



 A/= that the location of an electron affects the spectrum or
“color” of the light.
DATA ANALYSIS
2. If you had observed only the color if the flame as the salt burned,
you would have conducted a flame test. Would you say that a flame
test or a spectroscopic test is more accurate? Why?



 A/= I would say that the spectroscopic test is more accurate
because there is less chance of human error.
DATA ANALYSIS

3. Suppose that you had used the same wooden splint to burn all the
salts in the flame. What difficulty could this have introduced?


A/= If we would had used the same wooden splint to burn all the
salts in the flame, we would have some remains of other salts in the
splint, making it a compound, and if that would happen the spectrum
would be different.
DATA ANALYSIS

 Helium was discovered in the sun before it was discovered on the
earth. How could this be?



 A/= Because it has a very low density, therefore it was not found
in the sea nor on the surface of the earth’s crust, not even in the
Atmosphere there was found a considerable amount of it.
CONCLUSIONS

 We concluded that there are two types of visible light spectra that can be
distinguished, emission and absorption.


 We can observe the wavelength of a light by using a diffraction grating
spectroscope.


 The bright lines that we see in the diffraction grating spectroscope are produced
when the atoms receive energy and the valence electrons get “excited”.

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  • 1. S U N S H I N E C H R I S T I A N B I L I N G UA L S C H O O L ANTONIO RODRÍGUEZ MR. JOSÉ POPOFF C H E M I S T RY L A B R E P O RT: E N E RG Y O F ELECTRONS 03/07/2013
  • 2. INTRODUCTION Electromagnetic Radiation  The characteristics of electromagnetic radiation are that energy can travel by a combination of an electrical and magnetic field, radiation means that it can travel through a vacuum. Emission spectrum shows bright lines or bands of color, this means that it emits or reflects the colors. Absorption spectrum has intermittent dark lines, so it means that it absorbs the colors.
  • 3. OBJECTIVES  Observe how a simply diffraction grating spectroscope works.  Observe and draw the spectra of several salts.
  • 4. MATERIALS  Bunsen Burner  Copper (II) Sulfate  Lithium Chloride  Color Pencils  Potassium Chloride  Diffraction Grating  Copper (III) Chloride Spectroscope  Sodium Chloride  Matches  Calcium Chloride  Presoaked Wood Splints  Weight Paper  Incandescent Light
  • 5. PROCEDURE 1. First I observed the incandescent light, which was hydrogen. I observed the incandescent light’s spectrum with the diffraction grating spectroscope. 2. We labeled 6 weight papers with the names of the salts, one salt per paper. 3. After that, we lighted the Bunsen burner and we adjusted it until we saw that the color of the flame was light blue or slightly colorless. 4. Then, we dipped one soaked wood strip into a salt and burned it in the Bunsen burner.
  • 6. PROCEDURE 5. We stared at the light emitted by the salts when being burned with de diffraction grating spectroscope. 6. After that, we filled in the data table with what we saw while doing the test. 7. We repeated step #4 with all the salts.
  • 13. DATA ANALYSIS 1. Since each element produces a characteristic spectrum, what can you conclude about the location of the electron?  A/= that the location of an electron affects the spectrum or “color” of the light.
  • 14. DATA ANALYSIS 2. If you had observed only the color if the flame as the salt burned, you would have conducted a flame test. Would you say that a flame test or a spectroscopic test is more accurate? Why?  A/= I would say that the spectroscopic test is more accurate because there is less chance of human error.
  • 15. DATA ANALYSIS 3. Suppose that you had used the same wooden splint to burn all the salts in the flame. What difficulty could this have introduced? A/= If we would had used the same wooden splint to burn all the salts in the flame, we would have some remains of other salts in the splint, making it a compound, and if that would happen the spectrum would be different.
  • 16. DATA ANALYSIS  Helium was discovered in the sun before it was discovered on the earth. How could this be?  A/= Because it has a very low density, therefore it was not found in the sea nor on the surface of the earth’s crust, not even in the Atmosphere there was found a considerable amount of it.
  • 17. CONCLUSIONS  We concluded that there are two types of visible light spectra that can be distinguished, emission and absorption.  We can observe the wavelength of a light by using a diffraction grating spectroscope.  The bright lines that we see in the diffraction grating spectroscope are produced when the atoms receive energy and the valence electrons get “excited”.