Timmy physics #1
- 1. Phys 101 Learning Object By Danilo Veljovic Calculating Maximum Velocity
- 2. Timmy is at a beach, and is being carried by a oscillating wave in the form Timmy’s father deduces that he is oscillating at a frequency of 3.0 hz.
- 3. A coastguard 200m away tells Timmy that his vision changes 6.7 degrees when Timmy moves from his lowest point to his highest point. 6.7
- 4. Determine Timmy’s Maxiumum Velocity.
- 5. First, we must find Timmy’s angular frequency (w). When given the frequency, this is simple. 3.0 hz w=(2)(pi)(3)=6pi
- 6. Next we must find Timmy’s amplitude. This can be found by using the coastguards information and some simple trigonometry. 200 6.7 2A Opp = Tan x Adj 2A = Tan(6.7) x (200) 2A =23.4946… A = 11.7 We must remark that the coastguard gave Timmy the angle between his lowest and highest point. Amplitude is the distance from the mid-point to the highest/lowest point, so we must divide this value by 2.
- 7. Max velocity = (w)(A) Max velocity = (6pi)(11.7) Max velocity = 221 m/s