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Tn hi?u, h? th?ng v ph?n gi?i m?ch 13

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Linh Tr?n L

- The document provides calculations to analyze an op-amp circuit: 1) Using a four-terminal network model, it derives the impedance matrix Z of the circuit. 2) It then adds a voltage source Vg and load impedance ZL, and derives an expression for the ratio of output voltage V2 to input voltage Vg. 3) Key steps include using node voltage equations, applying the virtual ground property of op-amps, and solving the resulting equations to obtain expressions for the impedance and voltage ratio.

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-H? v tn: Tr?n L Duy Linh. -MSSV: 18200032. - L?p : 18DTV1_L1. - Tu?n 13. Bi t?p c?ng c? bu?i 13. Trnh by: Cho m?ch sau, xem op-amp l l? t??ng, a. S? d?ng t? c?c, tm th?ng s? Z c?a m?ch. b. N?u g?n thm ngu?n (Vg, Zg) v t?i ZL. Tm ?? ?? ? R1 C V2 Re V1 Rf + - R2 Tm t?t bi lm: a. ? = ( ?11 ?12 ?21 ?22 ) = ( ?1 + 1 ?? 0 ??+?? ???? ?2 ) b. ?2 ? ? = ???21 (?11 + ??)( ?22 + ??) ? ?12?21 = ?? ?? + ?? ???? (?1 + 1 ?? + ??) (?2 + ??) I1 I2 I3 I3 V V
a. S? d?ng t? c?c, tm th?ng s? Z c?a m?ch: V?i ? = ( ?11 ?12 ?21 ?22 ) ?? ?: V1 = Z11I1 + Z21I2 V1 = I1R1 + I1 1 CS = (R1 + 1 CS ) I1 + 0 I2 Ta l?i c: V2 = Z21I1 + Z22I2 V2 = R2I2 + RfI3 + ReI3 = R2I2 + (Rf + Re)I3(1) { ? = ???3 ? = ?1 1 ?? => I3 = I1 1 ???? (2) Thay (2) vo (1) ta c : V2 = I2 + (Rf + Re) I1 ReCS = Rf + Re ReCS I1 + R2I2 V?y ? = ( ?11 ?12 ?21 ?22 ) = ( ?1 + 1 ?? 0 ?? + ?? ???? ?2 ) b. Tm V2 Vg ? ZL Zg Vg V1 V2 I2 I1
?2 ? ? = ???21 (?11 + ??)( ?22 + ??) ? ?12?21 = ?? ?? + ?? ???? (?1 + 1 ?? + ??) (?2 + ??)

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Tn hi?u, h? th?ng v ph?n gi?i m?ch 13

  • 1. -H? v tn: Tr?n L Duy Linh. -MSSV: 18200032. - L?p : 18DTV1_L1. - Tu?n 13. Bi t?p c?ng c? bu?i 13. Trnh by: Cho m?ch sau, xem op-amp l l? t??ng, a. S? d?ng t? c?c, tm th?ng s? Z c?a m?ch. b. N?u g?n thm ngu?n (Vg, Zg) v t?i ZL. Tm ?? ?? ? R1 C V2 Re V1 Rf + - R2 Tm t?t bi lm: a. ? = ( ?11 ?12 ?21 ?22 ) = ( ?1 + 1 ?? 0 ??+?? ???? ?2 ) b. ?2 ? ? = ???21 (?11 + ??)( ?22 + ??) ? ?12?21 = ?? ?? + ?? ???? (?1 + 1 ?? + ??) (?2 + ??) I1 I2 I3 I3 V V
  • 2. a. S? d?ng t? c?c, tm th?ng s? Z c?a m?ch: V?i ? = ( ?11 ?12 ?21 ?22 ) ?? ?: V1 = Z11I1 + Z21I2 V1 = I1R1 + I1 1 CS = (R1 + 1 CS ) I1 + 0 I2 Ta l?i c: V2 = Z21I1 + Z22I2 V2 = R2I2 + RfI3 + ReI3 = R2I2 + (Rf + Re)I3(1) { ? = ???3 ? = ?1 1 ?? => I3 = I1 1 ???? (2) Thay (2) vo (1) ta c : V2 = I2 + (Rf + Re) I1 ReCS = Rf + Re ReCS I1 + R2I2 V?y ? = ( ?11 ?12 ?21 ?22 ) = ( ?1 + 1 ?? 0 ?? + ?? ???? ?2 ) b. Tm V2 Vg ? ZL Zg Vg V1 V2 I2 I1
  • 3. ?2 ? ? = ???21 (?11 + ??)( ?22 + ??) ? ?12?21 = ?? ?? + ?? ???? (?1 + 1 ?? + ??) (?2 + ??)