Transportation Safety Valerie Hall
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This document discusses probabilities related to airplane crashes between 1966-2003 using data from the National Transportation Statistics. It provides examples of calculating the probability of not dying in a crash for 1980 and 1990 by subtracting fatal crashes from total flights. It also shows how to calculate the probability of dying in a crash in 2001 or 2003 by adding the individual year probabilities, as well as 1996 or 1997. Finally, it addresses finding the probability of the same number of crashes occurring in consecutive years by multiplying the total outcomes.
Transportation Safety Valerie Hall
- 1. Statistics of Transportation Safety By: Valerie Hall
- 2. Probability using not.What is the probability of not dying in a fatal airplane crash in 1980?
- 3. Answer There was a total of 5,479 airplane departures in 1980. Among these departures 19 airplanes crashed. The probability of being in a fatal accident in 1980 is 19/5,479. in order to find the probability of not crash you subtract 1 from 19/5,479 which is 5,460/5479.
- 4. Prbability using not.What is the probability of not dying in a fatal airplane crash in 1990?
- 5. AnswerThere was a total of 8,092 airplane departures in 1990. Among these departures 39 airplanes crashed. The probability of being in a fatal accident in 1990 is 39/8,092. In order to find the probability of not crash you subtract 1 from 39/8,092 which is 8053/8092.
- 6. Probability of two mutually exclusive events.What is the Probability of dying in a fatal airplane crash in 2001 or 2003?
- 7. AnswerThe probability of dying in a fatal airplane crash in 2001 is 92/11,468 and in 2003 was 22/10,508. in order to find the probability of to exclusively mutual situations you have to add the two probability. 92/11,468 plus 22/10,508 is .0101159659.
- 8. Probability of two mutually exclusive events.What is the probability of dying in a fatal airplane crash in 1997 or 1996?
- 9. AnswerThe probability of dying in a fatal airplane crash in 1996 is 380/8,229 and in 1997 was 8/10,980. In order to find the probability of to exclusively mutual situations you have to add the two probability.380/8,229 plus 8/10,980 is .0469067479.
- 10. Probability using andWhat is the probability of the same amount of crash will occur in a consecutive years (1966 and 1967)?
- 11. AnswerWhen finding the probability using add you multiply the total outcomes. 8,229 times 10,318 =84,906,822
- 12. Work citedNational Transportation Statisticshttp://www.bts.gov/publications/national_transportation_statistics/html/table_02_09.htmlBudge text Thinking Mathematically Third edition. Blitzer (pg.579-604)