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Copyright 息 John OConnor
St. Farnans PPS
Prosperous
For non-commercial purposes only.. Enjoy!
Vectors and Scalars
Comments/suggestions please to the SLSS physics website forum
@ http://physics.slss.ie/forum
 A scalar quantity is a quantity that has magnitude
only and has no direction in space
Examples of Scalar Quantities:
 Length
 Area
 Volume
 Time
 Mass
 A vector quantity is a quantity that has both
magnitude and a direction in space
Examples of Vector Quantities:
 Displacement
 Velocity
 Acceleration
 Force
 Vector diagrams are
shown using an arrow
 The length of the arrow
represents its
magnitude
 The direction of the
arrow shows its
direction
Vectors in opposite directions:
6 m s-1
10 m s-1
= 4 m s-1
6 N 10 N = 4 N
Vectors in the same direction:
6 N 4 N = 10 N
6 m
= 10 m
4 m
 The resultant is the sum or the combined effect of
two vector quantities
 When two vectors are joined tail
to tail
 Complete the parallelogram
 The resultant is found by
drawing the diagonal
 When two vectors are joined
head to tail
 Draw the resultant vector by
completing the triangle
Solution:
 Complete the parallelogram (rectangle)
慮
 The diagonal of the parallelogram ac represents the
resultant force
2004 HL Section B Q5 (a)
Two forces are applied to a body, as shown. What is the
magnitude and direction of the resultant force acting on the
body?
5N
12 N
5
12
a
b c
d
 The magnitude of the resultant is found using
Pythagoras Theorem on the triangle abc
N13
512Magnitude 22
=
+==
ac
ac
属==
=

67
5
12
tan
5
12
tan:ofDirection
1
慮
慮ac
 Resultant displacement is 13 N 67尊
with the 5 N force
13 N
45尊
5 N
90尊慮
Find the magnitude (correct to two decimal places) and direction
of the
resultant of the three forces shown below.
5N
5
5
Solution:
 Find the resultant of the two 5 N forces first (do right angles first)
a b
cd
N07.75055 22
==+=ac
属=== 451
5
5
tan 慮慮
7.07
N
10
N
135尊
 Now find the resultant of the 10 N and 7.07
N forces
 The 2 forces are in a straight line (45尊 + 135尊
= 180尊) and in opposite directions
 So, Resultant = 10 N  7.07 N = 2.93 N in
the direction of the 10 N force
2.93
N
 What is a scalar quantity?
 Give 2 examples
 What is a vector quantity?
 Give 2 examples
 How are vectors represented?
 What is the resultant of 2 vector quantities?
 What is the triangle law?
 What is the parallelogram law?
 When resolving a vector into
components we are doing the
opposite to finding the resultant
 We usually resolve a vector into
components that are perpendicular
to each other
y
v
x
 Here a vector v is resolved into an
x component and a y component
 Here we see a table
being pulled by a force of
50 N at a 30尊 angle to the
horizontal
 When resolved we see
that this is the same as
pulling the table up with a
force of 25 N and pulling
it horizontally with a force
of 43.3 N
50 Ny=25 N
x=43.3 N
30尊
 We can see that it
would be more
efficient to pull the
table with a horizontal
force of 50 N
 If a vector of magnitude v and makes an angle 慮 with the
horizontal then the magnitude of the components are:
 x = v Cos 慮
 y = v Sin 慮
v
y=v Sin 慮
x=v Cos 慮
慮
y
 Proof:
v
x
Cos =慮
慮vCosx =
v
y
Sin =慮
慮vSiny =
x
60尊
2002 HL Sample Paper Section B Q5 (a)
A force of 15 N acts on a box as shown. What is the horizontal
component of the force?
Vertical
Component
Horizontal
Component
Solution:
N5.76015ComponentHorizontal =属== Cosx
N99.126015ComponentVertical =属== Siny
15N
7.5 N
12.99N
 A person in a wheelchair is moving up a ramp at constant speed.
Their total weight is 900 N. The ramp makes an angle of 10尊 with
the horizontal. Calculate the force required to keep the wheelchair
moving at constant speed up the ramp. (You may ignore the
effects of friction).
Solution:
If the wheelchair is moving at constant speed (no acceleration), then the force
that moves it up the ramp must be the same as the component of its weight
parallel to the ramp.
10尊
10尊80尊
900 N
Complete the parallelogram.
Component of weight
parallel to ramp:
N28.15610900 =属= Sin
Component of weight
perpendicular to ramp:
N33.88610900 =属= Cos
156.28 N
886.33 N
2003 HL Section B Q6
 If a vector of magnitude v has two perpendicular
components x and y, and v makes and angle 慮
with the x component then the magnitude of the
components are:
 x= v Cos 慮
 y= v Sin 慮
v
y=v Sin 慮
x=v Cos慮
慮
y

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Vectorsandscalars

  • 1. Copyright 息 John OConnor St. Farnans PPS Prosperous For non-commercial purposes only.. Enjoy! Vectors and Scalars Comments/suggestions please to the SLSS physics website forum @ http://physics.slss.ie/forum
  • 2. A scalar quantity is a quantity that has magnitude only and has no direction in space Examples of Scalar Quantities: Length Area Volume Time Mass
  • 3. A vector quantity is a quantity that has both magnitude and a direction in space Examples of Vector Quantities: Displacement Velocity Acceleration Force
  • 4. Vector diagrams are shown using an arrow The length of the arrow represents its magnitude The direction of the arrow shows its direction
  • 5. Vectors in opposite directions: 6 m s-1 10 m s-1 = 4 m s-1 6 N 10 N = 4 N Vectors in the same direction: 6 N 4 N = 10 N 6 m = 10 m 4 m The resultant is the sum or the combined effect of two vector quantities
  • 6. When two vectors are joined tail to tail Complete the parallelogram The resultant is found by drawing the diagonal When two vectors are joined head to tail Draw the resultant vector by completing the triangle
  • 7. Solution: Complete the parallelogram (rectangle) 慮 The diagonal of the parallelogram ac represents the resultant force 2004 HL Section B Q5 (a) Two forces are applied to a body, as shown. What is the magnitude and direction of the resultant force acting on the body? 5N 12 N 5 12 a b c d The magnitude of the resultant is found using Pythagoras Theorem on the triangle abc N13 512Magnitude 22 = +== ac ac 属== = 67 5 12 tan 5 12 tan:ofDirection 1 慮 慮ac Resultant displacement is 13 N 67尊 with the 5 N force 13 N
  • 8. 45尊 5 N 90尊慮 Find the magnitude (correct to two decimal places) and direction of the resultant of the three forces shown below. 5N 5 5 Solution: Find the resultant of the two 5 N forces first (do right angles first) a b cd N07.75055 22 ==+=ac 属=== 451 5 5 tan 慮慮 7.07 N 10 N 135尊 Now find the resultant of the 10 N and 7.07 N forces The 2 forces are in a straight line (45尊 + 135尊 = 180尊) and in opposite directions So, Resultant = 10 N 7.07 N = 2.93 N in the direction of the 10 N force 2.93 N
  • 9. What is a scalar quantity? Give 2 examples What is a vector quantity? Give 2 examples How are vectors represented? What is the resultant of 2 vector quantities? What is the triangle law? What is the parallelogram law?
  • 10. When resolving a vector into components we are doing the opposite to finding the resultant We usually resolve a vector into components that are perpendicular to each other y v x Here a vector v is resolved into an x component and a y component
  • 11. Here we see a table being pulled by a force of 50 N at a 30尊 angle to the horizontal When resolved we see that this is the same as pulling the table up with a force of 25 N and pulling it horizontally with a force of 43.3 N 50 Ny=25 N x=43.3 N 30尊 We can see that it would be more efficient to pull the table with a horizontal force of 50 N
  • 12. If a vector of magnitude v and makes an angle 慮 with the horizontal then the magnitude of the components are: x = v Cos 慮 y = v Sin 慮 v y=v Sin 慮 x=v Cos 慮 慮 y Proof: v x Cos =慮 慮vCosx = v y Sin =慮 慮vSiny = x
  • 13. 60尊 2002 HL Sample Paper Section B Q5 (a) A force of 15 N acts on a box as shown. What is the horizontal component of the force? Vertical Component Horizontal Component Solution: N5.76015ComponentHorizontal =属== Cosx N99.126015ComponentVertical =属== Siny 15N 7.5 N 12.99N
  • 14. A person in a wheelchair is moving up a ramp at constant speed. Their total weight is 900 N. The ramp makes an angle of 10尊 with the horizontal. Calculate the force required to keep the wheelchair moving at constant speed up the ramp. (You may ignore the effects of friction). Solution: If the wheelchair is moving at constant speed (no acceleration), then the force that moves it up the ramp must be the same as the component of its weight parallel to the ramp. 10尊 10尊80尊 900 N Complete the parallelogram. Component of weight parallel to ramp: N28.15610900 =属= Sin Component of weight perpendicular to ramp: N33.88610900 =属= Cos 156.28 N 886.33 N 2003 HL Section B Q6
  • 15. If a vector of magnitude v has two perpendicular components x and y, and v makes and angle 慮 with the x component then the magnitude of the components are: x= v Cos 慮 y= v Sin 慮 v y=v Sin 慮 x=v Cos慮 慮 y