This tutorial sheet contains 5 problems related to engineering mechanics:
1) Calculating the height of a tower given that two stones dropped from different heights on the tower reach the ground at the same time.
2) Determining the height above a higher point from which a body must have started falling to pass two points 20m apart vertically in 0.4 seconds.
3) Finding the magnitude of velocity and acceleration of a particle moving in a curvilinear motion at a given time.
4) Calculating the time difference between hits of a target by bullets shot from two guns at different angles but the same range and velocity.
5) Deriving an expression for the height of a point given that a particle
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Mechanics 7.docx suman anand
1. SKIT, JAIPUR.
SUBJECT : ENGINEERING MECHANICS SESSION2014-15
TUTORIAL SHEET NO: 7 DATE OF SUBMISSION: 15/04/15
1) When a stone has fallen a distance x after being dropped from the top of tower , another stone is
dropped from a distance y below the top of tower .If both reach the ground together , shown that the
height of the tower is (x+y)2
/4x. [RTU 2008]
2) A body fallinffreely under the action of gravity passes two points 20 m apart vertically in 0.4 sec, from
what height above higher point did body starts fall. [RTU 2010]
3) A particle moving in a curvilinear motion has coordinates.
x= 2t2
-4t
y= 3t2
-t3
/3
Determine the magnitude of velocity and acceleration at time t= 2 sec. [RTU 2011]
4) Two adjacent guns having shot the bullets at a velocity of 300 m/s simultaneously at angles a1 and a2
for the same target at a range of 5.6 km. Calculate the time difference between the hits.[RTU 2008]
5) A particle isprojectedandduringitsprojectilemotionitreachatheighthin time t1.Againit reachat this
height at time t2 taken from start. Show that the height of point is ? gt1t2. [RTU 2011]
![SKIT, JAIPUR.
SUBJECT : ENGINEERING MECHANICS SESSION2014-15
TUTORIAL SHEET NO: 7 DATE OF SUBMISSION: 15/04/15
1) When a stone has fallen a distance x after being dropped from the top of tower , another stone is
dropped from a distance y below the top of tower .If both reach the ground together , shown that the
height of the tower is (x+y)2
/4x. [RTU 2008]
2) A body fallinffreely under the action of gravity passes two points 20 m apart vertically in 0.4 sec, from
what height above higher point did body starts fall. [RTU 2010]
3) A particle moving in a curvilinear motion has coordinates.
x= 2t2
-4t
y= 3t2
-t3
/3
Determine the magnitude of velocity and acceleration at time t= 2 sec. [RTU 2011]
4) Two adjacent guns having shot the bullets at a velocity of 300 m/s simultaneously at angles a1 and a2
for the same target at a range of 5.6 km. Calculate the time difference between the hits.[RTU 2008]
5) A particle isprojectedandduringitsprojectilemotionitreachatheighthin time t1.Againit reachat this
height at time t2 taken from start. Show that the height of point is ? gt1t2. [RTU 2011]](https://image.slidesharecdn.com/mechanics7-150424020629-conversion-gate02/85/Mechanics-7-docx-suman-anand-1-320.jpg)