Mommentum and cm
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The document discusses linear momentum, impulse, and the conservation of momentum. It defines linear momentum as the product of an object's mass and velocity. Impulse is defined as the change in an object's momentum due to an applied force. Conservation of momentum states that if the total external force on a closed system is zero, the total momentum of the system does not change. The document also discusses the coefficient of restitution and center of mass calculations.
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Mommentum and cm
- 3. 10/10/2016 3 The linear momentum of a particle or an object that can be modeled as a particle of mass (m) moving with a velocity (v) is defined to be the product of the mass and velocity: p=mv The impulse of the force F acting on a particle equals the change in the momentum of the particle. Ft=m
- 4. 10/10/2016 4 CONSERVATION OF MOMENTUM Conservation of momentum is a fundamental law of physics which states that the momentum of a system is constant if there are no external forces acting on the system. It is embodied in Newton's first law (the law of inertia). SCIENCEWORLD
- 5. 10/10/2016 5 Conservation of Momentum for a System of Objects Internal forces have absolutely no effect on the net momentum of a system. If the net external force acting on a system is zero, its net momentum is conserved. That is,
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- 8. 10/10/2016 8 COEFFICIENT OF RESTITUTION How much bounce! The ration between the relative speeds = Perfectly elastic = , perfectly inelastic = , =
- 9. 10/10/2016 9 A tennis ball dropped on the floor from a height of 100 cm rebounds to a height of 60 cm. Find the coefficient of restitution.
- 10. 10/10/2016 10 Center of Mass The center of mass of a system of masses is the point where the system can be balanced in a uniform gravitational field.
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- 12. 10/10/2016 12 Suppose the masses are separated by 0.500 m, and that m1 = 0.260 kg and m2=0.170 kg. What is the distance from m1 to the center of mass of the system? = 11 + 22 1 + 2 = 0.260 0 + 0.170(.500) 0.260 + 0.170 = 0.198
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- 15. 10/10/2016 15 A persons arm is held with the upper arm vertical, the lower arm and hand horizontal. (a) Find the center of mass of the arm in this configuration, given the following data: The upper arm has a mass of 2.5 kg and a center of mass 0.18 m above the elbow; the lower arm has a mass of 1.6 kg and a center of mass 0.12 m to the right of the elbow; the hand has a mass of 0.64 kg and a center of mass 0.40 m to the right of the elbow. (b) A 0.14-kg baseball is placed on the palm of the hand. If the diameter of the ball is 7.4 cm, find the center of mass of the armball system.
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- 17. 10/10/2016 17 A 59-kg woman and a 71-kg man sit on a seesaw, 3.5 m long. Where is their center of mass?
- 18. 10/10/2016 18 A uniform carpenter's square has the shape of an L, as shown in the figure. Locate the center of mass relative to the origin of the coordinate system.
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