This document lists several types of fruit including orange, banana, apple, kiwi, pomegranate, pear, grapes, strawberry, pineapple, apricot, and peach.
The document contains mathematical equations and calculations. It begins with setting up the equation 123x54 and proceeds to work through the steps to solve for the answer. It ultimately calculates the solution as 6642.
This document lists several types of fruit including orange, banana, apple, kiwi, pomegranate, pear, grapes, strawberry, pineapple, apricot, and peach.
The document contains mathematical equations and calculations. It begins with setting up the equation 123x54 and proceeds to work through the steps to solve for the answer. It ultimately calculates the solution as 6642.
3. 族辿続巽続孫単続湛. 続鱈損 鱈続 叩探続叩探損単 奸媼奸娟娶媾妍婉侫妍 続晛単損谷損単, 揃単損
続続奪続誰続谷続 続単孫叩探湛損単. b
a
b s2 b
a
a
s1 b
s2 =..
a
b
s1 =..
a a
a s4
b s3 b
a
b
s3 =. s4=..
4. 続坦損 叩探続叩探損単 奸媼奸娟娶媾妍婉侫姆 鱈続 即叩鱈` 谷誰続続叩鱈 婀侫 奸媼奸媚妍婉
奸媼奸娟娶媾妍婉 :
族辿続巽続孫単続湛.続鱈損 続辿続巽続坦続 湛続辿続杦探谷叩探 続晛単損谷` s-
a b
辰続誰続谷続-------------
b s3 s2 b
a s1 s4
a
a b
5. 続鱈損` s s s s 1 + 2 + 3 + 4
=..
a b
b s3 s2 b
辰続誰続谷続.
a s1 s4 a 族辿続巽続坦続 湛続辿続杦探谷叩探 続晛単損谷
`..
a b
7. 族奪続坦叩探坦
s1 = a2
s 2 = b2
s1 + s2 + s3 + s4 = a2 + b2 + ab + ab (1)
s3 = ab
s4 = ab
損 湛続辿続杦探谷叩探 続晛単損谷` s = (a + b ) x ( a + b ) = (a + b ) 2 . (2)
1. 即 2. 続単孫叩探湛損単 続鱈続谷続単損坦損叩鱈
(a + b )2 = a2 + b2 + ab + ab
= a2 + 2ab + b2
`(a + b ) 2 = a2 + 2ab + b
8. 埀婬姜婀 奸婪奸娶侫婉 a2- b2=(a+b)(a-b) 妁奸婉奸娜姆 婉娶婬婉 婀侫姨娶佞娶嫋
続単坦`
a 杦叩鱈 湛続辿続杦探谷叩探 続晛単損谷 揃誰続単?
a
奪続誰続谷続.
a a
a
9. 続叩単孫 湛続辿続杦探谷叩探 損巽 続巽続誰損湛 b 杦叩鱈 湛続辿続杦探谷
a
其誰損 b 杦叩鱈 湛続辿続杦探谷叩探 続晛単損谷
a
b 奪続誰続谷続:..
b b
b
10. 損 湛続辿続杦探谷叩探坦 枙単損 即 続辿続続坦損 b a
杦叩鱈 湛続辿続杦探谷 a
s1 ab
a
b s2 b
b
ab
続鱈損湛 谷誰続坦鱈続 奪続誰晛単
続単坦. 達 多 続鱈続谷続単 谷誰続坦鱈続 続晛単損谷 続 袖続続損叩鱈 損単杦探
奪続誰晛単 続晛単損谷: 叩探続叩探損単` s1 即 s2
族 続鱈続谷続単 多 `..
s1=..
s2=
s1 + s2 =.
族単孫叩探湛損単 続損続誰損
11. 嘆叩探坦叩探損単 `続続晛単誰
損 湛続辿続杦探谷叩探 続. a x a = a2
旦叩湛単 湛続辿続杦探谷叩探 続. b x b = b2
損 湛続辿続杦探谷叩探坦 歎叩湛単 枙単損叩鱈, 谷誰続坦鱈続
奪続誰晛単 続.`a2 - b2 (1)
孫続叩探単 続単誰続孫単達 続損叩鱈
(a +b)
s1=(a b) x a
枑誰続続湛`
s2=(a b) x b a2 b2 =(a +b) x (a b)
s1 + s2 =(a b ) x a + (a b) x b (2)
1 即 2 続単孫叩探湛損単 続鱈続谷続単損坦損湛
a2 b2 = ( a b) x a + (a b ) x b
= a2 _ ab + ab - b2
= a2 + ab - ab - b2
=a(a +b) b(a +b)
12. 族奪続坦叩探坦損湛 (a b)2 = a2- 2.ab + b2
a 杦叩鱈 湛続辿続杦探谷 袖続続損湛 続谷損単 損誰即続 晛単奪
a
a a
a
13. 1.続鱈損 谷誰続坦鱈続 奪続誰晛単損単 続晛単損谷損単
b
(a b)
(a b) a
(a b)
b
s1=...............
S1 s2:.......................... s3:..........................
. .
14. 2.其誰損 谷誰続坦鱈続 奪続誰晛単 杦 即 続鱈損 続晛単損谷:
(a b)
b
(a b)
a S=
b
(a b) b
賊達 奪続誰晛単 多 谷誰続坦鱈叩探
15. 族奪続坦叩探坦.
1.S1=(a b) . (a - b ) = (a b )2
S2=a . b
S3=(a b) . b = a . b -b2
2. 其誰損湛 谷誰続坦鱈続 奪続誰晛単 杦`
(a b) + b = a b +b = a
即 続鱈損湛 続晛単損谷`S=a.a = a2
3.s1+s2+s3=s 続鱈続谷続単叩探叩探坦 杦探損続湛
(a b )2 + a.b + a . b -b2 = a2
4.損誰即続袖続単
(a b )2 = a2- 2.ab + b2