![畉i h畛c Hu畉 H畛 v t棚n:................................
Tr動畛ng 畉i h畛c S動 ph畉m S畛 b叩o danh:............................
畛 KI畛M TRA GI畛A K
M担n: Tin h畛c 畛ng d畛ng
L畛p Cao h畛c Gi畉i t鱈ch 畛ng nai, 畛 s畛 1
Th畛i gian lm bi: 60 ph炭t.
D湛ng c叩c l畛nh c畛a Maple 畛 th畛c hi畛n c叩c c担ng vi畛c sau:
C但u 1. T鱈nh t鱈ch ph但n hai l畛p
D
(x + cos(y + 1))exy+3y2x2
dxdy,
v畛i D l mi畛n x叩c 畛nh b畛i c叩c b畉t ph動董ng tr狸nh y 1 x 1 y2
.
C但u 2. T鱈nh 畛nh th畛c
2 3 12
5 4
4 12
2 6
3 4 21
.
C但u 3. V畉 畛 th畛 hm s畛 sau tr棚n o畉n [1, 2]:
f(x) =
錚
錚器２
錚器３
x2
1, x < 0,
cos x, 0 x 1,
3|2x 1|, x > 1.](https://image.slidesharecdn.com/demapletex-141231020848-conversion-gate01/85/De-mapletex-1-320.jpg)
![畉i h畛c Hu畉 H畛 v t棚n:................................
Tr動畛ng 畉i h畛c S動 ph畉m S畛 b叩o danh:............................
畛 KI畛M TRA GI畛A K
M担n: Tin h畛c 畛ng d畛ng
L畛p Cao h畛c Gi畉i t鱈ch 畛ng nai, 畛 s畛 2
Th畛i gian lm bi: 60 ph炭t.
D湛ng c叩c l畛nh c畛a Maple 畛 th畛c hi畛n c叩c c担ng vi畛c sau:
C但u 1. T鱈nh t鱈ch ph但n hai l畛p
D
(x + sin(y + 1))exy+3y2x2
dxdy,
v畛i D l mi畛n x叩c 畛nh b畛i c叩c b畉t ph動董ng tr狸nh x2
2 y x.
C但u 2. V畉 畛 th畛 c畛a hm s畛 sau tr棚n o畉n [0, 3]:
f(x) =
2x
1 x
x 1 2
2 3
.
C但u 3. Gi畉i h畛 ph動董ng tr狸nh vi ph但n
錚
錚器２
錚器３
x
(t) = 3x(t) + 11y(t) z(t),
y
(t) = x(t) + 4y(t) + 2z(t),
z
(t) = x(t).
v畛i i畛u ki畛n 畉u: x(0) = y(0) = 0, z(0) = 1.](https://image.slidesharecdn.com/demapletex-141231020848-conversion-gate01/85/De-mapletex-2-320.jpg)
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De mapletex
- 1. 畉i h畛c Hu畉 H畛 v t棚n:................................ Tr動畛ng 畉i h畛c S動 ph畉m S畛 b叩o danh:............................ 畛 KI畛M TRA GI畛A K M担n: Tin h畛c 畛ng d畛ng L畛p Cao h畛c Gi畉i t鱈ch 畛ng nai, 畛 s畛 1 Th畛i gian lm bi: 60 ph炭t. D湛ng c叩c l畛nh c畛a Maple 畛 th畛c hi畛n c叩c c担ng vi畛c sau: C但u 1. T鱈nh t鱈ch ph但n hai l畛p D (x + cos(y + 1))exy+3y2x2 dxdy, v畛i D l mi畛n x叩c 畛nh b畛i c叩c b畉t ph動董ng tr狸nh y 1 x 1 y2 . C但u 2. T鱈nh 畛nh th畛c 2 3 12 5 4 4 12 2 6 3 4 21 . C但u 3. V畉 畛 th畛 hm s畛 sau tr棚n o畉n [1, 2]: f(x) = 錚 錚器２ 錚器３ x2 1, x < 0, cos x, 0 x 1, 3|2x 1|, x > 1.
- 2. 畉i h畛c Hu畉 H畛 v t棚n:................................ Tr動畛ng 畉i h畛c S動 ph畉m S畛 b叩o danh:............................ 畛 KI畛M TRA GI畛A K M担n: Tin h畛c 畛ng d畛ng L畛p Cao h畛c Gi畉i t鱈ch 畛ng nai, 畛 s畛 2 Th畛i gian lm bi: 60 ph炭t. D湛ng c叩c l畛nh c畛a Maple 畛 th畛c hi畛n c叩c c担ng vi畛c sau: C但u 1. T鱈nh t鱈ch ph但n hai l畛p D (x + sin(y + 1))exy+3y2x2 dxdy, v畛i D l mi畛n x叩c 畛nh b畛i c叩c b畉t ph動董ng tr狸nh x2 2 y x. C但u 2. V畉 畛 th畛 c畛a hm s畛 sau tr棚n o畉n [0, 3]: f(x) = 2x 1 x x 1 2 2 3 . C但u 3. Gi畉i h畛 ph動董ng tr狸nh vi ph但n 錚 錚器２ 錚器３ x (t) = 3x(t) + 11y(t) z(t), y (t) = x(t) + 4y(t) + 2z(t), z (t) = x(t). v畛i i畛u ki畛n 畉u: x(0) = y(0) = 0, z(0) = 1.