Electrostatics
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This document provides an introduction to electrostatics and discusses electric charges, atomic structure, early theories of electricity from Thales and Franklin, conduction and insulation, Coulomb's law for electrostatic force between two charges, and examples of calculating electrostatic force and potential. It defines key terms like electrostatics, charge, proton, electron, conductor, insulator, and Coulomb's law. Diagrams and examples throughout illustrate electrostatic concepts and their applications.
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This document discusses atomic structure and properties related to electrons and subatomic particles. It begins by defining the atom and its main components: protons, neutrons, and electrons. It then discusses isotopes and the behavior of subatomic particles in electric fields. The document goes on to explain electronic configuration, ionization energy, and factors that influence ionization energy such as atomic radius, nuclear charge, and shielding effects. Trends in ionization energy across periods and down groups in the periodic table are also summarized.Temperature changes problems
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1) The rod consists of two portions made of different materials joined together. When the temperature increases by 50属C, a compressive force of 142.55 kN is induced in the rod.
2) A 0.5 mm gap exists in an aluminum bar at 24属C. The temperature at which the stress in the bar will be -75 MPa is 94.2属C. The length of the aluminum bar at this temperature is 0.45027m.F.Sc.1.Chemistry.Ch.5.Numericals (Malik Xufyan)
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The document summarizes key concepts from atomic structure including:
- Bohr's model of the hydrogen atom and calculations of energy levels, radii of orbits, and ionization energies using his equations.
- Energy levels and differences between levels are higher for He+ than hydrogen due to its higher nuclear charge.
- Spectral lines of He+ will appear at different wavelengths than hydrogen due to its different energy level structure.
- Calculations using Bohr's equations agree well with experimental ionization energy values for hydrogen and He+.Base excitation of dynamic systems
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This document discusses base excitation in vibration analysis and provides examples. It begins by introducing base excitation as an important class of vibration analysis that involves preventing vibrations from passing through a vibrating base into a structure. Examples of base excitation include vibrations in cars, satellites, and buildings during earthquakes. The document then provides mathematical models and equations to analyze single degree of freedom base excitation systems. Graphs of transmissibility ratios are presented and examples are worked through, such as calculating car vibration amplitude at different speeds. Rotating unbalance is also covered as another source of vibration excitation.W ee network_theory_10-06-17_ls2-sol
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The document discusses various problems involving binomial coefficients through combinatorial methods and integral calculus. It begins by proving 10 identities involving binomial coefficients using properties of binomial expressions. It then presents 10 additional problems for students to prove, involving further identities with binomial coefficients. Finally, it provides 4 problems for students to prove similar identities using integral calculus methods, involving integrating binomial expressions.Chemistry (F.Sc.1) Chapter # 05 Numericals- Malik Xufyan
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The document provides solutions to numerical problems regarding photons and the Bohr model of the hydrogen atom. Key points:
- A photon with energy 10-19 J is converted to a wavelength of 1.98810-6 m, frequency of 1.5091014 Hz, and wave number of 5.030105 m-1.
- Bohr's formula for energy levels of hydrogen is En = -2.1810-18/n2 J. The ionization energies of hydrogen and He+ are calculated to be 2.1810-18 J and 8.7210-18 J respectively using this formula.
- Spectral lines are classified based on the orbitAd
Electrostatics
- 2. (e) (ion)
- 7. Charges -
- 8. Atomic Structure (nucleus) : (Proton) (Neutron) (Electron)
- 12. 1. 2.
- 13. 2 leather
- 14. 2
- 16. Conclusion :
- 17. Diagram : + - + - - + - + + - + - + - + - - + - + + - + - Heat + + + + + + - - - - - -
- 19. Conclusion : 1
- 20. Conclusion :
- 21. Diagram : +4 -8 -2 -2 + + + + - - - - - - - - -4 -4 -4
- 28. Conclusion : 2 : :
- 29. Diagram : - + - + - + - + + + + + + - + - + - + - - - - -
- 32. (Electroscope)
- 39. Electroscope
- 40. Electroscope
- 41. Electroscope + - + - + + - - - - - - + ++ + :
- 42. Electroscope
- 44. Example A B C . A C B . A C B . A C B . A C B
- 45. Solution B A C A C B B
- 46. Example
- 47. Solution 2 3 5 4
- 48. Example
- 49. Solution
- 50. 1. 2. 3. 4.
- 51. Charles Augustus Coulomb 1 2 2 KQ Q F R
- 52. 1 2 2 KQ Q F R
- 55. Example
- 57. Example x
- 58. Example + . x C . x C cm + . x C
- 59. SOLUTION A BC +5x10-6 C -3x10-6 C+1x10-6 C 20 cm 10 cm
- 60. SOLUTION A BC +5x10-6 C -3x10-6 C+1x10-6 C 20 cm 10 cm FAC
- 61. SOLUTION A BC +5x10-6 C -3x10-6 C+1x10-6 C 20 cm 10 cm
- 62. SOLUTION A BC +5x10-6 C -3x10-6 C+1x10-6 C 20 cm 10 cm FBC
- 63. SOLUTION A BC +5x10-6 C -3x10-6 C+1x10-6 C 20 cm 10 cm FBC FAC
- 65. q Q Q q
- 68. + -
- 76. q qEF q F E 緒 緒
- 77. Q Q (q) 2 21 R QKQ F qEF 2 r KQq qE 2 r KQ E 緒
- 78. 1. 2. NOTE
- 79. 3 m A : 3x10-3 C SOLUTION B : 2x10-3 C C : -8x10-3 C 2 m
- 80. 3 m A : 3x10-3 C SOLUTION B : +1 C : -8x10-3 C 2 m
- 81. 3 m A : 3x10-3 C SOLUTION B : +1 C : -8x10-3 C 2 m EA
- 82. 3 m A : 3x10-3 C SOLUTION B : +1 C : -8x10-3 C 2 m EC
- 84. Example e- 9 x 1031 kg 1.6 x 1019 c 3 x 104 N/c . e- . e-
- 85. SOLUTION
- 86. Example 2 10 37
- 89. Example X10-5 kg C cm/s2 g = 9.8 m/s2
- 90. + a = 20 cm/s2 mg E qE SOLUTION
- 91. + a = 20 cm/s2 mg E qE SOLUTION
- 92. 0E
- 93. A : +3 C B: +3 C
- 94. A : +3 C B: +6 C
- 95. A : -3 C B: -3 C
- 96. A : -3 C B: -6 C
- 97. A : +3 C B: -6 C
- 98. A : -3 C B: +6 C
- 99. A : +4x10-8 C B : +9x10-8 C 0.5 m x (0.5 x)
- 100. a
- 101. E = 0 2 r KQ E 2. a KQ Esurf )/( CNE -a +a0 a
- 102. m m 5 m System I
- 103. m m U = 0 U = 10 m/s System II
- 105. Charge ; Q q R F = qE
- 106. Ep q V V
- 107. +Q x R1 y R2 Vx Vy +10 V +5 V
- 108. -Q x R1 y R2 Vx Vy -10 V -5 V
- 109. - Q Q - Q Q - - Q Q Q -
- 110. V X Y + Q r -Q r
- 112. Q x 30 cm y 70 cm Vx Ey = 3500 N/c
- 116. C B : -3x10-4 C A : +3x10-4 C
- 117. a VA A a B (VB a KQ V r KQ VB
- 118. V = V r KQ V a KQ V )(voltV -a +a0 a B A r
- 120. E q B A d d A B E WA速B = qEd
- 121. q Q q A B Q r r BA F r1 r2 WA速B = EB - EA
- 122. WA速B = qVB -qVA WA速B = EB - EA WA速B = q(VB -VA ) WA速B = qVBA
- 123. V d E (V/m) VAB A B (V) d (m) A B d V )( BAAB VVqW 緒 )( BA VVqqEd EdVV BA 緒 d V E AB
- 124. 犖. 犖. r KQ V qEdW )( BAAB VVqW 緒 AA qVW 緒 radius KQ VV surfaceinside 緒
- 125. Q : +10x10-6 C 10 cm 10 cm 10 cm A BC