Beats
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Beats occur due to the interference of waves with different frequencies. To find the resulting beat wave, the principle of superposition is used to add the two waves together using a specific formula. Beats are important in music as varying the frequencies creates different genres by interfering waves. The beat frequency is the difference between the frequencies of the interfering waves. When this difference is small, a single combined wave is heard, but two distinct tones are heard when the difference is large.
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Other Link :
1.Introduction to computer network - /slideshow/lecture-notes-introduction-to-computer-network/274183454
2. Physical Layer - /slideshow/lecture-notes-unit-ii-the-physical-layer/274747125
3. Data Link Layer Part 1 : /slideshow/lecture-notes-unit-iii-the-datalink-layer/275288798
Target Audience:
Final year B.Sc. Computer Science students at Alagappa University seeking a solid foundation in Computer Network principles for academic.
About the Author:
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Beats
- 1. E D I E Y E BEATS
- 2. BEATS • Beats are caused by the interference of waves that have different frequencies • To find the resulting wave of the beat, we use the principle of superposition to add the two waves
- 3. PRINCIPLE OF SUPERPOSITION • To add the waves we use the formula: s(0, t) = 2 sm cos(-ϖt)cos(Δϖt), where ϖ is the mean angular frequency and Δϖt is the angular frequency difference
- 4. CONNECTION • What is a purpose of beats? • A purpose of beats is the formation of music using waves that have different frequencies. Similar to how increasing the music on your iPod increases the amplitude of the wave, the formation of the distinct genres of music such as EDM Ii.e. electronic dance music) comes from the different frequencies of the waves interfering.
- 5. BEAT FREQUENCY • The beat frequency is the frequency difference between interfering waves • When this frequency is large, we hear two distinct tones but when it is small, we only hear one combined wave
- 6. CLICKER 1 • The period of wave one is 0.002 seconds and the period of wave two is 0.002008 seconds. Which of the frequencies are the highest and what beat frequency would we expect to hear if the waves were played simultaneously?
- 7. CLICKER 1 • a. wave one; 2 • b. wave one; -2 • c. wave two; 2 • d. wave two; -2 • e. can’t tell from information given
- 8. CLICKER 1 EXPLAINED • Even without calculation we can tell that frequency of wave one has a higher frequency as period and frequency are inversely proportional and wave one has a shorter period. From the options available, we can see that the frequency is either positive two or negative two, but because frequency can not be negative as it is function of time we can conclude that the answer is 2, thus the final answer is a. • Calculation of wave one: 1/ 0.002 = 500 Hz • Calculation of wave two: 1/0.002008 =498 Hz • Calculation of beat frequency: 500 Hz – 498 Hz = 2Hz
- 9. CLICKER 2 • A 300 Hz tone and a 304 Hz tone are played simultaneously over a period of five seconds. How many beats can we expect to hear?
- 10. CLICKER 2 • a. 4 • b. 8 • c. 12 • d. 16 • e. 20
- 11. CLICKER 2 • We first calculate the beat frequency which is 304 Hz- 300Hz =4Hz and then multiply by the duration (i.e. 5 seconds) to get 20 beats over the time frame.
- 12. CLICKER 3 • The beat frequency of a source is 1 Hz. The tone of one source is 100 Hz. What can we expect the frequency of the other source to be?
- 13. CLICKER 3 • a. 99 • b. 100 • c. 101 • d. 99 Hz or 101 Hz • e. 100 Hz or 101 Hz
- 14. CLICKER 3 EXPLAINED • Given the beat frequency of one Hz and the frequency of 100 for one tone we can see that there are two possible answers for the second tone. This is because the frequency is an absolute value and |99-100|would give us one Hz and |101-100 | would give us one Hz as well thus the answer is d.
- 15. THANK YOU FOR WATCHING
- 16. WORKS CITED • Hawkes, Robert, Javed Iqbal, Firas Mansour, Marina-Bolotin, and Peter Williams. Physics for Scientists and Engineers. Vol. 1. : Nelson, n.d. Print.