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PLD 
THI?T B? LOGIC L?P TR?NH ???C 
(Programmable Logic Device) 
NguyenTrongLuat 
1
BO? NH?? BA?N 
DA?N 
Bo? nh?¨´ ba¨´n da?n 
Bo? nh?¨´ ba?ng Bo? nh?¨´ ha?m 
RAM ROM 
t¨®nh ?o?ng MROM 
PROM 
EPROM 
EEPRO 
M 
PLD 
PLAPALLCA 
PPA 
LEPLPA 
LEEPPAL 
EPL 
D 
PEELGAL 
NguyenTrongLuat 
2
BO? NH?? ROM 
Input: ca¨´c t¨ªn hie?u ?¨°a ch? (Address) 
Output: ca¨´c t¨ªn hie?u d?? lie?u (Data) 
A0 
A1 
An-1 
D0 
D1 
Dm-1 
INPUT 
(n ????ng) 
OUTPUT 
(m ????ng) 
K¨ªch th??¨´c ROM: 2n x m (bit) 
NguyenTrongLuat 
3
word line 
bit 
line 
101 
1 
0 
1 
1 
1 
1 
1 
0 
1 
1 
1 
Ba?ng na?p ROM 
A2 A1 
0 
1 
0 
0 
A0 
D3 D2 D1 
0 0 D0 
0 
0 0 
1 
0 1 
0 
0 1 
1 
1 0 
0 
1 0 
1 
1 1 
0 
1 1 
1 
1 1 1 
0 1 1 0 
1 1 0 1 
1 0 1 1 
1 0 0 0 
1 0 0 1 
0 0 1 0 
0 1 0 0 
0 
Ca¨¢u tru¨´c no?i ROM 8 x 
4 (bit) 
1 
NguyenTrongLuat 
4
ROM 128 x 1 (bit) gia?i ma? 
2 chie¨¤u 
NguyenTrongLuat 
5
ROM 32K x 8 (bit) = 32KB 
NguyenTrongLuat 
6
Ca¨¢u tru¨´c ROM co¨´ ngo? va?o 
?ie¨¤u khie?n 
NguyenTrongLuat 
7
Co?ng ?e?m ba tra?ng tha¨´i (Tristate Output 
Buffer): 
3 tra?ng tha¨´i (tristate): LOW / HIGH / HIGH impedance 
Tra?ng tha¨´i to?ng tr?? cao (HIGH impedance): ngo? ra h?? ma?ch 
- Ngo? ?ie¨¤u khie?n 3 tra?ng tha¨´i: 
* HIGH: The buffer is Active 
* LOW: HIGH 
impedance 
NguyenTrongLuat 
8
Ca¨´c EPROM tho?ng du?ng 
NguyenTrongLuat 
9
PLA 
(PROGRAMMABLE LOGIC 
ARRAY) 
INPUT 
(n bit) 
OUTPUT 
(m bit) 
k product term (so¨¢ 
ha?ng t¨ªch) 
Da?y 
AND 
Da?y 
OR 
NguyenTrongLuat 
10
Da?y AND co¨´ the? la?p 
tr¨¬nh 
Da?y OR co¨´ the? la?p 
tr¨¬nh 
NguyenTrongLuat 
11
A Ca¨¢u tru¨´c PLA 3 x 2, 4 so¨¢ 
F1 = A B + A C + A B 
CF2 = A C + B C 
0 
1 
ha?ng t¨ªch 
B 
C 
C C B B A A 
A B 
A C 
B C 
A B 
C 
F1 
F2 
Ba?ng na?p 
PLA A B C F2 (C) F1 
(T) 
1 0 
- 
A B 
A C 1 - 
B C 1- 1 
A B 1 
C 
0 1 
0 
0 
11 
11 
00 
NguyenTrongLuat 1 
12
PAL 
(PROGRAMMABLE ARRAY 
LOGIC ) 
- Da?y AND la?p tr¨¬nh, da?y OR co¨¢ ?¨°nh 
- Mo?i ngo? ra la? co?ng OR co¨´ so¨¢ ngo? va?o 
co¨¢ ?¨°nh 
- So¨¢ ha?ng t¨ªch kho?ng s?? du?ng chung cho ca¨´c 
ngo? ra 
- Ca¨¢u tru¨´c PLA: so¨¢ ngo? va?o, so¨¢ ngo? ra va? 
so¨¢ co?ng AND tre?n 1 co?ng OR 
NguyenTrongLuat 
13
Ca¨¢u tru¨´c PAL 3 ngo? va?o, 3 ngo? ra, 3 
co?ng AND / OR 
1 
2 
3 
4 
5 
6 
7 
8 
9 
I1 
I2 
I3 
F1 
F2 
F3 
NguyenTrongLuat 
14
A 
1 
2 
3 
4 
5 
6 
7 
8 
9 
B 
C 
X 
Y 
Z 
A A B B C C X X 
X = A B + 
B C 
Z = A B + B C + B C + 
A C 
Y = A + B C 
= X + B C + A C 
NguyenTrongLuat 
15
X = A B + 
B C 
Z = A B + B C + B C + 
A C 
Y = A + B C 
= X + B C + A C 
Ba?ng na?p 
PAL 
A B C 
X 
OUTPUT 
X = A B 
+ B 
C 
1 1 
1 1 
0 Y = A 
0 0 
+ B C 
Z = X 
1 0 0 
+ B C 
0 1 
+ A C 
1 
2 
3 
4 
56 
7 
8 
9 
NguyenTrongLuat 
16
Ad

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Kts c5-pld

  • 1. PLD THI?T B? LOGIC L?P TR?NH ???C (Programmable Logic Device) NguyenTrongLuat 1
  • 2. BO? NH?? BA?N DA?N Bo? nh?¨´ ba¨´n da?n Bo? nh?¨´ ba?ng Bo? nh?¨´ ha?m RAM ROM t¨®nh ?o?ng MROM PROM EPROM EEPRO M PLD PLAPALLCA PPA LEPLPA LEEPPAL EPL D PEELGAL NguyenTrongLuat 2
  • 3. BO? NH?? ROM Input: ca¨´c t¨ªn hie?u ?¨°a ch? (Address) Output: ca¨´c t¨ªn hie?u d?? lie?u (Data) A0 A1 An-1 D0 D1 Dm-1 INPUT (n ????ng) OUTPUT (m ????ng) K¨ªch th??¨´c ROM: 2n x m (bit) NguyenTrongLuat 3
  • 4. word line bit line 101 1 0 1 1 1 1 1 0 1 1 1 Ba?ng na?p ROM A2 A1 0 1 0 0 A0 D3 D2 D1 0 0 D0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 1 1 1 0 1 1 0 1 1 0 1 1 0 1 1 1 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 Ca¨¢u tru¨´c no?i ROM 8 x 4 (bit) 1 NguyenTrongLuat 4
  • 5. ROM 128 x 1 (bit) gia?i ma? 2 chie¨¤u NguyenTrongLuat 5
  • 6. ROM 32K x 8 (bit) = 32KB NguyenTrongLuat 6
  • 7. Ca¨¢u tru¨´c ROM co¨´ ngo? va?o ?ie¨¤u khie?n NguyenTrongLuat 7
  • 8. Co?ng ?e?m ba tra?ng tha¨´i (Tristate Output Buffer): 3 tra?ng tha¨´i (tristate): LOW / HIGH / HIGH impedance Tra?ng tha¨´i to?ng tr?? cao (HIGH impedance): ngo? ra h?? ma?ch - Ngo? ?ie¨¤u khie?n 3 tra?ng tha¨´i: * HIGH: The buffer is Active * LOW: HIGH impedance NguyenTrongLuat 8
  • 9. Ca¨´c EPROM tho?ng du?ng NguyenTrongLuat 9
  • 10. PLA (PROGRAMMABLE LOGIC ARRAY) INPUT (n bit) OUTPUT (m bit) k product term (so¨¢ ha?ng t¨ªch) Da?y AND Da?y OR NguyenTrongLuat 10
  • 11. Da?y AND co¨´ the? la?p tr¨¬nh Da?y OR co¨´ the? la?p tr¨¬nh NguyenTrongLuat 11
  • 12. A Ca¨¢u tru¨´c PLA 3 x 2, 4 so¨¢ F1 = A B + A C + A B CF2 = A C + B C 0 1 ha?ng t¨ªch B C C C B B A A A B A C B C A B C F1 F2 Ba?ng na?p PLA A B C F2 (C) F1 (T) 1 0 - A B A C 1 - B C 1- 1 A B 1 C 0 1 0 0 11 11 00 NguyenTrongLuat 1 12
  • 13. PAL (PROGRAMMABLE ARRAY LOGIC ) - Da?y AND la?p tr¨¬nh, da?y OR co¨¢ ?¨°nh - Mo?i ngo? ra la? co?ng OR co¨´ so¨¢ ngo? va?o co¨¢ ?¨°nh - So¨¢ ha?ng t¨ªch kho?ng s?? du?ng chung cho ca¨´c ngo? ra - Ca¨¢u tru¨´c PLA: so¨¢ ngo? va?o, so¨¢ ngo? ra va? so¨¢ co?ng AND tre?n 1 co?ng OR NguyenTrongLuat 13
  • 14. Ca¨¢u tru¨´c PAL 3 ngo? va?o, 3 ngo? ra, 3 co?ng AND / OR 1 2 3 4 5 6 7 8 9 I1 I2 I3 F1 F2 F3 NguyenTrongLuat 14
  • 15. A 1 2 3 4 5 6 7 8 9 B C X Y Z A A B B C C X X X = A B + B C Z = A B + B C + B C + A C Y = A + B C = X + B C + A C NguyenTrongLuat 15
  • 16. X = A B + B C Z = A B + B C + B C + A C Y = A + B C = X + B C + A C Ba?ng na?p PAL A B C X OUTPUT X = A B + B C 1 1 1 1 0 Y = A 0 0 + B C Z = X 1 0 0 + B C 0 1 + A C 1 2 3 4 56 7 8 9 NguyenTrongLuat 16