際際滷

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Masters in Electrical & Microsystems
Engineering
Advanced Engineering Mathematics
Linear Systems Electric AC Circuit
Presented by:
Nima Aminfar (3362365)
Omer Rahama (3359754)
Solving Linear system of equations Mathematics.pdf.pptx
By applying Kirchhoff `s current law for points 1,2,3
腫4
腫1 腫2 腫3
腫5
腫6
腫1 腫2
腫1  腫1腫4= 0
腫2 + 腫1 腫5 腫2 = 0
腫3 + 腫2腫6= 0
腫1 = +  1 1
腫2 = +  2 2
腫3 = +  3 3
腫4 = 1  0 4
腫5 = 2  0 5
腫6 = 3  0 6
By applying Ohm's law:
V=X*I , Y=
1

I=V*Y
腫1 = (12) 1
腫2 = (23) 2
+  1 1 - (12) 1- 1  0 4 = 0
+  2 2 + (12) 1- 2  0 5 (23) 2 = 0
+  3 3 + (23) 2  3  0 6 = 0
1 = 1 ゐ
2 = 2 ゐ
3 = 3 ゐ
+ = + ゐ
And we know that :
1 =
1
1
=
1
1
=
1
103 2 =
1
2
=
1
2
=
1
2103
3 =
1
3
=
1
3
=
1
103 4=
1
4
=
1
4
=
1
2103
5 =
1
5
=
1
5
=
1
103 6 =
1
6
=
1
6
=
1
2103
1 =
1
1
= ゐ1 =   1000  106
=   103
2 =
1
2
= ゐ2 =   1000  0.5  106=   0.5  103
Admittance Calculation:
Three linear equation would be: 瑞 瑞 瑞 are unknown
(1.5 + )*1 + (-i)*2 + (0)*3= 3
()*1 + (1.5 + 1.5 )*2 + (- 0.5 )*3= 1.5
0 1 + (  0.5)2 + (1.5 + 0.5)3= 3
So the matrix will be:
=
*
(.  + )
X1 = 1.69369  0.162162 i
-
瑞
0
瑞
 (.  + .  ) .  
0 -0.  (.  + .  )
3
1.5
3
瑞
X2= 1.45045 + (0.297297) i X3= 1.85586  (0.135135) i
Gaussian elimination Method:
 Gauss Elimination Method is a procedure for solving systems of linear equation. It is also known as Row
Reduction Technique.
 In this method, the problem of systems of linear equation having n unknown variables, matrix having rows
n and columns n+1 is formed. This matrix is also known as Augmented Matrix.
 After forming n x n+1 matrix, matrix is transformed to upper triangular matrix by row operations. Finally
result is obtained by Back Substitution.
 In this project, we are dealing with 3 unknown variables . So the Augmented Matrix would be 3*4.
Definition Of Complex
Numbers
Enter The Value Of
The Matrix
Check 1st
diagonal is
zero
Gauss Elimination Can
Not Performed
Check The
Determina
nt is Zero
Gauss Elimination Can
Not Performed
Start
End
End
Proceed To Enter
Vector b
Print The Values Of
V1, V2, V3 and Phases
in degree
Print The Values Of
1, 2, 3
End
Flowchart Of The Program:
Yes
Yes
No
No
Start The Gauss
Elimination Process
Determinant calculation for 3*3 Matrix:

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Solving Linear system of equations Mathematics.pdf.pptx

  • 1. Masters in Electrical & Microsystems Engineering Advanced Engineering Mathematics Linear Systems Electric AC Circuit Presented by: Nima Aminfar (3362365) Omer Rahama (3359754)
  • 3. By applying Kirchhoff `s current law for points 1,2,3 腫4 腫1 腫2 腫3 腫5 腫6 腫1 腫2 腫1 腫1腫4= 0 腫2 + 腫1 腫5 腫2 = 0 腫3 + 腫2腫6= 0
  • 4. 腫1 = + 1 1 腫2 = + 2 2 腫3 = + 3 3 腫4 = 1 0 4 腫5 = 2 0 5 腫6 = 3 0 6 By applying Ohm's law: V=X*I , Y= 1 I=V*Y 腫1 = (12) 1 腫2 = (23) 2
  • 5. + 1 1 - (12) 1- 1 0 4 = 0 + 2 2 + (12) 1- 2 0 5 (23) 2 = 0 + 3 3 + (23) 2 3 0 6 = 0 1 = 1 ゐ 2 = 2 ゐ 3 = 3 ゐ + = + ゐ And we know that :
  • 6. 1 = 1 1 = 1 1 = 1 103 2 = 1 2 = 1 2 = 1 2103 3 = 1 3 = 1 3 = 1 103 4= 1 4 = 1 4 = 1 2103 5 = 1 5 = 1 5 = 1 103 6 = 1 6 = 1 6 = 1 2103 1 = 1 1 = ゐ1 = 1000 106 = 103 2 = 1 2 = ゐ2 = 1000 0.5 106= 0.5 103 Admittance Calculation:
  • 7. Three linear equation would be: 瑞 瑞 瑞 are unknown (1.5 + )*1 + (-i)*2 + (0)*3= 3 ()*1 + (1.5 + 1.5 )*2 + (- 0.5 )*3= 1.5 0 1 + ( 0.5)2 + (1.5 + 0.5)3= 3
  • 8. So the matrix will be: = * (. + ) X1 = 1.69369 0.162162 i - 瑞 0 瑞 (. + . ) . 0 -0. (. + . ) 3 1.5 3 瑞 X2= 1.45045 + (0.297297) i X3= 1.85586 (0.135135) i
  • 9. Gaussian elimination Method: Gauss Elimination Method is a procedure for solving systems of linear equation. It is also known as Row Reduction Technique. In this method, the problem of systems of linear equation having n unknown variables, matrix having rows n and columns n+1 is formed. This matrix is also known as Augmented Matrix. After forming n x n+1 matrix, matrix is transformed to upper triangular matrix by row operations. Finally result is obtained by Back Substitution. In this project, we are dealing with 3 unknown variables . So the Augmented Matrix would be 3*4.
  • 10. Definition Of Complex Numbers Enter The Value Of The Matrix Check 1st diagonal is zero Gauss Elimination Can Not Performed Check The Determina nt is Zero Gauss Elimination Can Not Performed Start End End Proceed To Enter Vector b Print The Values Of V1, V2, V3 and Phases in degree Print The Values Of 1, 2, 3 End Flowchart Of The Program: Yes Yes No No Start The Gauss Elimination Process