This document provides information on calculating surface area and volume for various 3D shapes including prisms, cylinders, pyramids and more. It defines key terms like surface area, volume, and includes formulas and examples for finding the surface area and volume of rectangular and triangular prisms, cylinders, and pyramids using measurements of lengths, widths, heights, radii, etc. Practice problems are provided throughout for additional examples of calculating surface area and volume.
This document provides information on calculating surface area and volume for various 3D shapes including prisms, cylinders, pyramids and more. It defines key terms like surface area, volume, and includes formulas and examples for finding the surface area and volume of rectangular and triangular prisms, cylinders, and pyramids using measurements of lengths, widths, heights, radii, etc. Practice problems are provided throughout for additional examples of calculating surface area and volume.
This document provides information about calculating the surface area and volume of various 3D shapes including prisms, cylinders, pyramids, and cones. It defines surface area as the total area of the object's surface that would be needed to wrap the entire shape. Various formulas are given to calculate the surface area and volume of different shapes by breaking them down into their 2D components and using the appropriate equations.
This geometry module covers calculating the surface area of various 3D shapes. Students will learn to find the surface area of cubes, prisms, pyramids, cylinders, cones, and spheres. The document provides examples and practice problems for students to test their understanding of surface area calculations for different solids.
1. The document lists 6 student ID numbers.
2. It provides definitions and formulas for calculating the surface area and volume of cylinders, including examples of working through sample problems.
3. It also defines what a circle is and provides formulas for calculating the area of a circle and sectors.
1. The document lists the names and student IDs of 6 students.
2. It provides definitions and formulas for calculating the surface area and volume of cylinders. Examples of calculations for the surface area and volume of cylinders with given radii and heights are shown.
3. Formulas and explanations for calculating the area of circles and sectors are provided, along with examples of calculations.
Area and Circumference.pptxArea and Circumference.pptxArea and Circumference....ladylouisecunananmer
油
Area and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptx
This document discusses perimeter, area, and volume. It begins by defining perimeter as the distance around a shape found by adding all the side lengths. It provides examples of calculating perimeters of rectangles, irregular shapes, and converting between units. It then defines area as a measure of how much surface a shape covers. It gives formulas and examples for finding the areas of rectangles, triangles, parallelograms, trapezoids, and irregular shapes. Finally, it discusses surface area as the total area of all faces of a shape. It provides the surface area formulas and worked examples for cuboids and cubes.
Surface Area_Volume of Solid Figures.pptLuisSalenga1
油
The document provides information about calculating the surface area of cylinders and cones. It begins by defining a cylinder and its components. It then derives the formula for the surface area of a cylinder by imagining unrolling the cylinder surface. The formula is presented as SA=2r(r+h). An example problem applying this formula is shown. Methods for finding the surface area of cones are also presented, with the formula given as the area of the base plus the lateral area. Several examples problems demonstrate applying the surface area formulas for cylinders and cones.
Here are the steps to solve this problem:
1) Area of square = s^2 = 4^2 = 16 cm^2
2) Area of shaded region 1 = 1/2 * 4 * 4 = 8 cm^2
3) Area of shaded region 2 = 1/4 * 4 * 4 = 4 cm^2
So the total area of the shaded regions is 8 + 4 = 12 cm^2.
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The document provides information about calculating geometric properties of circles such as circumference, area, perimeter and area of sectors, as well as the volumes of cylinders. It includes formulas, examples of calculations, and multiple choice questions to test understanding. Key formulas covered include circumference = x diameter, area of a circle = x radius^2, area of a sector = (angle of sector/360) x x radius^2, and volume of a cylinder = area of base x height. The document provides a review of foundational circle geometry concepts through examples, practice questions, and matching definitions to geometric terms.
Basic formula for Shapes - Area and Volume and SurfaeSurendra Rao
油
The document provides formulas and examples for calculating the surface areas and volumes of various geometric shapes including rectangular prisms, cubes, cylinders, spheres, cones, pyramids, and irregular shapes. Formulas are given for surface area and volume of each shape using measurements of lengths, widths, heights, radii, and other defining variables. Step-by-step worked examples demonstrate applying the formulas to specific geometric objects.
SYLLABUS FOR UNIT TEST- II TRIGONOMETRY-TRIGONOMETRIC RATIOS, SINE RULE, C...ShaniyaAbdulsamad
油
SYLLABUS FOR UNIT TEST- II
TRIGONOMETRY-TRIGONOMETRIC RATIOS,
SINE RULE,
COSINE RULE,
AREA OFTRIANGLE,
BEARINGS,
ANGLES OF ELEVATION AND DEPRESSION,
THREE-DIMENSIONALTRIGONOMETRY,
GRAPHS OF TRIGONOMETRIC FUNCTIONS,
SOLVING TRIGONOMETRICEQUATIONS
SYLLABUS FOR UNIT TEST- II TRIGONOMETRY-TRIGONOMETRIC RATIOS, SINE RULE, C...ShaniyaAbdulsamad
油
SYLLABUS FOR UNIT TEST- II
TRIGONOMETRY-TRIGONOMETRIC RATIOS,
SINE RULE,
COSINE RULE,
AREA OFTRIANGLE,
BEARINGS,
ANGLES OF ELEVATION AND DEPRESSION,
THREE-DIMENSIONALTRIGONOMETRY,
GRAPHS OF TRIGONOMETRIC FUNCTIONS,
SOLVING TRIGONOMETRICEQUATIONS
TRIGONOMETRY-TRIGONOMETRIC RATIOS, SINE RULE, COSINE RULE, AREA OFTRIANGLE...ShaniyaAbdulsamad
油
TRIGONOMETRY-TRIGONOMETRIC RATIOS,
SINE RULE,
COSINE RULE,
AREA OFTRIANGLE,
BEARINGS,
ANGLES OF ELEVATION AND DEPRESSION,
THREE-DIMENSIONALTRIGONOMETRY,
GRAPHS OF TRIGONOMETRIC FUNCTIONS,
SOLVING TRIGONOMETRICEQUATIONS
- A quadrilateral is a four-sided polygon. There are several types of quadrilaterals defined by their properties: square, rectangle, parallelogram, rhombus, trapezoid, kite, and irregular quadrilateral.
- The sum of the interior angles of any quadrilateral is always 360 degrees.
- Formulas are provided to calculate the perimeter and area of each quadrilateral type based on given side lengths or angles. This includes using side lengths, base and height, diagonals, and trigonometric functions like sine.
- An irregular quadrilateral can be divided into two triangles to calculate its total area using the individual triangle area formulas.
- A quadrilateral is a four-sided polygon. There are several types of quadrilaterals defined by their properties: square, rectangle, parallelogram, rhombus, trapezoid, kite, and irregular quadrilateral.
- The sum of the interior angles of any quadrilateral is always 360 degrees.
- Formulas are provided to calculate the perimeter and area of each quadrilateral type based on given side lengths or angles. This includes using side lengths, base and height, diagonals, and trigonometric functions like sine.
- An irregular quadrilateral can be divided into two triangles and their individual areas calculated using formulas like Heron's formula and added to find the total area.
- A quadrilateral is a four-sided polygon. There are several types of quadrilaterals defined by their properties: square, rectangle, parallelogram, rhombus, trapezoid, kite, and irregular quadrilateral.
- The sum of the interior angles of any quadrilateral is always 360 degrees.
- Formulas are provided to calculate the perimeter and area of different quadrilaterals depending on given side lengths or angles. This includes formulas for square, rectangle, parallelogram, rhombus, trapezoid, kite, and methods described to find the area of an irregular quadrilateral by dividing it into triangles.
- A cyclic quadrilateral has the special property
This document provides an introduction to basic geometry concepts including:
- Euclid's undefined terms of point, line, and plane
- Definitions of basic shapes such as rays, line segments, angles, and polygons
- Classifications of quadrilaterals and regular polygons
- Formulas for calculating perimeter and area of common shapes like triangles, rectangles, parallelograms, trapezoids, circles, and composite figures
- Examples of using definitions and formulas to solve perimeter and area problems for single and composite geometric shapes.
- A quadrilateral is a four-sided polygon.
- There are different types of quadrilaterals defined by their properties, including squares, rectangles, parallelograms, trapezoids, rhombuses, kites, and irregular quadrilaterals.
- The area of each type of quadrilateral is calculated using a specific formula related to its defining properties, such as side lengths, angles, or diagonals. For example, the area of a rectangle is length x width, and the area of a parallelogram is base x height.
- An irregular quadrilateral requires calculating the areas of the two triangles formed by its diagonal and adding them together.
This document contains information about geometry concepts including circles, special right triangles, and regular polygons. It provides formulas to find the area and circumference of circles using the radius or diameter. It also gives the formula for finding the area of a regular polygon using the apothem and central angle. Several examples show how to apply these formulas to calculate missing values for various circles and polygons.
Power point presentationof class 9 maths HERONS FORMULAshouvikdash35
油
This document provides an overview of Heron's formula for calculating the area of a triangle given the lengths of its three sides. It begins with examples of finding the area of right triangles, equilateral triangles, and isosceles triangles by calculating the height. It then introduces Heron's formula, which allows calculating the area directly from the side lengths. The document provides examples of applying the formula to find the areas of various triangles. It concludes by explaining how Heron's formula can be used when the height is difficult to determine.
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Area and Circumference.pptxArea and Circumference.pptxArea and Circumference....ladylouisecunananmer
油
Area and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptxArea and Circumference.pptx
This document discusses perimeter, area, and volume. It begins by defining perimeter as the distance around a shape found by adding all the side lengths. It provides examples of calculating perimeters of rectangles, irregular shapes, and converting between units. It then defines area as a measure of how much surface a shape covers. It gives formulas and examples for finding the areas of rectangles, triangles, parallelograms, trapezoids, and irregular shapes. Finally, it discusses surface area as the total area of all faces of a shape. It provides the surface area formulas and worked examples for cuboids and cubes.
Surface Area_Volume of Solid Figures.pptLuisSalenga1
油
The document provides information about calculating the surface area of cylinders and cones. It begins by defining a cylinder and its components. It then derives the formula for the surface area of a cylinder by imagining unrolling the cylinder surface. The formula is presented as SA=2r(r+h). An example problem applying this formula is shown. Methods for finding the surface area of cones are also presented, with the formula given as the area of the base plus the lateral area. Several examples problems demonstrate applying the surface area formulas for cylinders and cones.
Here are the steps to solve this problem:
1) Area of square = s^2 = 4^2 = 16 cm^2
2) Area of shaded region 1 = 1/2 * 4 * 4 = 8 cm^2
3) Area of shaded region 2 = 1/4 * 4 * 4 = 4 cm^2
So the total area of the shaded regions is 8 + 4 = 12 cm^2.
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The document provides information about calculating geometric properties of circles such as circumference, area, perimeter and area of sectors, as well as the volumes of cylinders. It includes formulas, examples of calculations, and multiple choice questions to test understanding. Key formulas covered include circumference = x diameter, area of a circle = x radius^2, area of a sector = (angle of sector/360) x x radius^2, and volume of a cylinder = area of base x height. The document provides a review of foundational circle geometry concepts through examples, practice questions, and matching definitions to geometric terms.
Basic formula for Shapes - Area and Volume and SurfaeSurendra Rao
油
The document provides formulas and examples for calculating the surface areas and volumes of various geometric shapes including rectangular prisms, cubes, cylinders, spheres, cones, pyramids, and irregular shapes. Formulas are given for surface area and volume of each shape using measurements of lengths, widths, heights, radii, and other defining variables. Step-by-step worked examples demonstrate applying the formulas to specific geometric objects.
SYLLABUS FOR UNIT TEST- II TRIGONOMETRY-TRIGONOMETRIC RATIOS, SINE RULE, C...ShaniyaAbdulsamad
油
SYLLABUS FOR UNIT TEST- II
TRIGONOMETRY-TRIGONOMETRIC RATIOS,
SINE RULE,
COSINE RULE,
AREA OFTRIANGLE,
BEARINGS,
ANGLES OF ELEVATION AND DEPRESSION,
THREE-DIMENSIONALTRIGONOMETRY,
GRAPHS OF TRIGONOMETRIC FUNCTIONS,
SOLVING TRIGONOMETRICEQUATIONS
SYLLABUS FOR UNIT TEST- II TRIGONOMETRY-TRIGONOMETRIC RATIOS, SINE RULE, C...ShaniyaAbdulsamad
油
SYLLABUS FOR UNIT TEST- II
TRIGONOMETRY-TRIGONOMETRIC RATIOS,
SINE RULE,
COSINE RULE,
AREA OFTRIANGLE,
BEARINGS,
ANGLES OF ELEVATION AND DEPRESSION,
THREE-DIMENSIONALTRIGONOMETRY,
GRAPHS OF TRIGONOMETRIC FUNCTIONS,
SOLVING TRIGONOMETRICEQUATIONS
TRIGONOMETRY-TRIGONOMETRIC RATIOS, SINE RULE, COSINE RULE, AREA OFTRIANGLE...ShaniyaAbdulsamad
油
TRIGONOMETRY-TRIGONOMETRIC RATIOS,
SINE RULE,
COSINE RULE,
AREA OFTRIANGLE,
BEARINGS,
ANGLES OF ELEVATION AND DEPRESSION,
THREE-DIMENSIONALTRIGONOMETRY,
GRAPHS OF TRIGONOMETRIC FUNCTIONS,
SOLVING TRIGONOMETRICEQUATIONS
- A quadrilateral is a four-sided polygon. There are several types of quadrilaterals defined by their properties: square, rectangle, parallelogram, rhombus, trapezoid, kite, and irregular quadrilateral.
- The sum of the interior angles of any quadrilateral is always 360 degrees.
- Formulas are provided to calculate the perimeter and area of each quadrilateral type based on given side lengths or angles. This includes using side lengths, base and height, diagonals, and trigonometric functions like sine.
- An irregular quadrilateral can be divided into two triangles to calculate its total area using the individual triangle area formulas.
- A quadrilateral is a four-sided polygon. There are several types of quadrilaterals defined by their properties: square, rectangle, parallelogram, rhombus, trapezoid, kite, and irregular quadrilateral.
- The sum of the interior angles of any quadrilateral is always 360 degrees.
- Formulas are provided to calculate the perimeter and area of each quadrilateral type based on given side lengths or angles. This includes using side lengths, base and height, diagonals, and trigonometric functions like sine.
- An irregular quadrilateral can be divided into two triangles and their individual areas calculated using formulas like Heron's formula and added to find the total area.
- A quadrilateral is a four-sided polygon. There are several types of quadrilaterals defined by their properties: square, rectangle, parallelogram, rhombus, trapezoid, kite, and irregular quadrilateral.
- The sum of the interior angles of any quadrilateral is always 360 degrees.
- Formulas are provided to calculate the perimeter and area of different quadrilaterals depending on given side lengths or angles. This includes formulas for square, rectangle, parallelogram, rhombus, trapezoid, kite, and methods described to find the area of an irregular quadrilateral by dividing it into triangles.
- A cyclic quadrilateral has the special property
This document provides an introduction to basic geometry concepts including:
- Euclid's undefined terms of point, line, and plane
- Definitions of basic shapes such as rays, line segments, angles, and polygons
- Classifications of quadrilaterals and regular polygons
- Formulas for calculating perimeter and area of common shapes like triangles, rectangles, parallelograms, trapezoids, circles, and composite figures
- Examples of using definitions and formulas to solve perimeter and area problems for single and composite geometric shapes.
- A quadrilateral is a four-sided polygon.
- There are different types of quadrilaterals defined by their properties, including squares, rectangles, parallelograms, trapezoids, rhombuses, kites, and irregular quadrilaterals.
- The area of each type of quadrilateral is calculated using a specific formula related to its defining properties, such as side lengths, angles, or diagonals. For example, the area of a rectangle is length x width, and the area of a parallelogram is base x height.
- An irregular quadrilateral requires calculating the areas of the two triangles formed by its diagonal and adding them together.
This document contains information about geometry concepts including circles, special right triangles, and regular polygons. It provides formulas to find the area and circumference of circles using the radius or diameter. It also gives the formula for finding the area of a regular polygon using the apothem and central angle. Several examples show how to apply these formulas to calculate missing values for various circles and polygons.
Power point presentationof class 9 maths HERONS FORMULAshouvikdash35
油
This document provides an overview of Heron's formula for calculating the area of a triangle given the lengths of its three sides. It begins with examples of finding the area of right triangles, equilateral triangles, and isosceles triangles by calculating the height. It then introduces Heron's formula, which allows calculating the area directly from the side lengths. The document provides examples of applying the formula to find the areas of various triangles. It concludes by explaining how Heron's formula can be used when the height is difficult to determine.
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UNIT 6 Factoring and Distributing Expressions _2_.pptxAreejAhmed38
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UNIT 6 Factoring and Distributing Expressions _2_.pptx
UNIT 6 Factoring and Distributing Expressions _2_.pptx
UNIT 6 Factoring and Distributing Expressions _2_.pptx
UNIT 6 Factoring and Distributing Expressions _2_.pptx
The document explains the order of operations (PEMDAS) for solving math problems with multiple operations:
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2) Evaluate exponents next, from left to right.
3) Multiply and divide from left to right.
4) Add and subtract from left to right.
Several examples are provided to demonstrate how to use PEMDAS to evaluate expressions step-by-step.
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Information Technology for class X CBSE skill SubjectVEENAKSHI PATHAK
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These questions are based on cbse booklet for 10th class information technology subject code 402. these questions are sufficient for exam for first lesion. This subject give benefit to students and good marks. if any student weak in one main subject it can replace with these marks.
2. Surface Area of Prisms
Surface Area of Prisms
Surface Area
Surface Area = The total area of the surface of a
= The total area of the surface of a
three-dimensional object
three-dimensional object
(Or think of it as the amount of paper youll need to
(Or think of it as the amount of paper youll need to
wrap the shape.)
wrap the shape.)
Prism
Prism =
= A solid object that has two identical ends and
A solid object that has two identical ends and
all flat sides.
all flat sides.
We will start with 2 prisms a
We will start with 2 prisms a rectangular prism
rectangular prism and
and
a
a triangular prism.
triangular prism.
6. Add the area of all 6 sides to find the Surface
Add the area of all 6 sides to find the Surface
Area.
Area.
10 - length
5 - width
6 - height
7. SA = 2lw + 2lh + 2wh
SA = 2lw + 2lh + 2wh
10 - length
5 - width
6 - height
SA = 2lw + 2lh + 2wh
SA = 2 (10 x 5) + 2 (10 x 6) + 2 (5 x 6)
= 2 (50) + 2(60) + 2(30)
= 100 + 120 + 60
= 280 units squared
8. Practice
Practice
10 ft
12 ft
22 ft
SA = 2lw + 2lh + 2wh
= 2(22 x 10) + 2(22 x 12) + 2(10 x 12)
= 2(220) + 2(264) + 2(120)
= 440 + 528 + 240
= 1208 ft squared
9. Surface Area of a Triangular Prism
Surface Area of a Triangular Prism
2 bases
(triangular)
3 sides
(rectangular)
10. Unfolded net of a triangular prism
Unfolded net of a triangular prism
11. 2(area of triangle) + Area of
2(area of triangle) + Area of
rectangles
rectangles
15ft
Area Triangles = 遜 (b x h)
= 遜 (12 x 15)
= 遜 (180)
= 90
Area Rect. 1 = b x h
= 12 x 25
= 300
Area Rect. 2 = 25 x 20
= 500
SA = 90 + 90 + 300 + 500
+ 500
SA = 1480 ft squared
12. Practice
Practice
10 cm
8 cm
9 cm
7 cm
Triangles = 遜 (b x h)
= 遜 (8 x 7)
= 遜 (56)
= 28 cm
Rectangle 1 = 10 x 8
= 80 cm
Rectangle 2 = 9 x 10
= 90 cm
Add them all up
SA = 28 + 28 + 80 + 90 + 90
SA = 316 cm squared
14. Review
Review
Surface area is like the amount of
paper youll need to wrap the shape.
You have to take apart the shape
and figure the area of the parts.
Then add them together for the
Surface Area (SA)
15. Parts of a cylinder
Parts of a cylinder
A cylinder has 2 main parts.
A rectangle
and
A circle well, 2 circles
really.
Put together they make a
cylinder.
16. The Soup Can
The Soup Can
Think of the Cylinder as a soup can.
Think of the Cylinder as a soup can.
You have the top and bottom lid
You have the top and bottom lid
(
(circles
circles) and you have the label (a
) and you have the label (a
rectangle
rectangle wrapped around the
wrapped around the
can).
can).
The lids and the label are related.
The lids and the label are related.
The circumference of the lid is the
The circumference of the lid is the
same as the length of the label.
same as the length of the label.
17. Area of the Circles
Area of the Circles
Formula for Area of Circle
Formula for Area of Circle
A=
A= r
r2
2
= 3.14 x 3
= 3.14 x 32
2
= 3.14 x 9
= 3.14 x 9
= 28.26
= 28.26
But there are 2 of them so
But there are 2 of them so
28.26 x 2 = 56.52 units squared
28.26 x 2 = 56.52 units squared
18. The Rectangle
The Rectangle
This has 2 steps. To find the
area we need base and
height. Height is given (6)
but the base is not as easy.
Notice that the base is the
same as the distance around
the circle (or the
Circumference).
19. Find Circumference
Find Circumference
Formula is
Formula is
C =
C = x d
x d
= 3.14 x 6 (radius doubled)
= 3.14 x 6 (radius doubled)
= 18.84
= 18.84
Now use that as your base.
Now use that as your base.
A = b x h
A = b x h
= 18.84 x 6 (the height given)
= 18.84 x 6 (the height given)
= 113.04 units squared
= 113.04 units squared
20. Add them together
Add them together
Now add the area of the circles and
Now add the area of the circles and
the area of the rectangle
the area of the rectangle
together.
together.
56.52 + 113.04 = 169.56 units
56.52 + 113.04 = 169.56 units
squared
squared
The total Surface Area!
The total Surface Area!
21. Formula
Formula
SA = (
SA = ( d x h) + 2 (
d x h) + 2 ( r
r2
2
)
)
Label
Label Lids (2)
Lids (2)
Area of Rectangle Area of Circles
Area of Rectangle Area of Circles
22. Practice
Practice
Be sure you know the difference between a radius and a diameter!
Be sure you know the difference between a radius and a diameter!
SA = (
SA = ( d x h) + 2 (
d x h) + 2 ( r
r2
2
)
)
= (3.14 x 22 x 14) + 2 (3.14 x 11
= (3.14 x 22 x 14) + 2 (3.14 x 112
2
)
)
= (367.12) + 2 (3.14 x 121)
= (367.12) + 2 (3.14 x 121)
= (367.12) + 2 (379.94)
= (367.12) + 2 (379.94)
= (367.12) + (759.88)
= (367.12) + (759.88)
= 1127 cm
= 1127 cm2
2
23. More Practice!
More Practice!
SA
SA = (
= ( d x h) + 2 (
d x h) + 2 ( r
r2
2
)
)
= (3.14 x 11 x 7) + 2 ( 3.14 x 5.5
= (3.14 x 11 x 7) + 2 ( 3.14 x 5.52
2
)
)
= (241.78) + 2 (3.14 x 30.25)
= (241.78) + 2 (3.14 x 30.25)
= (241.78) + 2 (3.14 x 94.99)
= (241.78) + 2 (3.14 x 94.99)
= (241.78) + 2 (298.27)
= (241.78) + 2 (298.27)
= (241.78) + (596.54)
= (241.78) + (596.54)
=
= 838.32 cm
838.32 cm2
2
11 cm
7 cm
25. Pyramid Nets
Pyramid Nets
A pyramid has 2
A pyramid has 2
shapes:
shapes:
One (1) square
One (1) square
&
&
Four (4) triangles
Four (4) triangles
26. Since you know how to find the
Since you know how to find the
areas of those shapes and add
areas of those shapes and add
them.
them.
Or
Or
27. you can use a formula
you can use a formula
SA = 遜 lp + B
Where l is the Slant Height and
p is the perimeter and
B is the area of the Base
28. SA = 遜 lp + B
6
7
8
5
Perimeter = (2 x 7) + (2 x 6) = 26
Slant height l = 8 ;
SA = 遜 lp + B
= 遜 (8 x 26) + (7 x 6) *area of the base*
= 遜 (208) + (42)
= 104 + 42
= 146 units 2
29. Practice
Practice
6
6
18
10
SA = 遜 lp + B
= 遜 (18 x 24) + (6 x 6)
= 遜 (432) + (36)
= 216 + 36
= 252 units2
Slant height = 18
Perimeter = 6x4 = 24
What is the extra information in the diagram?
32. Volume
Volume
The number of cubic units needed
to fill the shape.
Find the volume of this prism by
counting how many cubes tall, long,
and wide the prism is and then
multiplying.
There are 24 cubes in the prism, so
the volume is 24 cubic units.
2 x 3 x 4 = 24
2 height
3 width
4 length
33. Formula for Prisms
Formula for Prisms
VOLUME OF A PRISM
VOLUME OF A PRISM
The volume
The volume V
V of a prism is the
of a prism is the
area of its base
area of its base B
B times its height
times its height
h
h.
.
V
V =
= Bh
Bh
Note the capital letter stands for the AREA of the
Note the capital letter stands for the AREA of the
BASE not the linear measurement.
BASE not the linear measurement.
34. Try It
Try It
4 ft -
width
3 ft - height
8 ft - length
V = Bh
Find area of the base
= (8 x 4) x 3
= (32) x 3
Multiply it by the height
= 96 ft3
36. Cylinders
Cylinders
VOLUME OF A CYLINDER
VOLUME OF A CYLINDER
The volume
The volume V
V of a cylinder is the area
of a cylinder is the area
of its base,
of its base,
r
r2
2
, times its height
, times its height h
h.
.
V
V =
=
r
r2
2
h
h
Notice that
Notice that
r
r2
2
is the formula for area
is the formula for area
of a circle.
of a circle.
37. Try It
Try It
V = r2
h
The radius of the cylinder is 5 m, and the height
is 4.2 m
V = 3.14 揃 52
揃 4.2
V = 329.7
Substitute the values you
know.
38. Practice
Practice
7 cm - height
13 cm - radius
V = r2
h Start with the formula
V = 3.14 x 132
x 7 substitute what you know
= 3.14 x 169 x 7 Solve using order of Ops.
= 3714.62 cm3
39. Lesson Quiz
Find the volume of each solid to the nearest
tenth. Use 3.14 for .
861.8 cm3
4,069.4 m3
312 ft3
3. triangular prism: base area = 24 ft2
, height = 13 ft
1. 2.
41. Remember that Volume of a
Prism is B x h where b is the
area of the base.
You can see that Volume of a
pyramid will be less than that
of a prism.
How much less? Any guesses?
42. Volume of a Pyramid:
V = (1/3) Area of the Base x height
V = (1/3) Bh
Volume of a Pyramid = 1/3 x Volume
of a Prism
If you said 2/3 less, you win!
+ + =
43. Find the volume of the square pyramid with
base edge length 9 cm and height 14 cm.
The base is a square with a side
length of 9 cm, and the height
is 14 cm.
V = 1/3 Bh
= 1/3 (9 x 9)(14)
= 1/3 (81)(14)
= 1/3 (1134)
= 378 cm3
14 cm
45. Quiz
Quiz
Find the volume of each figure.
1. a rectangular pyramid with length 25 cm,
width 17 cm, and height 21 cm
2975 cm3
2. a triangular pyramid with base edge length
12 in. a base altitude of 9 in. and height
10 in.
360 in3