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?N T?P V? PH??NG TR?NH ???NG TH?NG TRONG M?T PH?NG
So?n: L?u H?i V?nh ¨C GV °Õ´Ç¨¢²Ô Tr??ng THPT NG
I/ L? thuy?t
1/T?a ??: H? t?a ?? Oxy hay (O, ,i j
r r
)
* T?a ?? c?a ?i?m; v¨¦c t?: M(x;y) ( ; ) . .OM x y OM x i y j? = ? = +
uuuur uuuur r r
* ?? d¨¤i c?a m?t v¨¦c t?; ?o?n th?ng:
2 2 2 2
( ) ( ) ( ) ( )A B A B B A B AAB AB x x y y x x y y= = ? + ? = ? + ?
uuur
* Hai v¨¦c t? b?ng nhau:
1 2
1 1 2 2
1 2
( ; ) ( ; )
x x
a x y b x y
y y
=?
= ? ?
=?
r r
* C¨¢c ph¨¦p ³Ù´Ç¨¢²Ô v? v¨¦c t?: Cho 1 1 2 2( ; ), ( ; )a x y b x y
r r
1 2 1 2 1 2 1 2
1 1 1 2 1 2
1 2
1 2
1 2 1 2
1 2 1 2
2 2 2 2
1 2 1 2
/ ( ; ) / ( ; )
/ . ( . ; . ) / . . .
.
/ cung phuong ; 0 :
.
/ . . 0
. . .
/ os( ; )
. .
a b x x y y a b x x y y
k a k x k y a b x x y y
x t x
a b b t
y t y
a b x x y y
a b x x y y
c a b
a b x x y y
+ + = + + + ? = ? ?
+ = + = +
=?
+ ¡Ù ? ? ¡Ê ?
=?
+ ¡Í ? + =
+
+ = =
+ +
r r r r
r r r
r r r r
?
r r
r r
r r
r r
* C¨¢c c?ng th?c li¨ºn quan ??n t?a ?? ?i?m:
+/ M l¨¤ trung ?i?m AB
2
0
2
A B
M
A B
M
x x
x
MA MB
y y
y
+?
=??
? + = ? ?
+? =
??
uuur uuur r
(hay v?i m?i ?i?m O;
1
( )
2
OM OA OB= +
uuuur uuur uuur
)
+/ M chia ?o?n AB theo t? s? k ( A;B ph?n bi?t; k 1¡Ù ) .MA k MB? =
uuur uuur
.
1
.
1
A B
M
A B
M
x k x
x
k
y k y
y
k
??
=?? ?
? ?
?? =
? ??
( hay v?i m?i ?i?m O;
1
( . )
1
OM OA k OB
k
= ?
?
uuuur uuur uuur
)
+/ M l¨¤ tr?ng t?m tam gi¨¢c ABC
3
0
3
A B C
M
A B C
M
x x x
x
MA MB MC
y y y
y
+ +?
=??
? + + = ? ?
+ +? =
??
uuur uuur uuuur r
(hay v?i m?i ?i?m O;
1
( )
3
OM OA OB OC= + +
uuuur uuur uuur uuur
)
* M?t s? t¨ªnh ch?t c?a tam gi¨¢c ABC:
+/ Tam gi¨¢c ABC vu?ng t?i C 2 2 2
. 0 (hay .....)CACB CA CB AB? = ? + = ?
uuur uuur
+/ Tam gi¨¢c ABC c?n t?i B .......BA BC? = ?
uuur uuur
+/ Tam gi¨¢c ABC vu?ng c?n t?i A
. 0AB AC
AB AC
? =?
? ?
=??
uuur uuur
uuur uuur
+ Tam gi¨¢c ABC ??u BA BC AC? = =
uuur uuur uuur
2/ Li¨ºn h? t?a ?? v¨¤ b?t ??ng th?c Bunhiacopxki:
V?i hai v¨¦c t? ( ; )u a b
r
v¨¤ ( ; )v x y
r
; ta c¨® 2 2 2 2
. ax+by
os( ; )
. .
u v
c u v
u v a b x y
= =
+ +
r r
r r
r r
2 2 2 2
2 2 2 2
2 2 2 2 2
ax+by
Do os( ; ) 1 1 ax+by .
.
(ax+by) ( ).( )
c u v a b x y
a b x y
a b x y
¡Ü ? ¡Ü ? ¡Ü + +
+ +
? ¡Ü + +
r r
D?u b?ng x?y ra os(u; ) 1c v = ¡À
r r
;u v?
r r
c¨´ng ph??ng ax=by?
3/ ???ng th?ng
a/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ nh?n v¨¦c t? 2 2
( ; ) ( 0)u a b a b+ ¡Ù
r
l¨¤m v¨¦c t? ch? ph??ng c¨®
ph??ng tr¨¬nh tham s? l¨¤ :
0
0
( )
x x at
t R
y y bt
= +?
¡Ê?
= +?
* N?u 0a ¡Ù th¨¬ h? s? g¨®c c?a ???ng th?ng l¨¤ k = b/a.
b/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ nh?n v¨¦c t? ( ; ) ( ; 0)u a b a b ¡Ù
r
l¨¤m v¨¦c t? ch? ph??ng c¨®
ph??ng tr¨¬nh ch¨ªnh t?c l¨¤ : 0 0x x y y
a b
? ?
= .
c/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ c¨® h? s? g¨®c k ; ph??ng tr¨¬nh l¨¤ : y = k(x-x0) + y0
d/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ nh?n v¨¦c t? ( ; ) ( ; 0)n a b a b ¡Ù
r
l¨¤m v¨¦c t? ph¨¢p tuy?n c¨®
ph??ng tr¨¬nh t?ng qu¨¢t l¨¤ : a(x-x0) + b(y-y0) =0
e/ ???ng th?ng ?i qua A(x1;y1) v¨¤ B(x2 ;y2) c¨® ph??ng tr¨¬nh l¨¤ :
? N?u x1 = x2 : Ph??ng tr¨¬nh l¨¤ x = x1
? N?u y1 = y2 : Ph??ng tr¨¬nh l¨¤ y = y1
? N?u
1 2
1 2
x x
y y
¡Ù?
?
¡Ù?
: Ph??ng tr¨¬nh l¨¤
1 1
2 1 2 1
x x y y
x x y y
? ?
=
? ?
f/ Ch¨² ? :
? N?u 2 2
( ; ) ( 0)u a b a b+ ¡Ù
r
l¨¤ 1 v¨¦c t? ch? ph??ng c?a (d) th¨¬ k. ( ; ) 0u ka kb k= ? ¡Ù
r
c?ng l¨¤ m?t
v¨¦c t? ch? ph??ng c?a (d).
? N?u 2 2
( ; ) ( 0)n a b a b+ ¡Ù
r
l¨¤ 1 v¨¦c t? ch? ph??ng c?a (d) th¨¬ k. ( ; ) 0n ka kb k= ? ¡Ù
r
c?ng l¨¤ m?t
v¨¦c t? ch? ph??ng c?a (d).
? N?u 2 2
( ; ) ( 0)u a b a b+ ¡Ù
r
l¨¤ 1 v¨¦c t? ch? ph??ng c?a (d) th¨¬ ( ; )n b a= ?
r
l¨¤ m?t v¨¦c t? ph¨¢p
tuy?n c?a (d).
4/ G¨®c gi?a hai ???ng th?ng
Gi? s? ¦Á l¨¤ g¨®c gi?a hai ???ng th?ng c¨® v¨¦c t? ph¨¢p tuy?n theo th? t? l¨¤ 1 2;n n
ur uur
1 2
1 2
1 2
n .
os = cos(n ; )
n . n
n
c n¦Á? =
uur uur
uur uur
uur uur (c¨® th? t¨ªnh theo v¨¦c t? ch? ph??ng)
5/ Kho?ng c¨¢ch t? ?i?m M ??n (d) : ax + by +c = 0
M
2 2
ax
( ;( )) Mby c
d M d
a b
+ +
=
+
6/ ???ng ph?n gi¨¢c c?a g¨®c h?p b?i hai ???ng th?ng
Cho (d1) : a1x + b1y +c1 = 0 v¨¤ (d2) : a2x + b2y +c2 = 0
Ph??ng tr¨¬nh ???ng ph?n gi¨¢c c?a g¨®c h?p b?i (d1) ; (d2) l¨¤ :
1 1 1 2 2 2
2 2 2 2
1 1 2 2
a x b y c a x b y c
a b a b
+ + + +
=
+ +
II/ B¨¤i t?p
B¨¤i 1 : A-2010
Cho tam gi¨¢c ABC c?n t?i A(6;6), ???ng th?ng ?i qua trung ?i?m canh AB v¨¤ AC c¨® ph??ng tr¨¬nh
x + y ¨C 4 = 0. T¨¬m t?a ?? B v¨¤ C bi?t E(1;-3) n?m tr¨ºn ???ng cao ?i qua C c?a tam gi¨¢c ?? cho.
B¨¤i 2: B-2010
Cho tam gi¨¢c ABC vu?ng t?i A; ??nh C(-4;1); ph?n gi¨¢c trong g¨®c A c¨® ph??ng tr¨¬nh
x + y -5 = 0. Vi?t ph??ng tr¨¬nh BC, bi?t di?n t¨ªch tam gi¨¢c ABC b?ng 24 v¨¤ ??nh A c¨® ho¨¤nh ??
d??ng.
B¨¤i 3: D-2010
? C?u VIa: Cho tam gi¨¢c ABC; A(3;-7); tr?c t?m H(3;-1), t?m ???ng tr¨°n ngo?i ti?p I(-2;0).
X¨¢c ??nh t?a ?? C bi?t ho¨¤nh ?? C d??ng.
? C?u VIb: Cho A(0;2); ? l¨¤ ???ng th?ng ?i qua O. G?i H l¨¤ h¨¬nh chi?u vu?ng g¨®c c?a A l¨ºn
? . Vi?t ph??ng tr¨¬nh ? bi?t kho?ng c¨¢ch t? H ??n tr?c ho¨¤nh b?ng AH.
B¨¤i 4: D-2009
? C?u VIa: Cho tam gi¨¢c ABC; M(2;0) l¨¤ trung ?i?m c?a AB. ???ng trung tuy?n v¨¤ ???ng
cao ?i qua A l?n l??t c¨® ph??ng tr¨¬nh l¨¤: 7x-2y-3=0 v¨¤ 6x-y-4=0. Vi?t ph??ng tr¨¬nh AC.
? C?u VIb: Cho ???ng tr¨°n (C): (x-1)2
+y2
=1. G?i I l¨¤ t?m c?a (C). X¨¢c ??nh t?a ?? ?i?m M
thu?c (C) sao cho ¡¤ 0
30IMO = .
B¨¤i 5 : B-2009
? C?u VIb: Cho tam gi¨¢c ABC c?n t?i A(-1;4). C¨¢c ??nh B;C thu?c ? : x-y-4=0. X¨¢c ??nh t?a
?? B ; C bi?t di?n t¨ªch tam gi¨¢c ABC b?ng 18.
B¨¤i 6: A-2009
? C?u VIa: Cho h¨¬nh ch? nh?t ABCD c¨® I(6;2) l¨¤ giao ?i?m hai ???ng ch¨¦o AC v¨¤ BD. ?i?m
M(1;5) thu?c AB v¨¤ trung ?i?m E c?a c?nh CD thu?c ? : x+y-5=0. Vi?t ph??ng tr¨¬nh AB.
? C?u VIb: Cho ???ng tr¨°n (C): x2
+y2
+4x+4y+6 =0 v¨¤ ? :x+my-2m+3=0. G?i I l¨¤ t?m c?a
(C). T¨¬m m ?? ? c?t (C) t?i hai ?i?m ph?n bi?t A; B sao cho di?n t¨ªch tam gi¨¢c IAB max.
B¨¤i 7: D-2008
Trong Oxy; cho (P) c¨® ph??ng tr¨¬nh 2
16y x= ; A(1;4). Hai ?i?m ph?n bi?t B; C kh?ng tr¨´ng v?i A
di ??ng tr¨ºn (P) sao cho 0
90BAC¡Ï = . CMR ???ng th?ng BC lu?n ?i qua m?t ?i?m c? ??nh.
B¨¤i 8: B-2008
Trong Oxy; cho tam gi¨¢c ABC; h¨¬nh chi?u vu?ng g¨®c c?a C l¨ºn AB l¨¤ H(-1;-1); ???ng ph?n gi¨¢c
trong c?a g¨®c A: x-y+2=0; ???ng cao k? t? B: 4x+3y-1=0; T¨¬m t?a ?? C?
B¨¤i 9: B-2007
Cho A(2;2); (d1): x+y-2=0; (d2): x+y-8=0. T¨¬m t?a ?? B thu?c (d1) ; C thu?c (d2) sao cho tam gi¨¢c
ABC vu?ng c?n t?i A.
B¨¤i 10: B-2006
Cho ???ng tr¨°n (C): x2
+y2
-2x-6y+6 =0 v¨¤ M(-3 ;1). G?i T1 ; T2 l¨¤ c¨¢c ti?p ?i?m c?a c¨¢c ti?p tuy?n
k? t? M ??n (C). Vi?t ph??ng tr¨¬nh T1T2.
B¨¤i 11: A-2006
Cho (d1) : x+y+3=0 ; (d2) : x-y-4=0 ; (d3) : x-2y=0.
T¨¬m t?a ?? M thu?c (d3) sao cho kho?ng c¨¢ch t? M ??n d1 b?ng hai l?n kho?ng c¨¢ch t? M ??n d2.
B¨¤i 12: A-2005
Cho (d1) : x-y=0 ; (d2) : 2x+y-1=0. T¨¬m t?a ?? c¨¢c ??nh c?a h¨¬nh vu?ng ABCD bi?t A thu?c d1 ; C
thu?c d2 v¨¤ B ; D thu?c tr?c ho¨¤nh.
B¨¤i 13: D-2004
Trong Oxy; cho tam gi¨¢c ABC; A(-1;0); B(4;0); C(0;m). T¨¬m t?a ?? tr?ng t?m G theo m; m 0¡Ù .
T¨¬m m ?? tam gi¨¢c GAB vu?ng t?i G.
B¨¤i 14: B-2004
Cho A(1;1); B(4;-3). T¨¬m C thu?c ???ng th?ng x-2y-1=0 sao cho kho?ng c¨¢ch t? C ??n AB b?ng 6.
B¨¤i 15: A-2004
Cho A(0;2); B(- 3 ;-1). T¨¬m t?a ?? tr?c t?m v¨¤ t?m ???ng tr¨°n ngo?i ti?p tam gi¨¢c OAB.
B¨¤i 16: B-2003
Cho tam gi¨¢c ABC c¨® AB=AC; ¡¤ 0
90BAC = . ?i?m M(1;-1) l¨¤ trung ?i?m BC v¨¤ G(
2
3
;0) l¨¤ tr?ng t?m
tam gi¨¢c ABC. T¨¬m t?a ?? A;B;C.
B¨¤i 17: B-2002
Trong Oxy; cho h¨¬nh ch? nh?t ABCD c¨® t?m I(1/2;0); ???ng th?ng AB c¨® pt: x-2y+2 = 0 v¨¤ AB
=2AD. T¨¬m t?a ?? A; B; C; D bi?t ho¨¤nh ?? A ?m.
B¨¤i 18: 2002
Trong Oxy; cho tam gi¨¢c ABC vu?ng t?i A. ???ng th?ng BC c¨® ph??ng tr¨¬nh: 3 3 0x y? ? = ; A
v¨¤ B thu?c Ox. B¨¢n k¨ªnh ???ng tr¨°n n?i ti?p tam gi¨¢c ABC b?ng 2. T¨¬m t?a ?? tr?ng t?m G c?a
tam gi¨¢c.
B¨¤i 19: Trong Oxy; cho tam gi¨¢c ABC; A(-5;6); B(-4;-1); C(4;3).
a/ T¨¬m to? ?? D ?? ABCD l¨¤ h¨¬nh b¨¬nh h¨¤nh.
b/ T¨¬m to? ?? h¨¬nh chi?u vu?ng g¨®c c?a A l¨ºn BC.
B¨¤i 20: Trong Oxy; cho tam gi¨¢c ABC; A(0;2); B(-2;-2); C(4;-2). H l¨¤ ch?n ???ng cao h? t? B; M
v¨¤ N l?n l??t l¨¤ trung ?i?m AB v¨¤ BC. L?p ph??ng tr¨¬nh ???ng tr¨°n qua H; M; N.
B¨¤i 21: Trong Oxy; cho ???ng tr¨°n (C): 2 2
( 2) ( 3) 2x y? + ? = ; ???ng th?ng (d): x-y-2=0.
T¨¬m M thu?c (C) ?? kho?ng c¨¢ch t? M ??n (d):
a/ max? b/ min?
B¨¤i 22: Trong Oxy; cho tam gi¨¢c ABC; C(-2;3). ???ng cao k? t? A c¨® ph??ng tr¨¬nh: 3x-2y-25=0;
???ng ph?n gi¨¢c trong g¨®c B c¨® ph??ng tr¨¬nh: x-y=0. L?p ph??ng tr¨¬nh AC?
B¨¤i 23: Trong Oxy; cho h¨¬nh vu?ng ABCD; CD c¨® ph??ng tr¨¬nh: 4x-3y+4=0; M(2;3) th?c BC;
N(1;1) thu?c AB. Vi?t ph??ng tr¨¬nh c¨¢c c?nh c¨°n l?i.
B¨¤i 24: Trong Oxy; cho parabol (P): 2
4y x= . L?p ph??ng tr¨¬nh c¨¢c c?nh c?a tam gi¨¢c ABC bi?t A
tr¨´ng ??nh O; hai ?i?m B; C thu?c (P); tr?c t?m tr¨´ng v?i ti¨ºu ?i?m c?a (P).
B¨¤i 25: Trong Oxy; cho tam gi¨¢c ABC; A(5;2); ???ng trung tr?c c?a BC c¨® ph??ng tr¨¬nh x+y-6=0;
???ng trung tuy?n CM c¨® ph??ng tr¨¬nh 2x-y+3=0. T¨¬m t?a ?? A; B; C.
B¨¤i 26: Trong Oxy; cho tam gi¨¢c ABC; A thu?c (d): x-4y-2=0; BC song song v?i (d); ???ng cao
BH c¨® ph??ng tr¨¬nh: x+y+3=0; M(1;1) l¨¤ trung ?i?m c?a AC. T¨¬m t?a ?? A; B; C.
B¨¤i 27: Trong Oxy; L?p ph??ng tr¨¬nh qua A(1;1) c¨¢ch ??u B(-2;3) v¨¤ C(0;4).
B¨¤i 28: Trong Oxy; cho tam gi¨¢c ABC; B(1;0); hai ???ng cao c¨® ph??ng tr¨¬nh l?n l??t l¨¤: x-
2y+1=0; 3x+y-1=0. T¨ªnh di?n t¨ªch tam gi¨¢c ABC.
B¨¤i 29: Trong Oxy; cho tam gi¨¢c ABC c?n t?i A; G(
4 1
;
3 3
) l¨¤ tr?ng t?m; ???ng th?ng ch?a c?nh BC
c¨® ph??ng tr¨¬nh l¨¤: x-2y-4=0; ???ng BG c¨® pt: 7x-4y-8=0. T¨¬m t?a ?? A; B; C.
B¨¤i 30: L?p ph??ng tr¨¬nh ???ng th?ng qua I(-2;0); c?t (d1): 2x-y+5=0 v¨¤ c?t (d2): x+y-3=0 l?n l??t
t?i A v¨¤ B sao cho: 2IA IB=
uur uur
B¨¤i 31: Cho ???ng th?ng (d1): x+y+5=0 v¨¤ (d2): x+2y-7=0. A(2;3); T¨¬m B thu?c (d1); C thu?c (d2)
sao cho tam gi¨¢c ABC c¨® tr?ng t?m G(2;0).
B¨¤i 32: Ll?p ph??ng tr¨¬nh ???ng th?ng qua M(
5
;2
2
); c?t (d1): x-2y=0 v¨¤ c?t (d2): 2x-y=0 l?n l??t
t?i A v¨¤ B sao cho: M l¨¤ trung ?i?m AB.
B¨¤i 33: Trong Oxy; cho ???ng th?ng (d): 2x-y-5=0 v¨¤ A(1;2); B(4;1). T¨¬m M thu?c (d) sao cho
MA MB? max.
B¨¤i 34: Trong Oxy; cho h¨¬nh vu?ng ABCD; CD c¨® ph??ng tr¨¬nh: 4x-3y+4=0; M(2;3) thu?c BC;
N(1;1) thu?c AB. L?p ph??ng tr¨¬nh AD.
B¨¤i 35: Trong Oxy; l?p ph??ng tr¨¬nh (d1); (d2) l?n l??t ?i qua A(4;0); B(0;5) v¨¤ nh?n (d): 2x-2y-
1=0 l¨¤ ph?n gi¨¢c.
B¨¤i 36: Cho tam gi¨¢c ABC c?n t?i A; ???ng th?ng AB: 2x-y+5=0; ???ng th?ng AC:3x+6y-1=0;
M(2;-1) thu?c BC. L?p ph??ng tr¨¬nh c?nh BC.
B¨¤i 37: Trong Oxy; cho tam gi¨¢c ABC; A(-1;2); B(2;0); C(-3;1).
a/ T¨¬m t?m ???ng tr¨°n ngo?i ti?p tam gi¨¢c ABC.
b/ T¨¬m M thu?c BC sao cho
1
3
AMB ABCS S? ?= .
B¨¤i 38: Cho h¨¬nh b¨¬nh h¨¤nh ABCD c¨® di?n t¨ªch b?ng 4. Bi?t A(1; 0); B(2;0); giao ?i?m hai ???ng
ch¨¦o I thu?c ???ng th?ng y =x. T¨¬m t?a ?? C; D?
B¨¤i 39: Cho (d1): x-2y=0; (d2): 2x-y=0; M(
5
;2
2
). L?p ph??ng tr¨¬nh ???ng th?ng ?i qua M c?t (d1);
(d2) t?i A v¨¤ B sao cho:
a/ M l¨¤ trung ?i?m AB b/ MB=2MA.
B¨¤i 40: Cho h¨¬nh thoi c¨® m?t ???ng ch¨¦o: x+2y-7=0; m?t c?nh: x+3y-3=0; m?t ??nh (0;1). L?p
ph??ng tr¨¬nh c¨¢c c?nh.
B¨¤i 41: Cho tam gi¨¢c ABC; A(-6;3); B(-4;3); C(9;2).
a/ L?p ph??ng tr¨¬nh ???ng ph?n gi¨¢c trong g¨®c A.
b/ T¨¬m M tr¨ºn AB; ?i?m N tr¨ºn AC sao cho MN//BC v¨¤ AM=CN.
B¨¤i 42: Cho tam gi¨¢c ABC; A(-6;3); B(-4;3); C(9;2). T¨¬m P thu?c ???ng ph?n gi¨¢c trong g¨®c A sao
cho ABPC l¨¤ h¨¬nh thang.
B¨¤i 43: Cho tam gi¨¢c ABC; A(-2;3); tr?c t?m H tr¨´ng v?i trung ?i?m c?a ???ng cao AK. ???ng
cao BM c¨® h? s? g¨®c b?ng 2. T¨¬m t?a ?? B; C.
B¨¤i 44: Cho tam gi¨¢c ABC c¨® tr?ng t?m G(-2;-1); AB: 4x+y+15=0; AC: 2x+5y+3=0. T¨¬m tr¨ºn
???ng cao AH c?a tam gi¨¢c ?i?m M sao cho tam gi¨¢c BMC vu?ng t?i M.
B¨¤i 45: Cho A(1;0); B(3;-1); (d):x-2y-1=0. T¨¬m C thu?c (d) sao cho 6ABCS? = .
B¨¤i 46: Cho tam gi¨¢c ABC; c?nh AB: y=2x; c?nh AC: y=
1 1
4 4
x? + ; tr?ng t?m G(
8 7
;
3 3
). T¨ªnh di?n
t¨ªch tam gi¨¢c ABC.
B¨¤i 47: T¨¬m to? ?? ?i?m M tr¨ºn (d): x-2y-2=0 sao cho 2 2
2MA MB+ nh? nh?t; A(0;1); B(3;4).
B¨¤i 48: Cho A(2;-1); B(1;-2); tr?ng t?m G thu?c (d):x+y-2=0. T¨¬m C bi?t di?n t¨ªch tam gi¨¢c ABC
b?ng 3/2.
B¨¤i 49: T¨¬m M n?m ph¨ªa tr¨ºn Ox sao cho g¨®c MAB=300
; g¨®c AMB = 900
; A(-2;0); B(2;0).
B¨¤i 50: Cho tam gi¨¢c ABC vu?ng t?i A; A(-1;4); B(1;-4); M(
1
2;
2
) thu?c BC. T¨¬m t?a ?? C?
B¨¤i 46: Cho tam gi¨¢c ABC; c?nh AB: y=2x; c?nh AC: y=
1 1
4 4
x? + ; tr?ng t?m G(
8 7
;
3 3
). T¨ªnh di?n
t¨ªch tam gi¨¢c ABC.
B¨¤i 47: T¨¬m to? ?? ?i?m M tr¨ºn (d): x-2y-2=0 sao cho 2 2
2MA MB+ nh? nh?t; A(0;1); B(3;4).
B¨¤i 48: Cho A(2;-1); B(1;-2); tr?ng t?m G thu?c (d):x+y-2=0. T¨¬m C bi?t di?n t¨ªch tam gi¨¢c ABC
b?ng 3/2.
B¨¤i 49: T¨¬m M n?m ph¨ªa tr¨ºn Ox sao cho g¨®c MAB=300
; g¨®c AMB = 900
; A(-2;0); B(2;0).
B¨¤i 50: Cho tam gi¨¢c ABC vu?ng t?i A; A(-1;4); B(1;-4); M(
1
2;
2
) thu?c BC. T¨¬m t?a ?? C?

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[Ph?n 1] Tuy?n t?p c¨¢c b¨¤i h¨¬nh gi?i t¨ªch ph?ng Oxy trong ?? thi th? ?H (2013...[Ph?n 1] Tuy?n t?p c¨¢c b¨¤i h¨¬nh gi?i t¨ªch ph?ng Oxy trong ?? thi th? ?H (2013...
[Ph?n 1] Tuy?n t?p c¨¢c b¨¤i h¨¬nh gi?i t¨ªch ph?ng Oxy trong ?? thi th? ?H (2013...
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De cuong on tap toan 9
De cuong on tap toan 9De cuong on tap toan 9
De cuong on tap toan 9
Hung Anh
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thi thu dh nam 2013 thpt trieu son-4
thi thu dh nam 2013 thpt trieu son-4thi thu dh nam 2013 thpt trieu son-4
thi thu dh nam 2013 thpt trieu son-4
Oanh MJ
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288ehq h9

  • 1. ?N T?P V? PH??NG TR?NH ???NG TH?NG TRONG M?T PH?NG So?n: L?u H?i V?nh ¨C GV °Õ´Ç¨¢²Ô Tr??ng THPT NG I/ L? thuy?t 1/T?a ??: H? t?a ?? Oxy hay (O, ,i j r r ) * T?a ?? c?a ?i?m; v¨¦c t?: M(x;y) ( ; ) . .OM x y OM x i y j? = ? = + uuuur uuuur r r * ?? d¨¤i c?a m?t v¨¦c t?; ?o?n th?ng: 2 2 2 2 ( ) ( ) ( ) ( )A B A B B A B AAB AB x x y y x x y y= = ? + ? = ? + ? uuur * Hai v¨¦c t? b?ng nhau: 1 2 1 1 2 2 1 2 ( ; ) ( ; ) x x a x y b x y y y =? = ? ? =? r r * C¨¢c ph¨¦p ³Ù´Ç¨¢²Ô v? v¨¦c t?: Cho 1 1 2 2( ; ), ( ; )a x y b x y r r 1 2 1 2 1 2 1 2 1 1 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 2 2 2 2 1 2 1 2 / ( ; ) / ( ; ) / . ( . ; . ) / . . . . / cung phuong ; 0 : . / . . 0 . . . / os( ; ) . . a b x x y y a b x x y y k a k x k y a b x x y y x t x a b b t y t y a b x x y y a b x x y y c a b a b x x y y + + = + + + ? = ? ? + = + = + =? + ¡Ù ? ? ¡Ê ? =? + ¡Í ? + = + + = = + + r r r r r r r r r r r ? r r r r r r r r * C¨¢c c?ng th?c li¨ºn quan ??n t?a ?? ?i?m: +/ M l¨¤ trung ?i?m AB 2 0 2 A B M A B M x x x MA MB y y y +? =?? ? + = ? ? +? = ?? uuur uuur r (hay v?i m?i ?i?m O; 1 ( ) 2 OM OA OB= + uuuur uuur uuur ) +/ M chia ?o?n AB theo t? s? k ( A;B ph?n bi?t; k 1¡Ù ) .MA k MB? = uuur uuur . 1 . 1 A B M A B M x k x x k y k y y k ?? =?? ? ? ? ?? = ? ?? ( hay v?i m?i ?i?m O; 1 ( . ) 1 OM OA k OB k = ? ? uuuur uuur uuur ) +/ M l¨¤ tr?ng t?m tam gi¨¢c ABC 3 0 3 A B C M A B C M x x x x MA MB MC y y y y + +? =?? ? + + = ? ? + +? = ?? uuur uuur uuuur r (hay v?i m?i ?i?m O; 1 ( ) 3 OM OA OB OC= + + uuuur uuur uuur uuur ) * M?t s? t¨ªnh ch?t c?a tam gi¨¢c ABC: +/ Tam gi¨¢c ABC vu?ng t?i C 2 2 2 . 0 (hay .....)CACB CA CB AB? = ? + = ? uuur uuur +/ Tam gi¨¢c ABC c?n t?i B .......BA BC? = ? uuur uuur
  • 2. +/ Tam gi¨¢c ABC vu?ng c?n t?i A . 0AB AC AB AC ? =? ? ? =?? uuur uuur uuur uuur + Tam gi¨¢c ABC ??u BA BC AC? = = uuur uuur uuur 2/ Li¨ºn h? t?a ?? v¨¤ b?t ??ng th?c Bunhiacopxki: V?i hai v¨¦c t? ( ; )u a b r v¨¤ ( ; )v x y r ; ta c¨® 2 2 2 2 . ax+by os( ; ) . . u v c u v u v a b x y = = + + r r r r r r 2 2 2 2 2 2 2 2 2 2 2 2 2 ax+by Do os( ; ) 1 1 ax+by . . (ax+by) ( ).( ) c u v a b x y a b x y a b x y ¡Ü ? ¡Ü ? ¡Ü + + + + ? ¡Ü + + r r D?u b?ng x?y ra os(u; ) 1c v = ¡À r r ;u v? r r c¨´ng ph??ng ax=by? 3/ ???ng th?ng a/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ nh?n v¨¦c t? 2 2 ( ; ) ( 0)u a b a b+ ¡Ù r l¨¤m v¨¦c t? ch? ph??ng c¨® ph??ng tr¨¬nh tham s? l¨¤ : 0 0 ( ) x x at t R y y bt = +? ¡Ê? = +? * N?u 0a ¡Ù th¨¬ h? s? g¨®c c?a ???ng th?ng l¨¤ k = b/a. b/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ nh?n v¨¦c t? ( ; ) ( ; 0)u a b a b ¡Ù r l¨¤m v¨¦c t? ch? ph??ng c¨® ph??ng tr¨¬nh ch¨ªnh t?c l¨¤ : 0 0x x y y a b ? ? = . c/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ c¨® h? s? g¨®c k ; ph??ng tr¨¬nh l¨¤ : y = k(x-x0) + y0 d/ ???ng th?ng ?i qua M0(x0;y0) v¨¤ nh?n v¨¦c t? ( ; ) ( ; 0)n a b a b ¡Ù r l¨¤m v¨¦c t? ph¨¢p tuy?n c¨® ph??ng tr¨¬nh t?ng qu¨¢t l¨¤ : a(x-x0) + b(y-y0) =0 e/ ???ng th?ng ?i qua A(x1;y1) v¨¤ B(x2 ;y2) c¨® ph??ng tr¨¬nh l¨¤ : ? N?u x1 = x2 : Ph??ng tr¨¬nh l¨¤ x = x1 ? N?u y1 = y2 : Ph??ng tr¨¬nh l¨¤ y = y1 ? N?u 1 2 1 2 x x y y ¡Ù? ? ¡Ù? : Ph??ng tr¨¬nh l¨¤ 1 1 2 1 2 1 x x y y x x y y ? ? = ? ? f/ Ch¨² ? : ? N?u 2 2 ( ; ) ( 0)u a b a b+ ¡Ù r l¨¤ 1 v¨¦c t? ch? ph??ng c?a (d) th¨¬ k. ( ; ) 0u ka kb k= ? ¡Ù r c?ng l¨¤ m?t v¨¦c t? ch? ph??ng c?a (d). ? N?u 2 2 ( ; ) ( 0)n a b a b+ ¡Ù r l¨¤ 1 v¨¦c t? ch? ph??ng c?a (d) th¨¬ k. ( ; ) 0n ka kb k= ? ¡Ù r c?ng l¨¤ m?t v¨¦c t? ch? ph??ng c?a (d). ? N?u 2 2 ( ; ) ( 0)u a b a b+ ¡Ù r l¨¤ 1 v¨¦c t? ch? ph??ng c?a (d) th¨¬ ( ; )n b a= ? r l¨¤ m?t v¨¦c t? ph¨¢p tuy?n c?a (d). 4/ G¨®c gi?a hai ???ng th?ng Gi? s? ¦Á l¨¤ g¨®c gi?a hai ???ng th?ng c¨® v¨¦c t? ph¨¢p tuy?n theo th? t? l¨¤ 1 2;n n ur uur 1 2 1 2 1 2 n . os = cos(n ; ) n . n n c n¦Á? = uur uur uur uur uur uur (c¨® th? t¨ªnh theo v¨¦c t? ch? ph??ng)
  • 3. 5/ Kho?ng c¨¢ch t? ?i?m M ??n (d) : ax + by +c = 0 M 2 2 ax ( ;( )) Mby c d M d a b + + = + 6/ ???ng ph?n gi¨¢c c?a g¨®c h?p b?i hai ???ng th?ng Cho (d1) : a1x + b1y +c1 = 0 v¨¤ (d2) : a2x + b2y +c2 = 0 Ph??ng tr¨¬nh ???ng ph?n gi¨¢c c?a g¨®c h?p b?i (d1) ; (d2) l¨¤ : 1 1 1 2 2 2 2 2 2 2 1 1 2 2 a x b y c a x b y c a b a b + + + + = + + II/ B¨¤i t?p B¨¤i 1 : A-2010 Cho tam gi¨¢c ABC c?n t?i A(6;6), ???ng th?ng ?i qua trung ?i?m canh AB v¨¤ AC c¨® ph??ng tr¨¬nh x + y ¨C 4 = 0. T¨¬m t?a ?? B v¨¤ C bi?t E(1;-3) n?m tr¨ºn ???ng cao ?i qua C c?a tam gi¨¢c ?? cho. B¨¤i 2: B-2010 Cho tam gi¨¢c ABC vu?ng t?i A; ??nh C(-4;1); ph?n gi¨¢c trong g¨®c A c¨® ph??ng tr¨¬nh x + y -5 = 0. Vi?t ph??ng tr¨¬nh BC, bi?t di?n t¨ªch tam gi¨¢c ABC b?ng 24 v¨¤ ??nh A c¨® ho¨¤nh ?? d??ng. B¨¤i 3: D-2010 ? C?u VIa: Cho tam gi¨¢c ABC; A(3;-7); tr?c t?m H(3;-1), t?m ???ng tr¨°n ngo?i ti?p I(-2;0). X¨¢c ??nh t?a ?? C bi?t ho¨¤nh ?? C d??ng. ? C?u VIb: Cho A(0;2); ? l¨¤ ???ng th?ng ?i qua O. G?i H l¨¤ h¨¬nh chi?u vu?ng g¨®c c?a A l¨ºn ? . Vi?t ph??ng tr¨¬nh ? bi?t kho?ng c¨¢ch t? H ??n tr?c ho¨¤nh b?ng AH. B¨¤i 4: D-2009 ? C?u VIa: Cho tam gi¨¢c ABC; M(2;0) l¨¤ trung ?i?m c?a AB. ???ng trung tuy?n v¨¤ ???ng cao ?i qua A l?n l??t c¨® ph??ng tr¨¬nh l¨¤: 7x-2y-3=0 v¨¤ 6x-y-4=0. Vi?t ph??ng tr¨¬nh AC. ? C?u VIb: Cho ???ng tr¨°n (C): (x-1)2 +y2 =1. G?i I l¨¤ t?m c?a (C). X¨¢c ??nh t?a ?? ?i?m M thu?c (C) sao cho ¡¤ 0 30IMO = . B¨¤i 5 : B-2009 ? C?u VIb: Cho tam gi¨¢c ABC c?n t?i A(-1;4). C¨¢c ??nh B;C thu?c ? : x-y-4=0. X¨¢c ??nh t?a ?? B ; C bi?t di?n t¨ªch tam gi¨¢c ABC b?ng 18. B¨¤i 6: A-2009 ? C?u VIa: Cho h¨¬nh ch? nh?t ABCD c¨® I(6;2) l¨¤ giao ?i?m hai ???ng ch¨¦o AC v¨¤ BD. ?i?m M(1;5) thu?c AB v¨¤ trung ?i?m E c?a c?nh CD thu?c ? : x+y-5=0. Vi?t ph??ng tr¨¬nh AB. ? C?u VIb: Cho ???ng tr¨°n (C): x2 +y2 +4x+4y+6 =0 v¨¤ ? :x+my-2m+3=0. G?i I l¨¤ t?m c?a (C). T¨¬m m ?? ? c?t (C) t?i hai ?i?m ph?n bi?t A; B sao cho di?n t¨ªch tam gi¨¢c IAB max. B¨¤i 7: D-2008 Trong Oxy; cho (P) c¨® ph??ng tr¨¬nh 2 16y x= ; A(1;4). Hai ?i?m ph?n bi?t B; C kh?ng tr¨´ng v?i A di ??ng tr¨ºn (P) sao cho 0 90BAC¡Ï = . CMR ???ng th?ng BC lu?n ?i qua m?t ?i?m c? ??nh. B¨¤i 8: B-2008 Trong Oxy; cho tam gi¨¢c ABC; h¨¬nh chi?u vu?ng g¨®c c?a C l¨ºn AB l¨¤ H(-1;-1); ???ng ph?n gi¨¢c trong c?a g¨®c A: x-y+2=0; ???ng cao k? t? B: 4x+3y-1=0; T¨¬m t?a ?? C? B¨¤i 9: B-2007 Cho A(2;2); (d1): x+y-2=0; (d2): x+y-8=0. T¨¬m t?a ?? B thu?c (d1) ; C thu?c (d2) sao cho tam gi¨¢c ABC vu?ng c?n t?i A.
  • 4. B¨¤i 10: B-2006 Cho ???ng tr¨°n (C): x2 +y2 -2x-6y+6 =0 v¨¤ M(-3 ;1). G?i T1 ; T2 l¨¤ c¨¢c ti?p ?i?m c?a c¨¢c ti?p tuy?n k? t? M ??n (C). Vi?t ph??ng tr¨¬nh T1T2. B¨¤i 11: A-2006 Cho (d1) : x+y+3=0 ; (d2) : x-y-4=0 ; (d3) : x-2y=0. T¨¬m t?a ?? M thu?c (d3) sao cho kho?ng c¨¢ch t? M ??n d1 b?ng hai l?n kho?ng c¨¢ch t? M ??n d2. B¨¤i 12: A-2005 Cho (d1) : x-y=0 ; (d2) : 2x+y-1=0. T¨¬m t?a ?? c¨¢c ??nh c?a h¨¬nh vu?ng ABCD bi?t A thu?c d1 ; C thu?c d2 v¨¤ B ; D thu?c tr?c ho¨¤nh. B¨¤i 13: D-2004 Trong Oxy; cho tam gi¨¢c ABC; A(-1;0); B(4;0); C(0;m). T¨¬m t?a ?? tr?ng t?m G theo m; m 0¡Ù . T¨¬m m ?? tam gi¨¢c GAB vu?ng t?i G. B¨¤i 14: B-2004 Cho A(1;1); B(4;-3). T¨¬m C thu?c ???ng th?ng x-2y-1=0 sao cho kho?ng c¨¢ch t? C ??n AB b?ng 6. B¨¤i 15: A-2004 Cho A(0;2); B(- 3 ;-1). T¨¬m t?a ?? tr?c t?m v¨¤ t?m ???ng tr¨°n ngo?i ti?p tam gi¨¢c OAB. B¨¤i 16: B-2003 Cho tam gi¨¢c ABC c¨® AB=AC; ¡¤ 0 90BAC = . ?i?m M(1;-1) l¨¤ trung ?i?m BC v¨¤ G( 2 3 ;0) l¨¤ tr?ng t?m tam gi¨¢c ABC. T¨¬m t?a ?? A;B;C. B¨¤i 17: B-2002 Trong Oxy; cho h¨¬nh ch? nh?t ABCD c¨® t?m I(1/2;0); ???ng th?ng AB c¨® pt: x-2y+2 = 0 v¨¤ AB =2AD. T¨¬m t?a ?? A; B; C; D bi?t ho¨¤nh ?? A ?m. B¨¤i 18: 2002 Trong Oxy; cho tam gi¨¢c ABC vu?ng t?i A. ???ng th?ng BC c¨® ph??ng tr¨¬nh: 3 3 0x y? ? = ; A v¨¤ B thu?c Ox. B¨¢n k¨ªnh ???ng tr¨°n n?i ti?p tam gi¨¢c ABC b?ng 2. T¨¬m t?a ?? tr?ng t?m G c?a tam gi¨¢c. B¨¤i 19: Trong Oxy; cho tam gi¨¢c ABC; A(-5;6); B(-4;-1); C(4;3). a/ T¨¬m to? ?? D ?? ABCD l¨¤ h¨¬nh b¨¬nh h¨¤nh. b/ T¨¬m to? ?? h¨¬nh chi?u vu?ng g¨®c c?a A l¨ºn BC. B¨¤i 20: Trong Oxy; cho tam gi¨¢c ABC; A(0;2); B(-2;-2); C(4;-2). H l¨¤ ch?n ???ng cao h? t? B; M v¨¤ N l?n l??t l¨¤ trung ?i?m AB v¨¤ BC. L?p ph??ng tr¨¬nh ???ng tr¨°n qua H; M; N. B¨¤i 21: Trong Oxy; cho ???ng tr¨°n (C): 2 2 ( 2) ( 3) 2x y? + ? = ; ???ng th?ng (d): x-y-2=0. T¨¬m M thu?c (C) ?? kho?ng c¨¢ch t? M ??n (d): a/ max? b/ min? B¨¤i 22: Trong Oxy; cho tam gi¨¢c ABC; C(-2;3). ???ng cao k? t? A c¨® ph??ng tr¨¬nh: 3x-2y-25=0; ???ng ph?n gi¨¢c trong g¨®c B c¨® ph??ng tr¨¬nh: x-y=0. L?p ph??ng tr¨¬nh AC? B¨¤i 23: Trong Oxy; cho h¨¬nh vu?ng ABCD; CD c¨® ph??ng tr¨¬nh: 4x-3y+4=0; M(2;3) th?c BC; N(1;1) thu?c AB. Vi?t ph??ng tr¨¬nh c¨¢c c?nh c¨°n l?i. B¨¤i 24: Trong Oxy; cho parabol (P): 2 4y x= . L?p ph??ng tr¨¬nh c¨¢c c?nh c?a tam gi¨¢c ABC bi?t A tr¨´ng ??nh O; hai ?i?m B; C thu?c (P); tr?c t?m tr¨´ng v?i ti¨ºu ?i?m c?a (P). B¨¤i 25: Trong Oxy; cho tam gi¨¢c ABC; A(5;2); ???ng trung tr?c c?a BC c¨® ph??ng tr¨¬nh x+y-6=0; ???ng trung tuy?n CM c¨® ph??ng tr¨¬nh 2x-y+3=0. T¨¬m t?a ?? A; B; C. B¨¤i 26: Trong Oxy; cho tam gi¨¢c ABC; A thu?c (d): x-4y-2=0; BC song song v?i (d); ???ng cao BH c¨® ph??ng tr¨¬nh: x+y+3=0; M(1;1) l¨¤ trung ?i?m c?a AC. T¨¬m t?a ?? A; B; C.
  • 5. B¨¤i 27: Trong Oxy; L?p ph??ng tr¨¬nh qua A(1;1) c¨¢ch ??u B(-2;3) v¨¤ C(0;4). B¨¤i 28: Trong Oxy; cho tam gi¨¢c ABC; B(1;0); hai ???ng cao c¨® ph??ng tr¨¬nh l?n l??t l¨¤: x- 2y+1=0; 3x+y-1=0. T¨ªnh di?n t¨ªch tam gi¨¢c ABC. B¨¤i 29: Trong Oxy; cho tam gi¨¢c ABC c?n t?i A; G( 4 1 ; 3 3 ) l¨¤ tr?ng t?m; ???ng th?ng ch?a c?nh BC c¨® ph??ng tr¨¬nh l¨¤: x-2y-4=0; ???ng BG c¨® pt: 7x-4y-8=0. T¨¬m t?a ?? A; B; C. B¨¤i 30: L?p ph??ng tr¨¬nh ???ng th?ng qua I(-2;0); c?t (d1): 2x-y+5=0 v¨¤ c?t (d2): x+y-3=0 l?n l??t t?i A v¨¤ B sao cho: 2IA IB= uur uur B¨¤i 31: Cho ???ng th?ng (d1): x+y+5=0 v¨¤ (d2): x+2y-7=0. A(2;3); T¨¬m B thu?c (d1); C thu?c (d2) sao cho tam gi¨¢c ABC c¨® tr?ng t?m G(2;0). B¨¤i 32: Ll?p ph??ng tr¨¬nh ???ng th?ng qua M( 5 ;2 2 ); c?t (d1): x-2y=0 v¨¤ c?t (d2): 2x-y=0 l?n l??t t?i A v¨¤ B sao cho: M l¨¤ trung ?i?m AB. B¨¤i 33: Trong Oxy; cho ???ng th?ng (d): 2x-y-5=0 v¨¤ A(1;2); B(4;1). T¨¬m M thu?c (d) sao cho MA MB? max. B¨¤i 34: Trong Oxy; cho h¨¬nh vu?ng ABCD; CD c¨® ph??ng tr¨¬nh: 4x-3y+4=0; M(2;3) thu?c BC; N(1;1) thu?c AB. L?p ph??ng tr¨¬nh AD. B¨¤i 35: Trong Oxy; l?p ph??ng tr¨¬nh (d1); (d2) l?n l??t ?i qua A(4;0); B(0;5) v¨¤ nh?n (d): 2x-2y- 1=0 l¨¤ ph?n gi¨¢c. B¨¤i 36: Cho tam gi¨¢c ABC c?n t?i A; ???ng th?ng AB: 2x-y+5=0; ???ng th?ng AC:3x+6y-1=0; M(2;-1) thu?c BC. L?p ph??ng tr¨¬nh c?nh BC. B¨¤i 37: Trong Oxy; cho tam gi¨¢c ABC; A(-1;2); B(2;0); C(-3;1). a/ T¨¬m t?m ???ng tr¨°n ngo?i ti?p tam gi¨¢c ABC. b/ T¨¬m M thu?c BC sao cho 1 3 AMB ABCS S? ?= . B¨¤i 38: Cho h¨¬nh b¨¬nh h¨¤nh ABCD c¨® di?n t¨ªch b?ng 4. Bi?t A(1; 0); B(2;0); giao ?i?m hai ???ng ch¨¦o I thu?c ???ng th?ng y =x. T¨¬m t?a ?? C; D? B¨¤i 39: Cho (d1): x-2y=0; (d2): 2x-y=0; M( 5 ;2 2 ). L?p ph??ng tr¨¬nh ???ng th?ng ?i qua M c?t (d1); (d2) t?i A v¨¤ B sao cho: a/ M l¨¤ trung ?i?m AB b/ MB=2MA. B¨¤i 40: Cho h¨¬nh thoi c¨® m?t ???ng ch¨¦o: x+2y-7=0; m?t c?nh: x+3y-3=0; m?t ??nh (0;1). L?p ph??ng tr¨¬nh c¨¢c c?nh. B¨¤i 41: Cho tam gi¨¢c ABC; A(-6;3); B(-4;3); C(9;2). a/ L?p ph??ng tr¨¬nh ???ng ph?n gi¨¢c trong g¨®c A. b/ T¨¬m M tr¨ºn AB; ?i?m N tr¨ºn AC sao cho MN//BC v¨¤ AM=CN. B¨¤i 42: Cho tam gi¨¢c ABC; A(-6;3); B(-4;3); C(9;2). T¨¬m P thu?c ???ng ph?n gi¨¢c trong g¨®c A sao cho ABPC l¨¤ h¨¬nh thang. B¨¤i 43: Cho tam gi¨¢c ABC; A(-2;3); tr?c t?m H tr¨´ng v?i trung ?i?m c?a ???ng cao AK. ???ng cao BM c¨® h? s? g¨®c b?ng 2. T¨¬m t?a ?? B; C. B¨¤i 44: Cho tam gi¨¢c ABC c¨® tr?ng t?m G(-2;-1); AB: 4x+y+15=0; AC: 2x+5y+3=0. T¨¬m tr¨ºn ???ng cao AH c?a tam gi¨¢c ?i?m M sao cho tam gi¨¢c BMC vu?ng t?i M. B¨¤i 45: Cho A(1;0); B(3;-1); (d):x-2y-1=0. T¨¬m C thu?c (d) sao cho 6ABCS? = .
  • 6. B¨¤i 46: Cho tam gi¨¢c ABC; c?nh AB: y=2x; c?nh AC: y= 1 1 4 4 x? + ; tr?ng t?m G( 8 7 ; 3 3 ). T¨ªnh di?n t¨ªch tam gi¨¢c ABC. B¨¤i 47: T¨¬m to? ?? ?i?m M tr¨ºn (d): x-2y-2=0 sao cho 2 2 2MA MB+ nh? nh?t; A(0;1); B(3;4). B¨¤i 48: Cho A(2;-1); B(1;-2); tr?ng t?m G thu?c (d):x+y-2=0. T¨¬m C bi?t di?n t¨ªch tam gi¨¢c ABC b?ng 3/2. B¨¤i 49: T¨¬m M n?m ph¨ªa tr¨ºn Ox sao cho g¨®c MAB=300 ; g¨®c AMB = 900 ; A(-2;0); B(2;0). B¨¤i 50: Cho tam gi¨¢c ABC vu?ng t?i A; A(-1;4); B(1;-4); M( 1 2; 2 ) thu?c BC. T¨¬m t?a ?? C?
  • 7. B¨¤i 46: Cho tam gi¨¢c ABC; c?nh AB: y=2x; c?nh AC: y= 1 1 4 4 x? + ; tr?ng t?m G( 8 7 ; 3 3 ). T¨ªnh di?n t¨ªch tam gi¨¢c ABC. B¨¤i 47: T¨¬m to? ?? ?i?m M tr¨ºn (d): x-2y-2=0 sao cho 2 2 2MA MB+ nh? nh?t; A(0;1); B(3;4). B¨¤i 48: Cho A(2;-1); B(1;-2); tr?ng t?m G thu?c (d):x+y-2=0. T¨¬m C bi?t di?n t¨ªch tam gi¨¢c ABC b?ng 3/2. B¨¤i 49: T¨¬m M n?m ph¨ªa tr¨ºn Ox sao cho g¨®c MAB=300 ; g¨®c AMB = 900 ; A(-2;0); B(2;0). B¨¤i 50: Cho tam gi¨¢c ABC vu?ng t?i A; A(-1;4); B(1;-4); M( 1 2; 2 ) thu?c BC. T¨¬m t?a ?? C?