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2.001 - MECHANICS AND MATERIALS I
                                  Lecture #1
                                   9/6/2006
                            Prof. Carol Livermore

  A 鍖rst course in mechanics for understanding and designing complicated
                                  systems.

PLAN FOR THE DAY:
  1. Syllabus
  2. Review vectors, forces, and moments
  3. Equilibrium
  4. Recitation sections
BASIC INGREDIENTS OF 2.001
  1. Forces, Moments, and Equilibrium  Statics (No acceleration)
  2. Displacements, Deformations, Compatibility (How displacements 鍖t to-
     gether)
  3. Constitutive Laws: Relationships between forces and deformations




                      Use 2.001 to predict this problem.

HOW TO SOLVE A PROBLEM
RULES:


  1. SI inits only.
  2. Good sketches.
         Labeled coordinate system.
 Labeled dimensions and forces.
  3. Show your thought process.
  4. Follow all conventions.
  5. Solve everything symbolically until the end.
  6. Check answer  Does it make sense?
         Check trends.
         Check units.
  7. Convert to SI, plug in to get answers.
VECTORS, FORCES, AND MOMENTS
Forces are vectors (Magnitude and Direction)




                                     i      j      
                               F = Fx + Fy  + Fz k
OR


                                                  
                          F = Fx i + Fy j + Fz k 
Where do forces come from?
    Contact with another object
    Gravity
    Attractive of repulsive forces
Moments are vectors. (Moment is another word for torque.)
    Forces at a distance from a point
    Couple
Moments are vectors.
      M = My 
             j.




 EX:




2D:


                                  FB = FBx + FBy 
                                          i       j
                                 rAB = rABx + rABy 
                                           i        j


                MA = rAB  FB     =
                                  =   (rABx + rABy   (FBx + FBy 
                                           i        j)       i      j)
                                  =   (rAB FB  rAB FB )k  
                                          x   y         y   x


      OR


                     MA = |rAB | FB sin  using Right Hand Rule
      3D:


                                       i        j        
                             rAB = rABx + rABy  + rABz k
                                      i       j       
                              FB = FBx + FBy  + FBz k


                                          
      MA = rAB FB = (rABx FBy rABy FBx )k +(rABz FBx rABx FBz )
                                                                  j+(rABy FBz rABz FBy )
                                                                                         i




                                          3
EX: Wrench


                                  rAB = d
                                         j
                                  FB = FB
                                         i
                                    j     i        
                   MA = rAB  FB = d  FB = dFB k




Equations of Static Equilibrium

           裡Fx = 0
    裡F = 0 裡Fy = 0
           裡Fz = 0
            裡M0 x = 0
    裡M0 = 0 裡M0 y = 0
            裡M0 z = 0
4
                                            F =0
                                      i=1

                               F1 + F2 + F3 + F4 = 0
                          F1x + F2x + F3x + F4x = 0
                          F1y + F2y + F3y + F4y = 0
                              F1z + F2z + F3z + F4z = 0

                                           Mo = 0

                r01  F1 + r02  F2 + r03  F3 + r04  F4 = 0
             i, j, 
a. Expand in   k .
b. Group.
c. Get 3 equations (x,y,z).

Try a new point? Try A.


                                   rA1 = rA0 + r01
                                            ...
                                           MA = 0

                rA1  F1 + rA2  F2 + rA3  F3 + rA4  F4 = 0


(rA0 + r01 )  F1 + (rA0 + r02 )  F2 + (rA0 + r03 )  F3 + (rA0 + r04 )  F4 = 0

rA0  (F1 + F2 + F3 + F4 ) + (r0 1  F1 + r0 2  F2 + r0 3  F3 + r0 4  F4 ) = 0
                        rA0  (F1 + F2 + F3 + F4 ) = 0

                                            F =0

               (r0 1  F1 + r0 2  F2 + r0 3  F3 + r0 4  F4 ) = 0
                                           M0 = 0
So taking moment about a new point gives no additional info.




                                            5

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Lec1

  • 1. 2.001 - MECHANICS AND MATERIALS I Lecture #1 9/6/2006 Prof. Carol Livermore A 鍖rst course in mechanics for understanding and designing complicated systems. PLAN FOR THE DAY: 1. Syllabus 2. Review vectors, forces, and moments 3. Equilibrium 4. Recitation sections BASIC INGREDIENTS OF 2.001 1. Forces, Moments, and Equilibrium Statics (No acceleration) 2. Displacements, Deformations, Compatibility (How displacements 鍖t to- gether) 3. Constitutive Laws: Relationships between forces and deformations Use 2.001 to predict this problem. HOW TO SOLVE A PROBLEM RULES: 1. SI inits only. 2. Good sketches. Labeled coordinate system.
  • 2. Labeled dimensions and forces. 3. Show your thought process. 4. Follow all conventions. 5. Solve everything symbolically until the end. 6. Check answer Does it make sense? Check trends. Check units. 7. Convert to SI, plug in to get answers. VECTORS, FORCES, AND MOMENTS Forces are vectors (Magnitude and Direction) i j F = Fx + Fy + Fz k OR F = Fx i + Fy j + Fz k Where do forces come from? Contact with another object Gravity Attractive of repulsive forces Moments are vectors. (Moment is another word for torque.) Forces at a distance from a point Couple
  • 3. Moments are vectors. M = My j. EX: 2D: FB = FBx + FBy i j rAB = rABx + rABy i j MA = rAB FB = = (rABx + rABy (FBx + FBy i j) i j) = (rAB FB rAB FB )k x y y x OR MA = |rAB | FB sin using Right Hand Rule 3D: i j rAB = rABx + rABy + rABz k i j FB = FBx + FBy + FBz k MA = rAB FB = (rABx FBy rABy FBx )k +(rABz FBx rABx FBz ) j+(rABy FBz rABz FBy ) i 3
  • 4. EX: Wrench rAB = d j FB = FB i j i MA = rAB FB = d FB = dFB k Equations of Static Equilibrium 裡Fx = 0 裡F = 0 裡Fy = 0 裡Fz = 0 裡M0 x = 0 裡M0 = 0 裡M0 y = 0 裡M0 z = 0
  • 5. 4 F =0 i=1 F1 + F2 + F3 + F4 = 0 F1x + F2x + F3x + F4x = 0 F1y + F2y + F3y + F4y = 0 F1z + F2z + F3z + F4z = 0 Mo = 0 r01 F1 + r02 F2 + r03 F3 + r04 F4 = 0 i, j, a. Expand in k . b. Group. c. Get 3 equations (x,y,z). Try a new point? Try A. rA1 = rA0 + r01 ... MA = 0 rA1 F1 + rA2 F2 + rA3 F3 + rA4 F4 = 0 (rA0 + r01 ) F1 + (rA0 + r02 ) F2 + (rA0 + r03 ) F3 + (rA0 + r04 ) F4 = 0 rA0 (F1 + F2 + F3 + F4 ) + (r0 1 F1 + r0 2 F2 + r0 3 F3 + r0 4 F4 ) = 0 rA0 (F1 + F2 + F3 + F4 ) = 0 F =0 (r0 1 F1 + r0 2 F2 + r0 3 F3 + r0 4 F4 ) = 0 M0 = 0 So taking moment about a new point gives no additional info. 5