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1. SOMMA PIU DIFFERENZA
RAGIONANDO SUL SEMIPERIMETRO DEL RETTANGOLO I CALCOLI SARANNO PIU SEMPLICI
QUINDI, DIVIDENDO IL PERIMERITRO 2p IN DUE PARTI OTTENIAMO IL SEMIPERIMETRO P
Perimetro/ 2 = semiperimetro, quindi..
abc = semiperimetro =p
p =2p/2 da cui
p = 138/2= 69 cm
2. SOMMA PIU DIFFERENZA
RAGIONAMENTO
Se ai due segmenti aggiungessimo la loro differenza sarebbero uguali
Quindi conoscendo la loro somma, aggiungendo la differenza e
dividendo per due ottengo la misura del segmento pi湛 grande
s + d
AB= (AB + BC) + CZ
2
G = (S + d) dove G竪 la misura + grande cio竪 AB
A
B DIFFERENZA
2
B
C
Z
3. SOMMA meno DIFFERENZA
RAGIONAMENTO
VICEVERSA
Se alla loro somma, sottraggo la differenza,
dividendo per due ottengo la misura del segmento pi湛 piccolo
s - d
BC= (AB + BC) -CZ
2
g = S - d dove g 竪 la misura + piccola BC
AB
BC DIFFERENZA
2
4. ORA TROVIAMO LA MISURA DEI DUE
SEGMENTI applicando le formule
CALCOLIAMO - segmento pi湛 grande
AB = (AB + BC) + CZ A B
2
G = AB = (S + d) dove G cio竪 AB = (69+11) = 40 m.
BC= (AB + BC) - CZ) B C z
g=BC= (S - d) dove g cio竪 BC = (69-11) = 29 m.
A = b x h = AB X BC 40X29= 1160 m.
AB
2
2
2
2 2
DIFFERENZA
5. SOMMA PIU DIFFERENZA
ANCHE PER I NUMERI
Questo ragionamento vale anche per qualsiasi
numero .. es. : se conosciamo la somma di 2 numeri
e la loro differenza applichiamo la stessa regola.
Quindi alla loro somma, aggiungendo la differenza e
dividendo per due otteniamo la misura del numero pi湛 grande
s + d
AB= (AB + BC) + BC
2
G = S + d dove G 竪 la misura + grande
AB
BC DIFFERENZA
2
6. SOMMA PIU DIFFERENZA
ANCHE PER I NUMERI
applichiamo la regola.
La somma degli anni di padre e figlio 竪 di 45 anni.
La loro differenza 竪 15. Quanti anni hanno
G = S + d dove G 竪 la misura + grande
padre = G = S + d = 45 + 15 = 30 anni
figlio = g (S d) = 45 15 = 15 anni
Et Padre + figlio = 45 anni
figlio DIFFERENZA
2
padre
2
2 2